Chad thank you so much, for having such organized, well-structured videos. These make me feel so confident in organic chemistry and really carry me throughout the units. :) You make hard concepts seem so simple!!
I used to love organic chemistry so much in high school, but my (real-life) organic chef professor is doing a terrible job. I've been studying organic chemistry with you for almost a month now, and you are making me ENJOY the beauty of organic chemistry all over again. Even sometimes my subconscious thinks that you're my real professor because I follow with you more than I do with the "real one" XD. Thanks a lot prof. Chad!
Chad, a year ago you saved me from failing my General Chemistry course, and this year I hope the same will happen with Organic Chemistry! You are the best in terms of science explanation. Thanks for what you are doing!
chad over the semester you have become the person that talks to me the most (my only freind) thats what these classes leave you with just me and chad every day for hours and hours and hours but atleast i can pass a test with your in depth videos and i actoully begin to get excited to watch your videos because its the most i socially interact
I was recommended your videos by another student and man, I'm impressed! These reactions gave me so much trouble since I missed out on the lectures and my professor is a bit all over the place so her explanations are a bit wonky (she's amazing but a bit inexperienced unfortunately). I'm finally understand what's actually going on! And I do have a final soon and I'm actually confident I'm gonna pass! Thank you for doing these!
At 20:32 when we add CH3OH to substitute Br, why we only put OCH3 where is that extra hydrogen go? Is it mix with Br become HBr? If so why don’t we just add the whole CH3OH to substitute Br
05:55 Wouldn't it be better for the bromide ion to deprotonate that oxonium? It is negatively charged, while the solvent (methanol) has no charge. Taking the proton would give it a positive charge, which I don't think it's willing to have. I mean, sure, the solvent may intermediate in carrying that proton from one molecule to another, but eventually, shouldn't it end up on the negatively-charged bromide and stick there to neutralize all the charges?
I thought more substituted carbocations would be more stable and therefore lower in energy (also more substituted is favored). Why is it at 15:27 you mention that the carbocation is higher in energy and less stable?
why fluoride is a good nucleophile in polar aprotic solvent? as we know the negative charge is stable on highly electronegativeatom.shouldnot iodine be good nucleophile due to high polarazibity.
Aprotic solvents are not capable of forming hydrogen bonds. In a polar aprotic solvent, F can not be surrounded by solvent molecules thus it can attack the leaving group. Since F is more electronegative than Iodine, it would be a better nucleophile.
Moving the hydride or methyl from further away can occur but in a stepwise manner - rather than it 'jumping' from 2 or 3 carbons away it would need to move between adjacent carbons with each step resulting in a more stable carbocation. I hope this helps
@@ChadsPrepBeside that what if had comparison of two reversible carbocation state where is bond broken through energy of solvation The one with rearrangement becomes more stable than the other one before being less stable the other one before rearrangement Would be consider ways by rate of rxn or thermodynamics chad Like for example having a carbocation after rearrangement 2 degree plus benzylic(before one degree)and other one with 3 degree stability without any rearrangement
Hey Nils, Nitrate is actually a very weak nucleophile due to stabilization by induction to electronegative atoms and considerable resonce. Remember stable negative ions are poor nucelophiles because they are happier on their own and don't readily attack anything via substitution
hello, i am by no means a professional...just another student taking the class. But I think this is because it is being deprotonated (losing a proton/hydrogen) to the Ch3OH (also works a solvent) and so if you remove a hydrogen from CH3OH it just becomes OCH3 (with a neg charge). OH is not as a result of this. I think the instance you are think of when it becomes OH is when it is in a strong base (but here we are looking at it as a nucleophile).
This Thanksgiving I am thankful for Chad and his musical mnemonics.
Haha! I recognized how bad they really are to the point that I almost didn't include them! 😂👍
I'm so glad you did!@@ChadsPrep
@@Optometrynerd Next time, with harmonica or recorder!
Chad thank you so much, for having such organized, well-structured videos. These make me feel so confident in organic chemistry and really carry me throughout the units. :)
You make hard concepts seem so simple!!
Glad to hear it, Janapriya - Happy Studying!
I used to love organic chemistry so much in high school, but my (real-life) organic chef professor is doing a terrible job. I've been studying organic chemistry with you for almost a month now, and you are making me ENJOY the beauty of organic chemistry all over again. Even sometimes my subconscious thinks that you're my real professor because I follow with you more than I do with the "real one" XD. Thanks a lot prof. Chad!
Very kind words - thank you, Ahmad Saeed.
someone get this man an award!!!!!
Thank you for your kind words!
Chad, a year ago you saved me from failing my General Chemistry course, and this year I hope the same will happen with Organic Chemistry! You are the best in terms of science explanation. Thanks for what you are doing!
Glad the channel is helping you out so much - all the best in your studies!
I ACTUALLY DO GET OUT MUCH!!! THANK U VERY MUCH, CHAD
You're welcome!
chad over the semester you have become the person that talks to me the most (my only freind) thats what these classes leave you with just me and chad every day for hours and hours and hours but atleast i can pass a test with your in depth videos and i actoully begin to get excited to watch your videos because its the most i socially interact
Glad the channel is helping you - get out there and share with others what you are learning. Happy Studying!
And if you ever find yourself in Phoenix, AZ... :)
@@ChadsPrep lol I just want to express my gratitude im really understanding this stuff thanks to you bless your doing gods work
Why on earth do you think that your song is horrible?! Its a musical masterpiece! man you have got talent.
Finally - someone with good taste!
thank you for making these videos available for everyone
You're welcome
Chad, you are a real God send. thank you
You're welcome and Thank You.
I was recommended your videos by another student and man, I'm impressed! These reactions gave me so much trouble since I missed out on the lectures and my professor is a bit all over the place so her explanations are a bit wonky (she's amazing but a bit inexperienced unfortunately). I'm finally understand what's actually going on! And I do have a final soon and I'm actually confident I'm gonna pass! Thank you for doing these!
You're welcome and I hope you do well on your final!
when the wizard is also a bard
😂😂😂
Simply masterful! Thanks Chad
Glad you enjoyed it!
Thank you for the great content! I have my exam tomorrow and your videos have been really helpful! If I get an A its because of you. 😆😊
Glad the channel could help you achieve your goals - hope you did well and continue doing so!
You are amazing teacher! Thank you so much for making this it helps me a lot!
You're welcome and Thank You!
At 20:32 when we add CH3OH to substitute Br, why we only put OCH3 where is that extra hydrogen go? Is it mix with Br become HBr? If so why don’t we just add the whole CH3OH to substitute Br
I love the song it's a hit
Excellent! I think we can safely say that I should give up teaching and pursue a career where my real talent lies!😜
05:55 Wouldn't it be better for the bromide ion to deprotonate that oxonium? It is negatively charged, while the solvent (methanol) has no charge. Taking the proton would give it a positive charge, which I don't think it's willing to have. I mean, sure, the solvent may intermediate in carrying that proton from one molecule to another, but eventually, shouldn't it end up on the negatively-charged bromide and stick there to neutralize all the charges?
Excellent video. Congrats.
Thank you
Super sir excellent explanation, iam from India ❤
Thanks and welcome from the USA!
Sn2 backside attack, sn1 carbocation! 🤩I will always remember them.🤩
👍👍👍
I thought more substituted carbocations would be more stable and therefore lower in energy (also more substituted is favored). Why is it at 15:27 you mention that the carbocation is higher in energy and less stable?
Thank you! you are amazing!
You're welcome and Thank You.
At 20:05 does the product have an internal plane of symmetry therefore its achiral? Or just bc its the same around the ring
in 19:52 , isn't the product of proton transfer produce CH2? Not CH3?
Thank you so much 😻❤️you really are a life saver
You're welcome and Thank You.
why fluoride is a good nucleophile in polar aprotic solvent? as we know the negative charge is stable on highly electronegativeatom.shouldnot iodine be good nucleophile due to high polarazibity.
Aprotic solvents are not capable of forming hydrogen bonds. In a polar aprotic solvent, F can not be surrounded by solvent molecules thus it can attack the leaving group. Since F is more electronegative than Iodine, it would be a better nucleophile.
If a more stable carbocation is farther away than the adjacent carbon, are multiple rearrangements possible? 19:08
Moving the hydride or methyl from further away can occur but in a stepwise manner - rather than it 'jumping' from 2 or 3 carbons away it would need to move between adjacent carbons with each step resulting in a more stable carbocation. I hope this helps
@@ChadsPrepBeside that what if had comparison of two reversible carbocation state where is bond broken through energy of solvation
The one with rearrangement becomes more stable than the other one before being less stable the other one before rearrangement
Would be consider ways by rate of rxn or thermodynamics chad
Like for example having a carbocation after rearrangement 2 degree plus benzylic(before one degree)and other one with 3 degree stability without any rearrangement
21:09 For this part do we need to show the substituents as a wedge or dash? Or is it okay to write them in a flat position?
Hey - around 20:15 I explain that since this is not a chiral center we don't have to show the wedge/dash
Why does the nitrate ion of the AgNO3 not perform as a nucleophil?
Hey Nils, Nitrate is actually a very weak nucleophile due to stabilization by induction to electronegative atoms and considerable resonce. Remember stable negative ions are poor nucelophiles because they are happier on their own and don't readily attack anything via substitution
@@ChadsPrepbut i thought nucleophile strength doesn’t matter for sn1?
i wish i had u as a professor
Thank you
omg your song is stuck on my mind loll
Making a difference in as many lives as I can, Julia! 😛🤣
why in the major product do we add a OCH3 instead of just OH?
hello, i am by no means a professional...just another student taking the class. But I think this is because it is being deprotonated (losing a proton/hydrogen) to the Ch3OH (also works a solvent) and so if you remove a hydrogen from CH3OH it just becomes OCH3 (with a neg charge). OH is not as a result of this. I think the instance you are think of when it becomes OH is when it is in a strong base (but here we are looking at it as a nucleophile).
Best song ever
You're for FREEEE!
i'm literally only passing thanks to you lol thanks
Very welcome!
that vacation joke really feels hurt
😜😎
your song makes me laugh so hard
Mission accomplished!
I will never forget the song🫡
Mission accomplished!