A beautiful explanation ma'am I like the way you teach and you explain every point. I hope every institute have the teaching faculty like you. Your work is really helping us It's the help to the society. I really appreciate your work. Thank You ma'am ones again. God bless u!
1. When taking an edge, for example V3V4, how do we know which one is the f? Do we take any one as the f? 2. How is the answer at 19:11 (1.2 , 1.8)? I put it into a calculator and I got (-1.2 , 4.2) instead. Please explain
Thanks a lot for the explanation, but your method to calculate normal vector will only work for the case you have considered. i and j coefficients of normal vector will not alway be unit or zero.
I think you need to define a normal vector that is perpendicular to the edge you are viewing and directed to the inside of your clipping area. Depending on the direction of the vector you set the values for its x and y attributes. Examples: A vector like that -----> would have values of [1,0]
What an explanation in every single video. Amazing.
A beautiful explanation ma'am I like the way you teach and you explain every point. I hope every institute have the teaching faculty like you. Your work is really helping us It's the help to the society. I really appreciate your work.
Thank You ma'am ones again. God bless u!
great work mam....you made the concept crystal clear :)
Beautifully Explained.. Hats off to you
Amazing explanatio and demonstration of the algorithm! Thank you very much for this video! :)
Thank you ma'am ☺ smjh a gayi algo 😎
1. When taking an edge, for example V3V4, how do we know which one is the f? Do we take any one as the f?
2. How is the answer at 19:11 (1.2 , 1.8)? I put it into a calculator and I got (-1.2 , 4.2) instead. Please explain
She's taking the first vertex as f.
Now I understand, thank you Jyothi!!!
awesome teaching maa'm!!
tysm:)
love you mam. you are a great teacher.
very good mam you made difficult concept in easy manner
Very useful content ma'am
Many thanx mam...🙏
awesome, now its clear
Thanks mam. It was very helpful.
I wanna question mam
If D.N is equal to 0 then what we select T upper limit or T lower limit
direction of the normal should be always away from the center of the polgyon, but you have taken it into the polygon.
Thanks a lot for the explanation, but your method to calculate normal vector will only work for the case you have considered. i and j coefficients of normal vector will not alway be unit or zero.
Very nice video for Cohen Sutherland algorithm..
loool
How to select boundary point?
Common point of two edges should be considered as boundary point for both the edges.
For every calculation you have taken point(-2, 1) then when to take (6, 3)
This algorithm doesn't put any condition on the choice of P1. That means you can consider P1 as (6,3) and get the same answer.
Thanks a lot. you are great
Teaching on par 👏
Boundary point kese choose krenge? 🙄 Example... V2 v3 mai se apne v3 hi kyun liya? 🙄
Mam there is a confusion in finding the normal vectors could you please expalin it
I think you need to define a normal vector that is perpendicular to the edge you are viewing and directed to the inside of your clipping area.
Depending on the direction of the vector you set the values for its x and y attributes.
Examples:
A vector like that -----> would have values of [1,0]
Thank u so much mam ❤
Mam, please tell me how to get the value of n??? please ans!!!
ooww, understanding
Here's how 11:26
U can check at 11.30
mam please tell me how tha value of n came
if this sign -> only indicate x-axis so the value of n [1 0] but indicate both x and y axis , so the value of n [1 1]
here's the explanation 11:26
U can check at 11.30
For edge v2v3,
V2v3.n3=0
(V3-v2).(n31-n32)=0
Whats t?
Super madam
Nice
less then 0 depicts interior and greater then zero depicts exterior i guess, ,,?
best
How to find out boundary point f ?