Civil FE/PE Exam - Water Resources - Solve for Required Pipe Size given Flow Demand

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  • Опубліковано 29 гру 2024

КОМЕНТАРІ • 6

  • @AndrewMcGinley-te7ym
    @AndrewMcGinley-te7ym 8 місяців тому +4

    There is a simpler equation - D = [C0*Q*n/Sqrt(S)]^(3/8) that should be used, in my opinion. Also, as others have noted, the manning's value is 0.013 for plastic.

  • @Imlivinlife27
    @Imlivinlife27 2 роки тому +18

    Hello on PDF pg 346 for the PE plastic is listed as " n = 0.013 "

  • @jagc1998
    @jagc1998 4 місяці тому +2

    With corrected n = 0.013 value I got d = 11.064 in

  • @andrewlecheminant1079
    @andrewlecheminant1079 Рік тому +8

    n=0.010 if pipe was PVC but problem statement states that pipe is plastic. Per the table, n=0.013. Please revise video.

  • @oleopathic
    @oleopathic 2 роки тому +3

    ncees pe hb 1.1, p. 3, 328-329.
    used hazen-williams to get a close-enough answer. anyone thinks this was dead wrong ?
    here are my numbers:
    . q = 1.81215 cfs
    . c = 150
    . s = 0.004
    solve for d.
    d = 0.7966' = 9.56" = 10.0".
    always round up pipes hence the 10". (B)

    • @abradablincoln3052
      @abradablincoln3052 Рік тому +5

      I would not say it is dead wrong as the results from using the hazen-williams equation versus manning's equation are around the same. Although, in industry, we typically don't use the hazen-williams equation for sizing sewer pipes, therefore I would use the manning's equation. The PE exam is the "profession & practice of engineering", so you would need to use the engineering theory mixed with what is typically done by most engineers in the practice of the profession.