How do we exactly understand which graph is above and which is below? Sometimes you can't say it just looking at the graphs. Is there any way to find out?
Ouch! well I found a possible start to answer this. let R = radius of meadow and r = radius of chain. (1/2)πR² = (r²)ArcCos[(2r²-R²)/2r²]+R²ArcCos[R²/2rR]-(1/2)√[R²(4r²-R²)] Now solve for r numerically if given R. Source Wolfram MathWorld Circle-Circle Intersection. There is an example for this problem where R=1 and little r comes to 0.8079455... on the page.
Can you give me a solution for the following problem: a goat can eat 1/2 of a round meadow The goat is connected with a chain at a point on the edge of the meadow. How long is the chain ? This problem haunts me for decades !! I can find a solution but it gives me an equation I can't solve.
:( I wish there was theoretical Physics available in my country. I don't want to do Law or anything else. I feel sad. I feel materialistic. I want to learn Physics.
Is there any possible way to quickly determine the intersections between curves so to know the limits of the integrand without using any graphical calculator??
I have a question. Why did you rearrange the formula to, (rootx-x^2)?, why not the other way round like, (X^2-rootX)???. This is where I sometimes lose marks because I rearrange them wrongly. So what's the logic behind re arranging them the correct way?
I know this is late, but you do so because the rule for the formula states that the top curve must be subtracted from the bottom curve; this is because the top curve takes dominance over the bottom curve for the equations sake.
When you realize that by the time you will actually need all this stuff you won't remember it, but you will still have to pay $1500 for the class you took 4 years ago.
+Detective-E when you set f (x) = g (x), it doesn't necessarily mean that both functions will cross at the point (0,0). what if his functions were f(x)=(x^2)-1 and g(x)=(sqrt(x))-1, you would have a y-intersect of (0,-1).
reply to rhoadess:your solution is for 2 equal circles but the circle of the goat must be bigger dan "1". to eat 1/2 of the round meadow Thanks for the information about Circle-Circle intersection
what if we don't have the graphic drawn out and we don't know how to draw the graphic, how would we know which function is on top/bottom or left/right to subtract one from another?
+Filippe Barros set f (x) = g (x) and solve for x to get the boundaries. from there, pick a x value between the boundary (both functions should have this point in common) and solve for y. whichever function has the higher y-value, is the top function. your top function is the left, bottom function is the right.
Instead of spending 2 weeks in class, I spend 4 min with this vid, and I end up knowing more than the people who go to class.
Six weeks of Calc 1 over the summer and I couldn't understand this. I'm now able to do it after watching this video lol.
Thank you Khan Academy! I just learned (what I couldn't learn in hours of class) in 4 minutes!
So many concepts explained well and quick. This is the way to go.
Last minute catching up, thank you once again Khan Academy
This is a godlike video.
Are u still using youtube?
This explanation was really clear, thank you!
dude i love you
How do we exactly understand which graph is above and which is below? Sometimes you can't say it just looking at the graphs. Is there any way to find out?
use the pen test
Mechaela Beatriz what pen test
Ouch! well I found a possible start to answer this. let R = radius of meadow and r = radius of chain.
(1/2)πR² = (r²)ArcCos[(2r²-R²)/2r²]+R²ArcCos[R²/2rR]-(1/2)√[R²(4r²-R²)]
Now solve for r numerically if given R. Source Wolfram MathWorld Circle-Circle Intersection. There is an example for this problem where R=1 and little r comes to 0.8079455... on the page.
Thank you.
Thank you so much
3 days in class... 3 days and I didn't get it as well as I did in this 4 minute video.
Thank you so much!
Amazing explanation, but can u tell me what is the name of the app you are using? I mean the one where you are drawing the graph. pd: sorry my bad eng
Can you give me a solution for the following problem: a goat can eat 1/2 of a round meadow The goat is connected with a chain at a point on the edge of the meadow. How long is the chain ?
This problem haunts me for decades !!
I can find a solution but it gives me an equation I can't solve.
:( I wish there was theoretical Physics available in my country. I don't want to do Law or anything else. I feel sad. I feel materialistic. I want to learn Physics.
Is there any possible way to quickly determine the intersections between curves so to know the limits of the integrand without using any graphical calculator??
What lesson is this on Khan academy
I have a question. Why did you rearrange the formula to, (rootx-x^2)?, why not the other way round like, (X^2-rootX)???. This is where I sometimes lose marks because I rearrange them wrongly. So what's the logic behind re arranging them the correct way?
to integrate you need a power, you cant integrate from rootX, it has to be X to the power of something
I know this is late, but you do so because the rule for the formula states that the top curve must be subtracted from the bottom curve; this is because the top curve takes dominance over the bottom curve for the equations sake.
When you realise that you are taught stuff that'll probably never come in handy in the future.
Or that you can just plug into a calculator and get an answer and not have to work it out at all.
try getting into college without it
When you realize that by the time you will actually need all this stuff you won't remember it, but you will still have to pay $1500 for the class you took 4 years ago.
physics is one of the most applicable areas for calculus tho
very good
4:06 i want to know how did it becomes x^3/2 then mutiply bye 2/3??
Applying the rule of integeration which is add 1 to the power and then divide the new power by the base
Thanks men it helps me a lot 😆
No problem, wish you good luck :)
If you didn't have the bounds...can you set f (x) = g (x) to find them? I just started Calculus 2. Doing homework lol.
Yes you can, that's how you find where the two curves intersect, which is essentially the bounds.
+Detective-E when you set f (x) = g (x), it doesn't necessarily mean that both functions will cross at the point (0,0). what if his functions were f(x)=(x^2)-1 and g(x)=(sqrt(x))-1, you would have a y-intersect of (0,-1).
reply to rhoadess:your solution is for 2 equal circles but the circle of the goat must be bigger dan "1".
to eat 1/2 of the round meadow
Thanks for the information about Circle-Circle intersection
can we find function by having area covered by that function in some limit s
no. there are probably infinite functions that would meet those requirements.
Thank u sir pz help me how can I findout the area between curve y=x^2-3x+8 and line y=x+5
reply to rhoadess: little "r" must be at least more dan "1" for R=1
How can u subtract them? They have two different exponents
You can't , that's why he splits up the integral
Base voice.......
what if we don't have the graphic drawn out and we don't know how to draw the graphic, how would we know which function is on top/bottom or left/right to subtract one from another?
+Filippe Barros set f (x) = g (x) and solve for x to get the boundaries. from there, pick a x value between the boundary (both functions should have this point in common) and solve for y. whichever function has the higher y-value, is the top function. your top function is the left, bottom function is the right.
+firedragon0529 you probably have no idea how useful that is to the people that have read your comment. Thank you
you just freed me. this question had been annoying me a long time
firedragon0529 thx saved life
this isnt simplified, HOW TO GET THAT 0 AND 1 ,,, zzzz
Kai MoMo Kai in the case of the example it is given, but if it is not given you set the equations equal to each other and solve for the two numbers
sixty ninth hehe
fifteenth
first
If u still use youtube please tell what are u doing ? what is going on?