Finally, someone who was able to explain it in simple words. I've been overcomplicating it so much and getting wrong answers when I practice. Thanks for your helpful video!!
Thanks for including the small details. You understand we aren't computers and can't remember every single detail we have learned in the past. Thank you AGAIN for this because you made it possible to follow along step by step while taking notes in an easy-to-understand way.
So glad the video was helpful! Thanks for sharing. What you described is how I try to teach all the time, and the exact reason for the way I explain things. Going through school, I was NOT a "math whiz", so I needed all the steps explained to me. So now as a teacher, I do my best to teach that way.
After a lot of videos of people i usually watch explaining this, i still couldnt understand because it all seemed so complicated. After watching this video and you emphasizing the key steps of what needs to be done in simple terms i can finally understand, thanks.
If you are struggling with the integration part of the problem, here are a couple videos that might help. The first link gives 3 examples dealing with Definite Integrals (an area problem and some that have trig functions - but it shows the integration). The second one demonstrates the Definite Integral using the TI-84. If you search my channel, you can find more videos that walk through the steps of evaluating Definite Integrals. Video #1: ua-cam.com/video/NeBOuEm-nPI/v-deo.htmlsi=E9-dMnXsSR6tDGUS Video #2: ua-cam.com/video/mQQ7avd6Sno/v-deo.htmlsi=LOXt5g92YbbvVw_F
this is very helpful, but i have a question- on another video, i saw that someone had the formula as 1/4(h)^2 instead of 1/2(h)^2 for the isosceles triangle like you have. i didn’t understand the math behind it, do you have an explanation for that? thanks
The problem in this video should have specified that the cross sections are isosceles right triangles with a leg along the base region (this is made clear in the picture at 4:48). The 1/4h^2 would be if the hypotenuse of the isosceles right triangle was on the base of the region, in which case h is standing for hypotenuse instead of height, but is still the distance between the curves.
Finally, someone who was able to explain it in simple words. I've been overcomplicating it so much and getting wrong answers when I practice. Thanks for your helpful video!!
You’re welcome! So glad the explanation was helpful for you!
Yeah
Very helpful explanation 👍
Thanks for including the small details. You understand we aren't computers and can't remember every single detail we have learned in the past. Thank you AGAIN for this because you made it possible to follow along step by step while taking notes in an easy-to-understand way.
So glad the video was helpful! Thanks for sharing. What you described is how I try to teach all the time, and the exact reason for the way I explain things. Going through school, I was NOT a "math whiz", so I needed all the steps explained to me. So now as a teacher, I do my best to teach that way.
She’s explaining the AP calculus topic like an elementary math question and I LOVE THIS😭
That's my goal......keep it simple!
Im so glad i stumbled upon this video after being confused for months on this topic
So glad it was helpful. Be sure to check out my calculus playlists. Lots of calculus videos on my channel!
After a lot of videos of people i usually watch explaining this, i still couldnt understand because it all seemed so complicated. After watching this video and you emphasizing the key steps of what needs to be done in simple terms i can finally understand, thanks.
So glad the video was helpful for you! I have always found that using logical steps to approach most math problems makes them easier.
Awesome video! Super easy to understand!
Great to hear!
Thank you for this clear explanation, and that nice illustrations.
Glad it was helpful! Thanks for watching and commenting.
Thank you, İ have an exam today, You are my helper, Really İ must thank you
All the best!
Great example, thanks.
You're welcome! Thanks for watching.
Thanks. It's all clear now.
That’s awesome!
Thank you so much. This helped tons.
You are welcome! Thanks for watching.
Excellent lesson
Thank you!
I’m just beginning to learn this and this makes sense
Glad it was helpful!
super explanation tutor
Glad you think so! Thanks for watching.
REALLY good explanation. Thank you
You’re welcome! Thanks for watching!
you are so awesome and amazing, this was so helpful!!!! thank you
Glad it was helpful!
incredible video!
Thanks!
Thank You so much!!
You are very welcome! Thanks for watching & commenting!
Great. Thanks.
You're welcome! Please share with your friends.
This was so helpful!
Glad it helped you out! Thanks for watching.
this was very helpful, but how did you end up getting the final answer. I had trouble putting in my calculator and also doing it by hand
If you are struggling with the integration part of the problem, here are a couple videos that might help. The first link gives 3 examples dealing with Definite Integrals (an area problem and some that have trig functions - but it shows the integration). The second one demonstrates the Definite Integral using the TI-84. If you search my channel, you can find more videos that walk through the steps of evaluating Definite Integrals.
Video #1: ua-cam.com/video/NeBOuEm-nPI/v-deo.htmlsi=E9-dMnXsSR6tDGUS
Video #2: ua-cam.com/video/mQQ7avd6Sno/v-deo.htmlsi=LOXt5g92YbbvVw_F
Awesome thank you
You're welcome! Thanks for watching. Please share with your friends so others can benefit.
this helped a lot
thank you.
Awesome! Thanks for watching.
this is very helpful, but i have a question- on another video, i saw that someone had the formula as 1/4(h)^2 instead of 1/2(h)^2 for the isosceles triangle like you have. i didn’t understand the math behind it, do you have an explanation for that? thanks
The problem in this video should have specified that the cross sections are isosceles right triangles with a leg along the base region (this is made clear in the picture at 4:48). The 1/4h^2 would be if the hypotenuse of the isosceles right triangle was on the base of the region, in which case h is standing for hypotenuse instead of height, but is still the distance between the curves.
Thank youuuuu
You’re welcome!
thank you!!
You're welcome!
Good video
Thanks!