A Level Physics Revision: All of Circular Motion (in under 20 minutes! )

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  • Опубліковано 23 лис 2024

КОМЕНТАРІ • 125

  • @lxghttt
    @lxghttt 6 місяців тому +36

    This man explained 2 hours worth of my school lectures in under 20 minutes, absolute life saver

  • @JoséAntonioBottino
    @JoséAntonioBottino 2 місяці тому +4

    In a Uniform Circular Motion, the linear speed (tangential speed) v remains constant.
    If the object makes n revolutions (cycles) in a time t, then it travels a distance s
    s = 2 • 𝜋 • r • n
    where n is the “number of revolutions”, n is dimensionless, n has unit rev/rev = 1.
    Since v = s / t, then
    v = (2 • 𝜋 • r • n) / t
    Since v = ω • r, then
    ω • r = (2 • 𝜋 • r • n) / t.
    This implies that
    ω = (2 • 𝜋 • n) / t
    If ω = 2 • 𝜋 • f, where f is the frequency, then.
    2 • 𝜋 • f = (2 • 𝜋 • n) / t.
    This implies that
    f = n / t
    or what is the same, the frequency f is the number of revolutions (cycles) per unit time (usually seconds).
    The unit of f should be
    (rev/rev)/s = Hz = 1/s
    equal to the number of revolutions per second [nrps = (rev/rev)/s, if the custom is to be maintained], and not in revolutions per second (rps = rev/s).
    The unit hertz (Hz) replaced the unit cycles per second, which was actually the number of cycles per second.
    Given that the period T = 1 / f, then
    T = t / n.
    Since the period T is the time it takes for the object to complete one revolution (one cycle), then the unit of T is:
    s/(rev/rev) = s
    equal to seconds per number of revolutions (second per number of cycles).
    As
    ω = θ / t
    and θ is the number of radians, θ is dimensionless, θ is measured in rad/rad = 1, that means that ω must be measured in
    (rad/rad)/s = 1/s = s^(-1)
    and not in rad/s.
    It is understood that in the formula
    ω = 2 • 𝜋 • f
    the unit conversion is
    1 (rad/rad)/s = 2 • 𝜋 • (rev/rev)/s
    so
    1 (rad/rad) = 2 • 𝜋 • (rev/rev).
    There the 2𝜋 allows us to go from “number of revolutions” (rev/rev) to “number of radians” (rad/rad).
    I will highlight the difference between the unit of angular speed, which seems to be 1/s and the unit of frequency which also appears to be 1/s. They are different. Hertz is number of revolutions per second (nrps) while angular speed is the number of radians per second (nrad/s, stretching the notation a bit).
    I will leave another comment where I show how to obtain the formula
    s = θ • r
    and what the variables represent.

  • @thealien4372
    @thealien4372 Рік тому +12

    i’ve watched all your videos this past week, certified chad

  • @ryanzdon
    @ryanzdon 6 місяців тому +8

    Coming back to this when I get my A in physics

  • @chanduliyatigala7341
    @chanduliyatigala7341 2 роки тому +25

    Thank you for the great explanation!! Bless you🙏

  • @shahadamjad3691
    @shahadamjad3691 Рік тому +24

    great explanation !! love your work

    • @zhelyo_physics
      @zhelyo_physics  Рік тому

      thanks a lot for your comment! Much appreciated!

  • @itzchaotic5518
    @itzchaotic5518 Рік тому +8

    Loving the background music on this one! Thank you for the videos :P

  • @zaffresand1720
    @zaffresand1720 2 місяці тому +1

    Brilliant explanation thank you!

  • @MarkQub
    @MarkQub 2 роки тому +122

    2x speed 10 mins 😁

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому +15

      😆 so true!

    • @herolivesnu
      @herolivesnu Рік тому +8

      I like his speed, no need for 2* speed. If you don't have enough data, buy more to enjoy his insightful tutorial, so that you won't miss a thing in your quest to save data.

    • @popo-os9qr
      @popo-os9qr Рік тому +27

      ​@herolivesnu it's not that deep man

    • @xodusgraphicdesigns3384
      @xodusgraphicdesigns3384 Рік тому +1

      Maths not mathing

    • @Jee-c8d
      @Jee-c8d 7 місяців тому +2

      ​@@herolivesnu this is 2024 bro , 😂

  • @jamieclifton2832
    @jamieclifton2832 2 роки тому +13

    This is really helpful thank you!

  • @amnashaikh-sl1qi
    @amnashaikh-sl1qi 11 місяців тому +2

    thank you for this!

  • @JoséAntonioBottino
    @JoséAntonioBottino 2 місяці тому +2

    Many people wonder why radians do not appear when we have radians*meters (rad • m).
    Here is an attempt at an explanation:
    Let s denote the length of an arc of a circle whose radius measures r.
    If the arc subtends an angle measuring β = n°, we can pose a rule of three:
    360° _______ 2 • 𝜋 • r
    n° _______ s
    Then
    s = (n° / 360°) • 2 • 𝜋 • r
    If β = 180° (which means that n = 180, the number of degrees), then
    s = (180° / 360°) • 2 • 𝜋 • r
    The units "degrees" cancel out and the result is
    s = (1 / 2) • 2 • 𝜋 • r
    s = 𝜋 • r
    that is, half of the circumference 2 • 𝜋 • r.
    If the arc subtends an angle measuring β = θ rad, we can pose a rule of three:
    2 • 𝜋 rad _______ 2 • 𝜋 • r
    θ rad _______ s
    Then
    s = (θ rad / 2 • 𝜋 rad) • 2 • 𝜋 • r
    If β = 𝜋 rad (which means that θ = 𝜋, the number of radians), then
    s = (𝜋 rad / 2 • 𝜋 rad) • 2 • 𝜋 • r
    The units "radians" cancel out and the result is
    s = (1 / 2) • 2 • 𝜋 • r
    s = 𝜋 • r
    that is, half of the circumference 2 • 𝜋 • r.
    If we take the formula with the angles measured in radians, we can simplify
    s = (θ rad / 2 • 𝜋 rad) • 2 • 𝜋 • r
    s = θ • r
    where θ denotes the "number of radians" (it does not have the unit "rad").
    θ = β / (1 rad)
    and θ is a dimensionless variable [rad/rad = 1].
    However, many consider θ to denote the measure of the angle and for the example believe that
    θ = 𝜋 rad
    and radians*meter results in meters
    rad • m = m
    since, according to them, the radian is a dimensionless unit. This solves the problem of units for them and, as it has served them for a long time, they see no need to change it. But the truth is that the solution is simpler, what they have to take into account is the meaning of the variables that appear in the formulas, i.e. θ is just the number of radians without the unit rad.
    Mathematics and Physics textbooks state that
    s = θ • r
    and then
    θ = s / r
    It seems that this formula led to the error of believing that
    1 rad = 1 m/m = 1
    and that the radian is a dimensionless derived unit as it appears in the International System of Units (SI), when in reality
    θ = 1 m/m = 1
    and knowing θ = 1, the angle measures β = 1 rad.
    In the formula
    s = θ • r
    the variable θ is a dimensionless variable, it is a number without units, it is the number of radians.
    When confusing what θ represents in the formula, some mistakes are made in Physics in the units of certain quantities, such as angular speed.
    My guess is that actually the angular speed ω is not measured in rad/s but in
    (rad/rad)/s = 1/s = s^(-1).

  • @huzaifagujjar2762
    @huzaifagujjar2762 2 роки тому +6

    Great explaination sir

  • @JoséAntonioBottino
    @JoséAntonioBottino 2 місяці тому

    At minute 3:44 you say that "we will also need to remember how to convert from rpm, which is revolutions per minute to radians per second for our units for our angular velocity". Revolutions per minute is a measure of frequency f, not angular velocity, and should not be rpm, but “number of revolutions per minute”, which could be renamed nrpm [nrpm = (rev/rev)/min], to follow custom. On the other hand, rad/s is not the unit of angular velocity as most of the scientific community believes and the International System of Units (SI) says. It should actually be
    (rad/rad)/s = 1/s = s^(-1)
    which is the “number of radians per second”. A subtle difference that is due to the fact that in the formula
    ω = Δθ/Δt
    the variable θ represents the number of radians of the angle measurement; it is a dimensionless variable, its unit is
    rad/rad = 1.
    I am going to write two more comments. In the first one I will try to clarify the Uniform Circular Motion and in the second one how to obtain the formula
    s = θ • r
    and what the variables represent, especially θ.

  • @HasanSheikh66
    @HasanSheikh66 2 місяці тому

    For the experiment. We are keeping the radius constant and since it is a straight line gradient is going to be constant, given that m = grad × r . Mass should also have a fixed value. How can this be possible when we are varying mass.

    • @zhelyo_physics
      @zhelyo_physics  2 місяці тому +1

      excellent question, the mass of the bung remains constant which is what is experiencing the acceleration. We are varying the added mass underneath the string and hence the force. Hope this helps!

  • @khyateeatolia9904
    @khyateeatolia9904 Рік тому +6

    Hello sir, thank you for your videos. Quick question- banked roads are not covered here... is there a separate video on that?

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +4

      Anytime! I have a detailed video on this here: ua-cam.com/video/K8bb8_Ufc1k/v-deo.html

  • @judeabumurshed4625
    @judeabumurshed4625 2 роки тому +6

    thank you for this !! but the background music is distracting.

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому +2

      I agree! I think this was one of the last videos I did with music : )

  • @vadapav777
    @vadapav777 2 роки тому +6

    Bro u explained very well but the way u write r , i understand that is r after the half video 😅

  • @deren6022
    @deren6022 Рік тому +2

    Thank you so much!! Amazing vid

    • @zhelyo_physics
      @zhelyo_physics  Рік тому

      Anytime! Thanks for the comment!

    • @deren6022
      @deren6022 Рік тому

      @@zhelyo_physics you're the best!! two days until my finals and you saved my life sir thank YOU

    • @saywaat3863
      @saywaat3863 Рік тому +1

      @@deren6022 what did u get

  • @shalfey_sage
    @shalfey_sage День тому

    Hi there!! Thank you soso much! I have a question tough:
    In the 8:01 experiment you say that weight of the mass provides centripetal force. However, by definition centripetal force acts towards the center of the circle, so in case of the bung whirling experiment it is tension, if I am not mistaken. Moreover, weigth of the mass is actually perpendicular to the radius of the circle... SOohow can it provide centripetal force and how do you calculate that tension?
    Thank you!

    • @zhelyo_physics
      @zhelyo_physics  6 годин тому

      Excellent question, so the tension always acts along the string meaning that the force is redirected at the top of the glass cylinder. Hope this helps!

  • @abdulhadiyaseen1288
    @abdulhadiyaseen1288 2 роки тому +6

    Hi. Really love your tutorials!!!! I want to ask that do you solve topical/paper questions?
    Thanks!

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому +3

      Hi I have solved a huge amount of past papers questions, you can check them here: ua-cam.com/play/PLSygKZqfTjPCuytpobPNdrLlcqePzXIq8.html

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому +4

      ua-cam.com/play/PLSygKZqfTjPDC32W1_5X73bidHeCHjTFo.html and here by topic

    • @abdulhadiyaseen1288
      @abdulhadiyaseen1288 2 роки тому +6

      @@zhelyo_physics OMG!!!! You are my A2 saviour. You deserve huge respect!

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому +2

      No problem! Good luck with the A2 year!

  • @ThomasScholes-x1r
    @ThomasScholes-x1r Рік тому

    This channel will get me into uni i swear 😂

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +1

      If you have the diligence to be going over videos, you already have the work ethic to go to uni. Well done and good luck!

  • @smartgreenhat5383
    @smartgreenhat5383 6 місяців тому

    I like the background music. What's it called?

  • @moisesnavarro6269
    @moisesnavarro6269 Рік тому +1

    Your work I love ❤️

  • @HasanSheikh66
    @HasanSheikh66 2 місяці тому

    For the experiment. Given that we are varying mass, shouldn't force be on the x-axis

    • @zhelyo_physics
      @zhelyo_physics  2 місяці тому +1

      at A-Level, we often chose what's on the axis for ease of what the gradient would be rather than strictly the variable being dependent/independent unless the questions asks for. To answer your question - both graphs would be accepted in a question as long as your gradient is correct. Hope this helps!

    • @HasanSheikh66
      @HasanSheikh66 2 місяці тому

      ​​@@zhelyo_physicsThanks

  • @dipeshkhadka5605
    @dipeshkhadka5605 Рік тому +1

    thanks

  • @luddy20
    @luddy20 Рік тому +5

    Hi sir do you have any vids for simple harmonic motion preferably damping and resonance, I have my exams soon and I need to cover that! thanks again :)

    • @zhelyo_physics
      @zhelyo_physics  Рік тому

      I do! Check out the relevant section here: ua-cam.com/video/bZ2FHLm_X64/v-deo.html Good luck!

    • @luddy20
      @luddy20 Рік тому +4

      @@zhelyo_physics you're an absolute legend, thanks so much sir! your vids are the best to binge before an exam

  • @As-iy2ki
    @As-iy2ki Рік тому

    At 15:58 why would R be greatest at that point. I know R will be equal to weight + centripetal force but why? If I were to look at a diagram of a plane in a loop or mass in a string and look to the lowest point (in this case 2) why would R be the greatest?

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +1

      So R equals weight + centripetal because the centripetal force is just another word for the resultant force when something is moving in a circle. I.e. Fresultant=R-mg (as they are in opposite) direction so R=Fresultant+mg
      intuitively, at this point R has two jobs:
      1) balance out gravity
      2) provide an additional component to keep it moving in a circle
      At the top gravity acts straight down and makes it turn into a circular orbit.
      Hope this helps!

  • @manujamethsith
    @manujamethsith 3 місяці тому

    what the hell is wrong with the letter r in the equation btw explanation is marvelous I couldnt get any shit they told in school but i got this so easily from you

  • @trexay2766
    @trexay2766 11 місяців тому

    Do you have a video for thermodynamics and fluids/pressure ?

    • @zhelyo_physics
      @zhelyo_physics  11 місяців тому

      For thermal - check those out:
      ua-cam.com/video/Usf8_ggnHc0/v-deo.html
      ua-cam.com/video/xgazuykYLDs/v-deo.htmlsi=9sSSxTOFBUVxAJ5L
      ua-cam.com/video/RLDX59ATeeA/v-deo.htmlsi=ABQIcS1W4xZqZ_yn
      I don't have a dedicated fluids video yet but thanks for the idea.

  • @Ngongang-bp1nc
    @Ngongang-bp1nc 6 місяців тому

    thanks

  • @wilfbond417
    @wilfbond417 Рік тому

    Great vid thank you

  • @cyclode
    @cyclode Рік тому +1

    Hello sir, are ur summarizations of all A2 level topics good for CAIE board?

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +1

      Yes, the physics is almost identical, you should always have your syllabus on hand to check if something is missing. The only difference is AC current but I am working on it. Good luck revising! : )

    • @cyclode
      @cyclode Рік тому

      @@zhelyo_physics thank you so much for your reply. i will use these videos then. will wait for the AC currents one too! 😄

  • @websterchidyagwai4771
    @websterchidyagwai4771 Рік тому

    Great teacher thank u man

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +1

      anytime!

    • @websterchidyagwai4771
      @websterchidyagwai4771 Рік тому

      @@zhelyo_physics I really appreciate sir u have helped me a lot on circular motion

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +1

      fantastic to hear! In this playlist you can find all my similar revision videos, including paper 3 ones: ua-cam.com/play/PLSygKZqfTjPC3hJ7nRSnnXTw3tI_o67dR.html&si=D1smgnBs_h4JkFgj

  • @abi4513
    @abi4513 4 місяці тому

    Love form srilanka

  • @major8409
    @major8409 Рік тому

    What is meant by circular displacement and how is it calculated ? Thanks

    • @zhelyo_physics
      @zhelyo_physics  Рік тому

      so it's the angular displacement, and it's just how much of an angle would the arc have covered, for instance one full circle is 360 degrees or 2pi rad, half a circle 180, pi, etc. Hope this helps!

  • @lilyxia9402
    @lilyxia9402 Рік тому

    really clear👍

  • @S_H-R
    @S_H-R Рік тому

    Nice video sir
    Stay happy

  • @major8409
    @major8409 Рік тому

    I’m doing OCR A level and on our text book is says that learning the conical pendulum stuff is extension - beyond the specification. Is the conical pendulum maybe outdated , as I know you teach OCR A. Thanks

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +2

      Absolutely not outdated, still definitely appears in many different situations. e.g. here is a question from the new spec: ua-cam.com/video/aQ0RBmazN4k/v-deo.htmlsi=a217IZAmqG7CqNWC

    • @major8409
      @major8409 Рік тому

      @@zhelyo_physics thanks for the fast reply

  • @Ash-ku7up
    @Ash-ku7up 2 роки тому +1

    Could you solve questions aswell

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому +1

      Sure! I have done that already here:
      ua-cam.com/video/jfUI7vJ7Owo/v-deo.html
      ua-cam.com/video/ICCNb0jQb_o/v-deo.html
      ua-cam.com/video/R1XNIOmnTwg/v-deo.html I hope these are helpful!

  • @sportmaster2586
    @sportmaster2586 2 роки тому +1

    Sir, is the force perpendicular to the velocity in an elliptical orbit ?

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому +2

      mmm that is an excellent question. I might have to think about it more deeply or make a video about it. For a highly eliptical orbit, there will be parts where F is not perpendicular to the velocity vector.

    • @sportmaster2586
      @sportmaster2586 2 роки тому

      @@zhelyo_physics Thanks!

  • @THE_LAST_STYLEBENDER
    @THE_LAST_STYLEBENDER 6 місяців тому

    hi sir, at 10:47 why would that equation work out the mass of the bung?

    • @zhelyo_physics
      @zhelyo_physics  6 місяців тому

      M is the weight which causes the bung to spin. Think of it this way, Mg=Net Force Net Force=ma, a is centripetal so a is mv^2/r, I.e. Mg=mv^2/r hope this helps

  • @ebadur-rahman3741
    @ebadur-rahman3741 Рік тому

    at 15:36 why did u subtract mg from R why couldn't you subtract R from mg can you explain it pls

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +1

      So in position two they are in opposite direction, R is up, mg is down so they have opposite signs.
      In position one they are both pointing in the same direction so we need to add them.
      check out my explanation here also: ua-cam.com/video/yt3h_HtI9WU/v-deo.htmlsi=Y115c-McL2HndV5f
      Hope this is helpful!

    • @ebadur-rahman3741
      @ebadur-rahman3741 Рік тому

      @@zhelyo_physics appreciate the clear explanation, so we take the upwards force as + and the downwards as - right?

  • @bBenzopyrrole
    @bBenzopyrrole Рік тому

    thanks a lot

    • @zhelyo_physics
      @zhelyo_physics  Рік тому

      Happy to help

    • @bBenzopyrrole
      @bBenzopyrrole Рік тому

      @@zhelyo_physics just finished my circular motion test, went really well thanks to the video, great help Sir

  • @Liupiu27
    @Liupiu27 Рік тому

    Can i watch this for Cambridge

  • @nikolayyordanov8986
    @nikolayyordanov8986 2 роки тому +4

    Hi, for the circular motion would the object be heavier at position 2, or at least the tension in the thread (if it had a thread) would be higher? I quite confused. Thank you!

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому +4

      Yep! We will experience a higher normal reaction, R, which will be mv^2/r + mg, the higher the speed, the larger R will be. You can feel that in a roller coaster as you are going down the loop (scary! : ) )

  • @Bobbio_Shop
    @Bobbio_Shop 2 місяці тому

    13:44 why does the m cancel out?

    • @zhelyo_physics
      @zhelyo_physics  2 місяці тому

      So if you eliminate the tension from the two equations you get m on both sides meaning you can divide both sides by m. Hope this helps!

  • @Rahim103.5
    @Rahim103.5 Рік тому

    3:18 wdym by tangential

    • @zhelyo_physics
      @zhelyo_physics  Рік тому

      the speed in the direction of motion (the tangent to the circle), can also refer to the tangential displacement, you can also call it linear speed. Hope this helps!

  • @taetamic
    @taetamic Рік тому

    Are these videos good for A2 Edexcel?
    Also, are there any videos for Further Mechanics of Unit 4?

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +1

      Hi, they are directly applicable to edexcel. I would say always use the spec as a checklist to make sure something is missed out (if there is anything missing , please leave a comment).
      What topics are included in further mechanics unit 4? I might have some.

    • @taetamic
      @taetamic Рік тому

      @@zhelyo_physics Unit 4-
      1) Further Mechanics covers impulse, conservation of momentum in two dimensions and circular
      motion.
      2) Electric and Magnetic Fields covers Coulomb’s law, capacitors, magnetic flux density and the laws of
      electromagnetic induction.
      3) Nuclear and Particle Physics covers atomic structure, particle accelerators and the standard quark-lepton
      model.
      Sir, do you have these? I really like your explanation so I wish to learn the whole A2 concept watching your videos but I'm under Edexcel.

    • @zhelyo_physics
      @zhelyo_physics  Рік тому

      ua-cam.com/play/PLSygKZqfTjPC3hJ7nRSnnXTw3tI_o67dR.html all covered in this playlist

  • @lilly8495
    @lilly8495 Рік тому +1

    ماني فاهمه شي بس تسلم👍

  • @varrickvarrick1792
    @varrickvarrick1792 Рік тому

    Please cut the music next time 🙏

    • @zhelyo_physics
      @zhelyo_physics  Рік тому +1

      hehe this is one of the older ones and all subsequent ones have no music : )

  • @Muttalib1
    @Muttalib1 2 місяці тому

    can you mute the music next time please

    • @zhelyo_physics
      @zhelyo_physics  2 місяці тому

      yep I removed the music for pretty much all subsequent videos : )

  • @abdinan
    @abdinan 2 роки тому

    What causes weightlessness at the top of a loop the loop

    • @zhelyo_physics
      @zhelyo_physics  2 роки тому

      a lack of normation reaction which is what causes the sensation of weight

  • @IbrahimAli-ku9ig
    @IbrahimAli-ku9ig 6 місяців тому +1

    The music in the background is quite distracting. The video would be better if it was just your voice

    • @zhelyo_physics
      @zhelyo_physics  6 місяців тому +1

      I agree, that's why I haven't had music in any of my later videos.