Thank you so much for teaching in your personal way, not speaking at students but talking with students (in the sense that ..."do you understand where I'm comming from, do I need to further explain the concept?" The Khan Academy would be proud of your teaching style.
A cat with a trail of neon - 10mn likes. A world-class teaching video series that introduces the fundamentals of EE so people can watch neon cat on youtube - 355 likes
Your lectures are wonderfully clear. I know that it takes a lot of time to prepare such lectures. Thank you so much for spending the time and for sharing your deep understanding of electrical engineering and physics with the rest of us.
Wish you could make a deep dive into the s-parameters because in my point of view that's the gold standard of RF characterization/representation....... Anyway, great lecture, thank you for that !
The past year and a half have been rough on students. Your videos are absolutely invaluable. I'm sure others agree with me when they say your lecture style is very guided in the intuitive process behind certain aspects of electrical engineering. Thank you
So excited to see a prof that derives things. This is what I feel like has been missing from all my classes and some books. Can't wait to finish watching your lectures.
The current through a capacitor is equal to the capacitance of it self times the rate of change in the voltage across it (aka the derivative of the voltage) that gives you the following equation: $i_c(t)=C{dv_c(t) \over dt}$ if you take the Laplace transform with zero initial conditions it results $I_c(s)=CSV_c(s)$ finally the admittance is the relation between current an voltage, et voila: $Y_c= {I_c(s) \over V_c(s)} = CS$ notice that i use LaTex notation for the equations you can copy(just the thing between $...$) and paste in this online sandbox equation editor: www.codecogs.com/latex/eqneditor.php to see how it looks like Cheers! Juan Chirino
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Your way of always reminding us where things ultimately come from is very rare in instructors and much appreciated.
You are welcome.
Extremely helpful! Thank you
Exelent explanation!
Thank you so much for teaching in your personal way, not speaking at students but talking with students (in the sense that ..."do you understand where I'm comming from, do I need to further explain the concept?" The Khan Academy would be proud of your teaching style.
Thanks for your comments. I believe learning is often a collective experience.
A cat with a trail of neon - 10mn likes.
A world-class teaching video series that introduces the fundamentals of EE so people can watch neon cat on youtube - 355 likes
Your lectures are wonderfully clear. I know that it takes a lot of time to prepare such lectures. Thank you so much for spending the time and for sharing your deep understanding of electrical engineering and physics with the rest of us.
Wish you could make a deep dive into the s-parameters because in my point of view that's the gold standard of RF characterization/representation....... Anyway, great lecture, thank you for that !
The past year and a half have been rough on students. Your videos are absolutely invaluable. I'm sure others agree with me when they say your lecture style is very guided in the intuitive process behind certain aspects of electrical engineering.
Thank you
So excited to see a prof that derives things. This is what I feel like has been missing from all my classes and some books. Can't wait to finish watching your lectures.
The way he motivated use of T-Parameters was good.
I am glad you liked it.
You are an excellent teacher. I thank you for uploading these lectures.
You are welcome.
at 17:21 , is it correct if i put z21xi1 ? or it just like in the video which is z21xv1
I agree with you.
Sir , if a network has a dependent source then can we directly say that it is non reciprocal???
Please clear this doubt
where does a and b come from? in minute 4:08
1:01:05 "What is Y of a capacitor: it's C S"
Where does this come from?
The current through a capacitor is equal to the capacitance of it self times the rate of change in the voltage across it (aka the derivative of the voltage) that gives you the following equation:
$i_c(t)=C{dv_c(t) \over dt}$
if you take the Laplace transform with zero initial conditions it results
$I_c(s)=CSV_c(s)$
finally the admittance is the relation between current an voltage, et voila:
$Y_c= {I_c(s) \over V_c(s)} = CS$
notice that i use LaTex notation for the equations you can copy(just the thing between $...$) and paste in this online sandbox equation editor:
www.codecogs.com/latex/eqneditor.php
to see how it looks like
Cheers!
Juan Chirino
Hi, Professor Hajimiri, would it be possible to get a post-doc sometime in your group in the future? LOL