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p=3 satisfy.9p^2-56=81-56=25=5^2
(3 p)^2 - q ^2 = 56 = 27 + 29 = 15^2 - 13^2 = 11 + 13 + 15 + 17 = 9^2 - 5^2 Hereby p = 3, -3, 5, -5
9p^2-6p+1-57+6p=(3p+1)^2+6p-57 a perfect sq .if 6p=57=>p=19/3 but it is not integer but rational.
Problem:Let p is an integer such that 9p^2-56 is a perfect square. Find all values of P? 9P^2-56=J^2 J = ± 13, P = ± 5 J = ± 5, P = ± 3
There are many sets of factors of a particular number. And if there is relation between sum of factors and anyone of factor please define as definition.
P=(±3,±5)
Sum is multiple of 6,not factor of 6
p=19/2 as such 9(19/2)^2-56=)9.361-224)/4=3025/4=(55/2)^2.thus apart from being integer p=19/2 the expn. is perfect square.
P=5. Then 9p^2= 225. So 225-56=169. Which is equal to 13^2. .So p = 13.
81-56=25 is a perfect square, so my guess is p=±3.
Greater than or equal to +or - 3
P=+5 or -5
P=-5
Please explain how you assume that multiplication product of factors of a number is equal to sum of factors or multiple of factors.
3
Sorry P is 5.
Hoc est p = 3 solutio realis unus, respondam.
(9a^2)^2 ➖ (56)^2,={81a^4➖ 3136}= 2955a^4 .100^200^10^90^55a^4 10^10^10^20^10^9^10^5^11a^4 10^10^10^2^10^10^9^10^5^11^1a^4 2^5^2^5^2^5^2^2^5^2^5^9^2^5^5^1^1a^4 1^1^1^1^1^1^1^1^1^1^1^3^2^1^1^1 3^2a^2^2 3^1a^1^2 3a^2 (a ➖ 3a+2).
p=3 satisfy.9p^2-56=81-56=25=5^2
(3 p)^2 - q ^2 = 56
= 27 + 29 = 15^2 - 13^2
= 11 + 13 + 15 + 17 = 9^2 - 5^2
Hereby p = 3, -3, 5, -5
9p^2-6p+1-57+6p=(3p+1)^2+6p-57 a perfect sq .if 6p=57=>p=19/3 but it is not integer but rational.
Problem:Let p is an integer such that 9p^2-56 is a perfect square. Find all values of P? 9P^2-56=J^2 J = ± 13, P = ± 5 J = ± 5, P = ± 3
There are many sets of factors of a particular number. And if there is relation between sum of factors and anyone of factor please define as definition.
P=(±3,±5)
Sum is multiple of 6,not factor of 6
p=19/2 as such 9(19/2)^2-56=)9.361-224)/4=3025/4=(55/2)^2.thus apart from being integer p=19/2 the expn. is perfect square.
P=5. Then 9p^2= 225. So 225-56=169. Which is equal to 13^2. .So p = 13.
81-56=25 is a perfect square, so my guess is p=±3.
Greater than or equal to +or - 3
P=+5 or -5
P=-5
Please explain how you assume that multiplication product of factors of a number is equal to sum of factors or multiple of factors.
3
Sorry P is 5.
Hoc est p = 3 solutio realis unus, respondam.
(9a^2)^2 ➖ (56)^2,={81a^4➖ 3136}= 2955a^4 .100^200^10^90^55a^4 10^10^10^20^10^9^10^5^11a^4 10^10^10^2^10^10^9^10^5^11^1a^4 2^5^2^5^2^5^2^2^5^2^5^9^2^5^5^1^1a^4 1^1^1^1^1^1^1^1^1^1^1^3^2^1^1^1 3^2a^2^2 3^1a^1^2 3a^2 (a ➖ 3a+2).