thanks for this, very helpful! in the PE Civil Handbook, this equation is in the Shears, Moments, and Deflections table (#24 Beam Overhanging One Support-Uniformly Distributed Load)
I like how you used the steel manual tables to find R2, it saves more time! I was summing the moment at the base. I still got the answer but I could use that extra time, thank you!
Great job working through the problem and then looking at how i went about it! That's the best way to study! I plan to continue to include little tricks I've learned to find solutions more quickly. that's a big part of the professional world, work smarter not harder! hope the studying is going great Elaine
You might assume 2560 lbs (16ftx8ftx20psf) acting 8 ft above point A. Take moment at A to get the vertical reaction at bracing base support which is 2048 lbs. Multiply with √2 as 45 degrees right triangle to get 2896 lbs.
Now that the PE Civil test is all CBT, where in the handbook should I be looking to derive this equation or just find it in general? I feel like it is either missing or they are deliberately not giving it to us.
i still believe these tables are given in the CBT civil reference manual - electronic edition. i just had a video going over the best parts of the manual you should check out
I still am not completely getting statics and my test is 11 days away. If you have any additional online resources that you think would be helpful I would greatly appreciate it!
I’ve always wondered, why/when do we know to use the height vs. on center (width/spacing)? I encountered this problem while studying and couldn’t make sense of why I had to do the center to center rather than the full height? In your side view, I would imagine that 20 psf would have to be multiplied by the height since you are dealing with height and not center to center spacing. Does my question make sense?
Hi Jeffrey - so you need to multiply by both. you have a wind pressure (lb/ft^2) and braces at 8ft o.c. this means that the trib width of each brace is 4ft (on both sides of the brace) totaling... 8ft of tributary width per brace. now we multiply the pressure 20psf x trib width 8ft to get us a line load that the brace is resisting of 160plf. finally you need the force (lb) acting at the brace. In order to get the line load (plf) to a force (lb) we need to multiple by another unit of length aka the height of the wall (ft). i hope this helps!
A bit of an aside, but theoretically, do the end braces experience less force than the inner braces because the end tributary width is 4 ft and the inner are 8ft?
I did this question in the practice exam and I remember this vid, but took the (hight)×(windload)=linear load on beam.....Whoops! I was so confused what I did wrong lol
thanks for this, very helpful! in the PE Civil Handbook, this equation is in the Shears, Moments, and Deflections table (#24 Beam Overhanging One Support-Uniformly Distributed Load)
Thank you! This was in my practice exam and I made the mistake of choosing A. Your explanation helped!!
Another great PE problem. Keep em coming
I like how you used the steel manual tables to find R2, it saves more time! I was summing the moment at the base. I still got the answer but I could use that extra time, thank you!
Great job working through the problem and then looking at how i went about it! That's the best way to study! I plan to continue to include little tricks I've learned to find solutions more quickly. that's a big part of the professional world, work smarter not harder! hope the studying is going great Elaine
Thank you from a fellow Mackenzie employee taking the PE in a month!
anytime MAK crew!
I love that you mention SohCahToa
my world revolves around sohcahtoa
SoCalTronics ?
You might assume 2560 lbs (16ftx8ftx20psf) acting 8 ft above point A. Take moment at A to get the vertical reaction at bracing base support which is 2048 lbs. Multiply with √2 as 45 degrees right triangle to get 2896 lbs.
Galib I love the alternative approach! thanks for giving the team another option to tackle this sucker.
Agree, because the brace is resisting all the wind load
thanks for this, only place i could find that went through this type of problem undertandably
You're welcome!
Please explain leveling methods
Is the force tension or compression?
compression
Now that the PE Civil test is all CBT, where in the handbook should I be looking to derive this equation or just find it in general? I feel like it is either missing or they are deliberately not giving it to us.
i still believe these tables are given in the CBT civil reference manual - electronic edition. i just had a video going over the best parts of the manual you should check out
I still am not completely getting statics and my test is 11 days away. If you have any additional online resources that you think would be helpful I would greatly appreciate it!
Is this from sample civil pe exam ?
I keep seeing this problem pop up all over the place.
What about more original problems?
its from the NCEES practice exam.
@@TurtleboyTom that why! Thanks for verifying what I thought was the case.
Hey can u do a lecture on asce code and aci code
absolutely!
I’ve always wondered, why/when do we know to use the height vs. on center (width/spacing)? I encountered this problem while studying and couldn’t make sense of why I had to do the center to center rather than the full height? In your side view, I would imagine that 20 psf would have to be multiplied by the height since you are dealing with height and not center to center spacing. Does my question make sense?
Hi Jeffrey - so you need to multiply by both. you have a wind pressure (lb/ft^2) and braces at 8ft o.c. this means that the trib width of each brace is 4ft (on both sides of the brace) totaling... 8ft of tributary width per brace. now we multiply the pressure 20psf x trib width 8ft to get us a line load that the brace is resisting of 160plf. finally you need the force (lb) acting at the brace. In order to get the line load (plf) to a force (lb) we need to multiple by another unit of length aka the height of the wall (ft). i hope this helps!
A bit of an aside, but theoretically, do the end braces experience less force than the inner braces because the end tributary width is 4 ft and the inner are 8ft?
RIGHT ON THE GOSH HECKIN MONEY ANDREW. YES!
Take a look at at ACI SP-4 page: 8-9. Might make things even faster
love it Ango! I just started blastin in this one. ;)
I did this question in the practice exam and I remember this vid, but took the (hight)×(windload)=linear load on beam.....Whoops! I was so confused what I did wrong lol
but you got into it and figured out your error. now you dont forget it. great job Jacob!
@@Kestava_Engineering Thank you!