Physics 44 Magnetic Field Generated (16 of 28) B=? Off-Axis Current Segment

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  • Опубліковано 16 гру 2024

КОМЕНТАРІ • 19

  • @capoman1
    @capoman1 9 років тому +4

    Michael, thank you so much for posting these videos. These will be a resource for so many students. And your work here is cemented into history. This is the most comprehensive set of examples and derivations I have found. I salute you.

  • @MrKeithkop
    @MrKeithkop 10 років тому

    Michel, your examples are awesome and so are you. You help many people like myself understand and compute higher level physics which is extremely important in my area of study. Thank you again. You will not go unnoticed because I will spread you channel.

    • @MichelvanBiezen
      @MichelvanBiezen  10 років тому +1

      Keith,
      Thanks for the feedback. It is good to know that students all over are benefiting from these videos.

  • @MsLoversky
    @MsLoversky 7 років тому +1

    i recommend your teaching to my chem.eng students

  • @ianhnizdo5864
    @ianhnizdo5864 5 років тому +1

    the whole dBy cos(theata) as opposed to sin(theta) was tricky as heck for me to get the hang of, but otherwise a good video as always.

  • @kirangudigar5394
    @kirangudigar5394 5 років тому +1

    Direction of db should be perpendicular to both dl and r right. But here it does not seems so

    • @MichelvanBiezen
      @MichelvanBiezen  5 років тому +1

      It is hard to visualize it, but dB is perpendicular.

  • @bruninie
    @bruninie 8 років тому

    Shouldn't dBy be dBz and dBx be dBy. And shouldn't the crossproduct between dl = (dx, 0, 0) and r-hat = (cos phi, sin phi, z0)? Which gives a dB in terms of dBz and dBy.

    • @MichelvanBiezen
      @MichelvanBiezen  8 років тому

      The video is fine as is. Thank you for checking.

    • @jarednicholas3180
      @jarednicholas3180 5 місяців тому

      @@MichelvanBiezenHello sir. First, I must say I love all your videos... I literally copy everything down in my notebooks that you teach, but I'm lost on the dB(x) direction pointing in the same direction as y(o) and dB(y) pointing in the direction of z(o)... You already defined R = sqrt(y^2 + z^2), meaning an x-component cannot point either up or to the side, yet dB(x) is pointing in the direction as either y(o) or z(o)... If you could explain this I'd greatly appreciate it! Thanks

  • @Jazmin267
    @Jazmin267 6 років тому +1

    why dont we want the x component of the magnetic field at that point? why only the y component?

    • @MichelvanBiezen
      @MichelvanBiezen  6 років тому +1

      Actually it is not the y-component, but the component perpendicular to the r vector. And that is because the magnetic field makes a circular path around a current carrying wire.

    • @xMrJanuaryx
      @xMrJanuaryx 6 років тому

      @@MichelvanBiezen So we know which direction the B field will be pointing at that location (right-hand rule) and that is why we only compute the component perpendicular to the r vector?

    • @williamp3677
      @williamp3677 5 років тому

      @@MichelvanBiezen but in your drawing By isn't perpendicular to the r vector, should we calculate both by and bx and then find then norm of that ? thanks

  • @umiturgutaswwsa
    @umiturgutaswwsa 2 роки тому +1

    THX

  • @Irfan-vo6fh
    @Irfan-vo6fh 4 роки тому

    As you mentioned here y component same should go with y component in this video also
    ua-cam.com/video/froA_4AooCA/v-deo.html
    But it was not so

  • @enesemreozturk7510
    @enesemreozturk7510 3 роки тому +1

    Zero