The timestamps for the different topics covered in the video is given below: 0:19 What is Slew Rate of an Op-Amp? 2:31 Causes of Slew Rate in Op-Amp 4:12 Effect of Slew Rate on Pulse Signal 7:46 Effect of Slew Rate on Sinusoidal Signal 10:21 Example 1 11:30 Example 2
sir you are great....you can see in last two video you have 0 % dislike means like/dislike = infinity ...you teaching like idle opamp...thank you sir... :D :D
Excellent, excellent video, really helped to clear many doubts I had about this concept during lecture. Took me a while to finish the video, but I have a much more thorough understanding of this now!
Professor tech slew rate But I don't understand anything Useful information Bus when I see your video I have no dout about slew rate You give me great information sir 💯💯💯
Voice is nice , but speaker has a long pause before the end of most sentence. Example “… slew rate changes” Had to get used to this . Liked and subscribed
Thank you for the great videos they are really enlightening. Just a couple of questions lets say we make an op-amp how can i find the SR and how would i measure it?
The slew rate is usually given in the datasheet of the particular op-amp. You can also approximately measure it by applying the square wave to the op-amp and finding the time required to reach the maximum voltage using the oscilloscope in the lab.
At 2 us the square wave pulse will have a transition. That means it will go from high to low. The output of the op-amp will follow that transition in 2 us. Also here, it has been assumed that the duty cycle of the square wave pulse is 50 %. So it will reapeat after 4 us. I hope you will be able to visualise what i am saying. If you still have any doubt then do let me know here.
Sir, I have got a doubt. Hope you will clear it. What I have actually understood is- In earlier opamps, there is a problem of instability and opamp may break into oscillations. So to avoid this, almost all new opamps are internally compensated . But this leads to reduction of gain even at very low corner frequency. So we add negative feedback which reduces gain and improves bandwidth because gain bandwidth product is constant. Is my understanding correct? Please let me know if I fail somewhere in relating all these things. And what is instability? Why is it happening? Please reply sir. Having an important interview.
Very nice job explaining slew rate and its limiting on-limiting effects on amplifier design specification. Many manufacturers don't include this spec in their manuals. Do you feel like this is due to a difficulty of their product to produce a clean signal throughout the designed 20-20,000 Hz band or is there so few examples of op-amp response not meeting criteria that they feel there is no reson to list the spec.
Most of the manufacturers provide the value of slew rate of the op-amp with different supply voltages and also provides the graph of the variation of slew rate with supply voltage, capacitance, input voltage, temperature etc. As a designer, we need to select the op-amp which suits best to our application and have minimum distortion from this specs. I hope it will help you.
What are the large signal and small signal frequencies? I mean isn't the large signal means DC biasing? if that is true then shouldn't the frequency be=0
It is the inherent property of the given op- amp.it can't be increased using external components. If the application requires higher slew rate, then it's better to select the op-amp which can provide that slew rate.
Since slew rate is 0.5 v/us, so it will take same 10 us time to reach 5V. But let's say, if on time is 5us, then it would reach only upto 2.5 V. It can't go beyond that because after that, signal goes to zero. So, in that case, we will get a triangular wave output with 2.5 V max.output. I hope it will clear your doubt.
Hi sir, For the triangular wave time period is 4us but for the square wave it is 2us. And frequency of square wave pulse is asked. so why is it 1/4MHz why not 1/2MHz
For square wave also, the time period will be 4 us. But it is ON for only 2 us. (2 us ON + 2 us OFF). So overall duration is 4 us. During the ON time of the square wave, there will be a positive slope of the triangular wave at the output, while during the OFF time, there will be a negative slope of the triangular wave. I hope, it will clear your doubt.
Sir thank you so much for the video. Got a doubt. Hope you respond. What are the possible ways to improve slew rate sir? And is non inverting amplifier of opamp has virtual ground concept? Please reply sir? Thanks in advance.
By using the op-amp with better slew rate, that problem can be solved. The different kinds of op-amp are used for different purpose. Some op-amps have better slew rate, some have better gain bandwidth product, some are low noise op-amps. So, depending on the requirement one can select the specific op-amp. And about your second question, the the concept of virtual short is applicable for non-inverting op-amp. As far as op-amp is operating in the linear region, V+ = V-. I hope it will clear your doubt.
In example2, 4volts need 4 us, so in one period it should need 8 us , isn't it? Because the period have -4 volts? Please correct me if im wrong. Thank you, nice video!
In example 2, the slew rate of the op-amp is 2V/us. So, to reach 4V, it requires 2us. And the waveform will not fo in negative, because the input square wave pulse only varies from 0 to 10V. So, output triangular wave will at max go up to 4V. And the time period of the output wave will be 4us. I hope it will clear your doubt.
Rise time is the time taken by a signal to reach from 10 % to 90 % of the maximum value. While the slew rate defines how fast the output of the op-amp can change. I hope it will clear your doubt.
There is a separate channel for that. ALL ABOUT ELECTRONICS - Quiz. You will find the solved questions on various topics (including op-amp over there). Here is the link: ua-cam.com/channels/GA2TO8ylVqFHpucwn_6Jlw.html
In case of a triangular wave, the slope of the triangular wave is the limiting factor. The output can not go faster than the slew rate, so slop has to be lesser than the slew rate. e.g if SR= 1V/ us And if the triangular wave has a slop of 5V/us, then the output of the op-amp cannot follow the triangular wave and output will be slew rate limited (to 1V/us) I hope it will clear your doubt.
741 has gain bandwidth product of 1 MHz, so for small signal unity gain bandwidth is 1 MHz. If you set a gain of 10, then it can be operated up to 100 kHz. For large signal (in Volts), the frequency is limited by the slew rate. The slew rate of 741 is 0.5 uV/s. So, depending on the amplitude of the signal, using the expression discussed in this video, you can find the usable frequency range.
The timestamps for the different topics covered in the video is given below:
0:19 What is Slew Rate of an Op-Amp?
2:31 Causes of Slew Rate in Op-Amp
4:12 Effect of Slew Rate on Pulse Signal
7:46 Effect of Slew Rate on Sinusoidal Signal
10:21 Example 1
11:30 Example 2
sir you are great....you can see in last two video you have 0 % dislike means like/dislike = infinity ...you teaching like idle opamp...thank you sir... :D :D
I don't understand where you find the time to make such high quality tutorials man, thank you so much
Excellent, excellent video, really helped to clear many doubts I had about this concept during lecture. Took me a while to finish the video, but I have a much more thorough understanding of this now!
Professor tech slew rate
But
I don't understand anything
Useful information
Bus when I see your video
I have no dout about slew rate
You give me great information sir 💯💯💯
Excellent video explaining the slew rate concept of op amp.
Thanks for making it so easy
Awesome. Best electronics tutorials on UA-cam for sure
Thanks for your explanation! It is very clear!
you SAVED my day!!!
At 13:09, shouldn't the input square wave frequency be 500Khz, such that output will have a 250Khz triangular wave at 4V peak?
thats what I got aswell
Sir! in 12:56,how did we find f=1/t=250kHZ from t=4 micro sec?
Thanks! I love those crystal clear explanations!
Excellent explanation of the concept of OP-AMP slew rate. Thank you !
Thanks for the explanation. It was very helpful. May the Lord Jesus bless you even more :)
hi sir...!
the way you explain is super
really i liked it so much
Tommorrow is my Exam and I dont know how to thank you.
Good Luck !!!
my viva is tomorrow. Wish me luck boys
All the best :)
thank you :) I passed
My viva is today.. wish me luck guys ✌🏻
@@kirtiparashar1726 well done kaisa geya
@@sksadiruddin4191postpone ho gya tha.. ab aaj h.. 2 bje 😅
Thank you brother ... Your voice is so nice..
Voice is nice , but speaker has a long pause before the end of most sentence. Example “… slew rate changes” Had to get used to this . Liked and subscribed
Nice video easy to understand, so the slew rate and rise/fall time are related
it's very helpful
we need more videos on electronic topic
Excelente video. Very clear your exposición.
Thanks
I like your video very much. It's really great. I'll keep an eye on your channel. I am your fan and I will support you.
This Is Good. I Am Learning This Acquired Towards Sound Synthesis
Thank you for the great videos they are really enlightening. Just a couple of questions lets say we make an op-amp how can i find the SR and how would i measure it?
The slew rate is usually given in the datasheet of the particular op-amp.
You can also approximately measure it by applying the square wave to the op-amp and finding the time required to reach the maximum voltage using the oscilloscope in the lab.
Thank you a lot :)
Thank you for the explation! I am slightly confused on why the time period for the last example is 4us rather than 8us
At 2 us the square wave pulse will have a transition. That means it will go from high to low. The output of the op-amp will follow that transition in 2 us. Also here, it has been assumed that the duty cycle of the square wave pulse is 50 %. So it will reapeat after 4 us. I hope you will be able to visualise what i am saying. If you still have any doubt then do let me know here.
@@ALLABOUTELECTRONICS thanks!
The way you say "zero to five volt" is the best thing ever for some reason
in a single breath
Very good explanation.
Thank you so much
Love from Kerala
Great Explaination!
Thanks
Sir, I have got a doubt. Hope you will clear it. What I have actually understood is- In earlier opamps, there is a problem of instability and opamp may break into oscillations. So to avoid this, almost all new opamps are internally compensated . But this leads to reduction of gain even at very low corner frequency. So we add negative feedback which reduces gain and improves bandwidth because gain bandwidth product is constant. Is my understanding correct? Please let me know if I fail somewhere in relating all these things. And what is instability? Why is it happening? Please reply sir. Having an important interview.
Yes, what you understood is correct. In simple terms, instability means, for the bounded input you are not getting bounded output.
why cant we use formula of sr to find frequency on 11:31
You mean to say, 1 /SR ?
@@ALLABOUTELECTRONICS f
That is only for sinusoidal signals.
In the last question can we not use the formula 2*pie*f*v=slew rate?
Sir, in 8:40 of this video, isn't the slew rate is in microsecond and frequency is in second. Don't we need to divide right hand side by 10^6
The unit of slew rate is V / us. And the unit of frequency is Hz or 1/ sec. I hope, it will clear your doubt.
@@ALLABOUTELECTRONICS thank you sir 🙏
9:01 Assuming coswt =1 i.e w=0 or t= 0
if t=0 then f infinite
if w=0 then f is 0
slew rate =0
plz clarify
Thankyou so much we get easy way for study
Very practical and usefull, thank you
Amzing Explanation
Very nice job explaining slew rate and its limiting
on-limiting effects on amplifier design specification. Many manufacturers don't include this spec in their manuals. Do you feel like this is due to a difficulty of their product to produce a clean signal throughout the designed 20-20,000 Hz band or is there so few examples of op-amp response not meeting criteria that they feel there is no reson to list the spec.
Most of the manufacturers provide the value of slew rate of the op-amp with different supply voltages and also provides the graph of the variation of slew rate with supply voltage, capacitance, input voltage, temperature etc. As a designer, we need to select the op-amp which suits best to our application and have minimum distortion from this specs.
I hope it will help you.
What are the large signal and small signal frequencies? I mean isn't the large signal means DC biasing? if that is true then shouldn't the frequency be=0
nice lecture sinks with my brains slewrate
I would like to thank you for your good learning. But i have question ,,what is the maximum freqency that may be used slew rate 0.5v/microsecond?,,
It depends, what voltage level you need at the output.
@@ALLABOUTELECTRONICS output is not given ,how can i conclude it,give me some assumtions as much as possible.
What is the use of given circuit in last question ??
Sir where did you get all these information..
That he will never tell.
Thank you so much for this awesome explanation....But i have a small question.....can we increase the slew rate of any op-amp???
It is the inherent property of the given op- amp.it can't be increased using external components. If the application requires higher slew rate, then it's better to select the op-amp which can provide that slew rate.
Thank you so much (•‿•)
great video. Really helped
Amazing🙌🔥
Any book to recommend?
Op-Amps and Linear Integrated Circuits by ramakant gayakwad.
@@ALLABOUTELECTRONICS are u kiddin? After reading that book I had to come to ur channel. Suggest something better.
great explanation thank you so much
please ex plane types of mosfet
5.54?
If new input signal has ton=10us
And slew rate is 0.5v/us then our output should take 5us to reach 5v???
Since slew rate is 0.5 v/us, so it will take same 10 us time to reach 5V.
But let's say, if on time is 5us, then it would reach only upto 2.5 V. It can't go beyond that because after that, signal goes to zero. So, in that case, we will get a triangular wave output with 2.5 V max.output.
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS
Ok.. Get it.. Thanks : )
Ur explanation is good but too fast for a beginner....
Please try to slow down in coming lectures...
Tnx. it was just what i wanted.
Thank u brooo awesome explaination...
is there any video for instrumentation amplifier
Yes, please go through the op-amp playlist. You will get it.
Boss tujhe salam 🙏🙏🙏
Hi sir, For the triangular wave time period is 4us but for the square wave it is 2us. And frequency of square wave pulse is asked. so why is it 1/4MHz why not 1/2MHz
For square wave also, the time period will be 4 us. But it is ON for only 2 us. (2 us ON + 2 us OFF). So overall duration is 4 us. During the ON time of the square wave, there will be a positive slope of the triangular wave at the output, while during the OFF time, there will be a negative slope of the triangular wave. I hope, it will clear your doubt.
@@ALLABOUTELECTRONICS yes sir, thank you
in the last example what is the use of slew rate of 2 mv
It will decide the frequency of the triangular wave.
Sir thank you so much for the video. Got a doubt. Hope you respond. What are the possible ways to improve slew rate sir? And is non inverting amplifier of opamp has virtual ground concept? Please reply sir?
Thanks in advance.
By using the op-amp with better slew rate, that problem can be solved. The different kinds of op-amp are used for different purpose. Some op-amps have better slew rate, some have better gain bandwidth product, some are low noise op-amps. So, depending on the requirement one can select the specific op-amp. And about your second question, the the concept of virtual short is applicable for non-inverting op-amp. As far as op-amp is operating in the linear region, V+ = V-.
I hope it will clear your doubt.
very well explained
Awesome video
Good concept
In example2, 4volts need 4 us, so in one period it should need 8 us , isn't it? Because the period have -4 volts? Please correct me if im wrong. Thank you, nice video!
In example 2, the slew rate of the op-amp is 2V/us. So, to reach 4V, it requires 2us. And the waveform will not fo in negative, because the input square wave pulse only varies from 0 to 10V. So, output triangular wave will at max go up to 4V. And the time period of the output wave will be 4us.
I hope it will clear your doubt.
Thank you, I got that,cheers
What is the diff blw raise time and the slew rate?
Rise time is the time taken by a signal to reach from 10 % to 90 % of the maximum value. While the slew rate defines how fast the output of the op-amp can change. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS yeah thankyou sir.
good work
Bro, can you solve questions also ? It would help us to apply the theory.
There is a separate channel for that. ALL ABOUT ELECTRONICS - Quiz.
You will find the solved questions on various topics (including op-amp over there).
Here is the link: ua-cam.com/channels/GA2TO8ylVqFHpucwn_6Jlw.html
@@ALLABOUTELECTRONICS Thank You!!
Thanks excellent work
i want to personally meet you and thank you
How to control slew rate in opamp
Crystal clear.. !
Thank you so much sir
What is the slew rate for rectangularwave
What's it formal Sir
In case of a triangular wave, the slope of the triangular wave is the limiting factor. The output can not go faster than the slew rate, so slop has to be lesser than the slew rate.
e.g if SR= 1V/ us
And if the triangular wave has a slop of 5V/us, then the output of the op-amp cannot follow the triangular wave and output will be slew rate limited (to 1V/us)
I hope it will clear your doubt.
In example 2 .... square width must be for 2 micro second on and 2 micro second off
Very good explanation. ndi Happy
Excellent
Thank you so much... Thank u really!!!!
Really appreciate! Thanks!
741 how much frequency we can use?
741 has gain bandwidth product of 1 MHz, so for small signal unity gain bandwidth is 1 MHz. If you set a gain of 10, then it can be operated up to 100 kHz.
For large signal (in Volts), the frequency is limited by the slew rate.
The slew rate of 741 is 0.5 uV/s.
So, depending on the amplitude of the signal, using the expression discussed in this video, you can find the usable frequency range.
Thank you so much
Please u prepared all videos
Really helped a lot...
ty bro
mindblowing
I didn't know Apu was also an Electrical Engineer, please don't be anger, this is justa bad joke XD
Excellent!
I wonder why you pause before the last word of every sentences :)
Crystal clear
Thanks
thanks a lot
Thank you
Nice
excellent
Thank u
Perfect
very nice
Thanks .
god level
Good
It mean more slew rate should be more is better
Yes, higher slew rate means, opamp can respond to the fast changing signals.
SUPER
Language is so so fast.
reduce the volume of your intro bro
It has been already reduced in the new videos.
@@ALLABOUTELECTRONICS That's great thank you and your new videos are really really good , thank you again for your great work !!
Simply reading continuously .bad explanation