Question I have got confused with BMD why moments on the column B should not be zero like column A ,I know because of the point load of at column B but only when you doing the Area bit confused,could anyone explain to me thanks
Ali Mohamed Remember, the moment is taken about reaction B so B is a fixed point. Imagine holding the frame in one hand at Reaction B. The 4 kN/m uniformly distributed load can be represented by a 40 kN point load at the center of the horizontal beam. If you’re holding a model frame in the air. Your left hand holds the frame at the bottom of the column supported by Reaction B. If you use your free right hand to push down on the center of the horizontal beam, what would happen? The left side of the Beam would bend or tilt counter clockwise. Hope this helps :)
OBJECTION . Given that beams A (8m) and B (4m) have different heights and therefore should NOT be represented as having the same dimension. The diagram is misleading.
LGL_137 No Name Both columns are the same height. The horizontal point load on column B is located in the center of the column, 4m away from Reaction B.
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Very understandable. Thank you!
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this is useful during this pandemic thank you guy
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short and precise,thanks for this very informative video!
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Very good explanation
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hi dear plz cmm there and jn
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Question
I have got confused with BMD why moments on the column B should not be zero like column A ,I know because of the point load of at column B but only when you doing the Area bit confused,could anyone explain to me thanks
👍 great video
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thanks for your excellent lecture.
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Very informative
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You should have explained well the SFD of right side column
nice class
pls jn there for more civil engineering updates and cls
Sir. Please make a video for flat plate slab with hidden beam, and how to design hidden beam, thank u
plz jn there too dear
hello sir, do you have examples for method of joints and method of sections for trusses?
Not yet
I thought the UDL would create a positive clockwise moment
Ali Mohamed Remember, the moment is taken about reaction B so B is a fixed point. Imagine holding the frame in one hand at Reaction B. The 4 kN/m uniformly distributed load can be represented by a 40 kN point load at the center of the horizontal beam. If you’re holding a model frame in the air. Your left hand holds the frame at the bottom of the column supported by Reaction B. If you use your free right hand to push down on the center of the horizontal beam, what would happen? The left side of the Beam would bend or tilt counter clockwise.
Hope this helps :)
In point B couple is 20 knm clock wise I am right
greeeeeeeeeeeeeeeeat
Thanks
nice
tnx
this is a strange way to do it, it appears wrong if you run it through a simulation like beamguru
U did not solved the moment about point b and c .
I think you're going too fast for beginners to grasa.
OBJECTION .
Given that beams A (8m) and B (4m) have different heights and therefore should NOT be represented as having the same dimension.
The diagram is misleading.
LGL_137 No Name Both columns are the same height. The horizontal point load on column B is located in the center of the column, 4m away from Reaction B.
right #Jargon (Y)
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