Bremsstrahlung Radiation | X-ray production | X-ray physics | Radiology Physics Course #19
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- Опубліковано 21 вер 2024
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Finally, we will review the production of X-rays at the anode. There are two mechanisms of X-ray production - Bremsstrahlung and Characteristic radiation. Let's start by looking at Bremsstrahlung radiation. Bremsstrahlung means 'braking', which describes this mechanism well. Bombarding electrons at the anode slow down when experiencing an attractive electromagnetic force of the positively charged nucleus. This loss in kinetic energy is accounted for by the release of electromagnetic radiation (the energy of which is proportional to the kinetic energy lost by the electron).
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First year of Radiography and your videos are literally saving my mental sanity. You speak so clear and in depth that it doesn't even feel I am learning, you make physics "easy" Thanks a lot!
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I'm finding it challenging to find the answer to this objective:
Identify factors affecting characteristic K-shell photon production.
Thank you so much for making xray physics so much interesting and easy. What i liked the most is that you are not just brushing the topics off, you are letting us dive deep into your wisdom
Thank you Aman. That's very kind of you!
Thank you is not enough. You saved my life !
Thank you so much for your input! Finally I got it!! 😊 Just a comment on the term "Bremsstrahlung" : "Bremsen" as you said means to "break or slow down" in German and "Strahlung" is nothing else than "radiation" . So Bremsstrahlung means "Radiation slowing down". Just to mention it, in case it helps and makes sense.👋
Thanks for letting me know 🙂☺️ glad the video is helpful!
Understanding physics for X-ray more with your videos than I did in my radiology classes and that was a very long time ago.
Amazing video. A couple of questions. 1) if electron directly hits the nucleus(kinetic energy becomes 0) and highest photon energy is produced, does the electron that hit the nucleus dies ? or what happens to it ? disappears ? dies ? on your video, on the screen, you didn't draw any line for it or mentioned it. 2) since we know Bremsstrahlung can produce continous spectrum, can it produce gamma-rays/visible light or it can only produce x-ray ? 3) would be awesome if you could have mentioned inner and outer Bremsstrahlung as the way it's explained on the internet is super difficult. Thank you.
Brilliantly explained! Thank you!
Location of
1.x ray tube
2.grid
3.image intensifiers
4.transformer
5.control panel
Please tell.
By far the best explanation I was able to find! Thanks! Subscribed!
Thank you for the great effort
Medical physics master student
Just completed my diploma level in radiography but am understanding what i missed out in school you the best
Nice! Well done on completing your diploma! Always good to refresh once in a while
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I’m so glad you find the videos helpful 🙂
incredibile spiegazione...
Your explanations are so brilliant! I finally understand bremsstrahlung and characteristic radiation 😁😁 Thank you!
Yay! Thanks Bianca 🙂
Brilliantly explained
you explained so clear thank you so much
Very nice👍👍👍..
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I hope it helps!
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I am Arabic students, I study in medical college.
Pleasure. Good luck with the studies!
Thanks for amazing explanation sir
amazing explanation ❤❤thank you .
2:20 - Major difference between Bremsstrahlung and characteristics radiation
Ty for this♥️
Thanks a lot you made it crystal clear
Sending gratitude, you helped a lot
Thank you Maemetja 🙏🏻
@@radiologytutorials can't see the bank of questions
this is amazing thank you!
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Are you referring to the Electron binding energy?
along the x-axis, why is the maximal keV up to 90-100? sorry i don't understand this
Please make the vid on auto transformer and self rectification before 13 please kindly request there is exam
very clearly
Thank you
Please can you explain why out of the 1% of Xray produced at the anode majority is Bremsstrahlung
Sure! Characteristic X-rays only occur when an electron collides with inner shell electrons in the target material. The atoms that make up the target material are large. Relatively speaking the electrons are tiny (they make up a very small proportion of the atom). Therefore, a bombarding electron is much more likely to ‘miss’ the electrons. Very few will actually collide with electrons. The majority will slow down when experiencing the attractive electromagnetic force of the nucleus - and subsequently release a bremsstrahlung radiation.
@@radiologytutorials thank you so much
Somewhere around the 6 minute mark on the bremsstrahlung diagram, you display the nucleus's positive magnetic field strength. Wouldn't each individual electron has its own negative magnetic field? I understand that could junk up the diagram and make things too complicated. I was just curious
الحمد لله
الله اكبر
لا اله الا الله
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Glad it was helpful 👍
Long lost memories🥲🥲thank you so so much
Helpful!
Glad to hear it Kennedi 👍🏼
awesome
what does p mean in the formula of the photoelectric effect probability? Thank you
density of the filter material (greek letter rho which looks like a p) :)
@@dareenjiad2246 thank you :)
How,i cant see the bank of question ......can u plz help m
Hi Fadhira. It should be in the first line of the description
As a German I shudder at your pronunciation of Bremsstrahlung.
Thanks for letting me know 👍🏻
Thanks a lot you made it crystal clear
Yay, I’m glad it helped Maram 🙂
Your question bank link is not opening 😕