After redrawing the circuit. We can use a short cut sir as it was a T network.... name the resistors as Ź a, zb and Zc...now Z parameters will be Za+zb Zb Zb Zb+Zc
We can also solve this problem by applying KVL in delta loop in circuit to obtain value of i' in form of i1 and can put it in our z parameters equations
The method shown is good but very lengthy. If you can convert this star network to delta or pi network and then directly using the short circuit admittance therom it will very easy and short
Thank you so much sir for your explanation mind blowing my doubt was cleared in jntua question paper the Z paramaeters are given but find y- Parameters like addmittence my mind is not working to see the question,after seen this video it's easly iam solved.thank you bro for these video 👌🙏🎇🎆😍😍
Sir can we solve the problem using KCL Equation? If we assume lower terminal as ground. Then V1 and V2 will be voltages as upper terminals. 20 ohm resistor between v1 and v2. T Network of other three in v1mand v2. We can assume A as intersection. Write KCL at 1,2,A.
Sir why can't we take current(I2") through the 20 ohm resistor as : I2"= (V1-V2)/20. ??? Problem becomes very easy using the value of this current(I2") in terms of V1 and V2. I solved and got almost same answers not exactly the same. If anybody can tell my method is right or wrong? Thanks
Underrated Channel, Amazing and clear explanation. Go ahead Sir.
Sir, U make the problem-solving look so easy. Amazing job sir. Honestly, your channel is underrated.
You're god sent sir!!
The video is really informative ..
Change the playback speed to 1.25x and thank me later
bruh, I am in 2x speed
After redrawing the circuit.
We can use a short cut sir as it was a T network.... name the resistors as Ź a, zb and Zc...now Z parameters will be
Za+zb Zb
Zb Zb+Zc
Whats about -ve sign
How he gave -z12 n 21 we don't take like this whil calculating adj.
We can also solve this problem by applying KVL in delta loop in circuit to obtain value of i' in form of i1 and can put it in our z parameters equations
Yess
Thanks so much for your lessons!
NICE AND DETAILED EXPLANATION SIR
THANK YOU SIR
Love u sir 💜 from vizag
The method shown is good but very lengthy. If you can convert this star network to delta or pi network and then directly using the short circuit admittance therom it will very easy and short
Real answer are: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12
thank you so much for clearing doubts
Super Teaching sir ......Amazing ✨
please sir upload more numerical problem on z , y parameter, h hybrids
I am getting Y11 = -Y21 = 31/260 and Y21 = - Y22 = 33/260
Can we use I1=Y11V1+Y12V2 and I2=Y21V1+Y22V2 I
Thanks Sir 😃😃
Thank you Sir for the video
I am getting different answers as
Y11=0.025,Y12=-0.015,Y21=-0.025,Y22 =0.035
Real answer are: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12
Directly we can solve through nodal analysis right ?
Guys the best method is not this it is to use nodal analysis and directly obtain the Y parameters
This lecture is not about the best method but the conventional method. This solution is important to set the tone for the upcoming lectures.
After changing from Delta to star......what happened to those 10ohm and 5 ohm resistors
All 3 resistors in delta is converted into 3 resistors in star form.. hence 20, 10, 5 ohms are disappeared to those 3 resistors..
Can we convert the inner star to delta and apply kvl?
yes you can, both are convenient though.
@@starkendeavours7072 thanks 👍
GOOD LICTUR CONTIUE
Thank you so much sir for your explanation mind blowing my doubt was cleared in jntua question paper the Z paramaeters are given but find y- Parameters like addmittence my mind is not working to see the question,after seen this video it's easly iam solved.thank you bro for these video 👌🙏🎇🎆😍😍
Which reference do you used🤔 please ,give a name
13:32 / 13:53
In Z12 and Z21, how did get - sign?
its matrics rule
how can i solve if there is capacitor instead of 10ohm and 5ohm resistor
Sir why whole current i2 will flow through 5 ohm only I think i2 will be divided into two branches initially through 5 ohm and 20 ohm
Same doubt
Sir can we solve the problem using KCL Equation? If we assume lower terminal as ground. Then V1 and V2 will be voltages as upper terminals. 20 ohm resistor between v1 and v2. T Network of other three in v1mand v2. We can assume A as intersection. Write KCL at 1,2,A.
I got the same idea. Can`t we do that?
sir for the above problem if we have delta connection of capacitor how to solve it sir ?
can anyone please explain why can't we calculate simply y parameters simply from the circuit and not through the inverse process?
i think we can do that also by using kirchoffs current law and write current equations
Me I calculated by using circuit for addmittance without using impedance and I get the same answer.
as follows: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12
Sir why can't we take current(I2") through the 20 ohm resistor as :
I2"= (V1-V2)/20. ???
Problem becomes very easy using the value of this current(I2") in terms of V1 and V2.
I solved and got almost same answers not exactly the same.
If anybody can tell my method is right or wrong?
Thanks
Forget everything and use mesh analysis
Don't get complicated, use mesh analysis to calaculate current.
Sir how to solve problem for capacitor and inductor
can we solve it directly using eq of Y parameters?
same doubt i have
Sir pls provide transient topic of network which is most imp
this is also for aktu?
Sir please make video on MATLAB
>> z1=10 z1 = 10 >> z2=20 z2 = 20 >> z3=5 z3 = 5
>> Ya=1/z1 Ya = 0.10000
>> Yb=1/z2 Yb = 0.050000
>> Yc=1/z3 Yc = 0.20000
>> Y=[Ya+Yb, -Yb; -Yb, Yb+Yc]
Y =
0.150000 -0.050000
-0.050000 0.250000
>> Zs=inverse(Y)+40*ones(2)
Zs =
47.143 41.429
41.429 44.286
🙂
🔥🔥🔥
Wheree did I²' & I²'' go
Ok
🙏❣
Bu çıkmaz
Sir,after getting Z values, can't we get Y parameters just by reciprocal of Z values
For delta to wye connection, refer to this video: ua-cam.com/video/7np1d5ez1hs/v-deo.html