I have an exam tomorrow, what if so 20 10 - 5 - - 10 40 i mean there are two different stations and they are doing same thing but one is doing in 20 sec and the other is in 40 sec ??
@@Justwil07 good luck with your exam! With parallel Process Times of 20 and 40 sec/unit, average Cycle Time can be calculated by thinking in ‘how many per time’, for instance: 20 sec PT => 2 per 40 sec & 40 sec PT is 1 per 40 sec = 3 per 40 sec => 40/3=16,7 sec average Cycle Time = on average every 16,7 secs one unit is produced by these two stations together.
I have an exam tomorrow, what if so
20
10 - 5 - - 10
40
i mean there are two different stations and they are doing same thing but one is doing in 20 sec and the other is in 40 sec ??
@@Justwil07 good luck with your exam!
With parallel Process Times of 20 and 40 sec/unit, average Cycle Time can be calculated by thinking in ‘how many per time’, for instance: 20 sec PT => 2 per 40 sec & 40 sec PT is 1 per 40 sec = 3 per 40 sec => 40/3=16,7 sec average Cycle Time = on average every 16,7 secs one unit is produced by these two stations together.