Hexadecimal Multiplication

[@proggenius2024]

Hexadecimal multiplication:
I) 818 * 21 = 10B18
II) DAF * 54 = 47D6C
Thank you very much!

[@kainaatmakhani6550]

Hexadecimal multiplication: 1) 818 * 21 = 10B18 2) DAF * 54 = 47D6C Thank you very much!❤

[@Chaloobolo]

1:-10B18 2:-47D6C

[@dileepbc5901]

i got same answer

[@akshitjasrotia9579]

10=A i.e. AB18

[@godfather5777]

@@akshitjasrotia9579 i dont think 10B18 is same as AB18
As if we consider 102 and D2
Both have different values

[@Shekhar1_official]

@@akshitjasrotia9579 Bro, after solving we get 10B18 that's it. Don't simplify it more.

[@tirumalphutane1792]

i) 10B18
ii) 47D6C
Thank you so much sir!! 🙏🏻

[@Raviverma-dx6iz]

kya app Q. 2ka solution send ker do ge kya

[@singraihansda1367]

@@Raviverma-dx6iz okay

[@aayushjoshi4757]

@@Raviverma-dx6iz D A F
x 5 4
----------------------------------------
3 6 B C
4 4 6 B x
--------------------------------------------
4 9 D 6 C

[@Raviverma-dx6iz]

@@aayushjoshi4757 thanku sooo much sir for this precious reply 🙏

[@ruhail9703]

@@aayushjoshi4757 47D6c u have mistakenly wrote 9 instead of 7

[@snehashishbanerjee2575]

🔴H/W problem 1:
✔️Ans: (818 × 21) = 10B18
.................................................................
🔴H/W problem 2:
✔️Ans: (DAF × 54) = 47D6C

[@huzaifakhalid7003]

I'm getting 44D6C could you show me the steps?

[@marah8158]

ANY numerical system MULTIPLICATION:
if the multiplication of two digit < base
we put it as it's.
else (the multiplication of two digit >= base)
we put the REMAINDER of (multiplication/base) in the result,
and the carry is (multiplication/base) integer.
it's like the addition method.

[@sakshisharma1056]

Thankyou so much nesoacademy.
P.S. it will be really helpful if you could also make a video series on assembly language programming for microcontrollers.

[@elenaasi3960]

Your videos are so useful sir.Thank you.

[@gaganrajchandrakar]

ans are 10B18 and 47D6C

[@suklasatapathy7540]

1) 10B18
2) 47D6C

[@thefighterbadrbelkok9258]

can you give me your account facebook please i want to ask you ??

[@adrreb]

You Are great! Thank's.
Greetings from Poland 🙂

[@piyughosh4542]

10B18 and 47D6C.. thank you sir

[@agrimgupta7998]

1. 10B18
2. 47D6C
Thanks

[@kainaatmakhani6550]

Hat's off to you sir.

[@NP_BROTHERS]

Ans :- 1)10B18
2)47D6C

[@chandrasekharreddymuthumul8313]

47D6C AND 10B18

[@nomanaasifgudur6756]

1)10B18. 2)47D6C

[@nepalbhushan4345]

Thankyou you guys are savior for us 🥰

[@shivamtiwari3679]

Your lectures are fruitfull

[@KunalKumar-zh4je]

Ans
1) 10B18
2) 47D6C

[@marouanebr409]

it was very helpful for me thank you so much sir !!

[@saisandesh.s.b.7036]

HW Answers: -
1) 10B18
2) 47B6C

[@kanhaikumar3453]

1.10B18
2. 4BD6C

[@Amisha-nt4vu]

Thank you Neso Academy 🌟

[@vakhariyajay2224]

Thank you very much. You are a genius.

[@sanafatmi2579]

1:10B18
2:47D6C
This is correct answer

[@Luna-fu7ix]

Thank you alot ! really Helped😌

[@nitishkumarprajapati6096]

Thanks Sir☺️☺️

[@markanthonyoccena7345]

thank you. really helpful

[@DeepakSingh-sl6nj]

Thankyou very much

[@ravidvann6456]

thank you

[@preetismile7659]

Q1 = 10B18
Q2 = 44B6C

[@ag_richa13]

Ans. 1. 10B18
Ans. 2. 47D6C

[@binoydarvin8957]

Very good.. Well explained

[@ahinsanipuni]

Thank you so much sir❤❤❤

[@allusivasantoshi77]

Thank u very much..so helpful
Ans..
10B18
47D6C

[@govindanetinti599]

Good explanation

[@simratsaini879]

1. 10B18
2. 47D66C

[@Abishekkws]

You are a good teacher!!!!!

[@salonichaurasia885]

Answer is 10B18
47D6C

[@raphaelmartinez2242]

It is better if you will designate which base system you are working with. 94 x 12 confused me at first glance.

[@samaaya7138]

very well explained ...

[@gopikrishnamoodu6152]

Ans :
1. 10B18
2. 47D6C

[@madhawiahmed16]

why did you take a carry of 2?

[@FierceBattle]

Why we are using 2 instead of 1 for 36,35 and 32

[@mema5165]

1 × 16 can't accommodate 32 and above. If we use 1 × 16 on 32, the "product" becomes 16 which is more than the max value of 15 (or F), and the same goes with those above 32.
Just like if the product becomes 48 and above, 2 × 16 won't be enough as well so we will use 3 × 16

[@krishnap3000]

a) 10B18 b) 44D6C

[@zezo2895]

Thank you sir ❤

[@leihlalainemartinez8096]

wherw did you get the number 4 3 and 0

[@chillsup7821]

this was soo helpfull!!!

[@BIT_RaginiV]

Hexa decimal division?

[@Shadowtainer735]

Answer- 1-16B78 2-8D436C

[@Shadowtainer735]

Good it's correct

[@prog2597]

@@Shadowtainer735 absolutely not

[@oron741990]

Thank you so much ^^

[@ganeshmula4508]

H. W problem answers
1)818 ×21=10B18
2)DAF×54=47D6C

[@mdshahidansari9126]

Glad to have neso platform 🤩

[@mahamejaz476]

How we can determine that the carry is 2 or 1 while breaking no hexadecimal numbers.... please tell

[@nitashajain8685]

R u got this point?

[@kentedriandiangco5522]

Thank you! Good sir

[@SNEHAPATIL-z2g]

Sir, can you please explain hexadecimal division also

[@01mahimajerushasingh74]

i) 10B18
ii) 44DAC

[@doomer101]

Helps me alot
Thanks very much

[@أعتزوافتخربمغربيتي]

thank you very much

[@upparasomu2039]

Thanks a lot sir

[@김경보-k6s]

thank u

[@techsupport4.0]

Can we do with first change all numbers into binary and then multiply

[@BlackOpal-dk6iv]

SIR I HAVE COMPLETED LECTURE 49 OUT OF 202. TREMENDOUS LECTURE AND THANKYOU FOR YOUR GUIDANCE !!

[@PraavinVenkat]

Cant believe its 7 yrs ago

[@Marc_zz]

8 years ago

[@jonasasare5775]

i.) 10B18
ii.) 47D6C

[@iVodkaBeerMaikMB]

ty

[@madhuchhandapriyadarshini6068]

H.W. :-
(i)818×21=10B18
(ii)DAF×54=47D6C

[@LightYagami-pw4wu]

thanks sir

[@Idi-k2q]

Thanks

[@OyejideOlamide]

Why does it carry 2 and not 1

[@vishalaher2734]

Sir plz tell me this is succecive addition method?

[@nikhilraj3434]

Answer to homework problems
1: 10B18
2: 45A6C
PLEASE PROVIDE WITH THE CORRECT SOLUTION

[@sajankumar8202]

I think answer is
1. 10B18 2. 48A6C

[@sajankumar8202]

@@lakshmanpatelofficial plzzz check ur ans. again

[@prog2597]

@@sajankumar8202 ans was correct

[@pranavadith8111]

How to do hexadecimal multiplication for 12*19

[@AtulKumar-cg3rl]

9*2 = 18 = 16 + 2
9*1 + 1 = 10 = A
1*2 = 2
1*1 = 1
Now, A2 + 120 = 1C2
Implies, 12 * 19 = 1C2

[@hetaeramancer]

1C2 is the answer. I got it by using the "look at the other comments" method.

[@cimos5133]

@@hetaeramancer lmao

[@MKumarThakur]

answer of
i) 10B18
ii)44D6C

[@ShivaKumar-xq8yk]

Sir
How to do the -58H * 79H?

[@chandrasekharnamala8399]

58*79= 299C ( 9 multi to 58 then =31C and 7 of 58 is 268 after that 31C
268X
ANS 299C

[@AtulKumar-cg3rl]

@@chandrasekharnamala8399 Your answer is wrong
9 * 58 = 318

[@AtulKumar-cg3rl]

9 * 8 = 72 = 16 * 4 + 8
9 * 5 + 4 = 49 = 16 * 3 + 1 = 31
7 * 8 = 56 = 16 * 3 + 8
7 * 5 + 3 = 16 * 2 + 6 = 26
Now, 2680 + 318 = 2998

[@appayyagariaswini2060]

@@chandrasekharnamala8399 9*58=318 bcoz 9*8=72, 72=4*16+8
7*58=268X
ans=2998

[@divakarkumar8353]

@@chandrasekharnamala8399 answer is 2998

[@mukulbikaspahari6583]

Ans :
10B18
47D6C

[@rashmikiranpandit8962]

pls teach hexadecimal division

[@RameenFallschirmjager]

So much shit to learn! I'm overwhelmed! My mind is exploding!

[@Rahulsingh-mq2ny]

Makaut ?

[@RameenFallschirmjager]

@@Rahulsingh-mq2ny what?!

[@hetaeramancer]

@@RameenFallschirmjager he said Makaut

[@FaaduMastiShorts]

A2XB4

[@amanpratapsingh1243]

71D8

[@solomonrajyerrolla7427]

2E*34.....pls reply

[@nadayassen7257]

958

[@pavansaik1104]

10B18
47D6C
Thank q sir

[@syedaasra2423]

how to multiply FFFF by FFFF?

[@easiestlearning6008]

F F F F
F F F F
-------------------------
3 E F F F 1
2 E F F F 1 X
E F F F 1 X X
E F F F 1 X X X
----------------------------
F F F E 0 0 0 1

[@easiestlearning6008]

F F F F
F F F F
-------------------------
3 E F F F 1
2 E F F F 1 X
E F F F 1 X X
E F F F 1 X X X
----------------------------
F F F E 0 0 0 1

[@devanandrp824]

FFFFxFFFFF =FFFE0001

[@officialanoopkumar]

a) 10B18 b) 47D6C :D

[@natashaganjoo4464]

10B18
47D6C

[@ritikshrivastava9442]

(i) 10B18
(ii) 47D6C

[@roshankumaryadav9479]

sir why we donot studied octal division and hexadecimal division

[@SapnaSharma-br8yi]

10B18 & 48A6C

[@studentcommenter5858]

Nope the answer is 10B18 and 47D6C. It is surprising to reply to a comment that is made "2 years ago" :-0

[@susantamondal3035]

47D6C is the answer of the second hw problem

[@darkfantasy9239]

How did you solve this can explain that

[@pasupuletipasupuleti8734]

10B18,47D6C

[@arfakhatoon7898]

i. 10B18
ii.47D6C

[@navpreetkaur9091]

10b18
47d6c

[@Rohitt6398]

2: 43D6C

[@ademg8819]

يسترو

[@natural_beauty573]

10B18
47D6C

[@thefighterbadrbelkok9258]

can you give me your account facebook please i want to ask you ??

[@SaurabhKumar-pq3jf]

1. 10B18
2. 47D6C

[@nitishkumarprajapati6096]

Thanks Sir☺️☺️

[@aayushjoshi4757]

Answers :
1. 10B18
2. 47D6C

[@vinodeslavath2098]

1)10B18
2)4C26C

[@omerfarooq6671]

answer is 47D6C

[@jahidrony9005]

i)10B18
ii)47D6C