"I'd rather have an A+ than a C-" is how I was taught to remember it. Slips of the tongue happen, but if someone is looking for a way to remember it, that's worked well for me.
I'm studying Radiotherapy and could never wrap my head around the difference between the two until this video so thank you so much! Your videos are gonna get me through my exams :)
I'm not studying medical imagine just interested in electromagnetic radiation and physics in general and have to say, this was a superb presentation.....you're a natural.
You can simply say Bremsstrahlung, without adding the word " radiation". Good pronounciation, btw. Breaking it down would be easier as Brems (break-) strahl (ray/radiate) -ung (-tion)
why photoelectric effect... only affects inner orbits (k-shell)... why not affect outer shells..? also, my another question is my componton effect affects outshell...since compton have high energy... why it affect outer shell first instead of innershell
Great question, it get's a bit complicated as we try to simplify the explanation of how photoelectric absorption and compton scatter occur, but here's a brief response to your question. It turns out that as the x-rays are coming and interacting with our tissues, they can be low energy or high energy (remember there's always a range of energies created as you saw with bremssttrahlung radiation). The x-rays coming in are all interacting with all the shells not necessarily just the inner or just the outer shells. It's just that WHEN an x-ray photon interacts with the inner k-shell, which is usually one that has a lower energy, then what results is an absorption event (aka photoelectric absorption). And this only occurs when the incoming photon has an energy that's equal or just greater than the binding energy of the inner k-shell (which will have the highest binding energy of all the shells). Now as said these x-ray photons are interacting with all the other electrons in other shells as well, and generally apart from that when they interact with the outer shell electrons, this results in a scattering event (aka compton scatter). So it's not necessarily that photoelectric effect only affects inner k-shell orbits, it's that x-ray photons interact with all electron shells, but the ones that have the right energy to interact with the k-shell orbit, that's when it results in an absorption event, and we call this process photoelectric absorption. Hope that helps!
Great question! The electron, being negatively charged, is indeed attracted to the positively charged nucleus due to their opposite charges. In the case of bremsstrahlung (braking) radiation, the electron approaches the nucleus and is deflected due to the attractive electromagnetic force. However, it's not a straightforward acceleration toward the nucleus because the electron doesn’t directly collide with it. Instead, as the electron passes by the nucleus, its path curves due to the attraction, which changes the direction and speed of the electron (i.e. velocity). This deflection leads to a rapid deceleration or reduction in the electron's velocity along its original path/trajectory. In this rapid deceleration, the electron releases energy in the form of X-ray photons, which are known as 'bremsstrahlung radiation'. So, while the electron does 'accelerate' in the sense that it changes direction due to the attractive force, it also loses energy as radiation because of this sudden change in velocity. Hope that helps
Correction: the Cathode is negative (-ve) and the Anode is positive (+ve)
"I'd rather have an A+ than a C-" is how I was taught to remember it. Slips of the tongue happen, but if someone is looking for a way to remember it, that's worked well for me.
@@fieryweasel I love it, and I will definitely not steal it 👀
@SahandHooshmand It's just another Free Fun Fact From Fieryweasel, enjoy, good sir!
I'm studying Radiotherapy and could never wrap my head around the difference between the two until this video so thank you so much! Your videos are gonna get me through my exams :)
I agree, it can get quite confusing, glad it was useful
You have incredible teaching methodology ,keep up the good work 👏
I'm not studying medical imagine just interested in electromagnetic radiation and physics in general and have to say, this was a superb presentation.....you're a natural.
Thank you the kind words!
I’m in my Second year of pure science and couldn’t understand this from the textbook. You’ve explained it really really well!
Glad you found it useful my friend
You rescued me Sahand;)
Great video! Thank you
👍🏼👍🏼
best explanation on youtube!
Very nicely explained and excellent presentation!
Brilliant teaching🙏🏻✌🏻
Nice explaination 😊
You can simply say Bremsstrahlung, without adding the word " radiation". Good pronounciation, btw.
Breaking it down would be easier as Brems (break-)
strahl (ray/radiate)
-ung (-tion)
How can someone concentrate on topic ... When the teacher is looking sooooo cute. 😅😂
Thank You!
why photoelectric effect... only affects inner orbits (k-shell)... why not affect outer shells..? also, my another question is my componton effect affects outshell...since compton have high energy... why it affect outer shell first instead of innershell
Great question, it get's a bit complicated as we try to simplify the explanation of how photoelectric absorption and compton scatter occur, but here's a brief response to your question. It turns out that as the x-rays are coming and interacting with our tissues, they can be low energy or high energy (remember there's always a range of energies created as you saw with bremssttrahlung radiation). The x-rays coming in are all interacting with all the shells not necessarily just the inner or just the outer shells. It's just that WHEN an x-ray photon interacts with the inner k-shell, which is usually one that has a lower energy, then what results is an absorption event (aka photoelectric absorption). And this only occurs when the incoming photon has an energy that's equal or just greater than the binding energy of the inner k-shell (which will have the highest binding energy of all the shells). Now as said these x-ray photons are interacting with all the other electrons in other shells as well, and generally apart from that when they interact with the outer shell electrons, this results in a scattering event (aka compton scatter). So it's not necessarily that photoelectric effect only affects inner k-shell orbits, it's that x-ray photons interact with all electron shells, but the ones that have the right energy to interact with the k-shell orbit, that's when it results in an absorption event, and we call this process photoelectric absorption. Hope that helps!
why it affects k-shell? insteated of M-shell?
if the electron is negative and the nucleus positive, why does electron decelerate? shouldnt it accelerate since opposite charges attract?
Great question! The electron, being negatively charged, is indeed attracted to the positively charged nucleus due to their opposite charges. In the case of bremsstrahlung (braking) radiation, the electron approaches the nucleus and is deflected due to the attractive electromagnetic force. However, it's not a straightforward acceleration toward the nucleus because the electron doesn’t directly collide with it. Instead, as the electron passes by the nucleus, its path curves due to the attraction, which changes the direction and speed of the electron (i.e. velocity). This deflection leads to a rapid deceleration or reduction in the electron's velocity along its original path/trajectory. In this rapid deceleration, the electron releases energy in the form of X-ray photons, which are known as 'bremsstrahlung radiation'. So, while the electron does 'accelerate' in the sense that it changes direction due to the attractive force, it also loses energy as radiation because of this sudden change in velocity. Hope that helps
@@SahandHooshmand Thank u!
6:23 I don't understand how electron is getting that much close to nucleus in bremsstrahlung
What is bindinh energy?
It’s the energy required to remove an electron from an atom/nucleus, overcoming the electrostatic force holding it in place.
Hi, I sorry but I think your drawer made a mistake and draw Cathode (+) instead of negative 😅
Indeed I did and learnt of it after the fact! I put a pinned comment under the video flagging that when I found out. Apologies for the confusion
And they said being a rad tech is easy🥴 they should study this too😂
This is the fun stuff though 😅
Can you tutor me?
Sure
@@SahandHooshmand contact number?
@@SahandHooshmand contact number ?