Continuous-time Convolution 2

[@misseralvel]

You just saved the entire engineering class from my room, thank you for the explanation.

[@rehamahmed5167]

I LOVE YOU !!!! you are unbelievable! this is amazing to no end! you saved my whole signals life ! there is no way to repay you ! thanks

[@RaiyaAcademy]

Lol@ signals life. I feel ya. Glad i did. You're very welcome indeed!

[@leonardoluizcubas4159]

Thank u so much for this explanation, you saved my life!!! I wish I had watched these videos before

[@RaiyaAcademy]

Leonardo Luiz Cubas you’re very welcome.

[@kommsk]

your lecture is very instructive and helpful....My teacher knows the material but due to the lack of time, most of us are just left confused....Again thanks and KUDOS

[@harisghafoor7474]

for 1

[@sandeepkumararya8182]

mam Please provide solution for intervals (1

[@harisghafoor7474]

for 1

[@andreskoszutski4364]

that's the tricky part I was waiting for.

[@rahmiEE]

@@harisghafoor7474 legend

[@mustafaaasim2944]

But what if in h(t) we have -1 and 1 on x axis???

[@raghidbahnam5136]

This is great. THANK YOU !!!

[@jacobvandijk6525]

And for t = 1 the overlap is 1/2, of course (just look at the pictures).

[@fightinggold7674]

wish you wouldve graphed it and explained it

[@daniyalyaseen6231]

in the last part means in integral stage I think that both of signal is having value 1 for each so after integrating it would give tow and finally applying limits final ans will be t plx confirm this. ....

[@mahakhan9762]

i love ur voice and thanks for explaining convolution so easily

[@Zuwwar]

Thanks for this simple understanding, but i have a question here.
In this example, where you mentioned the time interval as; 0

[@DavidBellinisantos]

This pure GOLD!

[@maxsalman783]

What about when the boxcar is in the centre of the triangular function?

[@ankitsinghyadav5466]

its not the full solution...where i can find the rest of it?

[@dopier12]

Ok, I'm hooked. Thanks a ton!!!!!!!

[@nakkelahari5898]

can you tell me software and electronic equipment used for recording and writing .

[@busterzz]

What is the MCCS book? I can't seem to find the title on the internet.

[@kekemoa8822]

I LOVE THIS!!!THANK YOU!

[@minasaad82]

the final shape of y(t) will be quadratic ?

[@muhammadnaufil5237]

Mina Saad for 2 to 3 seconds, i got the equation quadratic

[@varunsingh9432]

you didnt told here why tau square .. please explain for tau square

[@kailadavis8877]

How do you know that line is equal to tau?

[@УклетиХоланђанин]

That's the equation that describes that line
(y=kx+n, here n is zero, because it is the zero value where y axis is intercepted)

[@hernanifernandes7222]

It is the slope.

[@RaiyaAcademy]

Convolution Example 2

[@yagizyalcintasalumni3273]

dont we multiply the valuese of two functions and take integral?

[@bnur5111]

yes she is multiplying them, the function h(t) is a unit step function so it's amplitude is 1. so 1 * t = t , that's why in the integral sign she wrote only the line t

[@shushshaheen4276]

love it thank you ...from iraq

[@rivera82nd]

wow, you made it extremely simple

[@choudrywajahatali9599]

simply the best!

[@romelrosario1913]

WHAT is the equation for the second slope???????????? u did not finish it

[@timocinatuna5823]

ahhmmm!....the question asks to find y(t) in the interval 0

[@emreaknc6689]

the book is ntds (number theory and digital signals)

[@school_education242]

your voice ♥♥

[@jawharbekrozmetow3532]

good work )

[@powerelectric879]

This was FE question

[@sheharyarmalik7399]

I owe you a coffee...

[@shushshaheen4276]

l want all regin can you continue the Q

[@nofilkhan3164]

thumbs up

[@kaushanranasinghe2148]

Awesome :D

[@DivakarpandeyMT]

why r u affraid

[@marwaagha6772]

thanx :D

[@imadagli1759]

Seriously !! I'm just gonna give you a dislike