I've been breaking my head trying to figure this out in studying for my FE exam. Your video made it so clear that now I fully understand. Thank you so much.☺
Intersting part comes up at 19:38 I mean it is nice to watch it full, but in case you have your exam tomorrow, her slow drawing and talking would drive you mad
h(t-tau) actually moves to the right while t >0. However, she put the symbol "t" in X axis and in the negative side, that means t is negative. Under this situation, the h(-tau) will moves to the "negative" right, so it moves to the left.
I think transforming h(k) to h(t-k) requires flipping first[h(-k)] and then delaying by t [h( -(k-t) ) = h(t-k) ]. So your graph of h(t-k) should be on right side of Y axis if t>0. if t
Thank you so much for making this simple. Ive been through so many different university pages and examples and so many details are left out. Thanks again!!
thank you so much. ive spent so many hours alone (online classes) trying to figure this out and it's finally put in a way that even I can understand. If I ever graduate let it be known that you were a factor :)
wow. thank you very much. you just made something so confusing into something so simple. ive watch many you tube videos about this, and this is the most easiest to learn and clearest video ive seen. thanks.
example of convolution was amazing and very easy to understand with ur method. but i have a question, in last while plotting y(t) between region 2 and 3 ,it was -6t+18... you decreased it negative slope by -6.Where is +18 factor gone ?
Overall this is absolutely amazing and incredibly helpful. I have a question about the last section region of overlap. You have y(t) = -6 +18. You have the slope of -6. What about the +18? should it have jumped up to 18 and then -6?
The +18 is where it would cross the y-axis. If you were to take the line she drew from (2 < t < 3), at a -6 slope and extend it from -infinity to +infinity, it would cross the y-axis at +18. The reason she did not draw it is because the previous point of the graph she was drawing ended at t = 2. So drawing the extended line from -infinity to +infinity is unnecessary. She just drew it where it was needed, which was t = 2 to t = 3. That is where the limits of the last overlap occurred. Hope this helped!
Thank u very much for this amazing explanation, when u were saying professors don’t explain bla bla exactly u were talking about our professor gorkem 😂 thanks a lot
No, it shifts to the left: if t is positive, you will find the previous h(0) point to the left of the vertical axis because h(t-T)=h(0) => t-T=0 => -T is negative which is to the left of T=0, when the T axis is pointing right. ... but actually she should have written "-t" and "-t-1" on the yellow figure
As you say, t-T=0, which means that the new h(0) point happens for T = t, which is a point on the positive T axis. I don't know how you start off so well and then still fuk up your explanation. Gordon Borostraw is correct.
Gordon borostraw Good question, but when we shift to the right then the shifter should be negative and when we shift to the lift then the shifter should be postive. In other words, positive comes before, which is left shift and negative comes after which is right shift. So, I believe she is right.
h(t-tau) actually moves to the right while t >0. However, she put the symbol "t" in X axis and in the negative side, that means t is negative. Under this situation, the h(-tau) will moves to the "negative" right, so it moves to the left.
h(t - T) shifts h(-T) to the left, by t. Consider any function y = f(x), say y = 2x. This is a straight line of slope = 2, passing thru' the origin. Now, consider f(x+a). This is y = 2(x + a), i.e. y = 2x + 2a. It is a straight line of slope 2, with y-intercept = 2a, and x-intercept = -a. Thus, f(x+a) is f(x) shifted to the LEFT by a.
Thank you +199axelman. I'm from California. I really appreciate these videos and plan to take my test in December. Good luck to you on your test my friend.
Raiya Energy Academy specifically.. fourier series representation, filters, modulation ( signals and systems).. also some microelectronics topics BJT as amplifier... thnx in advnce..
Ark I got a few videos on Electronics and Communications, may not be enough but it's a start. I will upload more on Fourier/Modulation very soon. You're welcome.
Dear sir, i am generating a signal (PPM) and convoluting (in matlab) it with the wireless channel impulse response to get the received signal. For getting the correct Receiving signal, is it necessary for both (transmitted signal & impulse response) to have the same sampling rate? In other words, the width between samples should be same ???
Why are you multiplying 3 by 2 when 3 is clearly above the limit of 2, Is it not supposed to be just the area under the curve which in this case is from 2 and below it?
if you have y(t) = x(t-1), at t = 0 you have x(0-1)=x(-1), a shift to the left. So at every value of t, the output of the system is the value of the input right before x(t) (i.e. shifted once to the left.)
when convoluting we are flipping the signal. so assume we have a signal when flipped have a different signal. for example lets say a 90 degree triangle. then the convolution will give us a graph of the overlap of one signal to other in the inverse order other than the way we really want. can someone please tell me is this the way convolution is defined or do we have to inverse the convolution graph inorder to get the real overlap amount of the signal which varies with time??
Thank you for taking the time to explain the extra steps involved. Those 20 minutes saved me hours and hours of stress and web searching.
in 30 minutes you explained to me what my highly paid professor couldn't do in a month's worth of classes. You the real MVP
you said exactly what everyone here is saying ! She is AMAZING
Thank you very much :) Very encouraging words!
Awesome. I'm glad i was able to help. Your words are very encouraging. Thank you!!!
True
The best teaching I have ever seen on convolution period.
Thank you so much for breaking it down
I appreciate her. She taught full visual process that really professor never tell you in class room.
The way she ended it😂😂😂😂😂
"That's it" finishes the video in an instant
I passed the FE. Just wanted to say thanks you videos were a tremendous resource. 🙏
dre mckenzie, great to hear that. You’re welcome. Congratulations on passing the FE!
This is by far the best tutorial I have ever seen. You've just saved a life. Thank you so much.
I've been breaking my head trying to figure this out in studying for my FE exam. Your video made it so clear that now I fully understand. Thank you so much.☺
Intersting part comes up at 19:38
I mean it is nice to watch it full, but in case you have your exam tomorrow, her slow drawing and talking would drive you mad
play it on 2x
i had an exam in 3 hours and it drove me mad af
Don't criticise if it helped you. Be fucking grateful she did it.
I played it 2x
h(t-tau) actually moves to the right while t >0. However, she put the symbol "t" in X axis and in the negative side, that means t is negative. Under this situation, the h(-tau) will moves to the "negative" right, so it moves to the left.
honestly i understood more than my tutor shouting for whole 2 hrs, i will recommend this video to my friends as well. thank you!
"AND THAT'S IT!!!!" 😂😂❤, Thank you for this calm and clear course.
I think transforming h(k) to h(t-k) requires flipping first[h(-k)] and then delaying by t [h( -(k-t) ) = h(t-k) ]. So your graph of h(t-k) should be on right side of Y axis if t>0. if t
When t0 its all is not on right side when we take y[0]then it strts from - 1
best explanation of convolution I have seen. Didn't understand limits/boundaries until I watched this video
I can't even begin to describe how helpful this videos is. I'm grateful. Really I'm.
Thank you so much for making this simple. Ive been through so many different university pages and examples and so many details are left out. Thanks again!!
thank you so much. ive spent so many hours alone (online classes) trying to figure this out and it's finally put in a way that even I can understand. If I ever graduate let it be known that you were a factor :)
Thank you so much Ma'am 🙏 You made life so much more easier for me. Love and support from Bangalore, India 🇮🇳
wow. thank you very much. you just made something so confusing into something so simple. ive watch many you tube videos about this, and this is the most easiest to learn and clearest video ive seen. thanks.
The best video about convolution so far
You are a saver, that time interval was confusing until you explained it
I skipped at least half of the video but this was the most helpful one so far thnx for your efforts.
where does it overlap in the region of 2
Awesome video!!! you explained a difficult concept in an easy way!!! God bless you!!!!
That was pretty efficient, thx for rigorous explanations 😊
I wanted to say the intuition for finding the regions of overlapping is nicely done, at around 11 min to - 19 or so minutes
thank you for your all videos about convolution !!! I will bring them to my exam tomorrow! :)))
Well done you. Many lecturers are not only lazy but often they don't fully understand the concepts themselves.
Boom! You made everything easy. Well explained.
it will shift to right. and also watch it at 1.5x speed
Man!! Your comment deserves more likes, everyone should read it
Thank you so much for this! I was confused on how to select the intervals during convolution and this video helped a lot.
at 8:50 love how you pay attention to detail
"a little above three"
i have watched when i was learning conv the first time and i watched it again to remember some details and this vid. makes wonders thnx for the vid.
...its voice that makes me focus :-)! Thanks
same here lol
make sure play speed its at 2 , is the same as if she were talking normal. Really helpful video!
Super AWESOME explanation! Thank you so much :)
You're very welcome ;)
At least my time was used wisely today, BIG THANKS
The best video I ever watched that explain convolution 👍🏻
Thank you very much aljamela 1984!
Thanks for your perfect explanation of the convolution!! Good luck
example of convolution was amazing and very easy to understand with ur method.
but i have a question, in last while plotting y(t) between region 2 and 3 ,it was -6t+18... you decreased it negative slope by -6.Where is +18 factor gone ?
M.Munam Naseer 18 is y axis intercept. When you will extend that line it will cut y axis at 18
Mam, but when in a time reversed signal we add a constant t the shift is to the right Mam.
The t-values in the left quadrant, aren't supposed to be negative
Thank You teacher for such an awesome class.
It was really worth watching your video. Hoping more such educational videos from you.
Can I say I love you? Thank you so very much. 11th minute saved my life!
wow.. u made things so simple.. thank you so much
Overall this is absolutely amazing and incredibly helpful. I have a question about the last section region of overlap. You have y(t) = -6 +18. You have the slope of -6. What about the +18? should it have jumped up to 18 and then -6?
The +18 is where it would cross the y-axis. If you were to take the line she drew from (2 < t < 3), at a -6 slope and extend it from -infinity to +infinity, it would cross the y-axis at +18. The reason she did not draw it is because the previous point of the graph she was drawing ended at t = 2. So drawing the extended line from -infinity to +infinity is unnecessary. She just drew it where it was needed, which was t = 2 to t = 3. That is where the limits of the last overlap occurred. Hope this helped!
Thank you so much. You just saved my life.
Thank you so much for making this video. It's very helpful.
Such a fav explanation...
awesome video..... really appreciate your work
very very awesome explaination great work
Thank you I finally understand this thanks to your video!
Thank u very much for this amazing explanation, when u were saying professors don’t explain bla bla exactly u were talking about our professor gorkem 😂 thanks a lot
hocam 16290569 nolu öğrenci
clear concept ...great video.well done.Its clear and loud. thanx
Danke für die Erklärung ich hab lange nach einem einfachen Beispiel über die Faltung gesucht .....................noch mal danke
Daryl Berlioz Dongmo i guess you’re welcome!
Many many thanks for ur magnificent explanation!
ohoo. Are you sure about the h(t-T), where you shift the t to the left? I reckon it's supposed to be to the right.
You're right.
No, it shifts to the left: if t is positive, you will find the previous h(0) point to the left of the vertical axis because
h(t-T)=h(0) => t-T=0 => -T is negative which is to the left of T=0, when the T axis is pointing right. ... but actually she should have written "-t" and "-t-1" on the yellow figure
As you say, t-T=0, which means that the new h(0) point happens for T = t, which is a point on the positive T axis. I don't know how you start off so well and then still fuk up your explanation. Gordon Borostraw is correct.
Gordon borostraw
Good question, but when we shift to the right then the shifter should be negative and when we shift to the lift then the shifter should be postive. In other words, positive comes before, which is left shift and negative comes after which is right shift. So, I believe she is right.
h(t-tau) actually moves to the right while t >0. However, she put the symbol "t" in X axis and in the negative side, that means t is negative. Under this situation, the h(-tau) will moves to the "negative" right, so it moves to the left.
Thank you so much! This makes a lot more sense now. Very clearly explained.
life makes sense after this video!
Very well explained,and clear thanks a lot
You’re welcome
What happens to the problem if h(t) is more than 1 second. i'm getting an odd trapezoid with t-2 to t.
really helpful... just signed it on google to thump up..thnaks
Awesome. Thank you!
are u sure that h(t-T) shifts towards left?? if yes, can u Please explain!!!
h(t - T) shifts h(-T) to the left, by t. Consider any function y = f(x), say y = 2x. This is a straight line of slope = 2, passing thru' the origin. Now, consider f(x+a). This is y = 2(x + a), i.e. y = 2x + 2a. It is a straight line of slope 2, with y-intercept = 2a, and x-intercept = -a. Thus, f(x+a) is f(x) shifted to the LEFT by a.
thank you so much but can you tell me the name of the book that you show it in the video
Two things I like about this video.
1) your awesome voice.
2) your great explanation.
Excellent video! Thanks for the explanation!
Super mam... Extraordinary explanation
You're welcome Iaxmi! Thanks for watching.
Nice video and good explanation.
Thanks.
thank you for this vid, i never paid attention to my lecturer
thanks, answered most of my questions regarding convolution
Would i be able to get a copy of that formula sheet that popped up in the video?
crystal cleared the concept , thanks a lot!
Great video! I'm studying for the FE and will use your videos for supplement study material.
+Mario Gregory let me know how that goes for yo i might take a EE FE exam in the spring> and btw what state are u from
Best of luck
Thank you +199axelman. I'm from California. I really appreciate these videos and plan to take my test in December. Good luck to you on your test my friend.
thanks :) good luck for all yeah i have a signal test coming up and its really bad situation now
@@199alexman I hope you did well on your exam.
@@mariogregory4922 haha dude passed FE long time ago now its the freaken PE
Which software do you use to do this tutorials
THANKS SO MUCH, THIS WAS USEFUL FOR HOMEWORK!!!
Excellent video. The abrupt ending made me crack up though because I lack maturity.
thanks a lot mam.I was expecting a detailed diagrammatic
analysis of convolution of rectangular waves
thank you very much this video was really helpful for me in my assignment
Awesome. You're welcome Ahmed!
Awesome explaination, Thank you !
MOHD SUKRI MOHD ROSLI you’re welcome!
Thumbs Up.. Yesterday in class quiz I failed that convolution.. wished I have watched this before..
Convolution is kinda confusing though. Hope you pass the next time around.
Raiya Energy Academy Can you please help me with the signals and systems course??.. I really need your lectures.. I dnt understand my professor..
Ark What part specifically? Any particular subject? Let me know what you need help with and i'll be glad to help.
Raiya Energy Academy specifically.. fourier series representation, filters, modulation ( signals and systems).. also some microelectronics topics BJT as amplifier... thnx in advnce..
Ark I got a few videos on Electronics and Communications, may not be enough but it's a start. I will upload more on Fourier/Modulation very soon. You're welcome.
Dear sir, i am generating a signal (PPM) and convoluting (in matlab) it with the wireless channel impulse response to get the received signal. For getting the correct Receiving signal, is it necessary for both (transmitted signal & impulse response) to have the same sampling rate? In other words, the width between samples should be same ???
Thank you! I got my doubts cleared
Can you tell me the title of the document have you used !!
thank you.you have mane my confusion clear.
WOW thank you so much! keep the good work here plss !
At 16:48 I think you meant t >= 2
Excellent Explanation! Thank You!
You're welcome Zach. Some are complaining that it was too long but they were warned from the start haha
Why are you multiplying 3 by 2 when 3 is clearly above the limit of 2, Is it not supposed to be just the area under the curve which in this case is from 2 and below it?
you have got a very pleasant to hear cute voice. :)
thanku so much for making this video.
Awesome explanation
This was really helpful.. Thank you
could you please tell me why t-1 shift is on the left and not on the right.?
if you have y(t) = x(t-1), at t = 0 you have x(0-1)=x(-1), a shift to the left. So at every value of t, the output of the system is the value of the input right before x(t) (i.e. shifted once to the left.)
thank you
So good to learn God bless you
Very helpful and understandable, thank you so much!
You're very welcome Sonja!
I appreciate a lot the video! Thanks so much for such a good content!
You’re very welcome.
when convoluting we are flipping the signal. so assume we have a signal when flipped have a different signal. for example lets say a 90 degree triangle. then the convolution will give us a graph of the overlap of one signal to other in the inverse order other than the way we really want. can someone please tell me is this the way convolution is defined or do we have to inverse the convolution graph inorder to get the real overlap amount of the signal which varies with time??
Great Expalnation....Got to Learn it
Wow! This was very helpful!
Good explanation but i am so confused about the point n-1
Thank you for your time and effort I wish you a safe and happy from Jordan Amjad Almhakbh