A Nice Algebra Challenge | Can You Beat This Rational Equation?

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  • Опубліковано 18 чер 2024
  • A Nice Algebra Challenge | Can You Beat This Rational Equation?
    Ready for a nice algebra challenge? Join me as we tackle a fascinating rational equation together! 🧠💡 In this video, we'll explore simple yet effective strategies to conquer this mathematical puzzle. Whether you're a math enthusiast or just curious, this friendly challenge will put your algebra skills to the test in an enjoyable way. Get ready to flex those mental muscles and see if you can beat this rational equation!
    👉 Don't forget to like, subscribe, and share your thoughts in the comments below. Challenge your friends to join the equation-solving excitement!
    📚 Key Highlights:
    Step-by-step breakdown of the solution process
    Insights into the unique aspects of the tough rational equation
    Tips and tricks for mastering similar challenges
    Application of substitution, manipulations and algebraic identities
    🎓 Suitable for students, math enthusiasts, and anyone looking to explore the wonders of rational equations. Let's unravel the mystery together! 💡✨
    Timestamps:
    0:00 Introduction
    1:15 Substitution
    4:29 Quadratic equation
    6:05 Solving system of equations
    7:10 Quadratic formula
    7:55 Complex solutions
    9:08 Real solutions
    9:35 Verification
    #algebrachallenge #rationalequations #mathpuzzle #problemsolving #mathematics #algebra
    We'd love to hear from you! Did you manage to solve the equation? What other math problems would you like us to cover? Let us know in the comments below!
    🎓 Happy learning, and see you in the next video! 🎉
    Thanks for Watching !!
    @infyGyan ​

КОМЕНТАРІ • 5

  • @tejpalsingh366
    @tejpalsingh366 Місяць тому +3

    Let first part of l.h.s is t
    The eqn becomes
    t+ t^2/x= 20/x^ 2 i e
    tx(x+t)=20= 1x4x5.. for real soln
    x= 1,4
    t= 4,1
    Soln is 1; 4

  • @woobjun2582
    @woobjun2582 Місяць тому +2

    After tedious expantion and rearrangement of the given where x is not 0 nor -1,
    x^5 -9x^4 +9x^3 -41x^2 +20x =0;
    x(x^4 -9x^3 +9x^2 -41x +20) =0,
    by which
    x = 0 * rejected ;
    x^4 -9x^3 +9x^2 -41x +20 =0.
    By RRT and SDMs
    (x -1)(x -4)(x^2 -4x +5) =0,
    and thereof
    x = 1, 4;
    x = 2 +i, 2 -i

  • @user-nd7th3hy4l
    @user-nd7th3hy4l Місяць тому +1

    X=1 marche.

  • @mohammedsaysrashid3587
    @mohammedsaysrashid3587 Місяць тому +1

    x=4;1....x=2+i ,2-i ......too many variables

  • @user-sy9mb6rw2r
    @user-sy9mb6rw2r Місяць тому

    Too many variables !!!!