Help for Krista;A generic force field motivator:Could be a laboratory grade Tesla Force Field Generator.This would be an item that is approximately seven inches by ten, with a transformer, plus heavy transistors and capacitors, with controls that accumulates an electrical charge. Then device converts this charge into an electromotive force, possibly a generated wave sent out as a burst of scalable energy along set vector lines.A rubber ball two thirds the size of a standard baseball is coated with the light level of powdered metal.This coating to ensure that EMF generated from Tesla screen projector, will move object from starting points of A to C.This device would operate off of standard wall socket current deliver in the 110 to 120 alternating voltage range from power supply in lab.A large nonconductive 4 by eight foot universal experimental lab top, one hundred percent leveled, could demonstrate point of departure of ball, to planned extent of end of travel.This path along projected by guess-ti-mation lines to desired outcome._"Just an idea Krista. As most people might have trouble envisioning what you mean by force field along with moving an object".
The gradient function should be 2xy^3/2 + y + K because partial derivative with respect to y is equal to zero so must integrate to get g(y).. therefore 2xy^3/2 + y + k is function u want to plug P and Q into. Correct me if wrong
Starting 10.0 minutes you didn't integrate the funciton. You plugged in (2,4) and (1,1) and subtracted without integrating as far as I can see. Am I missing simething? Is this a speial property of the integral for the curve?
drjoephd no she input the potential function f into the line integral effectively saying f=del(f) which is wrong its the fundamental theorem for line integrals so if ScF•dr=Sc(del(f))•dr=f(r(b))-f(r(a)) where r(b)= r(a)=
Mansour Alkmim the integral is not wrong only thing wrong is he calls it the fundamental theory of calculus when in reality it’s the fundamental theory of line integral .
Thanks for the help, you've been helping me since cal 1 and now my cal3 w/ differential equations final is tomorrow, thanks!!!!
+LadysLoveLarkin That's awesome! I'm so glad I've been able to help along the way. Thanks for letting me know!
Thank you this saved me a lot of time ! Damn tomorrow's calculus final tonight's going to be a rough one !
+FireFoxDO I'm so glad it helped! Study hard, but get some sleep too! And good luck tomorrow, I hope you do great!
Help for Krista;A generic force field motivator:Could be a laboratory grade Tesla Force Field Generator.This would be an item that is approximately seven inches by ten, with a transformer, plus heavy transistors and capacitors, with controls that accumulates an electrical charge. Then device converts this charge into an electromotive force, possibly a generated wave sent out as a burst of scalable energy along set vector lines.A rubber ball two thirds the size of a standard baseball is coated with the light level of powdered metal.This coating to ensure that EMF generated from Tesla screen projector, will move object from starting points of A to C.This device would operate off of standard wall socket current deliver in the 110 to 120 alternating voltage range from power supply in lab.A large nonconductive 4 by eight foot universal experimental lab top, one hundred percent leveled, could demonstrate point of departure of ball, to planned extent of end of travel.This path along projected by guess-ti-mation lines to desired outcome._"Just an idea Krista. As most people might have trouble envisioning what you mean by force field along with moving an object".
How is the function simply connected when Q is undefined for y
The gradient function should be 2xy^3/2 + y + K because partial derivative with respect to y is equal to zero so must integrate to get g(y).. therefore 2xy^3/2 + y + k is function u want to plug P and Q into. Correct me if wrong
How would we calculate it if they were to give the r vector of the trajectory (path) and two points and the force vector?
good and interesting video thanks alot
Which writing platform it this? Thanks
Mam if force is along parabolic path?
life saver
I still don't get it, but I appreciate your effforts...
u didn't integrate the equation and substituted the limits directly at the end .
No need to integrate cause f is a scalar potential. F = grad(f). Then f = integral F.dr
Starting 10.0 minutes you didn't integrate the funciton. You plugged in (2,4) and (1,1) and subtracted without integrating as far as I can see. Am I missing simething? Is this a speial property of the integral for the curve?
drjoephd no she input the potential function f into the line integral effectively saying f=del(f) which is wrong its the fundamental theorem for line integrals so if ScF•dr=Sc(del(f))•dr=f(r(b))-f(r(a)) where r(b)= r(a)=
why is there so many steps wtf
the integral is wrong, why this video is still here?
Mansour Alkmim the integral is not wrong only thing wrong is he calls it the fundamental theory of calculus when in reality it’s the fundamental theory of line integral .