Gauss siedal method
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- Опубліковано 11 бер 2020
- In the beginning of the solution of this system of equation by this method we need to rewrite each equation in terms of x1, x2, and x3 respectively.
like 6x1+x2+x3=105
or, 6x1=105-x2-x3
or,. x1=(105-x2-x3)/6
same step is done for other two equation also.
you only need to remember that when +ve sign is moved from one side of equal to(=) to the other side then it is written as -ve and vice versa.
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#gausssidelmethod
#gausssidelmethodexample
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Awesome stuff man! This was great help for my class test prep
Thank you sir for your effort, it Helps me a lot ❤️❤️
Thanks so much the class was really helpful. Simple and short
thanks you sir it is very helpful to me your explination is awesome and i understood easily sir when you are teaching
Thank u very very very very much sir
U helped me a lot
God bless you
Clearly explained thank you sir
Very impressive brother, and was easy to understand 🤝💯.. tq for the effort 😊
Thank you for your compliment.
thank you sir, this video was very helpful for me
Easily explain..
Thank you sir.
Thank you sir , so helpful
Nice one bro... Really helpful
very good explanation 👏 👌 👍
great explanation bro its help me a lot
thanks 🌹❤ bro....
wow thank you so much its now easy to digest the questions
Welcome 😁
Brilliant exam in next hour and i am completed❤
Best of luck dear.❤️❤️
Thanks man umetisha
Thanks alot this clarified stuff
X3 in equ(iii)...What wasn't the like terms collected the same way as equ(i) and equ(ii)? Please explain
Thank u very much bro 😊💗
Thanks for the wonderful explanation!!
Welcome dear
Thanks Sir!
Today is my internal exam in the morning 😂
Thanks you 😊 bro very useful the Video
Thank you 😌
Thank you so much
Sir excellent💯
Nice!!
Thank you
Thank you❤🙏
Thank you sir🙏
thank you 🌹🌹
thank u so much sir
Why at last we find the iteration till 6 with last iteration 5,10,15 came from ?
Thanks
Tq. Sir
Thank you so much 💕
Welcome dear
Won't we solve for y1, y2, y3 and z1, z2, z3. Thanks for the discrete solving
kyo use krte h Guess Seidel jacobi method jab symple x y z find kr sakte h simple method se
nice explanation
Thank you
what about gauss jacobi method
Bro why do u take at the starting of the solution eq 1 nd 2 as( - ) and eq 3 as above step.why dnt u put ( - ) in eq 3
Hii
@@sarathisarathy7621 😐
As x3 is already -10x3 , so instead of taking all variables from left side to right, we just take -10x3 to the right side and 65 to left side. In this way, we'll get x3 without -ve sign. It's preety simple. Watch it again and you'll get it.
NICE QUESTION
NICE QUESTION
thank you so much !!! excelent video
Welcome come
Tq u sir
Welcome dear
Ok bro👌
I finally get what the hell was all those equations doing... You let me peek at the secrets of the universe.
Seriously though, who else has read walls of text and equations and understood nothing? Why are mathematicians encrypting their textbooks?
Thank you
Nyc explanation
Yes its very good
Repu exam ah...😂
@@shirishashirisha4676 ha avunu
🥰thank u v much
Welcome
It will work in r18 syllabus?
If this method is mentioned then yes it will work.
Is this method is useful in load flow studies ?
No idea
31(nm)
hatsoff sir very good explanation
51(NM)👍
Bhai gauss seidal method mein second iteration tak bhi kar denge to bhi chalega
Full Karen ki try krna. Agar time nai he to phir thik he.
Sir hav u upload Ed eighen meathod??
Not yet.
Ok
029,cs,sec=C
main differece between jacobi and gauss seidel 6:20
Sir 5th iteration lo
X2=155-4×15.006-3×4.9784÷8
=10.0051 sir
The is right sir
10.008 is wrong sir
Plize chikeing sir this value sir
Yes. Your are right. It's not going to create any problem actually.
One need to take up to two decimal place
56(nm)👍
Y to do 6 iterations
It depends on question until, you start getting value close to zero.
SIR WHERE WE CAN APPLY THIS METHOD IN REAL LIFE PROBLEMS
😁😁😁
Good Question
@@Civillearningonline sir plz answer
Bhai 2 ghante me exam hai
Thank you 💗
Welcome bhai
And best of luck
0009 b.sc c.s
👍 👍
Sooo Helpiful 🫂
🙏🙏
Sir why you taken -65
In the question given only 65
When number changes side then its sign also changes.
Also in 3rd equation X3 is -ve so of we make it positive the sign of other terms changes.
05 Mehak bsc cs sec c
Thank you very much, very helpful
Plz reply
What?
Can you please tell ki ham kaise decide karenge ki hame kitni baar iterations nikalni hai taki hame answer mil jaae
Plz Reply 🙏🙏🙏
When we don't get much difference among the values in each iteration.
Take a look to iteration 5 and 6. You will come to know.
Bad
ua-cam.com/video/mOKy8gCybCU/v-deo.html
In hindi