I am hemi-spherically balanced which means I use both sides of my brain equally which is and advantage when it comes to grasping some form of most kinds of concepts but I cannot use one side more than the other. In other words when I need to do math unless my visual side is stimulated it takes me twice as long as people only using the logic side of their brains. So I need visual representation as well as equations to understand complex concepts. You are the person I needed. Excellent cues make me focus when I need to pay attention to small but differentiating variables. Not to sound crude but there is an audible tone change in your voice. Reminds me of the clickers they use for dogs to get them to focus on the action.(Classical Conditioning) My Stats and Chemistry Professors taught the same dry all left brain way but it took my MFT Professor to teach the way I needed. So I want to thank you for helping me through what is my last class to receive my BS in Psychology. Keep it up...
rickeisha steele Thanks for the feedback bro. Now that you understand it, just put the time into practicing it and you'll do great. Best wishes, let me know how it goes.
LOVE YOUR VIDEOS !!! Im wondering if you can help me out with this problem ! 2 H2(g) + O2(g) → 2 H2O(l) Suppose we carry out the above reaction with 30.0 g of O2 and 4.00 g of H2. (a) Which reactant is the limiting reactant? (b) How much of the other reactant remains at the end of the reaction? (c) What mass of water is produced? In part a - I found that the limiting reactant is oxygen and hydrogen is in excess, can you help me with the other two please?
In the last problem i tried it myself before you would do it and i endid up doing it differently and i dont know if it is right or wrong ? here is what i did. i tranformed 150ml into 0.15l i multiplied 58.5(NaCL) times 3mol =175.5 and then i divided 175.5 and 0.15= 26.32g
(you dont have to solve it, just my question in the bottom) So what if it asks the molarity of Na+ in the solution when .20 mol of Na2SO4 is dissolved in water to produce 100 mL of solution. Do I have to multiply by 2 in order to get the molarity of Na+*
thericate Bingo. Bear in mind that the molarity expressed is for the ionic compound. When it dissociates, you'll have 2x the Na+ ions. In the end, you'll have to divide by the volume to get the molarity.
Thank you so much, I finally understand it now! You're much more clearer and to the point than my teacher.
LaurenJoeyandme So stoked that you got it bro. Be awesome in chem!
I've been suffering because of silly stuff and you came out here like an angel and saved my life. Thank you very much sir.
I have a super important chemistry exam coming up and your videos are the only thing that have helped me understand anything. Thank you so much.
Natalia Alexandrov you study when the exam is like tomorrow right ? Lmao
You're the reason I passed Chemistry. I really wish that you were my teacher.
Thank so so SOOO much!
That is like the coolest thing to hear! You made my day!
sciencepost yeah I think we can all agree we wish you were our teacher!!💕💕🥰
Oh my gosh you actually speak a language I can understand!! THANK YOU!!!
Thanks for the kind words, sometimes chem is a foreign language!
You're a life saver ! I was confused on my homework but I understand it all now. great video !
"alraight dudes" thanks for the video!
leoverpowerednoob Right on dude! Be awesome in chem!
Loved it! I liked that your problems went from basic and walked through rearranging formulas and conversions :)
That is so cool to hear that the video worked for you! Keep up you hard work!
Thank you, this helped me with a problem I was stuck on, continue making videos like this if you can!
adam burros Right on Adam! Thanks for tuning in! Try my playlist ua-cam.com/play/PL2000C71D43F2EEE2.html
Thanks soo much. your so much better than my chemistry teacher!!
Was stuck trying to figure this out on my own for almost an hour... thank you!!
Excellent Video!
Thank you so much for clarifying this. I am very confident now. Ready to write the test.
Thanks so much! I was freaking out over this for my test this week and I finally got it down!
Fantastic video! Extremely helpful!
Thank you so much all of your videos are so helpful! I have exams this week and this makes me feel so much better about them!
That's awesome! Keep studying!
I am hemi-spherically balanced which means I use both sides of my brain equally which is and advantage when it comes to grasping some form of most kinds of concepts but I cannot use one side more than the other. In other words when I need to do math unless my visual side is stimulated it takes me twice as long as people only using the logic side of their brains. So I need visual representation as well as equations to understand complex concepts. You are the person I needed. Excellent cues make me focus when I need to pay attention to small but differentiating variables. Not to sound crude but there is an audible tone change in your voice. Reminds me of the clickers they use for dogs to get them to focus on the action.(Classical Conditioning) My Stats and Chemistry Professors taught the same dry all left brain way but it took my MFT Professor to teach the way I needed. So I want to thank you for helping me through what is my last class to receive my BS in Psychology. Keep it up...
Thanks for the feedback. I'm glad the video worked you you. I did the best that I could when I made them. Keep up the great effort on your part!
THANK YOU I HAVE MY CHEM TEST TODAY. SAVED ME A FEW POINTS ;)))
Thanks for taking the time to work out the problem and leaving a comment.
best video as help me so much of the confusion of molarity problem I thank you so much for making this video,,,,,,, hope I pass my test this Friday
rickeisha steele Thanks for the feedback bro. Now that you understand it, just put the time into practicing it and you'll do great. Best wishes, let me know how it goes.
Thank you so much at first I was confused but I completely understand now.
I didn't understand any bit of this in class, but your video makes it seem so easy! Thank you :D
This video is amazing, thank you so much.
I am love you for these reviews. Thanks for sharing.
Thanks Dude
Alright! You made it so easy. I just realized that I am pretty good at dimensional analysis 👏
Thank you so much you saved my life , I wish my chem. teacher would be this specific
Jessica Ramos me too
This is a great video. Many thanks
helped tremendously! thanks! never do i comment on videos thanking for information too.
Your videos have really helped me! I've been so confused and frustrated but these videos help me understand what to do. Thank you!!!
Monica Rodgers That is something to be thankful for! And I am thankful for your feedback. Best wishes!
sciencepost Keep on putting you effort in, and it will pay off. It just takes time and effort! Go for it, be amazing!
learned more from this video that I spent 500 dollars on a class. fuck college.
082256694 Give college a chance, it'll work out. Best wishes though in chem.
+082256694 Seriously! My lecture professor only reads the powerpoint and doesn't go in depth into the mathematical problems.
thanks a lot dude you saved my life!
I FINALLY GET THIS THANK YOU
great video it really helped
You really saved me with this one man. Thank you! ; )
Awesomeness!
Thank u so much ... understand nicely
Stoked that it worked for you!
Wow god bless you for this video 😭
Thank U 😊
Bruh this really helpful
LOVE YOUR VIDEOS !!!
Im wondering if you can help me out with this problem !
2 H2(g) + O2(g) → 2 H2O(l)
Suppose we carry out the above reaction with 30.0 g of O2 and 4.00 g of H2.
(a) Which reactant is the limiting reactant?
(b) How much of the other reactant remains at the end of the reaction?
(c) What mass of water is produced?
In part a - I found that the limiting reactant is oxygen and hydrogen is in excess, can you help me with the other two please?
I cant thank you enough for posting this
Thanks!
thank you sir
What if all you have is mL? And you're looking for moles? Do you get the molarity from the balance equation?
In the last problem i tried it myself before you would do it and i endid up doing it differently and i dont know if it is right or wrong ?
here is what i did.
i tranformed 150ml into 0.15l
i multiplied 58.5(NaCL) times 3mol =175.5
and then i divided 175.5 and 0.15= 26.32g
Let me know how the test goes! Best wishes
thankyou, thankyou, thankyou.
Thank s
thank you :-)
did you move the decial in the 228 to .228 because of the sig figs?
Thanks
(you dont have to solve it, just my question in the bottom)
So what if it asks the molarity of Na+ in the solution when .20 mol of Na2SO4 is dissolved in water to produce 100 mL of solution.
Do I have to multiply by 2 in order to get the molarity of Na+*
thericate Bingo. Bear in mind that the molarity expressed is for the ionic compound. When it dissociates, you'll have 2x the Na+ ions. In the end, you'll have to divide by the volume to get the molarity.
still rlly helpful in 2021 hahaha!
When do we use 1000/25 and when do we use 25/1000 cm3
my favorite part was when he said: " now we're all set dudes." 5:15
how do i work out the volume if not given
Isn’t 5L of water the liters of solvent and NOT the liters of solution? Im confused
The molar masses are not correct that are given from the video try to check them again
How do you get 111g/mol?? If it's not given?
+RaxrQie Beetle He took the Atomic Masses of Ca and Cl2 and added them (40.1+70.8~111)
I love you. and i mean it ahahahah thank you so much
Thanks so much! Keep being awesome!
First question: instead of writing 5.0 L of water, write 5.0 L of SOLUTION.
Sorry i didnt divided 175.5 and 0.15 i multiplied them.
Hey man that is soooo cool and all, but who asked
Horrible explanation
Excellent! Thx, babe! 💛