Bisection Method | Numerical Methods | Solution of Algebraic & Transcendental Equation
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- Опубліковано 6 сер 2024
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This video lecture of Bisection Method | Numerical Methods | Solution of Algebraic & Transcendental Equation | Problems & Concepts by GP Sir will help Engineering and Basic Science students to understand following topic of Mathematics:
1. How to solve Algebraic & Transcendental Equation ?
2. Various Methods to solve Algebraic & Transcendental Equation
3. Bisection methods and its working procedure
4. Example Based on Bisection Method
#BisectionMethod #NumericalMethods
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This Concept is very important in Engineering & Basic Science Students. This video is very useful for B.Sc./B.Tech students also preparing NET, GATE and IIT-JAM Aspirants.
Find Online Engineering Maths. Online Solutions Of Bisection Method | Numerical Methods | Solution of Algebraic & Transcendental Equation| Problems & Concepts by GP Sir (Gajendra Purohit)
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Time Stamp
0:00 - An introduction
2:19 - Formula and procedure of Bisection method
8:39 - Q1.
14:16 - Q2.
22:18 - Conclusion of video
23:58 - Detailed about old videos
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Dr.Gajendra Purohit thnx sir from pak.
Sir can you suggest me best book of engineering mathematics
سر ماشاءاللہ بہت اچھا سمجھاتے ھیں ۔۔۔۔۔ لیکن سر جی آپکا ایک تکیہ کلام ھیں مطلب جو جملہ آپ بار بار کہتے ھیں وہ ھے ۔۔۔۔۔۔۔۔۔ " ھیں نا "
Thanks a lot sir
Love from kashmir sir ajj poora smg aaya
Really love u sir
Working hard and expecting nothing from us... A person like you is hard to find sir... Thanks a lot sir.. May God bless you with everything you deserve 😊
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Really ture☺
Really working hard .....
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Sir, you are really teaching us free of cost. You are legend
He earns through yt
Nothing is free of cost...,If you are not paying for the product then you are the product.
No he is not earning that much from youtube . Because indian ads are cheap . Not sure about he do paid promotions or not .
No one can legend
He's earning money from our views and subscribes too.
Sir my name is Sheraz Ali
From Rawalpindi (Pakistan)
You are my ideal I am so stressed about numerical Analysis
But I attended your lectures and got 3.50 CGPA out of 4
Thanks alout sir
2:15 "save time"
Thanks
Thank you
🙏🏻
thanks dude
Exactly I want to say the same👽
TO Find FX , we can directly get answer from calculator , 1. set your calculator in mode , To set it click on mode and press 7 . step2. after that in fx write your equation : for example if question is x^2-2x-5=0 then we have to do , alfa x square - 2 alfa x - 5 . step3 shift slove . step4 : start -6 end +6 then you will get an table of up to -6 and 6 fx
Learning in 2020 lockdown ✌
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Sir you deserve so much more… your teaching methods go straight in the core of our brain❤… thankyou sir❤
Thank You Soo Much Sir...I was just Confused with this method then One Of my friend shared this video to me... and then I Saw It...and It Was like...Woww...this became so easy to me.... Thank you sooo much sir... please keep uploading this type of videos...🙏🙏❤️❤️❤️
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This is the best explanantion out of all the videos i have seen on bisection method till now.....
Stucked in bisection method from 2 days just by watching your video i learned 2 approach to solve bisection methods problems. thank you .
concepts and methods are clear now ...all thanks to you sir!
Thank u soo much sir🙏...you made every complex problem so easy to understand...you r one of the best teacher sir.❤️
Sir You Are Best Teacher In The World For Mathematics Subject
Ya
U r great sir ..ur teaching way can't be compared with others..it's so simple thanks a lot for providing us such a valuable nd important content...
Thank You Sir, Again !!
I observed that this is just Binary Search Algo.
But not normal one, involving decimal(similar used to solve - Gas Station Problem).
Learning by Observing the interlinking of things is AWESOME.
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College mein itna sikha tha but ek heee confusion tha ki line par minus ya plus mein kaise aata hai aaj samjh gaya sir ji.... f(x) par value put karke nikalna hota hai.... Dr. Gajendra purohit sir ji you are awesome sir ji❤❤🎉🎉 awesome
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Calculator allow tha kya exam m ?
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One doubt sir:
We could have more than one roots in btw two opposite values of f(x).
For exmp.- function could have 1,3,5,7,..... and many more number of roots.
Will bisection method applicable in that case?
Sir your leacture supporting me very much
Thanks sir
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Thank you Sir 😊
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saving us during exams ;)
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Thanks Sir! Great Tutorial!