Buffer Solutions
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- Опубліковано 8 вер 2024
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5 years later and people are still benefitting from your videos, thank you very much for this simple yet very informative video
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7 years later
its kind of wrong
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Top kek
Thanks for the video! I've been trying to understand how Buffers work with a simple explanation and you did it! Great job!
Great explanation. So helpful. Thank you.
4 minute video is insane, thank u so much
Thank you so much for this video. Such a simple concept, yet my lecturer overcomplicated it to "exhaustion". Much appreciated
Thank you I've been so confused about this now I get it!
So simple yet so educational. Keep up the good work :)
Simple and to the point explanation. Kudos!
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Simple and easy. Love it.
I didn"t understand the point that when we add a strong base "OH" to the medium , It will combine with the HA to give A- which is strong conjugate base , so it will change the pH !
The conjugate base is strong because it comes from weak acid.
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(edit) man
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Thank you. By the way, it would be better to state that a buffer solution is made up of a weak acid(CH3COOH) and its salt(CH3COONa) or a weak base(NH4OH) and its salt(NH4CL)
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8 years still helpful
Explanation was very clear
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Dhanyavad sir
شكرا جزيلا 💛
very welll explained
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Thank you.
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Good explaination sir👍
question - if the conjugate base of the weak acid is a strong base, then when u add OH, doesn't this populate the solution with strong bases now? so that would shift the pH towards the base
Yeah, when OH^- is added, the weak acid combines with it and gives out water and strong base and if you don't add H^+ to the solution, then the strong base will be there and would populate the base concentration in the solution. But the experiment shows that pH has not changed, so there is something wrong with our reasoning.
I got it! In my textbook, it says that a typical buffer solution is made up of a weak acid and its sodium salt. So let's take ethanoic acid as our weak acid. Then, a buffer solution would be made up of ethanoic acid and sodium ethanoate salt. Then, if we add OH into the solution, ethanoic acid which is the weak acid would deal with it and give out water and a strong base which is CH3COO^-. Since, sodium ethanoate is a salt, it would dissociate into Na^+ and CH3COO^-. Then, the strong base we got from the weak acid combining with OH would then combine with Na^+ and become CH3COONa!!! So, pH of the solution would not be changed!
Buffer solution is made up of a weak acid and its conjugate base ❎
Buffer solution is made up of a weak acid and its salt ✅
@@junaid6730 okay, so the salt neutralizes the base to maintain the pH, thanks for explaining
@@pokemonjynx1019 thanks for thanking
Just what I needed :))
this really helped. Thank you :))
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So helpful! Thanks :)
Isn't it the hydrogen ion (not hrydronium ion) which conjugate base consumes ?
thank u a lot
This is all u need to understand buffer
Perfect
Is it better to use a PES or a PVDF filter for buffer solutions?
Nice video
Thq
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Thanks 😊 🙏
11.01 وقطع
great vid
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lifesaver
Thanks😭❤️
Can't the 'H' Which you added and the added 'OH' react with each other?
no (im not an expert), but im pretty sure H is to make something acidic whole OH is to make something basic. and itll just be weired if u put those 2 together.
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Please watch this video
Right sis... Me too ... Facing the same condition
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