Integral of the Day 6.16.24 | Semi-Spicy Trig Integral with some Slick Tricks! Math with Professor V

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  • Опубліковано 15 чер 2024
  • Here's a trig integral that really required some clever tricks and determination! Did you solve it differently? I'm curious if there's a more succinct and elegant solution. Let me know in the comments below! :) Thank you all for your continued support, it means the world to me!
    Here's the video on the Weierstrass substitution of t=tan(x/2):
    • Substituting t=tan(x/2...
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КОМЕНТАРІ • 10

  • @benriakchangdar4963
    @benriakchangdar4963 9 днів тому +1

    I liked it.

  • @Algebrainiac
    @Algebrainiac 10 днів тому +3

    I couldn’t do this LOL 😂 you find the craziest integral problems!! Woooo they’re hard LOL. As always great job ❤

    • @mathwithprofessorv
      @mathwithprofessorv  10 днів тому +2

      This one was extra spicy!!!! 🌶️ 🥵 Haha great job, and I’ll do a more mild one next! Every now and then it’s fun to spice things up 😉

  • @isaacfielsted37
    @isaacfielsted37 День тому

    Outstanding example

  • @tony413chow
    @tony413chow 9 днів тому

    Thanks for letting me know to multiply sine(theta).

  • @Algebrainiac
    @Algebrainiac 10 днів тому +1

    I multiplied sin(θ) of course not illegally. Lol I multiplied it on top and bottom. I did that as my first step and so then I got integral of
    Sin(θ)/sin²(θ)cos(2θ)
    And then I made the bottom into terms of cosine
    So I got
    sin(θ)/(1-cos²(θ))(2cos²(θ)-1)
    Then I made u=cos(θ) and then du=-sin(θ) dθ
    So I got
    - integral(-du/[(1-u²)(2u²-1)])
    And then that’s where I got lost because I don’t know how to do partial fractions with quadratic factors at the bottom LOL

    • @mathwithprofessorv
      @mathwithprofessorv  10 днів тому +2

      That’s really great!!!! 👍🏻 I think figuring out the substitution in the beginning was pretty tricky, be proud of yourself! ☺️☺️☺️

    • @Algebrainiac
      @Algebrainiac 10 днів тому +1

      @@mathwithprofessorv thank you 🥰