Maximizing an Integral | Putnam 2006 B5

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  • Опубліковано 15 вер 2024
  • In today's video I go over Putnam 2006 B5. This problem was about maximizing an integral, and a clever representation allowed it to be maximized. If you wanna see me solve some problem, let me know in the comments.
    Related Links : / creative_math_
    Putnam 2006 Paper : math.hawaii.edu...
    #Calculus​ #Putnam​ #Integral

КОМЕНТАРІ • 6

  • @BigLeagueChewie
    @BigLeagueChewie 3 роки тому +6

    Euler-Lagrange equation also is a cheap way to arrive at the answer, tho this way is more clever and with Euler-Lagrange you have to prove the function is maximal somehow anyways. Subbed!

    • @CreativeMathProblems
      @CreativeMathProblems  3 роки тому +4

      Oh you're right it directly gives us f(x) = x/2
      I think if you take f(x) = 1 you get - 1/6 as the result of the integral so you can be sure it's not a minimum, and since it's an extremal maybe you can then say it can only be a maximum 🤷‍♂️

  • @potath10e
    @potath10e Рік тому +2

    Nice method
    You could also define another function h(y)= integral from 0 to 1
    (x^2y-xy^2)dx
    Then since we need Max we can equate h'(y)=0
    So integral 0 to 1 ( x^2-2xy)=0
    Therefore y=x/2

  • @masoomladka8017
    @masoomladka8017 3 роки тому +2

    Thanks upload more videos 😎🔥🔥😊

  • @shaheerabbas54
    @shaheerabbas54 3 роки тому +3

    I like it