What if calcium chloride was not there, and the water was not absorbed. Will the H2O still combine with the remaining O2 to form the residual gas. Or that's not possible since it's no longer a gas
Only gases can be part of the residual gas...if water is form,it's no longer part of the residual gas as once it's converted away from the gaseous phase
Phosphorus burns in oxygen according to the equation P4 + 502 = P4O10 ,how many litres of oxygen will be required at STP for complete oxidation of 12.4 g of phosphorus (p=31,O=16 31 0 = 16 and molar volume of a gas at STP= 22.4
@@utmesciencetutor4722 10cm3 of co is mixed and sparked with 10cm3 of air containing 21% of O2. If all the volumes are measured at S.T.P the volume of resulting gases would be?
@@POPEFF1 kindly tell me the min of the question because I can't remember those figures without watching through the video again Tell me the min,so that I'll go there straight to address your question
The shortest short cut I have ever seen 💯
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Thanks sir I now understand it better than the first video I watched😮❤
Wow,I'm happy to hear that
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Thank you Sophia, God bless you more
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Very helpful thank you sir 🎉
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What if calcium chloride was not there, and the water was not absorbed. Will the H2O still combine with the remaining O2 to form the residual gas. Or that's not possible since it's no longer a gas
Only gases can be part of the residual gas...if water is form,it's no longer part of the residual gas as once it's converted away from the gaseous phase
OK thank you sir
@@ismailkhadijat8718 you're welcome
Wow Gay Lussas's law simplified ❤
Phosphorus burns in oxygen according to the equation P4 + 502 = P4O10 ,how many litres of oxygen will be required at STP for complete oxidation of 12.4 g of phosphorus (p=31,O=16 31 0 = 16 and molar volume of a gas at STP= 22.4
Have you seen the video
Which one
Check the last video I post
Please subscribe to know when I post a video
Nice one Sir 👍u to good
Thank you so much 👍😊
@@SagirMuhammad-f5z thank you ❣️
Are the pressure and temperature irrelevant in Gay Lussac's law??
They're factors to be kept constant for the validity of the Gay Lussac's laws
They're relevant and therefore must be kept constant throughout the experiment
perfecto
Thank you
Thank u so much sir
You're welcome 🤗
How do you know is 25cm
@@RejoiceAnthony-d3i sorry what number??
Sir can u explain why in the second to last example, why this isn't correct
2CO + O2 -
10cm3 21cm3 -10cm3
10cm3 20cm3 -10cm3
1cm3-10cm3
11 +89 =100
Maybe you should give a better description of your question,I can't remember the second to the last question
@@utmesciencetutor4722 10cm3 of co is mixed and sparked with 10cm3 of air containing 21% of O2. If all the volumes are measured at S.T.P the volume of resulting gases would be?
@@OgbonnaChiamaka-wy8fi I'm going to solve this in a short video tomorrow with series of explanation
@@utmesciencetutor4722 okay,tnxs
I made a video to show the solution to the problem,you can now check it
Please I have questions
You said we had to reduce from 50 to mix 20cm of oxygen but why did you use 40cm
Can't you use 45 or another number
@@POPEFF1 kindly tell me the min of the question because I can't remember those figures without watching through the video again
Tell me the min,so that I'll go there straight to address your question
@@utmesciencetutor4722 okay
@@utmesciencetutor4722 I watched the other videos you posted I understand now thanks so much for sharing your Idea
@@POPEFF1 you're welcome 🤗,❤️❤️
#chemistry this is genius 👀💯
Thank you 😊😊
🎉❤❤❤❤❤❤❤❤❤❤❤❤ understood
Thank you ❤️❤️
Calculate the volume of oxygen required to burn 500cm3 of methane completely
I already solved it and post the video
The answer is 1dm cube