Thin Pressure Vessel | L 2 | Strength of Materials | Apuroop Sir

[@princeraj3975]

For last question just put hoop stress = -0.6 Mpa in formula of hoop stress and find p,
p= -0.1Mpa
This should be net p...hence p required outside = -0.1 - 0.15 = -0.25 Mpa
= 0.25 Mpa compressive
Use rho*g*h = 0.25 Mpa
get h = 25.48 m

[@jahangirali3578]

You are the best teacher on unacademy platform for som+dme

[@priya-pm2mq]

these questions are really good

[@ajaypatel7966]

thanks sir bahut maja aaya

[@deepakdev2501]

At 53:36 in area pi d t , dia should have been mean dia. If we take mean dia answer will come out to be 57.97 MPa. (Usally dia is very large as compared to thickness so doesn't matter we take inner dia or dmean but here thickness isn't negligible as compared to dia and answer will change )

[@akhilsharma1779]

1:07:38 sigma 2 = +39.83Mpa

[@wwecharcha4518]

25:34 Sir it's 70×10^9 in denominator

[@RG-wz9ks]

sir last question ka answer 25 m aa raha ha

[@himanshukumarsingh6327]

same my ans is also 25.48m

[@shabana9929]

not 25.48 meter will be wrong
25.48 mm will be correct

[@ranarajsingh9699]

Sir why we are not taking the volume of thin cylinder as (pi*d*t*l). While the area of the base of thin cylinder is taken as pi*d*t in case of calculating longitudinal stress.

[@Hello00World00]

Calculation mistake at 1:23:00 answer comes out to be 25.484m.

[@shabana9929]

not meter
25.47mm

[@shabana9929]

sir last Wale question ka answer 25.48 mm aa rha hai 1:23:00

[@anchalsingh771]

Haa mujhe bhi wahi ayaa

[@yt_gauravgg]

Prabhakarna Sripalawardhana Atapattu Jayasuriya Laxmansriramkrishna Shivavenkata Rajasekara Sriniwasana Trichipalli Yekya Parampeel Parambatur Chinnaswami Muthuswami Venugopal Iyer