I got a 60 on my first exam, watched and took notes on all of these videos before the midterm (instead of going to lectures im afraid), and got a 90 on the midterm. Thanks!
I just want to say thank you for your in-depth discrete math playlist. Saved my life for my discrete math exam.. This channel deserves more recognition.
I think this video gave me the biggest "ah-ha" moment that I've ever had learning math. Not a single part of this concept made any sense to me until it suddenly all clicked into place. I have an exam tomorrow so this video saved my grade. Thank you!
Thank you for producing this series. Due to the amount of material my professor must cover in one semester, she moves too fast for me to adequately comprehend and internalize the information. I used your videos to review for my midterm and earned 100%! (After scoring a 68% on a previous quiz). I truly appreciate your videos because they are well-produced and clear. I also can watch them as often as needed until I understand the concepts.
you explained everything so clearly and detailed but still concise enough to understand these videos are so well done thankyou so so so much you are doing gods work.
I'm a bit confused about your answering the question of whether the space of polynomial functions is a subspace of all real valued functions. At about the 8-minute mark of the video you you check for the requirement of multiplication being closed. Previously I thought you would said that this was scalar multiplication. But in this example, it seems that you are checking to see if the polynomials are closed under a different form of multiplication rather than scalar multiplication. Have I misinterpreted something here or did you slip up?
why did not you check for all of the 10 axioms in the previous video, in fact you only checked for these 3 conditions (which you described in this video).
The zero vector [0 0 0] must belong to a vector space. Since the middle term of our. Vector is 4, it is impossible for the zero vector to be H (since 4 can never equal zero). Does that make sense?
at 17:53 i still dont understand how 0 is not an element in H just because there is a four. Can't you times H by 0 to make it a zero vector? like 0 x 4 = 0
this was like 6 months ago, but just in case you still need an explanation, or if anyone else stumbles upon this who had the same question: to get the 0 vector, you make each scalar equal to 0 (a and b, in this case) to get 0*v1 + 0*v2 = 0. if you make a = 0 and b = 0, you're left with the vector [0 4 0]. this means you can never get the 0 vector since that 4 will always be there. multiplying a vector by 0 is different than the 0 vector being a part of a vector space (recall that one way to show if a vector is a part of a system is through linear combination; the same applies here). in short, the 2 processes are different which is why we couldn't simply multiply H by 0! if i got smth wrong or if u need smth to be cleared up, shoot me a reply 😋
@@lareina9316 ok, but then how can I show that 0 does not belong in H in the exam? I can't just write that 0 does not belong in H without doing anything. I hope you can tell us if you know how to do that.
I got a 60 on my first exam, watched and took notes on all of these videos before the midterm (instead of going to lectures im afraid), and got a 90 on the midterm. Thanks!
I got a 30 on mine. Trying to get out with a D 😂😂😂😂
If you still remember lol
Where can I find proper practice examples because all I see online is super intuitive stuff
I just want to say thank you for your in-depth discrete math playlist. Saved my life for my discrete math exam.. This channel deserves more recognition.
Koov Thanks! I appreciate it!
I don't mind the usage of etc. I love the lectures and they have helped me tremendously as supplementary material to my LA class. Thank you so much!!!
First you saved me in discrete math and now you're saving me in linear algebra, thank you !
How does this video only have 41 likes out of 2900 views? What else do you people want?!
Thank you for this course!!
You are welcome!
I think this video gave me the biggest "ah-ha" moment that I've ever had learning math. Not a single part of this concept made any sense to me until it suddenly all clicked into place. I have an exam tomorrow so this video saved my grade. Thank you!
Your explanations are gold. Thank you for putting in the effort
Thank you for producing this series. Due to the amount of material my professor must cover in one semester, she moves too fast for me to adequately comprehend and internalize the information. I used your videos to review for my midterm and earned 100%! (After scoring a 68% on a previous quiz). I truly appreciate your videos because they are well-produced and clear. I also can watch them as often as needed until I understand the concepts.
Go glad I could help!
I watch all of your videos before every exam, thank you so much!
Whenever there is a math course final , I come here for quality revision and insights.
Thanks a lot for your effort providing these great lectures.
Thank you! Glad I could be of help!
Ma'am Thank you for this. We truly appreciate your effort.
may God bless you for your effort & time making these videos. Most videos on linear algebra are too basic => these are perfect
you explained everything so clearly and detailed but still concise enough to understand these videos are so well done thankyou so so so much you are doing gods work.
Yall so lucky to have legit math and science youtube videos. I was stuck with indian tutorials and they weren't much help😥
You are a great teacher. Thank you so much!!!
Best UA-cam channel ❤❤❤❤
Thanks Kimberly. Very useful for Machine Learning linear algebra maths
I died when you made the etc comment XD "thanks so much" lol
Thank you etc
p(t) and q(t) don't necessarily have the same degree, and typically we should use different letters for the degree exponent, such as n and m.
Agreed
Nice Video, Thank you!!
How could I have made it in linear Algebra without this Channel? . Merci beaucoup
thank you
You are welcome!
I'm a bit confused about your answering the question of whether the space of polynomial functions is a subspace of all real valued functions. At about the 8-minute mark of the video you you check for the requirement of multiplication being closed. Previously I thought you would said that this was scalar multiplication. But in this example, it seems that you are checking to see if the polynomials are closed under a different form of multiplication rather than scalar multiplication. Have I misinterpreted something here or did you slip up?
Yeah I realized that as well.
What she said isn't right. It should be closure under scalar multiplication.
She slipped up.
Thank you so much. You are really a Grade-saver..haha
Is this material appropriate for supplementing “Linear Algebra and it’s Applications “, 5th Edition textbook. Thank you.
Yes. This book follows the 5th edition of Lay's text.
Hi, where can I get more example questions and answers where I can practice?
I suggest picking up a copy of the textbook, David Lay's Linear Algebra. Lots of practice questions.
why did not you check for all of the 10 axioms in the previous video, in fact you only checked for these 3 conditions (which you described in this video).
i think it's because remaining 7 conditions become automatically true if these 3 conditions are true
Hii love your videos can you please give me the name of the textbook you are referring to
Thank youuu!!
@@waterfall-r1n David Lays Linear Algebra and its Applications
@@SawFinMathThank youu ❤❤
i dont understand the last example, what does it mean by the zero vector not belonging to H?
The zero vector [0 0 0] must belong to a vector space. Since the middle term of our. Vector is 4, it is impossible for the zero vector to be H (since 4 can never equal zero). Does that make sense?
@@SawFinMaththat makes sense, thanks!
@@SawFinMath so 4 cannot become 0 because it does not have an a, b or c? the vector 0 is when a,b,c are equal to 0 right? is 4 here just a point then?
at 17:53 i still dont understand how 0 is not an element in H just because there is a four. Can't you times H by 0 to make it a zero vector? like 0 x 4 = 0
this was like 6 months ago, but just in case you still need an explanation, or if anyone else stumbles upon this who had the same question:
to get the 0 vector, you make each scalar equal to 0 (a and b, in this case) to get 0*v1 + 0*v2 = 0.
if you make a = 0 and b = 0, you're left with the vector [0 4 0]. this means you can never get the 0 vector since that 4 will always be there.
multiplying a vector by 0 is different than the 0 vector being a part of a vector space (recall that one way to show if a vector is a part of a system is through linear combination; the same applies here).
in short, the 2 processes are different which is why we couldn't simply multiply H by 0!
if i got smth wrong or if u need smth to be cleared up, shoot me a reply 😋
i don't understand this subject. watched your video over and over again and i don't get it
Why 0 belongs to the H in the 2nd last question but not the last question????
If anyone got that please explain it.
She explains in the video, because of the 4 constant, you can never have the 0 vector, which is a requirement for a subspace
your explanation sounds like gibberish to me. please ELI5@@lareina9316
@@lareina9316 ok, but then how can I show that 0 does not belong in H in the exam? I can't just write that 0 does not belong in H without doing anything. I hope you can tell us if you know how to do that.
@@hasanal-dhubaibi1507 yeah I don't understand either :/
What is this text book ??I want it
David Lay's Linear Algebra
you have way too many ads in your videos
just get ad block bro
thank you