I've been breaking my head trying to figure this out in studying for my FE exam. Your video made it so clear that now I fully understand. Thank you so much.☺
h(t-tau) actually moves to the right while t >0. However, she put the symbol "t" in X axis and in the negative side, that means t is negative. Under this situation, the h(-tau) will moves to the "negative" right, so it moves to the left.
thank you so much. ive spent so many hours alone (online classes) trying to figure this out and it's finally put in a way that even I can understand. If I ever graduate let it be known that you were a factor :)
Thank you so much for making this simple. Ive been through so many different university pages and examples and so many details are left out. Thanks again!!
I think transforming h(k) to h(t-k) requires flipping first[h(-k)] and then delaying by t [h( -(k-t) ) = h(t-k) ]. So your graph of h(t-k) should be on right side of Y axis if t>0. if t
wow. thank you very much. you just made something so confusing into something so simple. ive watch many you tube videos about this, and this is the most easiest to learn and clearest video ive seen. thanks.
Intersting part comes up at 19:38 I mean it is nice to watch it full, but in case you have your exam tomorrow, her slow drawing and talking would drive you mad
example of convolution was amazing and very easy to understand with ur method. but i have a question, in last while plotting y(t) between region 2 and 3 ,it was -6t+18... you decreased it negative slope by -6.Where is +18 factor gone ?
Thank u very much for this amazing explanation, when u were saying professors don’t explain bla bla exactly u were talking about our professor gorkem 😂 thanks a lot
Overall this is absolutely amazing and incredibly helpful. I have a question about the last section region of overlap. You have y(t) = -6 +18. You have the slope of -6. What about the +18? should it have jumped up to 18 and then -6?
The +18 is where it would cross the y-axis. If you were to take the line she drew from (2 < t < 3), at a -6 slope and extend it from -infinity to +infinity, it would cross the y-axis at +18. The reason she did not draw it is because the previous point of the graph she was drawing ended at t = 2. So drawing the extended line from -infinity to +infinity is unnecessary. She just drew it where it was needed, which was t = 2 to t = 3. That is where the limits of the last overlap occurred. Hope this helped!
Thank you +199axelman. I'm from California. I really appreciate these videos and plan to take my test in December. Good luck to you on your test my friend.
Raiya Energy Academy specifically.. fourier series representation, filters, modulation ( signals and systems).. also some microelectronics topics BJT as amplifier... thnx in advnce..
Ark I got a few videos on Electronics and Communications, may not be enough but it's a start. I will upload more on Fourier/Modulation very soon. You're welcome.
h(t - T) shifts h(-T) to the left, by t. Consider any function y = f(x), say y = 2x. This is a straight line of slope = 2, passing thru' the origin. Now, consider f(x+a). This is y = 2(x + a), i.e. y = 2x + 2a. It is a straight line of slope 2, with y-intercept = 2a, and x-intercept = -a. Thus, f(x+a) is f(x) shifted to the LEFT by a.
No, it shifts to the left: if t is positive, you will find the previous h(0) point to the left of the vertical axis because h(t-T)=h(0) => t-T=0 => -T is negative which is to the left of T=0, when the T axis is pointing right. ... but actually she should have written "-t" and "-t-1" on the yellow figure
As you say, t-T=0, which means that the new h(0) point happens for T = t, which is a point on the positive T axis. I don't know how you start off so well and then still fuk up your explanation. Gordon Borostraw is correct.
Gordon borostraw Good question, but when we shift to the right then the shifter should be negative and when we shift to the lift then the shifter should be postive. In other words, positive comes before, which is left shift and negative comes after which is right shift. So, I believe she is right.
h(t-tau) actually moves to the right while t >0. However, she put the symbol "t" in X axis and in the negative side, that means t is negative. Under this situation, the h(-tau) will moves to the "negative" right, so it moves to the left.
Thank you for taking the time to explain the extra steps involved. Those 20 minutes saved me hours and hours of stress and web searching.
in 30 minutes you explained to me what my highly paid professor couldn't do in a month's worth of classes. You the real MVP
you said exactly what everyone here is saying ! She is AMAZING
Thank you very much :) Very encouraging words!
Awesome. I'm glad i was able to help. Your words are very encouraging. Thank you!!!
True
The best teaching I have ever seen on convolution period.
Thank you so much for breaking it down
This is by far the best tutorial I have ever seen. You've just saved a life. Thank you so much.
I appreciate her. She taught full visual process that really professor never tell you in class room.
I passed the FE. Just wanted to say thanks you videos were a tremendous resource. 🙏
dre mckenzie, great to hear that. You’re welcome. Congratulations on passing the FE!
I've been breaking my head trying to figure this out in studying for my FE exam. Your video made it so clear that now I fully understand. Thank you so much.☺
h(t-tau) actually moves to the right while t >0. However, she put the symbol "t" in X axis and in the negative side, that means t is negative. Under this situation, the h(-tau) will moves to the "negative" right, so it moves to the left.
honestly i understood more than my tutor shouting for whole 2 hrs, i will recommend this video to my friends as well. thank you!
thank you so much. ive spent so many hours alone (online classes) trying to figure this out and it's finally put in a way that even I can understand. If I ever graduate let it be known that you were a factor :)
The way she ended it😂😂😂😂😂
"That's it" finishes the video in an instant
Thank you so much for making this simple. Ive been through so many different university pages and examples and so many details are left out. Thanks again!!
I can't even begin to describe how helpful this videos is. I'm grateful. Really I'm.
"AND THAT'S IT!!!!" 😂😂❤, Thank you for this calm and clear course.
I think transforming h(k) to h(t-k) requires flipping first[h(-k)] and then delaying by t [h( -(k-t) ) = h(t-k) ]. So your graph of h(t-k) should be on right side of Y axis if t>0. if t
When t0 its all is not on right side when we take y[0]then it strts from - 1
Thank you so much Ma'am 🙏 You made life so much more easier for me. Love and support from Bangalore, India 🇮🇳
best explanation of convolution I have seen. Didn't understand limits/boundaries until I watched this video
wow. thank you very much. you just made something so confusing into something so simple. ive watch many you tube videos about this, and this is the most easiest to learn and clearest video ive seen. thanks.
Well done you. Many lecturers are not only lazy but often they don't fully understand the concepts themselves.
Intersting part comes up at 19:38
I mean it is nice to watch it full, but in case you have your exam tomorrow, her slow drawing and talking would drive you mad
play it on 2x
i had an exam in 3 hours and it drove me mad af
Don't criticise if it helped you. Be fucking grateful she did it.
I played it 2x
I skipped at least half of the video but this was the most helpful one so far thnx for your efforts.
I wanted to say the intuition for finding the regions of overlapping is nicely done, at around 11 min to - 19 or so minutes
The best video about convolution so far
You are a saver, that time interval was confusing until you explained it
thank you for your all videos about convolution !!! I will bring them to my exam tomorrow! :)))
Thank you so much for this! I was confused on how to select the intervals during convolution and this video helped a lot.
where does it overlap in the region of 2
Can I say I love you? Thank you so very much. 11th minute saved my life!
That was pretty efficient, thx for rigorous explanations 😊
Awesome video!!! you explained a difficult concept in an easy way!!! God bless you!!!!
at 8:50 love how you pay attention to detail
"a little above three"
i have watched when i was learning conv the first time and i watched it again to remember some details and this vid. makes wonders thnx for the vid.
make sure play speed its at 2 , is the same as if she were talking normal. Really helpful video!
Boom! You made everything easy. Well explained.
...its voice that makes me focus :-)! Thanks
same here lol
example of convolution was amazing and very easy to understand with ur method.
but i have a question, in last while plotting y(t) between region 2 and 3 ,it was -6t+18... you decreased it negative slope by -6.Where is +18 factor gone ?
M.Munam Naseer 18 is y axis intercept. When you will extend that line it will cut y axis at 18
Such a fav explanation...
The best video I ever watched that explain convolution 👍🏻
Thank you very much aljamela 1984!
Super AWESOME explanation! Thank you so much :)
You're very welcome ;)
a life saver is what you're
Thank you so much for making this video. It's very helpful.
At least my time was used wisely today, BIG THANKS
clear concept ...great video.well done.Its clear and loud. thanx
wow.. u made things so simple.. thank you so much
Excellent video. The abrupt ending made me crack up though because I lack maturity.
life makes sense after this video!
Thank you so much. You just saved my life.
Thank You teacher for such an awesome class.
It was really worth watching your video. Hoping more such educational videos from you.
Mam, but when in a time reversed signal we add a constant t the shift is to the right Mam.
Danke für die Erklärung ich hab lange nach einem einfachen Beispiel über die Faltung gesucht .....................noch mal danke
Daryl Berlioz Dongmo i guess you’re welcome!
Very well explained,and clear thanks a lot
You’re welcome
Thank u very much for this amazing explanation, when u were saying professors don’t explain bla bla exactly u were talking about our professor gorkem 😂 thanks a lot
hocam 16290569 nolu öğrenci
it will shift to right. and also watch it at 1.5x speed
Man!! Your comment deserves more likes, everyone should read it
Two things I like about this video.
1) your awesome voice.
2) your great explanation.
finally i have learned how to convolve, thanks to you!
+Arsam Ali Humein bhi sikha do thora bhai xP
+Usman Shahid milo na mujhy khusbhoo lga k
Aaj subah mila toh tha. Frisky hona he? ;)
+Usman Shahid dobara milo na monday ko
Scene awnn (y) xP
Overall this is absolutely amazing and incredibly helpful. I have a question about the last section region of overlap. You have y(t) = -6 +18. You have the slope of -6. What about the +18? should it have jumped up to 18 and then -6?
The +18 is where it would cross the y-axis. If you were to take the line she drew from (2 < t < 3), at a -6 slope and extend it from -infinity to +infinity, it would cross the y-axis at +18. The reason she did not draw it is because the previous point of the graph she was drawing ended at t = 2. So drawing the extended line from -infinity to +infinity is unnecessary. She just drew it where it was needed, which was t = 2 to t = 3. That is where the limits of the last overlap occurred. Hope this helped!
Thanks for your perfect explanation of the convolution!! Good luck
Thank you I finally understand this thanks to your video!
Wow! This was very helpful!
really helpful... just signed it on google to thump up..thnaks
Awesome. Thank you!
The t-values in the left quadrant, aren't supposed to be negative
Awesome explaination, Thank you !
MOHD SUKRI MOHD ROSLI you’re welcome!
WOW thank you so much! keep the good work here plss !
Excellent Explanation! Thank You!
You're welcome Zach. Some are complaining that it was too long but they were warned from the start haha
Great video! I'm studying for the FE and will use your videos for supplement study material.
+Mario Gregory let me know how that goes for yo i might take a EE FE exam in the spring> and btw what state are u from
Best of luck
Thank you +199axelman. I'm from California. I really appreciate these videos and plan to take my test in December. Good luck to you on your test my friend.
thanks :) good luck for all yeah i have a signal test coming up and its really bad situation now
@@199alexman I hope you did well on your exam.
@@mariogregory4922 haha dude passed FE long time ago now its the freaken PE
Excellent video! Thanks for the explanation!
thank you very much this video was really helpful for me in my assignment
Awesome. You're welcome Ahmed!
thanks, answered most of my questions regarding convolution
awesome video..... really appreciate your work
Thumbs Up.. Yesterday in class quiz I failed that convolution.. wished I have watched this before..
Convolution is kinda confusing though. Hope you pass the next time around.
Raiya Energy Academy Can you please help me with the signals and systems course??.. I really need your lectures.. I dnt understand my professor..
Ark What part specifically? Any particular subject? Let me know what you need help with and i'll be glad to help.
Raiya Energy Academy specifically.. fourier series representation, filters, modulation ( signals and systems).. also some microelectronics topics BJT as amplifier... thnx in advnce..
Ark I got a few videos on Electronics and Communications, may not be enough but it's a start. I will upload more on Fourier/Modulation very soon. You're welcome.
Thank you so much! This makes a lot more sense now. Very clearly explained.
Many many thanks for ur magnificent explanation!
Awesome explanation
thank you for this vid, i never paid attention to my lecturer
crystal cleared the concept , thanks a lot!
you're a life saver, thank you!
I appreciate a lot the video! Thanks so much for such a good content!
You’re very welcome.
THANKS SO MUCH, THIS WAS USEFUL FOR HOMEWORK!!!
very very awesome explaination great work
Super mam... Extraordinary explanation
You're welcome Iaxmi! Thanks for watching.
Thank you, you are an angel.
thank you.you have mane my confusion clear.
You are the best. Thank you !
Nice video and good explanation.
Thanks.
Thank you! I got my doubts cleared
So good to learn God bless you
Awesome explanation mam tq
YOU ARE AWESOME .THANKS
You're very welcome Guillermo!
It finally makes sense! Thank You!!
Very helpful and understandable, thank you so much!
You're very welcome Sonja!
are u sure that h(t-T) shifts towards left?? if yes, can u Please explain!!!
h(t - T) shifts h(-T) to the left, by t. Consider any function y = f(x), say y = 2x. This is a straight line of slope = 2, passing thru' the origin. Now, consider f(x+a). This is y = 2(x + a), i.e. y = 2x + 2a. It is a straight line of slope 2, with y-intercept = 2a, and x-intercept = -a. Thus, f(x+a) is f(x) shifted to the LEFT by a.
you're my hero
you have got a very pleasant to hear cute voice. :)
thanku so much for making this video.
u saved my life
Really, at 2
Love ittttttt! Thank you so much for making this videos:)
You are amazing. Thank you!
Thank you for your time and effort I wish you a safe and happy from Jordan Amjad Almhakbh
This was really helpful.. Thank you
ohoo. Are you sure about the h(t-T), where you shift the t to the left? I reckon it's supposed to be to the right.
You're right.
No, it shifts to the left: if t is positive, you will find the previous h(0) point to the left of the vertical axis because
h(t-T)=h(0) => t-T=0 => -T is negative which is to the left of T=0, when the T axis is pointing right. ... but actually she should have written "-t" and "-t-1" on the yellow figure
As you say, t-T=0, which means that the new h(0) point happens for T = t, which is a point on the positive T axis. I don't know how you start off so well and then still fuk up your explanation. Gordon Borostraw is correct.
Gordon borostraw
Good question, but when we shift to the right then the shifter should be negative and when we shift to the lift then the shifter should be postive. In other words, positive comes before, which is left shift and negative comes after which is right shift. So, I believe she is right.
h(t-tau) actually moves to the right while t >0. However, she put the symbol "t" in X axis and in the negative side, that means t is negative. Under this situation, the h(-tau) will moves to the "negative" right, so it moves to the left.