Visit brilliant.org/TedEd to check out Brilliant’s 60+ courses in math, logic, science, and computer science. They feature storytelling, code-writing, interactive challenges, and plenty of puzzles for you to solve. And as an added bonus, the first 833 of you to use that link will receive 20% off the annual premium subscription fee.
@Nintendo of America be like: We do not like this. Zelda Director Eiji Aonuma be like: I am canceling all Zelda games, that, are currently in development, as a result of this. Yes, even Breath Of The Wild’s sequel. @Platinum Games Head Hideki Kamiya be like: I am going to block the Twitter, now X, accounts of all of your related divisions, @TED.
@@joaquimsartoridesouzacampo301 NOPE. WHY would he spend 52?????? He has magic mirror and could see you have ZERO bid. He just needs to bid 1 GEM! And why does this riddle presume that Gordon will match you at the second BID? If he's gonna let you win the 2nd gold anyway he just needs to go ZERO bid and block your 3rd bid by 1 more gem. He knows he have the gem advantage and will enter the silver bids and win EASILY with his gem advantage. Gordon could spend 0 gem and you 24 gem at round 2. That means gordon HAS 99 GEMS at round 3 and you 51. EVEN IF you spend all 51 at round 3 he just needs to counter with 52 and he still has 47 left and you 0 for the silvers. This riddle is fail.
By the way, on the serious side, are you sure you guys will not get into trouble with copyright issues? Even though efforts were made to avoid mentioning the copyrighted names, every Legend of Zelda fan will know the video was referring to that Nintendo series. Also, the protagonist also looks very similar to Link. But I hope Nintendo takes a light touch on this, since you are an educational non-profit org. Cheers!
@@eclipse0073 well not really, because in his altered world he still had the stones. so it's effectively free as long as the initial requirements were met
"but your ingenuity kept you on link ahead in the chain of inference" Link is so powerful that he doesn't let -Ganon- Gordon win in a totally different world
So Dongle collected the golden hexagons just to hold ONE auction? That is such a small brained answer to his troubles. Why not use the hexagons to make it so he can hold an auction whenever he wants, regardless of circumstance? That would be the best way to make the most of the limitless power at his fingertips.
Gordon's fatal flaw here is that he bid 0 instead of 24 on the first of the gold hexagons which forces him to use an extra gem to one up you, which results in a disadvantage going into the silver hexagon bids....What a shame. Also, did anyone else notice that our hero lost a finger between 1:31 and 3:57? Would like to hear what kind of trick Gordon had up his sleeve that removed his opponent's finger.
That's not quite true. If he bid 24 in the first round, you could bid 25 in the 2nd round and still win. 1. You bid 25 and he bids 0, in which case he still has to at least match you in the 3rd round. If you bid 50, that leaves you with a 50-49 advantage. 2. You bid 25 and he matches you with 25, he wins rounds 2. But now he only has 74 to your 75, so you bid 0 on round 3 and then head into the silver rounds with the same advantage.
@@DeathnoteBB Because both of them would already have a hexagon at that point. One for you, one for Gordon. You need 3 to reshape the world, so spending gems on the last one is pointless.
One thing I noticed is that the rules never state that gordon knows how much you have, so if he lets you win the second gold auction you could technically bid any number and he would have to +1 or match. meaning that the three silver hexagons you need are easily bid for since he would no longer be able to match.
Yo I spent 5 hours banging my head against the wall thinking about this until I saw in a random comment that YOU GET TO KEEP THE GEMS FROM LOST AUCTIONS. THIS INFORMATION WILL SAVE LIVES.
You can also bid 25 for the second gold stone. The reasoning at 3:34 is based on the simplified worst case of losing all draws. If draws alternate then any 1 gem advantage (regardless of multiples of 3) is sufficient to ensure victory.
I noticed that too. We: 75 coins, 1 gold Gordon: 99 coins, 0 gold We bid 25 (golden). - He bids 0. We're 2-0 up and have 50 left. - He bids 24. We're 2-0 up and have 50 left. Then we bid 50, "lose" and he has 48 left. The prio is still ours. - He bids 26. It's 1-1 and he has 73 left. Then we bid 0 until the second round, Worst case, 75 vs 73 and the prio is his. - He bids 25. We're 2-0 up and have 50 left. Then we bid 50, "lose" and he has 49 left. 50-49 with prio ours, or 50-48 with prio his. - 50-48, prio ours. We bid 16 (silver): - He bids 15. 34-48, 1-0, prio ours. Then we bid 17s. - He bids 16. 34-48, 1-0, prio his. Then we bid 17s. - He bids 17. 50-31, 0-1, prio ours. 16, then 17s. - 50-49, prio ours. We bid 16 (silver): - He bids 15. 34-49, 1-0, prio ours. Then we bid 17s. - He bids 16. 34-49, 1-0, prio his. Then we bid 17s. - He bids 17. 50-32, 0-1, prio ours. 16, then 17s.
I thought about it for a while in bed. Surprisingly, you can even bid 26 and still win! Your possessing the first tiebreak is enough to win a 49-49 contest even though Gordon has the mirror, which turns out to be oddly weak. Your strategy is to bid 17 whenever you don't have the tiebreak and 16 whenever you do.
@@Ringcaatthat won't work, because Gordon will be able to buy the third gold for 49 after matching your bids. Therefor he will go into the second round with a 50-49 advantage.
This is probably my favorite Ted-Ed riddle. I really was so stumped, I absolutely couldn't see any way in which this would be possible -- but the way it was explained made such a light flick on in my head. Loved it!
Love how ted-ed uses random video games and shows, changes the names of the characters, and makes it a riddle. That's what makes ted-ed riddles my favorite. Keep up the good work guys!
I would have wrote a "6" on the second auction. And then at the last moment, I would have turned my page to a "9" to win the auction against a "7" :D Gniark ! Gniark ! Gniark !
This reminds me of a certain game with a blonde princess and a blonde knight that get reincarnated for eternity and have to face off a character that is named ganon. Maybe it’s just me
-tell dongle about gordon’s mirror -gordon is disqualified -tell dongle he has green eyes -dongle says “Ozo” and gives you the 1 emerald that can change the world
@@juanmanuelpenaloza9264 juan this video is not protected because of 'educational purposes' as this video isnt educative its a fun riddle, and this video is probably monetized. the reason this isnt infringing of Zelda copyright is that its literally not even close to being infringement.
@@lunaJAMv9 That's not the "Educational" clause of fair use. That clause would be explaining about Zelda itself. To educate about a Zelda game is fair use. This still fall under fair use as Satire and because the riddle is novel and doesn't compete on Nintendo buisness at all. If this was made into an entire game, it would be copyright infringement.
again a really nice riddle. its allways the same situation. after listening to it i think "how should that work" after 5 minutes " ok this could work" after 10 minutes "i have it" it is really satisfactory
@@mrjoe332 that’s completely fine. You know how long it takes to create a complicated riddle like these? Some of these riddles are absurdly specific too.
The only reason there's a guaranteed winning strategy is because Gordon messed up the first round. He should have bid 24 so that the advantage of winning initial tie goes to him.
Right... but no. If you go on with the reasoning, you'll find out that whatever he does, he will finally lose. The trick of wining the first tie is a decisive advantage.
I don't think he can still win even with a bid of 24 to get the advantage in case of a tie. We just have to bet 25 to guarantee a win Here is a breakdown: Scenario A : Gordon decides to let us have the second round. So it would be 50 vs 99 going into round 3 which would become 50 vs 49 in our favour going into the silver hexagons and we can adopt a similar strategy of betting 17(w) 17(w) 16(L) 16(L) 16(W). The best Gordon can do is 0(L) 0(L) 16(w) 17(W) 16(L). This is just an example but no matter what he does we win 3 to 2 even with him having the advantage on tiebreakers. Scenario B: Gordon decides to win the second round for golden hexagon So it would be 74 vs 75 going into round 3 as Gordon would bet 25 to match us and get the win because of him having the advantage in case of ties. Round 3 both will bet 0 as it doesn't matter who wins the 3rd coin. We will get the 3rd coin but lose the advantage over to Gordon. Now onto the silver hexagons we just need to bet 25 everytime. Gordon only has 74 so he can't win more than twice even with the advantage enabling us to win 3 silver coins
So happy I solved this one. I went to the notes app to work this out and got the EXACT numbers from the example solution. I bet 24 on the next gold to get ahead no matter what and then bet a third of what I have left to win 3 silvers. Great mental puzzle!
Love this puzzle and even more that it's a Zelda reference. XD Have to admit I racked my brain a bit until I realized it's impossible to get all the gold with Ganon-I mean Gordon's tactics and waiting for silver will leave him with 24 more gems than us. So the only possible way is to use the gold to force NotGanon into wasting his gems before getting to the silver.
Seriously, though, I can definitely think of worse videos to be caught watching in math class. A good teacher would hopefully recognize it and possibly even bring it up for the class. I wonder how many math classes feature these in their curriculum.
Fun Facts: Gordon is lost on move 1. Even if Gordon goes for 25 in the 1st bid, he would still lose. Calling 24 in the 1st bid is such a sick move of you. In the sense that it's the only way for you to win by force (despite the obvious information disadvantage). Other than 24, Gordon's win is guaranteed. Analysis: First, note that with any gem advantage, entering 2nd stage is completely winning. If it's same on both sides, the guy with better tiebreaker wins. Also note that, Gordon can manipulate tiebreaker by bidding the same number on the bid that he does not intend to win anyway. Gordon's Alternative: Let's see why Gordon still lose when he calls 25 in the 1st bid. If Gordon goes for 25 in the 1st bid. You can bid 24 in the 2nd bid, forcing Gordon to spend 25, then win the 3rd bid with 49. Your Alternatives: Let's see how Gordon punish you for other possible 1st bids of you. If you bid 23, Gordon can bid 24, then 24, then 0 (counter your 24, 25) or 51 (counter your 0). If you bid 25, Gordon can bid 25 (changing the tiebreaker), then 0 (to counter x>=25) then 49 (using tiebreaker when x =25); or x+1 (to counter x
Yes, even if Gordon matches the first bid with 24 and gets back the tiebreak advantage, this time you can bid 25 on the second round. If he lets you win you will bet all 50 remaining, he will have to match and you will be going to the silver rounds with a 50-49 gem advantage. if he matches with 25 you will just bid 0 and go to the silver rounds with a gem advantage once again.
@@flamingcarrot8898 Nice catch. How about this? 25 -> 0 -> if 25 or more -> same as you ... if 24 -> 25 -> 0 -> 0 (entering 2nd stage with better tiebreaker) if less than 24 -> your bid+1 ...
Step 1: Ask Gordon, "If I were to ask you if you were going to bid more gems then me, would you say OZO?" Step 2: Tell Dongle that Gordon is cheating. Step 3: Use the 3 silver gems that you get to make Gordon your servant Step 4: Force him to go to work and earn your gems back Step 5: Make his body really tiny Step 6: "Accidently" step on him Step 7: Auction the gems
@@matheusGMN In the green eyes video, if you had green eyes, that was an unassailable ticket to freedom. You can just "ask to leave" as it were. This version of the joke still involves asking and leaving, but you're asking the other people to leave.
3 easy steps: Step-1: Go to Auction. Step-2: Confirm you have eyes that has color of emerald.😉 Step-3: Leave with all the sources and let gordon and dongle dabble, diddle and dangle over what has just happened, while getting erased out of existence Thanos style. 😅 Note: you can make a world full of riddles for this Ted guy using those sources. 😊
My first thought was just "forcing him to spend more on the golds gives you an advantage on silvers". Then figured "repeat your bid and he has to +1 you and if he takes it you double it". Kind of like that roulette "double until you win" strategy. Sure enough, that got me to the answer. The silver was a bit more tricky, since you don't need to double.
I solved it. It took me a solid 2 hours but I solved it. I'm about to watch the solution. I just watched the solution. I calculated that there are actually 2 solutions where you can win. The second solution involves you bidding 25 instead of 24 for the second gold piece. Gordon literally has no "good" choice to make in this situation other than drawing. *In both scenarios, you are up by 2* , with your gems being at 75 or 50, and Gordon's gems being at 73 or 48. If you are at 50 and Gordon is at 48, you can simply bet 16 gems every time in order to win.
My ridiculous solution which I proudly conceived involved writing 61 on the paper so the opponent would bid 62 and then rotating the paper before presenting it thus tricking the opponent into bidding 62 while you’ve only bid 19. Sad-ed.
You are incorrect. My brain: Are you gonna watch a ted Ed riddle? Me: yes My brain: you would neither be able to understand it nor solve it Me: *Did I stutter?*
For the 2nd bid, go 25 If he buys it for more, on 3rd bid go 0 If he bids for 25 or less, on 3rd bid go 50 Either way you'll be bidding for the silver ones with you having 75/50 and he will be at 73 (with next right for draw)/49(without next right for draw) respectively You will always win by bidding 25 everytime for 75, and 17 twice winning then 16 for 50
I think this also works though. for gold one: bet 25 on 2nd other has 2 choices i.e bid 26 or 0. If 26 than he will have 73 leftover and if 0 than in 3rd round you can bid all 50 to make him bid 51 leaving him with 48. So, when the bid for gold one is over he will have 2 less coins you. Silver can be won in similar fashion as mentioned in the video above. Correct me if i am wrong
You're right! In fact, I thought about this for too long in bed and worked out that a second bid of 26 is also (just) sufficient to win, since you have the first tiebreak.
Okay, either this was not explained well enough or it doesn't make any sense: Our hero has already spent 24 out of his 99 gems, leaving him with 75. Our hero has one gold already. The solution is to bid "X" amount (let's assume 0) on the second gold and Gordon does the same, tying the first time therefore our hero gets the second gold. Then the hint suggests that the hero bids everything which he has left, which would be 75 gems, therefore we go into the second round with nothing so Gordon would win by bidding just one gem each time. Am I missing something or was this poorly explained?
Unless Gordon wants to allow you to claim the third gold and win outright, he'll have to bid at least 75 to win the third one to stop you. So he'll be the one that spends that money, not you. Except if you only bid zero for the second one, he'll bid one and stop you there. You definitely lose doing that. You need to bid enough that he either spends some or lets you take it, letting you force his third bet. If he can easily win the second one then he wins.
Dont worry about it, I dont think there is an actual answer to the riddle anyhow. In his explanation he give two scenarios. One where Gordon ties for the 2nd golden hex and the second scenario where Gordon wins the 2nd golden hex, but he doesnt cover the 3rd scenario where gordon doesnt spend any money at all on the 2nd golden hex. There for you spent 24 tens for no reason and now you have 51 gems to his 99 gems
@@joshuapowers3270 No you missed the answer. If he doesn't spend gems on the 2nd auction, Gordon has 99 gems for the 3rd auction and you have only 51 gems. But you auction the 51 remaining gems for the 3rd auction and Gordon has no choice and has to pay at least 51 gems for the third auction. Therefor, you begin the auctions for silver stones with 51 gems and Gordon with maximum 49 gems...
@@joshuapowers3270 Oups ! Sorry :) They should have specified that the one who lose the auction keeps the money. It would have save many comments ;) People are tricked because the first bid of Gordon is "0" instead of "10" or "18"... thus people assume that it is meaningfull to bid "0" instead of any other number under "24",.... wich is not.
Am I missing something here? Since your rival knows what you'll bid he could just not bid if you bid on the second gold hexagon and then block you by bidding one more on the third and keep his gem advantage, and if you don't bid on the second gold he could just bid one and not bid on the third, in this case he'll go to the silvers with gem advantage and first draw being his.
Yes, you are missing something. If I bid 24 in round 2 and Gordon doesn't bid, then I win the 2nd gold for 24. I would have 75-24 = 51 gems left and Gordon has 99. For the 3rd gold, I would go all in, as winning the final gold ends the game immediately and silver doesn't even come into play. So, I bid 51. Per your strategy, Gordon blocks by bidding one more = 52. Gordon wins the 3rd gold for 52 and has 99 - 52 = 47 gems left. I still have my 51 gems. 51 > 47. So, no Gordon doesn't have an advantage heading into the silver round. Also, per your strategy there are no ties in the gold round, making your second conclusion is also wrong -- the first tie would still belong to me heading into silver.
Well, no. Say you bid 20. If Gordon lets you take the 2nd one for that price, then you have 55 money left on round 3, forcing Gordon to buy the third one for 55. Then you've only spent 44 to his 55. If you low-ball the 2nd bid then Gordon should snap it up as a bargain to block you, if you high-ball it, then Gordon should let you take that one too, and can get away with a cheaper bid on round 3.
25 should work as well. Because you win every other tie, so long as you have one more gem in the second round you can win. Split your gems as evenly as possible, make the lower bids first and the higher bids second. He Must spend as much as you do to get the first 2 gems, leaving you an extra gem to win the final auction. Winning the first tie is a decisive advantage, if you bid 24 on the first auction you should be able to win no matter what your opponent does.
I think you are right about the fact that there is always a way to win by bidding 24 on the 1st auction but your explanation for the second round (I assume you speak about the silver stones) is not complete. Gordon can start the second round with the advantage on the following tie. He can decide wether he wins or looses the auction (with tie or not) regarding what you bid. Finally, I think there is way to win but the solution is not as simple as you described it.
@@Peter-bv2ho I may not have explained it thoroughly, If you have even one more gem going into the silver round you should be able to win following my basic strategy. Yes Gordon can win ties but at the cost of passing priority to you. In other words he wins the 1st tie but then you win the 2nd, Then you pass priority back. I worked out for all 3 cases but long story short, you can control the amount Gordon is forced to bid and by the 5th bid he won't have the gems needed even to tie.
Seriously give it a try, I will even tell you my bids in advance. 24 25 if I win, 24 if I lose. Everything I have if I have to 2 wins, The same number as you if you have 2 wins, 0 if we each have one win. Round 2, Divide is evenly as possible, Do higher bids later.
@@johnschmidt1262 We saw in the riddle solution that if Gordon loses the first auction, he loses the game. Thus, he has to bid 25 at the first auction. Then you have to bid 24 and Gordon will bid 25 because otherwise he loses too. So you reach the 2nd round with 50 gems and Gordon with 49 gems (and the tie advantage). If you divide 50 in "even" parts, you'll get 16,17 and 17. I think that what you wanted to say is that you have to bid 16 until you finally win with 16 and only then, you bid 17... but it was not clear for me in your explanation. ... so we agree on the result from the beginning ;) Last question : When you say "25 should work as well" in your first comment, what do you mean ?
Am I missing something? So 24 was bet first, then it was realized that the opponent was cheating. That's the setup. So now, according to the solution, you bet 24 on the second bid. Couldn't the opponent just let you win that one as well (bets 0). So now you have 51 and he still has 99. Then on the next bid, he bids one more than you do, no matter what. He'd be at a serious advantage going into the silvers.
so the next bit he has to beat you, you bet the rest of your gems, 51, he has to bet 52. now you have 51gems and he has 47gems. YOU are at a serious advantage!
@@mauritz3912 Oh. Wait. Duh. This is an auction. I was thinking both people lose their coins. For example, for a bid if you bet 1 and he bet 2, I was for some reason calculating that you both would lose your gems. But obviously only the winning bid loses their gems :). Thanks!
I swear there’s gonna be a riddle like: “you have a bag of chips and a swimsuit. You put the swimsuit on and ate a chip. Now what’s pi plus the square root of Dr. Doofinshmirtz?”
„You have a t-shirt and 5 dollars. You put on the t-shirt. Now what is the lenght of the uranium decay chain to the power of 4 plus the square root of the UK's nuclear arsenal?”
Visit brilliant.org/TedEd to check out Brilliant’s 60+ courses in math, logic, science, and computer science. They feature storytelling, code-writing, interactive challenges, and plenty of puzzles for you to solve. And as an added bonus, the first 833 of you to use that link will receive 20% off the annual premium subscription fee.
cool
@Nintendo of America be like: We do not like this.
Zelda Director Eiji Aonuma be like: I am canceling all Zelda games, that, are currently in development, as a result of this. Yes, even Breath Of The Wild’s sequel.
@Platinum Games Head Hideki Kamiya be like: I am going to block the Twitter, now X, accounts of all of your related divisions, @TED.
@@lucng8102 in the third round he gonna spent 52 gems, so in the silver ones its gonna be 51 against 48 for gordon. So he would lose anyway
@@joaquimsartoridesouzacampo301 NOPE. WHY would he spend 52?????? He has magic mirror and could see you have ZERO bid. He just needs to bid 1 GEM!
And why does this riddle presume that Gordon will match you at the second BID? If he's gonna let you win the 2nd gold anyway he just needs to go ZERO bid and block your 3rd bid by 1 more gem. He knows he have the gem advantage and will enter the silver bids and win EASILY with his gem advantage.
Gordon could spend 0 gem and you 24 gem at round 2. That means gordon HAS 99 GEMS at round 3 and you 51. EVEN IF you spend all 51 at round 3 he just needs to counter with 52 and he still has 47 left and you 0 for the silvers.
This riddle is fail.
By the way, on the serious side, are you sure you guys will not get into trouble with copyright issues? Even though efforts were made to avoid mentioning the copyrighted names, every Legend of Zelda fan will know the video was referring to that Nintendo series. Also, the protagonist also looks very similar to Link.
But I hope Nintendo takes a light touch on this, since you are an educational non-profit org. Cheers!
Viewers: What did you do??
Dongle : "I USED THE STONES TO MAKE THE STONES"
I did nothing but create stones for 3 days
Probably had something to do with fairies.
What did it cost?
@@Dexaan stones
@@eclipse0073 well not really, because in his altered world he still had the stones. so it's effectively free as long as the initial requirements were met
"Mom, can we have Legend of Zelda?"
"We have Legend of Zelda at home".
Legend of Zelda at home:
Legends
@@CubicalLaboratory ?
Perfect comment
lol
@@CubicalLaboratory *Legends* of Zelda?
"but your ingenuity kept you on link ahead in the chain of inference"
Link is so powerful that he doesn't let -Ganon- Gordon win in a totally different world
umm
um
ummm
Universe my boy
xd
So Dongle collected the golden hexagons just to hold ONE auction? That is such a small brained answer to his troubles. Why not use the hexagons to make it so he can hold an auction whenever he wants, regardless of circumstance? That would be the best way to make the most of the limitless power at his fingertips.
Nothing is better than an auction with stakes
I mean wouldn't holding an auction kinda lose its excitement if you can do it at any moment?
He loves every step of the auction process, and rigging up a world of auctions would make it all pointless.
Or it might be so he trapped link in his imagination, starting different auctions all over and over again.
True
Dongle: "Who are you?"
the hero: "I'm Link, but Blurer."
Isn't Link blue in some games?
Blink
I absolutely love image of link writing down a bunch of math on his note before bidding against ganon to get a budget triforce from tingle.
where's zelda?-
It's lok
@@user-fm5vp7yu3u Zelda's doing the bidding. He's the mc.
@@Chance57 ? Link is The main character
XD
"A hexagonal piece of cheese is a lot better than a square piece of cheese."
Hod Lipson: "Sometimes my genius, it's almost frightening."
Lmao
Clarkson
"Hexagons are the bestagons"
- CGP Grey
@@PramkLuna I came here looking for this. So thanks.
@@PramkLuna I just watched that video
Also can we just appreciate how Ted-Ed acknowledges Tingle as the most powerful Zelda character
Ted Ed knows the Zelda facts and the real facts
I wanted to confirm Dongle was Tingle so thank you lol!
ua-cam.com/video/E_r0_dezb5A/v-deo.html
😇😇😇
Lol
You mean Zoldu
Gordon's fatal flaw here is that he bid 0 instead of 24 on the first of the gold hexagons which forces him to use an extra gem to one up you, which results in a disadvantage going into the silver hexagon bids....What a shame. Also, did anyone else notice that our hero lost a finger between 1:31 and 3:57? Would like to hear what kind of trick Gordon had up his sleeve that removed his opponent's finger.
0 is perfectly fine, you only LOSE gems on a win
That's not quite true. If he bid 24 in the first round, you could bid 25 in the 2nd round and still win.
1. You bid 25 and he bids 0, in which case he still has to at least match you in the 3rd round. If you bid 50, that leaves you with a 50-49 advantage.
2. You bid 25 and he matches you with 25, he wins rounds 2. But now he only has 74 to your 75, so you bid 0 on round 3 and then head into the silver rounds with the same advantage.
Oh yeah lol
What I don’t get is why “no one” would bid at 4:43. Surely Gordon would want the hexagon, and if you bid 0 he gets it just for 1 gem?
@@DeathnoteBB Because both of them would already have a hexagon at that point. One for you, one for Gordon. You need 3 to reshape the world, so spending gems on the last one is pointless.
One thing I noticed is that the rules never state that gordon knows how much you have, so if he lets you win the second gold auction you could technically bid any number and he would have to +1 or match. meaning that the three silver hexagons you need are easily bid for since he would no longer be able to match.
True. Though in that case, you don't know how much Gordon has either. Your overall point is right though, they should have included that information.
I'm not ready for these "rules never said that" 😭 y'all stop finding loopholes and try solving instead 😒
@randomdude What you have proposed is what I shall dub "a bad answer." There is a difference between bad problems and bad solutions.
yeah but he knows that both of you have 99 rup... I mean gems. So all he had to do is subtract 24 from 99
@jaypee9575 Nope, you are told he also has 99 gems. No proof he knows about your total, but you do know his.
Yo I spent 5 hours banging my head against the wall thinking about this until I saw in a random comment that YOU GET TO KEEP THE GEMS FROM LOST AUCTIONS. THIS INFORMATION WILL SAVE LIVES.
Now the explanation in the video makes sense. I've been trying to understand since yesterday. Thanks.
XD
Thank you. Now it all makes sense.
Don't Know How Auctions Work Club
Cant gordon just bid 0 a second time and beat your all in by +1 for the third? Then win all 5 silvers?
The story of this riddle is so good, someone should make a videogame out of this
Duuuude i just wrote the same thing just to find your comment
Give me a computer, a summer break, and some time from about 2 weeks, to a month and a half.
@@swordf5345 I'm certain you won't be sued by a certain Japanese gaming company...
I'm waiting to r/woosh someone
"legend of zelda? whats that, never heard of it"
"Sorry Gordon, I can't give hexagons. Come back when your bids are a litttle mmm... richer!"
Wait a minute that's Morshu
gordon last name is rams
Lamp oil, Rope , Bombs!
You can also bid 25 for the second gold stone. The reasoning at 3:34 is based on the simplified worst case of losing all draws. If draws alternate then any 1 gem advantage (regardless of multiples of 3) is sufficient to ensure victory.
You absolutely can, it's a shame they didn't even mention this, as it seems from the video a bid of 24 is the only way to win.
Thanks I also had 25 as my solution guess.
I noticed that too.
We: 75 coins, 1 gold
Gordon: 99 coins, 0 gold
We bid 25 (golden).
- He bids 0. We're 2-0 up and have 50 left.
- He bids 24. We're 2-0 up and have 50 left. Then we bid 50, "lose" and he has 48 left. The prio is still ours.
- He bids 26. It's 1-1 and he has 73 left. Then we bid 0 until the second round, Worst case, 75 vs 73 and the prio is his.
- He bids 25. We're 2-0 up and have 50 left. Then we bid 50, "lose" and he has 49 left. 50-49 with prio ours, or 50-48 with prio his.
- 50-48, prio ours. We bid 16 (silver):
- He bids 15. 34-48, 1-0, prio ours. Then we bid 17s.
- He bids 16. 34-48, 1-0, prio his. Then we bid 17s.
- He bids 17. 50-31, 0-1, prio ours. 16, then 17s.
- 50-49, prio ours. We bid 16 (silver):
- He bids 15. 34-49, 1-0, prio ours. Then we bid 17s.
- He bids 16. 34-49, 1-0, prio his. Then we bid 17s.
- He bids 17. 50-32, 0-1, prio ours. 16, then 17s.
I thought about it for a while in bed. Surprisingly, you can even bid 26 and still win! Your possessing the first tiebreak is enough to win a 49-49 contest even though Gordon has the mirror, which turns out to be oddly weak. Your strategy is to bid 17 whenever you don't have the tiebreak and 16 whenever you do.
@@Ringcaatthat won't work, because Gordon will be able to buy the third gold for 49 after matching your bids. Therefor he will go into the second round with a 50-49 advantage.
This is probably my favorite Ted-Ed riddle. I really was so stumped, I absolutely couldn't see any way in which this would be possible -- but the way it was explained made such a light flick on in my head. Loved it!
Why didn't Dongle just use the power of the hexagons to create a world in which he can have as many auctions as he wants...
Plot twist. That is what he did, he just trapped the hero in his imagination, to repeat the auction forever and ever
@@srijanumesh5355 It went dark so quickly 😦
There's the risk he'd have enough auctions to kill his live for auctions.
And hence hypixel SKYBLOCK
he probably has more in the back
The TED-Ed crossover episode we didn't know we wanted
Tell ne about it
i love it
Damn sure your comment will have more than 1 k like in near future now it's at 145
👌🏻
Start the boss music
Love how ted-ed uses random video games and shows, changes the names of the characters, and makes it a riddle. That's what makes ted-ed riddles my favorite. Keep up the good work guys!
“Dongle’s dangled a difficult dilemma” hahaha
4:57 "your ingenuity kept you one LINK ahead". we get it TedEd
I would have wrote a "6" on the second auction. And then at the last moment, I would have turned my page to a "9" to win the auction against a "7" :D Gniark ! Gniark ! Gniark !
Modern problem requires modern solutions
@@phoenixav9550 ancient problems require nukes
@@imanaxolotl7999 LMAOOOOOO
Except you don't know he's cheating.
😂😂😂
The Legend of Ted Ed: Riddle of Knowledge
The demon of reason can be a recurring boss
@@philosophicalpatriot1883 I think he should be like that fairy from zelda
@@MrSkabrus Oh like figure out the problem and get like a buff or an item.
@@philosophicalpatriot1883 yep
Coming soon to a notebook near you
"A hexagonal piece of cheese ist a lot better than a square piece of cheese"
Or as CGP Grey would say: "Hexagon Bestagon"
Did you wachted that video?
@@pepperren8 Yes/No/Maybe/I don't know/Do I have Alzheimer/Werde ich jetzt vollends verrückt/Verschlingt mich letztendlich doch der Wahnsinn
@@pepperren8 yep, it's my favorite CGP video
Triangles better, don't @ me.
@@brandonnguyen6718 Agreed, triangles are the bestangles
0:04 And that's because: Hexagons, are the bestagons.
Because, bees. Bees are the best and build only the bestagon, the hexagon.
i like the easy ones like this one, make me feel smart
*E-easy?*
This reminds me of a certain game with a blonde princess and a blonde knight that get reincarnated for eternity and have to face off a character that is named ganon. Maybe it’s just me
🤔Hm interesting, sounds like a cool game
@@TEDEd It truly is
Wonder what game that could be though? It sure looks amazing to play
I'm now busy trying to find the game than solve the riddle 😂😂😂
@@TEDEd I remember playing a game like that, cant remember the name tho
"A Hexagonal piece of cheese is a lot better than a square piece of cheese." - Hod Lipson
Happy CGP Grey noises
Hexagons are the bestagons.
Now go, share the enlightenment with others.
I was waiting for this comment
Hexagons are STILL the Bestagons
and they will ALWAYS be.
Wonderful
Dongle is extremely calm throughout this entire video and I just love that
very trueee
-tell dongle about gordon’s mirror
-gordon is disqualified
-tell dongle he has green eyes
-dongle says “Ozo” and gives you the 1 emerald that can change the world
2:17 Take legal action, call Gordon out for cheating and tell Dongle that Gordon is ruining the spirit of the auction.
Ted Ed is dodging copyright infringement like Neo in the Matrix with this one.
Educational purposes
@@juanmanuelpenaloza9264 juan this video is not protected because of 'educational purposes' as this video isnt educative its a fun riddle, and this video is probably monetized. the reason this isnt infringing of Zelda copyright is that its literally not even close to being infringement.
@@BD-lq4id that, and also yes it is educational, all of these videos are
@@lunaJAMv9 That's not the "Educational" clause of fair use. That clause would be explaining about Zelda itself. To educate about a Zelda game is fair use. This still fall under fair use as Satire and because the riddle is novel and doesn't compete on Nintendo buisness at all. If this was made into an entire game, it would be copyright infringement.
@@hurktang hmm now i've completely forgotten about why i'm even here
i would defend my argument, but i'd likely be wrong
Next problem is to prevent the princess from taking all the credit calling it the legend of zelpha .
underrated comment :))
The true problem of legend of zelda
Yeah I fkin hate it she fkin does nothing
The legend of zeb
The real dilemma here is why did anyone think that “Dongle” was a good surname? 💀
*Apple has entered the chat*
my party mate in D&D
I don't know; "Dongle, Dongle, doolo-limpah!" has a nice ring to it.
Dongle sort of rhymes with Tingle. Too bad none of his games ever made it to America.
@@avoprim5028 he’s a major character in wind waker though. Everyone should know him by now
Love how Gordon's mirror is in the wrong direction
again a really nice riddle. its allways the same situation. after listening to it i think "how should that work" after 5 minutes " ok this could work" after 10 minutes "i have it" it is really satisfactory
Gordon: Ain't nobody got time for this *murders Dongle and takes the hexagons*
Today is Monday. My brain can't solve a riddle right now.
So, just like everyday, then
@@fathfez7991 Yeah pretty much
I literally only solved like, 3 riddles in all the years watching this channel
@@mrjoe332 that’s completely fine. You know how long it takes to create a complicated riddle like these? Some of these riddles are absurdly specific too.
My brain couldn't even understand the riddle
The only reason there's a guaranteed winning strategy is because Gordon messed up the first round. He should have bid 24 so that the advantage of winning initial tie goes to him.
Couldn't gordon also just bid nothing the 2nd round as well?
Right... but no. If you go on with the reasoning, you'll find out that whatever he does, he will finally lose.
The trick of wining the first tie is a decisive advantage.
@@joshuapowers3270 Gordon lose nothing if he bid nothing or 24, the result is the same. If he doesn't win the auction, he keeps his money.
@@Peter-bv2ho yup fair point forgot how auctions worked there for a bit.
I don't think he can still win even with a bid of 24 to get the advantage in case of a tie.
We just have to bet 25 to guarantee a win
Here is a breakdown:
Scenario A : Gordon decides to let us have the second round.
So it would be 50 vs 99 going into round 3 which would become 50 vs 49 in our favour going into the silver hexagons and we can adopt a similar strategy of betting 17(w) 17(w) 16(L) 16(L) 16(W). The best Gordon can do is 0(L) 0(L) 16(w) 17(W) 16(L). This is just an example but no matter what he does we win 3 to 2 even with him having the advantage on tiebreakers.
Scenario B: Gordon decides to win the second round for golden hexagon
So it would be 74 vs 75 going into round 3 as Gordon would bet 25 to match us and get the win because of him having the advantage in case of ties. Round 3 both will bet 0 as it doesn't matter who wins the 3rd coin. We will get the 3rd coin but lose the advantage over to Gordon.
Now onto the silver hexagons we just need to bet 25 everytime. Gordon only has 74 so he can't win more than twice even with the advantage enabling us to win 3 silver coins
So happy I solved this one. I went to the notes app to work this out and got the EXACT numbers from the example solution. I bet 24 on the next gold to get ahead no matter what and then bet a third of what I have left to win 3 silvers. Great mental puzzle!
The transition to the add Was just... smooth!
Love this puzzle and even more that it's a Zelda reference. XD
Have to admit I racked my brain a bit until I realized it's impossible to get all the gold with Ganon-I mean Gordon's tactics and waiting for silver will leave him with 24 more gems than us. So the only possible way is to use the gold to force NotGanon into wasting his gems before getting to the silver.
me trying to do this while in math class then realizing that I wasn't on mute:
*chuckles* im in danger
Confirm that you have green eyes.
Ask your teacher if you can leave.
GOOD
@@seventeencarattrash This is the funniest comment I've seen today, thanks!
Seriously, though, I can definitely think of worse videos to be caught watching in math class. A good teacher would hopefully recognize it and possibly even bring it up for the class. I wonder how many math classes feature these in their curriculum.
Fun Facts: Gordon is lost on move 1. Even if Gordon goes for 25 in the 1st bid, he would still lose. Calling 24 in the 1st bid is such a sick move of you. In the sense that it's the only way for you to win by force (despite the obvious information disadvantage). Other than 24, Gordon's win is guaranteed.
Analysis:
First, note that with any gem advantage, entering 2nd stage is completely winning. If it's same on both sides, the guy with better tiebreaker wins. Also note that, Gordon can manipulate tiebreaker by bidding the same number on the bid that he does not intend to win anyway.
Gordon's Alternative:
Let's see why Gordon still lose when he calls 25 in the 1st bid.
If Gordon goes for 25 in the 1st bid. You can bid 24 in the 2nd bid, forcing Gordon to spend 25, then win the 3rd bid with 49.
Your Alternatives:
Let's see how Gordon punish you for other possible 1st bids of you.
If you bid 23, Gordon can bid 24, then 24, then 0 (counter your 24, 25) or 51 (counter your 0).
If you bid 25, Gordon can bid 25 (changing the tiebreaker),
then 0 (to counter x>=25) then 49 (using tiebreaker when x =25);
or x+1 (to counter x
Yes, even if Gordon matches the first bid with 24 and gets back the tiebreak advantage, this time you can bid 25 on the second round. If he lets you win you will bet all 50 remaining, he will have to match and you will be going to the silver rounds with a 50-49 gem advantage. if he matches with 25 you will just bid 0 and go to the silver rounds with a gem advantage once again.
"or x+1 (to counter x
@@flamingcarrot8898 Nice catch. How about this?
25 -> 0 ->
if 25 or more -> same as you ...
if 24 -> 25 -> 0 -> 0 (entering 2nd stage with better tiebreaker)
if less than 24 -> your bid+1 ...
@@annannz9047 yup in that case gordon would win
Step 1: Ask Gordon, "If I were to ask you if you were going to bid more gems then me, would you say OZO?"
Step 2: Tell Dongle that Gordon is cheating.
Step 3: Use the 3 silver gems that you get to make Gordon your servant
Step 4: Force him to go to work and earn your gems back
Step 5: Make his body really tiny
Step 6: "Accidently" step on him
Step 7: Auction the gems
“Dongle’s Dangled a Difficult Dilemma” ( 2:30 ) is another gem..!🤯
They should really make a game about this.
"The myth of belda" would be a great name
Then they could do a sequel: "The Journey of Lincoln", though I think most would refer to it as 'Belda 2'
"The Myth of 🅱elda' is one of 'Nintinos' best selling games, 'Mark Car Race', and 'Powerful Mark Brothers' surpasses it."
@@yayeetmeoffacliff4708 bruh it’s up there with “Turbys Sleepworld”
Yeah even better, the main character Dink, is in a platform fighter crossover game Ultra Smosh Brother
Step 1: confirm you have green eyes
Step 2: ask Dongle and Gordon to leave
i love how this is like our inside joke in the ted ed community
@@maxine9263 I have been watching ted videos for a long time, but what? I remember the green eyes one but not this ask to leave hahaha
@@matheusGMN In the green eyes video, if you had green eyes, that was an unassailable ticket to freedom. You can just "ask to leave" as it were. This version of the joke still involves asking and leaving, but you're asking the other people to leave.
Ted-Ed is the last channel you'd expect to have an inside joke among the commenters, but I'm so glad we have it
All jokes aside, this will only let Gordon win.
This is the highest levels of copyright-dodging I’ve ever seen.
this sounds like the beginning of an amazing d&d campaign
3 easy steps:
Step-1: Go to Auction.
Step-2: Confirm you have eyes that has color of emerald.😉
Step-3: Leave with all the sources and let gordon and dongle dabble, diddle and dangle over what has just happened, while getting erased out of existence Thanos style. 😅
Note: you can make a world full of riddles for this Ted guy using those sources. 😊
ted ed you just lifted my mood. thnk you :)
Thanos after realizing that he could just collect three hexagons instead of six.
*The Lores of Gilda: The Chain of Inference*
Now all we need is the princess herself...
Dongle
honestly, that's a damn cool title.
My first thought was just "forcing him to spend more on the golds gives you an advantage on silvers".
Then figured "repeat your bid and he has to +1 you and if he takes it you double it". Kind of like that roulette "double until you win" strategy.
Sure enough, that got me to the answer. The silver was a bit more tricky, since you don't need to double.
The quote at the beginning was so inspirational
**wipes tears**
I recently started watching your channel and all of your riddles are very challenging and awesome.
Why didn't Gordon just take the hexagons from him after the auction? He is a magical wizard after all.
Dongle would probably rewrite reality with the hexagons he is currently auctioning so Gordon has no head
What you dont know is that Dongle created 8 silver counter parts, and kept 3 for himself.
Probably made three gold knock offs and kept the originals
The Legend of Belda: Flute of Tim
I solved it. It took me a solid 2 hours but I solved it. I'm about to watch the solution.
I just watched the solution. I calculated that there are actually 2 solutions where you can win. The second solution involves you bidding 25 instead of 24 for the second gold piece. Gordon literally has no "good" choice to make in this situation other than drawing. *In both scenarios, you are up by 2* , with your gems being at 75 or 50, and Gordon's gems being at 73 or 48. If you are at 50 and Gordon is at 48, you can simply bet 16 gems every time in order to win.
It is Monday morning, ted-ed really thinks I have the capacity to solve a riddle!
"It's 7 in the morning."
I have never been able to solve Ted Ed's riddles but I always watch them to find out the solution.
If this is a Ad I'll definitely not skip it
dongle is my new favourite character in the ted ed cinematic universe
This is why Hexagons are the bestagons
My ridiculous solution which I proudly conceived involved writing 61 on the paper so the opponent would bid 62 and then rotating the paper before presenting it thus tricking the opponent into bidding 62 while you’ve only bid 19. Sad-ed.
For real though, your solution is incredibly creative and I can see it working for the 3rd bid for the golden hexagon
@@whochangedyoutube 😅 Thanks.
He surely wouldn't have bidden "62" but your trick could work with a "6" turned to a "9" (praying for Gordon to bid a "7").
@@Peter-bv2ho That’s even better, dude. 😀
@@dheerajahuja8394 ... but if he bids "10"... omg !!! ;)
You should definitively follow the strategy of the video if you want to win for sure :)
My brain: Are you gonna watch a ted Ed riddle?
Me: yes
My brain: you would neither be able to understand it nor solve it
Me: I'm still gonna watch tho
Ur more optimistic than ur brain...... 😂😂
You are incorrect.
My brain: Are you gonna watch a ted Ed riddle?
Me: yes
My brain: you would neither be able to understand it nor solve it
Me: *Did I stutter?*
"If all three hegzagons are brought together, they can do whatever they want"
* flashbacks from think like a coder intesifies *
For the 2nd bid, go 25
If he buys it for more, on 3rd bid go 0
If he bids for 25 or less, on 3rd bid go 50
Either way you'll be bidding for the silver ones with you having 75/50 and he will be at 73 (with next right for draw)/49(without next right for draw) respectively
You will always win by bidding 25 everytime for 75, and 17 twice winning then 16 for 50
Eeeeeh
Similar answer, but I guess the ted-ed answer is technically better.
You'd still win with 50 against 49 on the silver.
Gordon's strategy to defeat the given solution:
Win both golds, and then stab link for the third.
First time when notification was faster than recommendations. 😀
these riddles in a nutshell: a bunch of cool things happened, now math
Step 1: Confirm you have green eyes.
Step 2: Ask your rival to leave
How’d you...
hahah solves everytime
@TED-Ed Why do you have to bet at most 24 on the second round of gold? Won't you also come out ahead by betting 25 on the second round of gold?
The copyright dodging is the best part of this.
Can’t wait for the incredibly confusing legend of dongle time line riddle
The Zelda reference was unexpected, and so beautiful.
*the moment you realize that the people who can actually solve it are not watching cause they are saving the world*
Kinda proud of myself for figuring this one out.
I think this also works though.
for gold one: bet 25 on 2nd other has 2 choices i.e bid 26 or 0. If 26 than he will have 73 leftover and if 0 than in 3rd round you can bid all 50 to make him bid 51 leaving him with 48. So, when the bid for gold one is over he will have 2 less coins you. Silver can be won in similar fashion as mentioned in the video above.
Correct me if i am wrong
You're right! In fact, I thought about this for too long in bed and worked out that a second bid of 26 is also (just) sufficient to win, since you have the first tiebreak.
I’d love to see a video about how people come up with puzzles
2:21 just tell him that the goblin guy is cheating
0:21 Power Rangers were so powerful. Why are they not found in my history books?,🤔🧐🤔
Okay, either this was not explained well enough or it doesn't make any sense:
Our hero has already spent 24 out of his 99 gems, leaving him with 75.
Our hero has one gold already. The solution is to bid "X" amount (let's assume 0) on the second gold and Gordon does the same, tying the first time therefore our hero gets the second gold.
Then the hint suggests that the hero bids everything which he has left, which would be 75 gems, therefore we go into the second round with nothing so Gordon would win by bidding just one gem each time. Am I missing something or was this poorly explained?
Unless Gordon wants to allow you to claim the third gold and win outright, he'll have to bid at least 75 to win the third one to stop you. So he'll be the one that spends that money, not you.
Except if you only bid zero for the second one, he'll bid one and stop you there. You definitely lose doing that. You need to bid enough that he either spends some or lets you take it, letting you force his third bet. If he can easily win the second one then he wins.
This is one of the few riddles that I got right so I'm happy
"Hexagons are Bestagons"
- CGP Grey
"mom can we have zelda?"
"we have zelda at home"
zelda at home:
This is the first riddle whose explanation I actually did not understand.
Fr
Dont worry about it, I dont think there is an actual answer to the riddle anyhow. In his explanation he give two scenarios. One where Gordon ties for the 2nd golden hex and the second scenario where Gordon wins the 2nd golden hex, but he doesnt cover the 3rd scenario where gordon doesnt spend any money at all on the 2nd golden hex. There for you spent 24 tens for no reason and now you have 51 gems to his 99 gems
@@joshuapowers3270 No you missed the answer. If he doesn't spend gems on the 2nd auction, Gordon has 99 gems for the 3rd auction and you have only 51 gems. But you auction the 51 remaining gems for the 3rd auction and Gordon has no choice and has to pay at least 51 gems for the third auction.
Therefor, you begin the auctions for silver stones with 51 gems and Gordon with maximum 49 gems...
@@Peter-bv2ho ya I know I just forgot how auctions worked there for a while for whatever reason. You should completely ignore my first comment lol
@@joshuapowers3270 Oups ! Sorry :)
They should have specified that the one who lose the auction keeps the money. It would have save many comments ;)
People are tricked because the first bid of Gordon is "0" instead of "10" or "18"... thus people assume that it is meaningfull to bid "0" instead of any other number under "24",.... wich is not.
5:22 and that’s just a theory a game theory
You win the award of “smoothest sponsorship ever”
Am I missing something here? Since your rival knows what you'll bid he could just not bid if you bid on the second gold hexagon and then block you by bidding one more on the third and keep his gem advantage, and if you don't bid on the second gold he could just bid one and not bid on the third, in this case he'll go to the silvers with gem advantage and first draw being his.
If you lose an auction you dont lose the gems.
I asked myself the same question.
Yes, you are missing something. If I bid 24 in round 2 and Gordon doesn't bid, then I win the 2nd gold for 24. I would have 75-24 = 51 gems left and Gordon has 99. For the 3rd gold, I would go all in, as winning the final gold ends the game immediately and silver doesn't even come into play. So, I bid 51. Per your strategy, Gordon blocks by bidding one more = 52. Gordon wins the 3rd gold for 52 and has 99 - 52 = 47 gems left. I still have my 51 gems. 51 > 47. So, no Gordon doesn't have an advantage heading into the silver round.
Also, per your strategy there are no ties in the gold round, making your second conclusion is also wrong -- the first tie would still belong to me heading into silver.
@@67L48 thanks man I also had the same question
Well, no. Say you bid 20. If Gordon lets you take the 2nd one for that price, then you have 55 money left on round 3, forcing Gordon to buy the third one for 55. Then you've only spent 44 to his 55. If you low-ball the 2nd bid then Gordon should snap it up as a bargain to block you, if you high-ball it, then Gordon should let you take that one too, and can get away with a cheaper bid on round 3.
25 should work as well. Because you win every other tie, so long as you have one more gem in the second round you can win. Split your gems as evenly as possible, make the lower bids first and the higher bids second. He Must spend as much as you do to get the first 2 gems, leaving you an extra gem to win the final auction.
Winning the first tie is a decisive advantage, if you bid 24 on the first auction you should be able to win no matter what your opponent does.
Yes! I found the same thing
I think you are right about the fact that there is always a way to win by bidding 24 on the 1st auction but your explanation for the second round (I assume you speak about the silver stones) is not complete. Gordon can start the second round with the advantage on the following tie. He can decide wether he wins or looses the auction (with tie or not) regarding what you bid.
Finally, I think there is way to win but the solution is not as simple as you described it.
@@Peter-bv2ho I may not have explained it thoroughly, If you have even one more gem going into the silver round you should be able to win following my basic strategy. Yes Gordon can win ties but at the cost of passing priority to you. In other words he wins the 1st tie but then you win the 2nd, Then you pass priority back. I worked out for all 3 cases but long story short, you can control the amount Gordon is forced to bid and by the 5th bid he won't have the gems needed even to tie.
Seriously give it a try, I will even tell you my bids in advance.
24
25 if I win, 24 if I lose.
Everything I have if I have to 2 wins, The same number as you if you have 2 wins, 0 if we each have one win.
Round 2, Divide is evenly as possible, Do higher bids later.
@@johnschmidt1262 We saw in the riddle solution that if Gordon loses the first auction, he loses the game.
Thus, he has to bid 25 at the first auction.
Then you have to bid 24 and Gordon will bid 25 because otherwise he loses too.
So you reach the 2nd round with 50 gems and Gordon with 49 gems (and the tie advantage).
If you divide 50 in "even" parts, you'll get 16,17 and 17.
I think that what you wanted to say is that you have to bid 16 until you finally win with 16 and only then, you bid 17... but it was not clear for me in your explanation.
... so we agree on the result from the beginning ;)
Last question : When you say "25 should work as well" in your first comment, what do you mean ?
Am I missing something?
So 24 was bet first, then it was realized that the opponent was cheating. That's the setup. So now, according to the solution, you bet 24 on the second bid. Couldn't the opponent just let you win that one as well (bets 0). So now you have 51 and he still has 99. Then on the next bid, he bids one more than you do, no matter what. He'd be at a serious advantage going into the silvers.
so the next bit he has to beat you, you bet the rest of your gems, 51, he has to bet 52. now you have 51gems and he has 47gems. YOU are at a serious advantage!
@@mauritz3912 Oh. Wait. Duh. This is an auction. I was thinking both people lose their coins. For example, for a bid if you bet 1 and he bet 2, I was for some reason calculating that you both would lose your gems. But obviously only the winning bid loses their gems :). Thanks!
Not really? You bid 51, he has to bid 52. You now have 51 going into the silvers and he only has 48. How is that a serious advantage?
The Legend of TEDEd
I swear there’s gonna be a riddle like: “you have a bag of chips and a swimsuit. You put the swimsuit on and ate a chip. Now what’s pi plus the square root of Dr. Doofinshmirtz?”
„You have a t-shirt and 5 dollars. You put on the t-shirt. Now what is the lenght of the uranium decay chain to the power of 4 plus the square root of the UK's nuclear arsenal?”
A false triforce as a main plot in a Zelda game would be interesting
"I used the hexagons to create the hexagons" -Dongle
Today I learned Hyrule would be doomed if the game were like this and I were to bid lmao
The image of Link and Ganondorf having a bitting war with Tingle is funnier then it should be