Can you solve the stolen rubies riddle? - Dennis Shasha
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- Опубліковано 20 вер 2024
- Practice more problem-solving at brilliant.org/...
Solution to Bonus Riddle: brilliant.org/...
Townspeople are demanding that a corrupt merchant’s collection of 30 rubies be confiscated to reimburse the victims of his schemes. The king announces that the fine will be determined through a game of wits between the merchant and the king’s most clever advisor - you. Can you outfox the merchant and win back the greatest amount of rubies to help his victims? Dennis Shasha shows how.
Lesson by Dennis Shasha, directed by Artrake Studio.
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Why do not they add subtitles in Spanish TED 🤔???
Add subtitles with translation in Spanish please!!!
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"The situation resembles an adversarial game like chess only here you can't see the opponent's position." Sounds a lot like a game of Battleship...
Stratigo
@@georgestafford7843 I was going to say the same thing.
Also FYI it's spelled with an e (stratego)
so basically Kriegspiel?
I don't how you've been playing battleship
Thats not how I play battleship
If I’m the kings most clever adviser, there’s a problem somewhere
Its medieval times knowing basic maths makes you a witch to them
Maybe he's paranoid so he killed all the actually clever ones
😂😂😂
If I’m the smartest person in the room, I’m in the wrong room.
Seventh commet
"The king's most clever advisor, you"
Weird they have a guy named 'Yu' in the middle of-ohhhhhh
😂 That is some advanced humor. Thanks
I actually have a friend called "Yu" so I got really confused there xD
Dis underrated! :D
It's all fun and games until the advisor crushes a tarot card to summon a god
@@ashuto2025 or the tarot card represents a manifestation of their fighting abilities
"The king's most clever adviser : you"
Lol what? You guys are screwt
*s c r o o t*
y'all are *s c r e u t t e*
No the king is smarter he made the rules so you would win the most
Yes
o o f lmao
I never bother to solve these lol. I just find the explanation interesting.
Same
Yippieyiyo same all might. Same.
Me too
yeh same, and then I forget it seven seconds later-
I stay for the stories
You can acquire “more than half” of his treasure
Me: OOOOOH
Reality: 1 extra gem.
Half of 30 is 15. If you write 8 for each box, you get 24 and the kings keeps only 6.
@@amirul3233 15+1=16, not 24.
@@R.F.9847 no, you can only get from 2 boxes, so it's 16, not 24
@@amirul3233 wtf you can get from all 3 boxes you’re lucky?
@@sebastiangottlieb1527 if u are lucky yeah, but think of worst possible case. (11,17,2)
U "only" get 16
"The game will be played between the merchant and the king's most clever advisor-- you."
*We're screwed*
We're ded
Copied
@@ok-xh7dn i guess people arent allowed to comment similar stuffs
@@eagletgriff no but this is tha same exact comment. Almost word for word. Also the comment you copied is one of the top coments So?🤷♀️
😂
I don't even know which way should I plug the USB
sideways
Just look for that little icon on top of it, also the side of the metal prong with a line through it goes down
Just look which one is able to fit in....
Just smash it in ur cpu with hammer or smthing like a brick
@@abdulsamadansari222 isn't that how you do it?
For the bonus riddle: 10
The merchant will always take the 2 most valuable piles, only leaving you with the lowest value one. That means you can only get it if you split it into 3 equal piles, 10,10,10. If I take any out of any pile and put it in another the merchant will take that more valuable pile leaving me with one less than 10.
Quite similar to the first one.
They asked what was the most one can keep. The most you can keep is 28, assuming that you can place a minimum of one ruby per pile. This gives you a perfect 1/3 chance that you will keep 28 rubies.
@@griffitethehuman5006 Except the Merchant always gets to choose which one and knows which piles to take. Your argument would only work if it was blind luck, but that's not the case.
@@steeledminer616 I was thinking he couldn't see the piles, like they had been in chests and he had to pick randomly, but I guess the video never mentions that
@@griffitethehuman5006 Yeah at no point does the video ever mention the merchant not getting to see the piles, it just says "make 3 piles"
Props to the king for designing a game that allows his clever adviser to win more than half the rubies in every scenario!
If he'd required that each box contained at least 3 rubies, we could have guaranteed 18 of them.
but what if the guy guesses what you are gonna do and puts 2 2 26 into the boxes. he would get 22 rubys back cause he KNOWS that you cannot know which box he put the majority in and to be on the safe side you could only get 6 rubies....
@@dervakommtvonhinten517 He can't do that. One of the boxes must contain 6 more than the content of another box. and 26-2 =/= 6.
That's only if you're smart, or lucky. Betting on 8 is the ONLY scenario that allows you to consistently win more than half of the rubies without the risk of getting less.
2 8 20 combination?
I love the art style of this episode. It reminds of those early 2000s children's shows. Where a narrator reads a storybook brought to life with cheap flash animation lol.
So true
"You have to divide 30 rubies into 3 piles. The scoundrel will then choose and keep 2 of those piles."
Me: **Makes piles of 28, 1 and 1, then pees on the 28 rubies.**
Scoundrel: Bugger.
😂
let's just hope the scoundrel isnt into urination
@@ReinisDoesMinecraft Then we'd have him charged for indecency or something.
Every box may have more than 2 rubies
@@geanbenicio1338 This is referring to the "bonus riddle" - which has no such constraints.
Bonus riddle: The maximum amount of rubies you can have is 10, as putting any more in a pile will result in the opponent taking it
I thought so too but it seems too simple to just divide it by three.. Oi
Parth Sankhe I got same dude👍
Clara Kapustka I guess they’re expecting us to overthink it
These questions get dumber every time, I guess they ran out of ideas and are doing quantity over quality for their patrons and sponsorships
@@111moonk I thought the same, i was like no it just CANNOT be that easy. Goddamn it even when i'm right, i'm wrong😂😂😂😂😂😂😂
Guard: *guards king*
Also guard: *completely fails to detect group of people rushing up to king*
Failed his perception check
Bonus riddle
Put them in groups of 10
He'll take 2 groups and leave you with the last one.
If you put them in any other way, he'll take the two biggest group, leaving you with less then ten.
At first I thought it was too simple to be that answer compared with the previous one, but I stand corrected, too simple
This is eaither the correct answer or else the question was worded poorly and there was supposed to be more conditions. If the original question was worded coreectly, this is the only answer that makes sense
Yes. The thing is that they say that the scoundrel CHOOSES and KEEP, so i guess he can see the piles... Btw, the first problem says that you want to guarantee the maximum number of rubies, but maybe other combinations could have a better risk/reward overall, i'm lazy about listing everything i should just do a computer program lol
You are correct.
However, if we assume that the scoundrel can't see the amount in each pile, then the answer is 28. This is because of the wording of the question - what is the MAXIMUM amount you can keep? If the two piles he choose each have just one ruby, then you can keep the pile with 28.
Assuming 1 ruby can be called a 'pile'...
Technically you could arrange the piles so that a closer packed pile of more rubies would look less than the 2 other piles which are not as densely packed.
I solved it ! I solved it Someone give me a cookie or something.
And why does king face looks like a seal
🍪...There you go ....A cookie..
Walrus, not seal
Looks like you already found a new riddle to solve
yoink my cookie now
🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪🍪
For a second I thought the solution was wrong because in the merchant’s shoes, I’d have done 2-8-20, except that combo still gives you 16 gems by the proposed 8-8-8 method. And if you got lucky enough to hit the 8-8-14 scenario, that’s 24 gems for you. So good riddle, but perhaps the logic behind the solution could be explained better by showing more distribution patterns going through 8-8-8?
They are only 10 possible scenarios and knowing them you easily solve the riddle:
If the 3 numbers are a b and c then
A+6=B C=30-A-B
A>1 B>1 C>1
Resulting scenarios are:
2 8 20
3 8 18
4 10 16
5 11 14
6 12 12
7 13 10
8 14 8
9 15 6
10 16 4
11 17 2
Choosing 8 8 8 (all of them have at least 2 numbers greater than 7) guarantees 16 rubies at least
Best case would be 8 14 8, getting 24 rubies, any other case you get 16
Kenny Arias, now that's clarity.
The problem included the assumption that the merchant knew the rules and assigned the rubies to maximise his gain, so he would never assign them in a way that gives you more than 16
@@alejrandom6592 there are only 9 scenarios. 4 10 16 and 10 16 4 are the same. Also, it shld be 3 9 18 and not 3 8 18.
@@zclin84 then its 8 possible scenarios
Step one: confirm the Ruby theif has green eyes.
Step 2: ask them to leave
I don't get it
@@Bloobinton it's a meme
@@Bloobinton it was a reference to the green eyes riddle
@@H8NN9H758 OOOOO that makes more sense
@@Bloobinton we say these people are 'madlads'
I’ll feel really smart whenever I solve a riddle but realise its not that big of a deal
We think you're smart!
Haha 🤠
r/IamVerySmart. See you there.
TED-Ed umm. Thanks...?
akshay barve wut
“The king’s most clever advisor... you.”
If you need me, I’ll probably be getting executed for my terrible service as the most clever advisor
The way I solved it was thinking of 3 scenarios(using the same number on all 3 cards seems pretty straight forward):
1. A box with minimum amount of rubies, so 2. The other two boxes bound by the +6 relation so 11 & 17. (2,11,17)
2. A box with minimum amount of rubies, so 2. One other boxes bound to this one by the +6 relation so 8, and then 3rd box with what's left 14. (2,8,20).
3. Starting with 11 in each box, satisfying the +6 relation while keeping rubies as evenly spread as possible: (8,8,14).
While looking at these numbers in the last two cases, picking anything above 8 will yield just 1 box of stolen rubies with this number. In order for this to be better than 2x8 the number must be 17. But in the 3rd case this would give no rubies at all. Therefore picking 8 is the only logical solution.
I also thought the same
"One box must contain exactly 6 more" small details that make or break your guess
Doesn't it seem that "exact" should have been in the rules...
@@jdramirez77 The answer would be the same, whether it’s exactly 6, or at least 6, so no, it’s irrelevant.
@@chriswebster24 It's actually relevant. Had the word "exactly 6" not been there, the merchant could put 2, 2 and 26 into those 3 boxes (26-2 = more than 6). So if we write 8 on each paper, we will only get 8 in total.
But since the difference must be exactly 6, the merchant now has very limited options. Whether it's (2,8,20), (3,9,18), (4,10,16), (5,11,14), (6,12,12), (7,13,10), (2,11,17), (6,9,15) or (8,8,14), if we write 8 on each paper we will get at least 16 rubies instead of only 8.
Best case scenario, we would get 24 because if the merchant sorted the rubies as 8,8,14, it will guarantee us 8 rubies from each boxes
The wording " exactly 6" changes the problem completely. As suggested, and that was my line of thinking, 2,2, 26 would be the merchant safest bet
It doesn't even need to say exactly 6. The rules say that one box has to have 6 more than one other box. That means only one box has to have 6 more than only one other box. Therefore the other two can be the same. 2, 2, and 26 is the answer I came up with.
The King:
Everyone else in the kingdom:
Everyone in this comment section: hOw aM i ThE cLeVEreSt ThE KiNgDoMs ScReWeD
Very true...
I dont understand why people think making the same "hOw aM I tHe SmArTeSt" joke is funny
@@isha- its fun to see a verity of a same joke lol
@@isha- Because they are not very smart....hence why it's funny to them.
I really enjoy these TED-Ed riddle videos. I’ve watched a bunch of them and this was the first one I was able to solve on my own.
Same!
this one, THIS one, NOT the REBEL one
this one, THIS one, NOT the REBEL one
this one, THIS one, NOT the REBEL one
I did it! I did some math and saw that one of the boxes had to contain between 2 and 11 rubies. From there I calculated how many rubies each box would have in each scenario, and noticed that in every case, at least two of the boxes contained 8 or more rubies. I did it!
The answer to the riddle at the end is 10. Because obviously he's going to take the two biggest piles. So your best bet is to split those 30 rubies evenly 10 in each pile
He doesn’t know how many rubies are in each pile
@@DLAppleGamez but he could be lucky and pick the two biggest piles anyways. With ten rubies for each pile you will always keep ten rubies
@@elisanateri4390 but can’t you just split them 28/1/1 and hope he gets unlucky?
@@DLAppleGamez yeah but I'm unlucky too
Since he pick 2 out of 3, you have 2/3 to get 1, 1/3 to get 28. I think you improve your chances by doing 2 piles of 14. But in the end, would you rather have 100% to get 10 or 66.6% to get 14 or 33.3% to get 28
me be like: **opens all three boxes with an axe and dumps out the rubies and “accidentally” throws the axe at the merchant, instantly killing him then proceeds to give some of the rubies back to the people and keeps some for myself**
**i am forcefully escorted out of the kingdom**
Medieval problems require medieval solutions
@@pyr4625 Pfft!
Where you get axe?
"the kings most clever advisor: you"
haha then our budget is going down to the ground
Ted videos: “Can you solve the riddle?”
Me: No
Me: immediately clicks on video
solution: confirm u have green eyes then leave
@@thetexc genius
Can you stop posting the same comment on every vid it’s getting annoying
@@champluvdogz4470 why read it
Give 1 gold to Eliza and Charlotte, and keep 98 for yourself
Enter 1 room, self destruct that room, re enter the stage, self destruct that, then leave
Plot twist: The trader did not watch Ted-Ed videos! He had put 8 in two and 14 in third. You get 24 gems.
That sucka paid for his sins!
I literally said "8" because it's the minimum there can be in one box. I was accidentally correct
That's actually related to it, because for two of the chests, there can never be less than 8, so yeah, not so much of an accident, just a different way of looking at it.
2 is the minimum that there can be in one box.
Why not just put 2 for all the chests since you the advisor is not restricted by rules like the merchant ? I think in this case 2 is actually the easy answer.
@@thichinhphan4010 ...in the second riddle?
Because you have to distribute all the rubies, not just six of them.
And in the first riddle, you're not the one putting them in the box.
@@thichinhphan4010 Because you want the number to be as high as possible. Remember, you have to guess a high number correct, so that you can take more rubies.
"The King's most clever adviser: you"
The kingdom is doomed
Stolen comment
I’m sorry but this joke never gets old lmao, I’ve seen it so many times but I always laugh
How is the answer not just 10 for the bonus riddle? Assuming the scoundrel always picks the two larger piles
Luther Williamson you could go for 1-1-28 and hope to get lucky
@@neelparmar6690 but you need to win in the average of cases... Either way, 10 seems like the best solution.
Actually the answer is probably 26 as the definition of "pile" is 2 or more. Best case scenario is 2-2-26 and he keeps 4.
this is assuming he is using the definition of pile that everyone uses.
edit: wouldn't making a pile of 1 break the rules as 1 isn't equal to a pile, it must be 2+ and so 2-2-26 and you get to keep 26 is the best case scenario.
@@BankruptGreek it's a different riddle altogether...
@@BankruptGreek
It's actually paradoxical to think about a pile , in common sense , two things doesn't actually make a pile,it's just...two.
And anyway he didn't mention that he could not count the number of gems in each pile, so the best bet is 10 10 10,
(Or maybe I'm wrong)
"The king's most clever advisor: you."
Your majesty, your faith in me is appreciated, but it is also *SEVERELY* misplaced.
Faith is not a virtue; believing despite any evidence to the contrary will sabotage your capacity for learning.
The last riddle is easy. He will choose the two largest piles, so you're left with the smallest one. The maximum size for the smallest one is 10. You divide the rubies into 3 piles of 10, you give the king 10, the criminal keeps 20.
There's nothing that says the scoundrel will choose the two largest piles, that is a (reasonable) assumption. But the question is what is the maximum number you "can" keep, which includes the possibility, however unlikely, that the scoundrel decides to take the two smallest piles. So technically, assuming that each pile has to have at least one ruby, the maximum number you "can" keep is 28.
“Can you solve this riddle?”
I dont even understand the answer
This is less of a riddle and more of a math problem
YAAS, I FINALLY SOLVED A TEDED RIDDLE JUST BY THINKING!!!!
"The king's most clever adviser. You"
Everyone probably has single digit IQ at this point
The answer to the bonus riddle is you should divide them up into piles of 10. If you give an unequal amount to each pile then the scoundrel will always take the two biggest piles. So giving each pile 10 is the maximum amount you can get.
From an expected value perspective, the answer would actually be 9. Even though there are two instances you would only get 9 rubies ( 8-8-14 or 20-2-8) this is actually outweighed by the fact that the other 8 times you are getting 18. This can be shown as 8*18 + 2*9 = 162 > 160 = 16*10. Note this answer is only true under the assumption that the merchant distributes his rubies at random. The riddle stated after the fact that the merchant would choose the worst case scenario.
Almost, you need to account for the fact that, using 8, there's one scenario(8-8-14) where you score 24. Therefore the expected value would be 16*9 + 24 = 168, thus making 8 optimal also from an expected value standpoint
This is the first riddle I actually solved I'm so happy. This one was quite easy honestly!
Don't bother you solve it wrong
I’m in a math program that sponsors/ uses brilliant and at first I thought it would be like a normal math program. I’m in love with brilliant for some reason
Every video I watch, it always sponsers something. Wix, brilliant, and squarespace. Wow.
Why does the king face looks like a seal lmao
ARF ARF
He's the royal seal.
Just choose the number 1 for all boxes. The rules said 1
I thought the same, but youll get total 3 gems, as it says you get the number you write down
I know, link steal them all
Lol
Quick change the boxes to pots and grass!
Oak synia, nice Legend of Zelda reference!
Great choice, links an expert at stealing rupies
The Alpaca Redstoner do you know what a joke is
The solution ends up being the same, but I don't understand why the scoundrel couldn't arrange the rubies as 2+8+20? There's no rule that says two of the boxes have to have the same number of rubies as each other...
But if you did what the video said, you’d still guarantee 16 rubies
*TED-Ed gives great animation in exchange for rubies*
Thank you, I worked hard for that animation :3
Watching for 4 years now
Allies: some of his wealth was made by himself
King: my give a f cks are on vacation
The king's clever advisor - us :D thank you
I misheard and thought 1 box must have AT LEAST 6 more, I noticed if we exclude that extra 6 then each box would have 8 rubies (24/3=8) which is how this riddle works. I was assuming there was a game theory method to guess if the merchant would try to spread out his rubies or pile them into 1 chest. very interesting idea though
YES ME TOO AND I SPEND WHOLE WEEK TRYING TO SOLVE THIS ONE USING THAT METHODS...
The add placement was just ......... BRILLIANT...
The king should have let his ADVISOR advise on his rules! Change his seemingly arbitrary rules to each box must have at least 2, and at least one but must have exactly 12 more gems than another. This makes the only possible combination 2-14-14, and with three 14s we can give the people 28/30 gems!
In this scenario you would only get 14 because of choices such as 3-15-12 or 4-16-10. There is also the tricky 2-8-20 where 20 is 12 above 8.
The king: your my most trusted advisor
Me: lol what, I don’t even live in the same time period, also I can only think of overused comments
*were screwed*
This is the first riddle that I was able to solve by myself
everyone: I GUESSED 8 AND IT WAS RIGHT
me: wait, if it's his rubies why does he have to give it away??
i've watched every one of the riddles and i finally solved this one, not the same way they did it, but i got the same answer!!
How to maximize rubies as scoundrel:
Box 1: 2 rubies
Box 2: 8 rubies
Box 3: 20 rubies
The advisor gets off with only 16 rubies
The scoundrel gets off with 12
(assuming advisor goes with the best possible strategy)
Yeah, my first strategy was to guess 20 for all the boxes before I saw the written rules at the end explaining what happens if you guess less.
Its simpler to look at the graphs of
y = x
y = x + 6
y = 24 - 2x
At x=2, the intersection with the graphs are in
2, 8, 12
So minimum of 8 is certainly in two of the boxes.
Interesting approach. This is why logic is fun, as long as you know the rules things can be approached in different ways but always seem to be closely related, just at a different angle. My solution was that the formula for the boxes were:
a
x
x + 6
since there are always 30 gems among them:
a + x + (x + 6) = 30
so
a + 2x = 24 and I concluded that a has a range of even integers from [2, 20]. a can only be integers because there has to be an integer number of gems in the box that equals a. 2 is the smallest amount a can be because of the rules and 20 is the biggest because the smaller a is, the bigger x has to be so the inverse is true and the smallest x can be is 2 by the rules so in that smallest case, a = 20. a has to be even because the monomial 2x is even and so is 24. If one integer is even in a sum of two integers, the other has to be as well to produce an even number. So, I looked at the 10 cases made by the constraints and found that the two largest boxes are never lower than 8 in each case.
Thats pretty smart. The graphs can be useful for more complicated questions.
I thought there'd be a solution where you could keep them all.
Punch the merchant and steal his rubies
Also, thats not guarantee the best either. What if the scoundrel just put 2,2 and 26 in the boxes. Then you only get 8 back, and he will get 22.
2 2 and 26 isn't possible, one of the rules is that one of the chests must contanin EXACTLY 6 more. The only legal setups are as follows:
2 8 20
3 9 18
4 10 16
5 11 14
6 12 12
7 13 10
8 14 8
9 15 6
10 16 4
11 17 2
The best scenario for corrupt merchant is 20 , 8 , 2 so if we select 8,8,8 we get to keep 16 (minimum for us) and he keeps 14 (maximum for him) , I have explained why in my comment ..
@UC-qh5Ljca3ccH6R3fgMI6oA I mean if you know the numbers then they might be no reason to guess xD I guess you mean if you know the box with maximum rubies ..
There's a flaw in this riddle, the king never said that the merchant had to put all of the rubies in the collection of chests, he can at minimum put 12 up for grabs (2-8-2) and thus the answer isn't perfect (it is assuming he did put all 30 in the boxes)
0:57 He needs to devide his rubys between the boxes
I would write the words "A number between one and thirty" on all 3 cards and then collect all 30 rubies, rather than settle for 16.
The riddle after the video:
It has to be 10? Like the other guy will always choose the biggest 2 piles so you have to distribute it 10:10:10
I mean I don't think he can see the piles, but either way there is a chance that he'll pick the largest 2 piles and you'll be left with 10. I really don't see how this is even a riddle, like it's actually way too easy, there has to be a trick but I can't find one
Yes, the answer is 10. Its surprisingly easy, but I guess it wasnt really meant to be hard since it wasnt the main focus of the video.
I can think of 2 answer 1 is if the other person can see and choose the pile then the answer would be 10 but if the other person have to choose randomly the answer could be 28 if the other person got the 2 lowest pile and they say maximum so i think that could work
I think I got it!!. Supposing he can't see the piles (which is the only way all this makes any sense) you arrange the following piles of rubies: 15, 14 & 1. Thus you have a 66.7% chance of getting almost half the pile.
@Jaeden Vaithianathan the expected value doesn't even change no matter how you distribute the stones so it is even less of a riddle than it first appears.
www.wolframalpha.com/input/?i=Maximize+1%2F3+*+a+%2B+1%2F3*b+%2B1%2F3+*+%2830-a-b%29%2C+a+in+%5B0%2C30%5D%2Cb++in+%5B0%2C30%5D
I'd put 8 on each card. 30-6=24 24/3=8. If you do 8 you'll get at least a decent amount.
Edit: Wow I got it right!
Ted-Ed: Giving us riddles they can't solve since 1990
But we've only been around since 2012... ;)
@@TEDEd is this Ted original riddle ?
"The Kingdom's most clever advisor: you".
Well, looks like my time to shine is now.
Gets pissed drunk.
Bonus riddle solution: Divide the rubies into three equal piles of 10/10/10. If they are uneven, the scoundrel will pick the two bigger ones and leave the smallest one to you.
Yay another riddle!!! I love these!!
Lol a chest wont cut it. The rubies are gonna reform you need to bubble it and teleport to the temple
This comment is great.
steven fan ?
@@Ark_Mark I'm an air conditioner
HAHAHAHAHAHA 😂
what i dont get it
“You’re the king’s mote clever advisor”
Sir, there may be a bigger problem than some stolen rubies.
"The king's most clever advisor ...YOU"
I'm surprised that half of the kingdom isn't in blazes??
Why not just take all the rubys, he's the king, and that man who took the robys did a crime.
The king can say: "Not my problem that he mixed his gems with the ones gotten unfairly."
If I'm the king's most clever advisor then that scoundrel is about to end up walking away somehow gaining 10 more rubies on top of his 30...
Well, I knew from the beginning they were all going to be the same cards. I thought of three 10's, but realized it would be too easy to get stuck with just ten. I thought maybe of trying to find the highest number so I could get one successful batch at both 15 then 12. Then, I thought obviously if you put in for 6 or 8, you'd be sure to get two of them, so I settled with 8. I didn't have a proof, but I at least feel smart, lol. The one box being x + 6 was pretty confusing, but made 8 fairly obvious.
Always love the animated/riddle uploads! This is one of the few which I actually got, I'm sure it was one of the easy ones.
2,8,20
2,11,17
3,9,18
4,10,16
5,11,14
6,12,12
7,10,13
8,8,14
Those appear to be the only ways the coins can be split. Of course we don't know which box is which. In each scenario, there is a minimum number of 2 boxes with 8 or more coins, so put 8 in front of each and you're guaranteed at least 16 coins. Best scenario is the last, where you get 24.
Wow. This is the first one I’ve actually been able to solve! 😃
I thought so too... but I do not know why the 6, 12, 12 does not work..? I thought that was also possible and I would aim for 12 on all 3 cards...
@@theumbrellaofdoom 6, 12, 12 works, and if you would have put 12 on all boxes, you would be rich, but what if he put them in a order of 2, 8, 20? then you would just get 12. or 5, 11, 14, you would again only get 12 rubies.
in all of those cases you would get 16 rubies if you said 8 on all boxes which is better than getting 12 rubies unless he divides them like you said.
So, to minimize his possible max loss, the merchant should arrange the rubies either 3,9,18 or 6,9,15. Because both arrangment is countered by 9, I would pick 9.
2,8,20 after all is an option for the thief on which if you bet 9,9,9, you'll get just 11 rubbies. But the safest option basing on logic is 8,8,8 which will always give you 16 rubbies no matter the arrangement done by the thief.
@@johncarlo2807 I would agree if Rule 5 didn't exist."The merchant knows the rules ahead of time and will do his best to maximize his chances of keeping as many rubies as possible." 2,8,20 would potentially cause him to lose 20 if I pick 20 3 times. While these two arrangement only cost him a maximum of 18. If he choose 2,8,20, he is not "maximize his chances of keeping as many rubies as possible."
@@amazonprimeminister1099 He won't do 2,8,20, it's just an option which will counter 9,9,9. My point is the safest is 8,8,8 logically based.
And also I was mistaken saying you'll always get 16 rubies if 8,8,8, but always gonna be 16 or more
@@amazonprimeminister1099 to clear misunderstanding, it's the thief which may do 2,8,20, but its you which should always go for 8,8,8
The way this was worded, the second rule implied that there would be exactly one box that had exactly six more gems than exactly one other box. By that logic, 14 8 8, as well as 12 12 6 isn‘t possible, therefore I advised him to say nine on every single box. But I would have even understood if he would have guessed 10 because the expected value would still be 18 rubies, only 1/5 of the time he would get 10 rubies. But maybe I just understood it wrong
The smallest possible numbers for exactly two boxes are 2 and 8, making 8 the only number that guarantees you get more than half the rubies no matter the arrangement. Everything else is risky.
This one actually becomes pretty easy once you turn it into a math problem.
As seen starting at 1:43, the normal amount of rubies in two of the boxes is x, and the number in one of the boxes is x +6.
So, the problem can be written like this:
3x + 6= 30
3x=24
x=8
So, your best guess for each box is 8, just as the video concluded.
"The king's most clever advisor: you."
Me: Wot
I didn't notice just how pretty the background drawings were. They're very lovely.
"The King's most clever adviser, You"
Me:
no wonder there was money that got stolen. I'm their smartest adviser.. wait how about the other advisers... uh oh
You are the kings most trusted adviser
Me:so you have chosen death.
The legend says that the scoundrel is still waiting for his fine.
"the kings most clever advisor"
guys i dont think the king built schools
Answer for last is 10.
Is it right?
I mean technically the maximum amount you could keep should be 28 if he picks the ones with 1 ruby in them. But thats not guaranteed.
Have you MET ME!? I'm not the slightest bit "clever."
I was trying to figure this out for hours. I misheard the "exactly" for the 6 more rule.
Figured it out in less than 1 min aftet that.
What was it
Rubies missing? Zel... I mean LINK!!!!!
that was a fun riddle, but i figured out the solution in a different way:
Minimum rubies per box: 2
One of the boxes must have exactly six more than another: 2+6 = 8 that box must at least eight. Therefore, you should always guess 8.
if the first box has 2, the second one has 8 and the third one has 20 (= 30 - 2 - 8)
If you increase the rubies in box 1 by one, then the amount of rubies in box 2 also goes up by one, and the rubies in box 3 go down by two:
2, 8, 20
3, 9, 18,
4, 10; 16
5, 11, 14
6, 12, 12
7; 13: 10
8, 14, 8
Every configuration except for the last one yield 16 rubies 100% of the time. The last one gives a yield of 24, which is the highest you can get.
The explanation in the vid is more elegant but i've always been bad at math and found this solution more intuitive :3
Seems like a legend of Zelda
If I am the smartest advisor, the town is doomed
Indeed!
Me: *trying to solve this riddle*
My brain: *starts singing* "You know the rules and so do I"
I'm also amazed how I managed to pick (8,8,8) as my solution while thinking that one box would hold 2, one 8, and one 14 rubies withouth realising that 6 rubies got lost.
1. Confirm the rubies have green eyes
2. Walk away with the rubies
0:01 stick around for the advertisement of our sponsor
😅😂