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hi datta thats nice observation and thanks for correction and you are correct i have done the mistake. thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.
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Good evening sir...i'm soumya..Sir please make more videos on graphics....the lectures are really helpful... topic like.bsp tree, Bezier curves.. visible surface detection method...etc..Thank u sir..
hi sridhar I would like to have a feedback from you so please make a selfie video with a feedback regarding our channel and send to my WhatsApp number 9885 466 061 expecting a feedback from you I will collect all the feedback and I will upload the feedback in my channel
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hi tanvir thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.
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Sir always we can perform logical and operation sir,, both end points are equal to zero perform logical and incase one end point is zero and another point is non zero perform logical and last case both are non zero here also perform only logical and opertatios sir is it right
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Sir ur videos are superb easy to understand alsooo so now sir it's humble request to uh please make video on nicholl lee nicholl line clipping algorithm please sir i urgently need this algorithm 🙏🙏🙏🙏🙏🙏🙏🙏🙏
But u showed we have to take only AND operation u didn't show about OR operation we have to take OR operation or not please solve my doubt This algorithm is correct or not
If 4 bit for both point is 0000 then we have to do OR operation ????but u did AND operation ,is it true??? And for p9 and p10 its completely outside the window then how is it be partial???
HI SANDEEP SHARMA IN THIS CASE WE NEED TO FIND THE INTERSECTION POINT AND REPEAT THE PROCESS. THAT MEANS IF BOTH THE POINTS ARE NON-ZEROS AND THE 'AND' OPERATION IS ZERO WE SHOULD NOT FINALIZE IT AS PARTIAL WE NEED TO FIND THE INTERSECTION POINT. HOPE YOUR DOUBT HAS BEEN CLARIFIED...
Sundeep Saradhi Kanthety sir if both the points are zero then AND operation will be zero then we want to accept it ...but it is outside the window how is it possible?
hi samarth thanks for your interest and in the next session i will upload one line clipping ( LIANG-BARSKY) and then polygon clipping algorithm(SUTHERLAND-HODGEMAN).
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thanks a million sir for explaining this so beautifully! would really appreciate if you could also share the code for this problem at the earliest, preferably in c language! Thank you again.
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hi sriaditya thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel. already given one example for every case in this video plz let me know if you feel any difficulty.
@Sundeep Saradhi Kanthety, Sir can we have example which shows clearly how to find the intersection point coordinates, when window and line coordinates are given !!!
When the AND operation of two end points is zero that does not mean that clipping is required always! It means either clipping is needed or the line is rejected
hi das exactly only if two endpoints are zeros then the line can be considered as it lies inside the window. if AND operation of two endpoints with non-zeros is zero then some part of line may be inside and some portion of line may be outside then we have to find the intersection points.
ya but you said when AND operation gives non zero that means we need to clip some part! But it may happen even if AND gives non zero we might not have to clip any part at all! like if a line starts from code 0001 through 0101 and ends in 0100
hi sudhendra thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.
sir- p8-0100 and p7-0010, both are non zero. we know if both are non zero after "and" operation result becomes non zero. but you have shown the result is "zero". how is it possible?
AND operation gives the result TRUE only if both are TRUE and if any one is FALSE the result of AND will be FALSE. here 0100 0010 --------- 0000 -------- i think its correct so if AND operation of both NON-ZEROS becomes ZERO it implies some portion lies inside the window. so we have to calculate the intersection points and follow the same procedure. Hope your doubt has been clarified.
There are loads of mistakes in this video.First you said that if after applying 'and' operation,we get 0000 this means no clipping is required and then you said partial clipping is required.Furthermore in case of p7' and p8 ,how p8 is changed from 0010 to 0100?
Hi Baishali If both the values are zeros then we can say the line is inside. If any one value is zeros and other is non-zero and if we get the result of doing AND operation as zeros then we can say the line is partial inside and partial outside. In such case we need to find the intersection point and again we have to repeat the same procedure.. I think this one is clear and correct. If you think it was wrong then plz post the correct procedure so that all the viewers will be get corrected. Waiting for the correct procedure from you.
hi sinha here the line p1 & p2 completely lies outside the clipping window so we can reject that line. but in the line p7 & p8 some portion of the line lies inside and some portion lies outside the window that mean some intermediate points lies inside the window so i said it as partial case. hope your doubt has been clarified.
Thanks a lot sir bcoz,i found this at last day before my exam was started and it really helped me a lot
This video is best to watch at speed 1.25. Nicely explained
Sir u r great world needs great gurus like u
hi shivam
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Perfectly explained sir... But plz increase your sound quality...
And plz. Do upload mathematics on line clipping.
Thank you.
Sir ! in 21.02 min u told that region code of p8 is 0010 but according to ABRL formula region code of p8 is - 0100 .
hi datta
thats nice observation and thanks for correction and you are correct i have done the mistake.
thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.
Thanks sir your lectures are very clear and easy
Marvellous lecture sir! Thank God I found your tutorial 😊
You are a excellent Guru.
thank you senthil
hi senthil
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Good evening sir...i'm soumya..Sir please make more videos on graphics....the lectures are really helpful... topic like.bsp tree, Bezier curves.. visible surface detection method...etc..Thank u sir..
Absolutely Rocking Sir
hi Amit
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Very well explained. Thank you very much for your time.
Thank u very much sir. I have learned a lot from ur videos
hi sridhar
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Sundeep Saradhi definitely sir
thank you sridhar
Sir thank you for this video ... helped me well.. keep this going
hi devil dota2
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Nice idea to fill an region code ,superb sir! pls do more videos
thank you moan for your interest towards our channel and if you like my videos share with your friends.
Sundeep Saradhi sure sir
hi mani
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Awesome presentation Sir.
sir really very helpul all lectures keep it up
hi
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Sir important question teaching I'm very useful
region code finding is soooper siir..
Thank u for ur easy explaination
Thank you sir.
It's very helpful.
hi tanvir
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Thank you sir...very useful
thank you sir ...very uesful
hi archana
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Thank you sir for all your videos. Helped me a lot
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Awesome explanation.thank you
hi
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Sir always we can perform logical and operation sir,, both end points are equal to zero perform logical and incase one end point is zero and another point is non zero perform logical and last case both are non zero here also perform only logical and opertatios sir is it right
Keep up the good work
Thanks sir for ur precious time
hi ishan
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thank you sir, very help full
Thank you very much sir, you nailed it
hi chakandinakira
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Do we need to find the intersection points too and if yes then by which method or algorithm we should do?
sir what should be done on last case? reject it or find intersection? Some1 pls clarify on dis.
Sir pls tell me.... Ki Sutherland hodgeman and polygon clipping algorithm are same procedure to solve questions? I m very confused
Sutherland hodgeman is one of the polygon clipping algorithm.
U r awesome sir😊
hi das
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Sir ur videos are superb easy to understand alsooo so now sir it's humble request to uh please make video on nicholl lee nicholl line clipping algorithm please sir i urgently need this algorithm 🙏🙏🙏🙏🙏🙏🙏🙏🙏
hi Thakur
sorry to say i am not much aware of that algorithm.
Sundeep Saradhi ok sir😢
Thanks a lot sir.
hi naima
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thank you sir , greetingl from indonesia
Sir I think you have mixed OR with X-OR.
sir where is concept of finding slope and points on the window edge of the lines which are partially outside the clipping window
sir... this example is insufficient. we also need to get the intersection points,slope concepts.
excellent explanation... thank u so much :-)
hi swati
thanks for watching my sessions and if you like my sessions share with your friends.
sir,,, when line is inside:::::or operation is applied u need to correct
hi javist
yes corret
But u showed we have to take only AND operation u didn't show about OR operation we have to take OR operation or not please solve my doubt
This algorithm is correct or not
Thanks sir! Helpful
hi
thanks for your interest towards our channel and share my sessions with your friends and subscribe to our channel.Keep following our channel.
If 4 bit for both point is 0000 then we have to do OR operation ????but u did AND operation ,is it true??? And for p9 and p10 its completely outside the window then how is it be partial???
hi neetu
i think we have to do AND operation itself. if you thought i am wrong plz post the correct one so that it will make viewers easy to learn.
sir what will happen for p9- p10..they are completely outside but according to algo this is partially inside.. now what will happen....?
HI SANDEEP SHARMA
IN THIS CASE WE NEED TO FIND THE INTERSECTION POINT AND REPEAT THE PROCESS.
THAT MEANS IF BOTH THE POINTS ARE NON-ZEROS AND THE 'AND' OPERATION IS ZERO WE SHOULD NOT FINALIZE IT AS PARTIAL WE NEED TO FIND THE INTERSECTION POINT.
HOPE YOUR DOUBT HAS BEEN CLARIFIED...
sir it means. we will check intersection point repeatedly until we find that both point are non zero?
yes we need to check continuously until both points are equal to zero.
Sundeep Saradhi Kanthety sir if both the points are zero then AND operation will be zero then we want to accept it ...but it is outside the window how is it possible?
Sir, please upload a video on polygon clipping.
hi samarth
thanks for your interest and in the next session i will upload one line clipping ( LIANG-BARSKY) and then polygon clipping algorithm(SUTHERLAND-HODGEMAN).
Sir the region code for p8is 0100...bt u have written 0010 for p8
It's happened by mistake....but result don't vary😄
thank you so much indeed
Sir p1 region code 0001 ala vachindi sir...
Thanks sir 👌👍
very helpful lectures sir....thank you
hi roop
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Please upload more videos on computer graphics...
hi swarup
definitely i will upload more.
Please make a video on Bresenham circle algorithm and mid point line algorithm ASAP
hi swara
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Sir please add videos of visibility like z -buffer algo, depth sort algo, scan line algo
thank you my brother sir!
thanks a million sir for explaining this so beautifully!
would really appreciate if you could also share the code for this problem at the earliest, preferably in c language!
Thank you again.
hi joseph
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Sir at last you should have solved one problem on it for the better idea of the problem
sir,why p7&p7' and p8&p8' are clipped?
hi swathi
here p7&p7' and p8&p8' are outside the window so they are clipped.
How the p5dash got 0000 please explain sir
Super sir
sir please upload a vedio on example regarding this
hi sriaditya
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already given one example for every case in this video plz let me know if you feel any difficulty.
@Sundeep Saradhi Kanthety, Sir can we have example which shows clearly how to find the intersection point coordinates, when window and line coordinates are given !!!
When the AND operation of two end points is zero that does not mean that clipping is required always! It means either clipping is needed or the line is rejected
hi das
exactly only if two endpoints are zeros then the line can be considered as it lies inside the window.
if AND operation of two endpoints with non-zeros is zero then some part of line may be inside and some portion of line may be outside then we have to find the intersection points.
ya but you said when AND operation gives non zero that means we need to clip some part! But it may happen even if AND gives non zero we might not have to clip any part at all! like if a line starts from code 0001 through 0101 and ends in 0100
oh ok sorry may be i may explained wrong and thanks for the correction.
Sir at point p7 and p8 the intersection point concept is not working as u applied that at point p5 and p6
Please clear it.
yes in the P7 & P8 we have to find two intersection points by following the same procedure.
sir cyrus beck algo nd mid point subdivision clipping algo upload kr dijiye
sir u r amazing
Thank you saurabh kumar
Sir can you cover hidden surface and hidden line removal topic from computer graphics
hi rekha srinivas
sorry i am not much aware of those concepts so i didn't uploaded the videos.
thank you sir
WHAT IS 'AND' OPERATION?
Logical AND
0.0=0
0.1=0
1.0=0
1.1=1
SIr, you didn't explained the last case i.e, P9 & P10 .
i need to know the answer of it.
hi pratap
visually P9 and P10 lies outside the window
practically apply the same procedure for both the points so that you will get the same.
completely outside the window so just ignore and no clipping will be performed.
thank you so much
Thank you
awesome
hi sudhendra
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Sir plz explain cohens Sutherland program
sir- p8-0100 and p7-0010, both are non zero. we know if both are non zero after "and" operation result becomes non zero. but you have shown the result is "zero". how is it possible?
AND operation gives the result TRUE only if both are TRUE and if any one is FALSE the result of AND will be FALSE.
here
0100
0010
---------
0000
--------
i think its correct so if AND operation of both NON-ZEROS becomes ZERO it implies some portion lies inside the window. so we have to calculate the intersection points and follow the same procedure.
Hope your doubt has been clarified.
Gud video :)
Hi Malayalam Tips & Tricks
Thank you
There are loads of mistakes in this video.First you said that if after applying 'and' operation,we get 0000 this means no clipping is required and then you said partial clipping is required.Furthermore in case of p7' and p8 ,how p8 is changed from 0010 to 0100?
Hi Baishali
If both the values are zeros then we can say the line is inside.
If any one value is zeros and other is non-zero and if we get the result of doing AND operation as zeros then we can say the line is partial inside and partial outside. In such case we need to find the intersection point and again we have to repeat the same procedure..
I think this one is clear and correct.
If you think it was wrong then plz post the correct procedure so that all the viewers will be get corrected.
Waiting for the correct procedure from you.
Still waiting for your solution Baishali, getting old.
boi we're waiting for your reply.
sir ho sake to jaldi upload karna..
Join your ✋ hands with "unacedamy"
hi gaurav
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Video is not clear
Chacha zor s bola kro
not good do correction in ur video
hi shivani
pls tell me where and what correction i have to do in this video.
hi sinha
here the line p1 & p2 completely lies outside the clipping window so we can reject that line.
but in the line p7 & p8 some portion of the line lies inside and some portion lies outside the window that mean some intermediate points lies inside the window so i said it as partial case.
hope your doubt has been clarified.
use your brain
Thank you