75% reaction is complete in 90 minutes. First-order reaction. 2. Formula for First-Order Reaction: t = \frac{2.303}{k} \log \frac{[A_0]}{[A]} 3. For 75% Completion: At 75% completion, because 25% of the reactant remains. Substituting into the formula: 90 = \frac{2.303}{k} \log 4 90 = \frac{2.303}{k} \times 0.602 ] Solving for : k = \frac{2.303 \times 0.602}{90} = 0.0154 \, \text{min}^{-1} 4. For 25% Completion: At 25% completion, because 75% of the reactant remains. Using the same formula: t = \frac{2.303}{0.0154} \log 1.33 t = \frac{2.303}{0.0154} \times 0.124 ] t = 18.6 \, \text{minutes}
Could you please tell me from where you got the value of k Acc to me in this formulla we have to find 2 things 1) logk 2) temp which we can't find from the following equation mentioned by sir 😢
you don't need to find value of k it is given in que k1 and k2 and why you need to find temperature ? Question me TEMPERATURE KI VALUE GIVEN HAI @@Saniya-19s-g2x
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1:30:12
2.303/90log 4 =2.303/t log 4-log3
t=90×.125/0.602=18.6ans✓
19 min bcz 18 min 60 sec
22.5 and
1:12:50 for third order rxn is
Mol^-2 L^2 Sec^-1
28:30 R=-1/2∆(H2)/∆t[Rate of disappearance of Hydrogen] =-∆(O2)/∆t[Rate of disappearance of Oxygen] =1/2∆(H2O)/∆t[Rate of apperance of Water]
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37:01 reaction, N2 + 3H2 ----> 2NH3
1. The rate of the reaction R= 1/2 dNH3/dt
Given, dNH3/dt = 0.5 ×10^3 or 5 ×10^-4 .
=> R = 1/2 × 5× 10^-4
=> R = 2.5 × 10^-4 mol / LS
2 ,.
R = - dN2/ dt
dN2/ dt = -R
= - 2.5 ×10^-4 mol/ LS
R = -1/3 dH2/dt
dH2/dt = -3R
= -3× 2.5×10^-4.
= 7.5×10^-4
rate of disappearance of H2 k answer mein (-) lagega
Right
The answer on 36:27 homework=R=0.25*10*-3 and second -0.25*10*-3 and 3rd=-0.083*10*-3
Is this right?
3rd glt h 3 ka multiple hogaa
3rd ka -0.75×10^-3
36:39
N²/∆t= 0.5×10-³ mol L -¹ S-¹
∆H²/∆t = -1 × 10 -³ mol L -¹ S -¹ ❤
∆H²/∆t = -1.5 × 10-³ Mol L-¹ S-¹
Wrong do proper balance @@Armylovers1117
This one is wrong. I am saying this to just let you know and that you don't get any wrong idea.
It's
1= 2.5 x 10^-4
2= -2.5 x 10^-4
3= -7.5 x 10^-4
And it depends how you write your answer.
Yes this is the right answer@@shishimaru._.Chan00
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1:30:18 answer is 18.68 for 25 %
36:28
-ΔN2/Δt = 0.5 *10^-3 mol / L s
-ΔH2/Δt = 1.5*10^-3 mol / L s
ΔNH3/Δt = 0.1*10^-2 mol / L s
This lecture is really helpful 😊😊😊
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1:12:51 unit of 3rd order reaction=mol-²L²S-¹
Hemant sir is the best teacher of chemistry ❤❤
It really helped me in my exams , thank you so much to sir and whole magnet brains team ❤️
1:12:50 third order rxn is k=mol^-2 L^2 s^-1
😮😮
Mol^-2L^2S^-1. 1:12:58
36:24
1. R= 0.25 x 10^3 or 2.5 x 10^4
2. delta N2= 0.25 x 10^3 or 2.5 x 10^4
3. deltaH2 = 0.75 x 10^3 or 7.5 x 10^4
- Koun dega 🤣
2 and 3 ka answer -ve mein ni aaega????
Ayega@@shaluverma0997
1:13:30 for 3rd order rxn K= mol ^ -2 l ^ 2 s ^ -1
This was the one of awesome lecture of my life.... ❤ Thank you sir
You are the one of best teacher in youtube ...❤️
1:14:03 3rd order reaction k=mol*-2 L*2 s*-1
39:00 spring constant😂
Velocity constant/rate constant directly proportional to tempt ROR , diff for diff reaction, independent of conc
36:34 Rate of reaction is -∆N2/∆t = -1/3 ∆H/∆t = 1/2 ∆NH3/∆t
Rate of dissapearence of N2 0.5 × 10^-3 mol
Rate of dissaperence of H2 -1.5 × 10^3 mol
Best one shot of chemical kinetics..
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Yup best one
28:30 -1/2∆(H2)/∆t=-∆(O2)/∆t=1/2∆(H2O)/∆t
1:30:04 18.6 min
Hii
28:36 ans hai -∆1/2 ∆H2\∆t = -∆o2\∆t = 1/2 ∆H2O/∆t
Thanks for conformation ❤
@Awmxvision2707 it's okay brother 🫂🫶🏻💯
2024-25 attendance
1:12:57 for 3rd order reaction ' rate constant (K) unit is mol^-2L^2 s^-1
1:12:51 mol -2 l -2 sec -1
1:30:16 answer is 18.6 min
Same!
1:12:51 mol^-2 L² s^-1
36:36
1×10-3
2×10-3
3×10-3
01:12:52
K = mol^-2 L^2 s^-1
Tank sir for best explanation 😊😊
very nice sir time saving lecture for quick revision
ua-cam.com/video/3qrGnr1MiEI/v-deo.html
2:10:56 ⬇️
182.28 KJ Sir is this right
Mine is 18.228 KJ 😅
2:10:35 ans --Ea=49.73
1:13:43
K= mol-² L-² S-¹
2:10:49 ans is 49,23.765
Wrong answer
Right answer
28:30 R= -d[H_2]/dt=-d[O_2]/dt=d[H_2O]/dt
Very nice lecture sirr....Thanku for being there for us❤
28:40 =-1/2∆H2/∆t= -∆o2/∆t=1/2∆H2o/∆t
U're teaching style plus ur writing style is damn good sir.
One of the teacher i've ever found in UA-cam ❤😊
1:13:56 mol-²L²s-¹
Hello
Sir one shot ch4 d and f block elements please you are best teacher
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Sir aap bahut achcha padhaate hain main aapse padhta hun UA-cam per you are best teacher❤
2:11:05 ans: Ea=18.228 KJ/mol
can you tell me how?
Excellent one shot Thank you sir ❤
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Amazing lecture ❤️🔥
28:36 H2 + 2O2 -> 2H2O
Rate= -∆(H2)/∆t = -1/2∆(O2)/∆t= 1/2∆(H2O)/∆t
thank you sir well teached❤❤
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2:10:40 18.1 KJ
1:30:12 sir mera ans 30min ara h please koi explain kr skta ki ans 18.6 kese aya
75% reaction is complete in 90 minutes.
First-order reaction.
2. Formula for First-Order Reaction:
t = \frac{2.303}{k} \log \frac{[A_0]}{[A]}
3. For 75% Completion:
At 75% completion, because 25% of the reactant remains.
Substituting into the formula:
90 = \frac{2.303}{k} \log 4
90 = \frac{2.303}{k} \times 0.602 ] Solving for :
k = \frac{2.303 \times 0.602}{90} = 0.0154 \, \text{min}^{-1}
4. For 25% Completion:
At 25% completion, because 75% of the reactant remains.
Using the same formula:
t = \frac{2.303}{0.0154} \log 1.33
t = \frac{2.303}{0.0154} \times 0.124 ]
t = 18.6 \, \text{minutes}
Are bhai Mera bhi😢
Best content for us in preparation of board exam 😊
2H2 + O2 ------------->2H2O
R =-1/2∆H2/∆t = -∆O2/∆t =1/2∆H2O/∆t
Great one shot sir ❤
Thank you so much sir ❤
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R.o.r=5×10-3
∆n2=5×10-3molL-1S-1
∆H2=-4.5×10-3molL-1S-1
Can uh explain?
your h2 is right but n2 is not right
n2 will be 1.5
Very beneficial ❤
2:10:45 Ea = 1.5 x 10^2
sir pls tell if answer is wrong or right????
I think it wrong
Could you please tell me from where you got the value of k
Acc to me in this formulla we have to find 2 things 1) logk 2) temp which we can't find from the following equation mentioned by sir 😢
you don't need to find value of k
it is given in que k1 and k2
and why you need to find temperature ? Question me TEMPERATURE KI VALUE GIVEN HAI
@@Saniya-19s-g2x
I think it will be 1.8 x 10^4 approx
2:11:30 answer 107.9 kelvin
Mine is 547.649 kelvin 😢😢
Sir ,abse me aapke hi one shot lecture dekhungi sach me best he ...
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Hello
@@sharkzpro6673 hello
@@sharkzpro6673 hello
1:27:10 A∅ Ki jagah 50 hoga na
Kew ki Dobara 50% se 90% ja raha h na ki
Starting se
2:01:53
Sir you are the best teacher 😭💗
Thank you vey much sir 🥹🥹❤❤❤❤🥹🥹🥹🥹🥹
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-0.75 ×10^-3 mol l^-1 s^-1
01:29:17
t25% =18.69
Is it for bihar board english medium
Very helpful lecture in one shot 👌👌👍☹️
Best video lecture🤩🤩 I understand each and every topic thankyou so much sirr ✨✨
3rd order reaction=mol-1L2S-1
Thankyou sir 🙏🙏🙏
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Radhe radhe
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Best chemistry teacher
18:52 reaction 😂😂
Voting for next one short revision
Best one shot ever
Is this enough without watching the full explanation.....??(Please reply because my exam is there day after tomorrow).
how was your exam..???.....is this video helpful..??
@@shreya2976yes it is maine chapter nahi pdha hau par sir n jo bola exam crack hogaya acte se
@@shreya2976hello
1:30:19 18.77
Sir pls provide short notes of all chapters of chem.
Please Sir...
www.magnetbrains.com/notes/
Video starts 2:10
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Thank you sir🥰
Best oneshot for ever thank you so much sir
1:29:25 :- 18.67 min
*Rate of diss. Of H²
*Rate of diss. Of O²
* Rate of formation of H²O
Sir plz bring D and F block one shot
Sir pehle chapter 10 complete karao please 🥺
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Half life se sir khud hi padhne Lage h 😅 😢
kl pre board h😭👍🏻
Thank you so much sir done 💪🤘🤘
Sir please sabhi chapter ka video ki Jo banki hai one shot
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You are the best❤❤❤❤❤❤
@Magnet Brains ( sir aap biomolecules kb se padhaoge ) 😮
½ ∆h2/∆t = ½∆O/∆t = ½h20/∆t
Sir,ye jo last me arehinious equation ko aapne drive kiya to ye derivation important he kya ,ya bass formula yaad karlu...
Bro derivations do not comes in chemistry they are just in the book for the clearance of concept , at least Google says that😅
@@RohitSharma-y1r4l pta tha mujhe mere class teacher ne btaya tha me bass clear Karana chahta tha
2:10:54 4925.76
1:30:13 45 min for 25%