I swear to god yall are sadistic I was watching khan academy projectile motion and he used a person jumping off a cliff as an example Now I'm both getting shot at and being hit by a train, thanks shorts !
really wanna give you hug for this, i have my exams in 8 days and i am hardly prepared... im a pretty avg scoring person. this video really helped me internalize the concepts. thank you so much!
Hello sir, I just wanted to show my gratitude towards you for the videos, they are extremely concise and well explained. My grades in physics have taken a boost ever since and I always revise these videos before my exams.
I really hope you still reply to questions T_T Can we just plug in values for the equation in the last sum or do we have to show how we derived our answer?
Change from 'u' to '- u' : You have to subtract one 'u' to get from 'u' to zero, then another 'u' to get from zero to '-u'. So in total it's -2u. Then multiply by the mass to get -2mu.
Or change in velocity is , v - u , so v is final velocity and u is initial velocity, in this case v = -u and u =u , so -u - u = -2u . Thus its -2mu / t. Hope this helps.
If they collide and bounce off, m1u1 + m2u2 = m1v1 + m2v2 U=initial velocity V=final velocity And if they collide and 'don't' bounce off, final velocity v is the same for both as they are stuck together: m1u1 + m2u2 = (m1 + m2) v
/\p =m/\v = m(-u-u) = -2mu It could be easier to split this into two stages: Pa (after) and Pb (before) Pb = mu Pa = -mu /\P = Pa - Pb = -mu - mu = -2mu
so what he got initially was change in mass divided by time which can be written as kgs^-1 which is what he managed to make an equation for at 20:06 but if you look at the initial equation for force for the fluid which he wrote at 17:57 , it is VELOCITY x change in mass over time.
Technically yes, but in the recoil situation, we can be cheeky and just concern ourselves with the magnitudes, seeing as we know they have to be travelling in opposite directions.
@@ScienceShorts still need to fully wrap my head around separating out magnitude and direction from equations, sounds stupid but something I trip up on regularly. Thank you for the swift explanation.
it's TOTAL momentum before the collision equals TOTAL momentum after the collision, he only shows the graph for the stationary object, there would be another moving object that would hit the stationary object before the collision that would balance it out.
At the start you say that momentum is always conserved but then when you talk about the car accident you say that after the accident momentum goes down to zero. Im confused. Can someone please explain
Cuz momentum is mass x velocity, a moving object would stop after hitting something applying force to the opposite direction of the moving object , that cancels out the velocity , therefore the the momentum which is mass x velocity would be zero since velocity will be = to zero.Hope it help.
In the example of a boy and bullet (which you discussed) can we say that "total momentum of boy and bullet after collision is 0." OR is it that total momentum of bullet and gun is zero? please reply. thankyou
Hi Sir, when you were answering the water equation, you used rho as density however I thought rho was resistivity? Is rho used for both or have I made a mistake? Thanks a lot for these great videos!
I swear to god yall are sadistic
I was watching khan academy projectile motion and he used a person jumping off a cliff as an example
Now I'm both getting shot at and being hit by a train, thanks shorts !
lolol nice
what too much physics does to a person
@@abdulrehmannagi352 facts
@@khaliljasiah4631 bot
@Joe Bradley bot
Sir you have single handedly saved my A level physics grade
the glazing is insane
@@ARCPolusreal
really wanna give you hug for this, i have my exams in 8 days and i am hardly prepared... im a pretty avg scoring person. this video really helped me internalize the concepts. thank you so much!
How'd it go?
Thank you, to this day your video still holds up. This has made it so simple to understand my A level physics
Sir, You are really doing a great job.
life saver
i wouldve failed my a levels without you!
How did you do in them
@@zannino7889 good q
@@haroonqadir3474 Nice, good too
Hello sir, I just wanted to show my gratitude towards you for the videos, they are extremely concise and well explained. My grades in physics have taken a boost ever since and I always revise these videos before my exams.
The best explainatory video i've found about this. Very well done!
Brilliant channel. Clear. Concise. Unlike the textbook XD
yh the textbook thinks were already physicist!
yeah I can literally never learn from textbooks
my new physics teacher for a-level since my other one is terrible x
8:56 if u do physics and drillings u know
You should become an ASMRtist. Such a soothing voice.
10:30 sad thing is this would probably be a 1 marker in the exam
Good luck for Monday pepes
Good luck
good luck!
Good luck lol
which unit do you guys think will come up the most?
@@ayeshaa44 unit 3 and 5 on Monday 4+6 Friday...?
Anyone else are giving As level exams? Good luck!💕
Sadiya And Sarah me and physics MCQ's are really hard. But gotta keep trying to achieve good grades.
Thanks ❤
Meeee😭😭😭😭😭😭
Cheers
@@amywinter9453 😥
I think its time to drop physics
Which uni does ya read in
@@fardinahmedtameem5332 MIT
Its too late for me the as level exam is after 1 month
You can do it, I scored A
@scienceshorts bros violating
Thanks, my mind feels a little cleared.
I genuinely love you, thank u smm youre saving lives😣
14:24 why does change in momentum = -2mu? Thank you!
@Ariana Saly thanks !
16:10 might be easier just to use 1/2 base x height on that one triangle you already have 😄
...🥲
its not a right angled triangle, is it sherlock?
@@ASRtuness it doesn’t have to be, watson
Excellent channel nice one!
+Fiziks Friend Tar muchly!
Watching this before my a levels, great videos
Good luckkk. In the same boat
@@tillytiger5041 Ty u too buddy
AQA ?
@@tanvirahmed1010 yes
Are you revising only the advance information topic given by AQA ?
I'm just gonna call it v I can't be bothered to write v12
lmao I love this guy xD
THANKYOU SO MUCH YOUR VIDEOS ARE INCREDIBLE
why is it -2 pls reply i have test in ten minutes
thank you sir, this has really helped me out.
I really hope you still reply to questions T_T Can we just plug in values for the equation in the last sum or do we have to show how we derived our answer?
17:11
This is so useful, thank you very much
you're doing a great job
18:07 velocity cant be constant cuz in that case acceleration will be equal to zero and change in momentum and F will all be zero
Thank you for this amazing video!
this is amazing
no other words
Thanks for the help! really love your videos
Got Unit 4 on monday, 0 prep but these videos are definitely gonna make me pass!
This was extremely helpful. Thank you for making this
its been 4 years, how did you do? what are you doing now
@@rin_morts got an A in physics and about to graduate uni!
@@serena1330 i’m so proud that you got an A, i’m sitting mine in less than a months time 😭 wish me luck
@@rin_morts good luckkk!!
@@rin_morts how was it?
this is helpful thank you sir
14:33 why is it -2mu
Change from 'u' to '- u' : You have to subtract one 'u' to get from 'u' to zero, then another 'u' to get from zero to '-u'. So in total it's -2u. Then multiply by the mass to get -2mu.
On the wall by the ball.... the direction if force is to the right?
Or change in velocity is , v - u , so v is final velocity and u is initial velocity, in this case v = -u and u =u
, so -u - u = -2u . Thus its -2mu / t. Hope this helps.
@@Umer-rg8ik thanks bro
love your videos, theyre amazing
U cut out the part in video where u explain rebound....y sir 😢😢😢 I really needed that information
14:33 shouldnt it just be 2mu because v--v adds up to 2u
I dont rlly like collision questions :/ for example, people ice skating that collide then bounce off. Dont understand those questions.
If they collide and bounce off,
m1u1 + m2u2 = m1v1 + m2v2
U=initial velocity
V=final velocity
And if they collide and 'don't' bounce off, final velocity v is the same for both as they are stuck together:
m1u1 + m2u2 = (m1 + m2) v
@@vsmoonchildmahir283 legend
14:29 Why is it -2mu Please help
/\p =m/\v = m(-u-u) = -2mu
It could be easier to split this into two stages: Pa (after) and Pb (before)
Pb = mu
Pa = -mu
/\P = Pa - Pb = -mu - mu = -2mu
thx sir. it‘s clear than what i know now
Watching in 2019👍
Watching in 2021 xD
Watching in the end of 2022
thank you!
this probably wont get answered but why did you put v^2 in end while deriving the formula through density at 20:33
so what he got initially was change in mass divided by time which can be written as kgs^-1 which is what he managed to make an equation for at 20:06 but if you look at the initial equation for force for the fluid which he wrote at 17:57 , it is VELOCITY x change in mass over time.
Really good video .Thanks
a great work done really a good work done.
wouldn't it be MgVg = -MbVb at 10:31 ?
Technically yes, but in the recoil situation, we can be cheeky and just concern ourselves with the magnitudes, seeing as we know they have to be travelling in opposite directions.
@@ScienceShorts still need to fully wrap my head around separating out magnitude and direction from equations, sounds stupid but something I trip up on regularly. Thank you for the swift explanation.
At 17:02 , if momentum is zero at the start, how is momentum mv at the end if momentum is meant to be conserved?
it's TOTAL momentum before the collision equals TOTAL momentum after the collision, he only shows the graph for the stationary object, there would be another moving object that would hit the stationary object before the collision that would balance it out.
Thank you!
what was he talking about at 7:47 couldnt red it
He was talking about recoil m8
At the start you say that momentum is always conserved but then when you talk about the car accident you say that after the accident momentum goes down to zero. Im confused. Can someone please explain
Cuz momentum is mass x velocity, a moving object would stop after hitting something applying force to the opposite direction of the moving object , that cancels out the velocity , therefore the the momentum which is mass x velocity would be zero since velocity will be = to zero.Hope it help.
great video thanks
How will we get to know if the colision is elastic or inelastic
GREAT HELP! THANKS!!
mass of the gun, mg - proceeds to chuckle xD
Sir what is the effect of different masses of objects on momentum and kinetic energy?
how do yo find momentum when they expect you to use vertical and horizontal component
how can impulse AND momentum both be the area under the graph f=i/t
thank you
Because in essence impulse IS momentum. Same units too. Impulse is only the CHANGE in momentum
Thank you so much for this lit video you definitely will get to heaven with this much love
Thank You so muchhhhh
8:50 how can you get negative velocity?
Velocity is a vector so needs direction . As it is going the opposite direction it is negative.
Thanks
Thanks, the last part was especially useful because those water pipes and density questions comes up quite a bit in AQA
alevel right? not GC right?
@@hlomphoprincess3573 yeah not gcse
Great video
Is this edexcel phy?
How did you get 3.29 from 140? 7:16
Because you add the two momenta (300+160=460) and divide by 140.
460/140=3.285...=3.29m/s (2dp)
In the example of a boy and bullet (which you discussed) can we say that "total momentum of boy and bullet after collision is 0." OR is it that total momentum of bullet and gun is zero?
please reply.
thankyou
You would say: the total momentum of everything in the system is zero". In other words, the total momentum of the gun, boy and bullet is zero.
Ok thanks a lot
No problem
Hi Sir, when you were answering the water equation, you used rho as density however I thought rho was resistivity? Is rho used for both or have I made a mistake?
Thanks a lot for these great videos!
it is used for both
1. coupling
2.??
I can't see pls
what is the name for 2?
recoil
What about if particle hits a wall at an angle? would I have to find the horizontal component of that particle? Great video btw
Yep! Vertical momentum doesn't change, only horizontal component.
thanks :)
Sir it helped a lot but i didnt get that u didnt explaind inelastic colliaion
the video is helpful thx
life saver
it would be great if you demonstrate us practically, which would send us further the bullet or train... hehe
btw 1 tonne is 1x10*3 kg ;)
he used 10 tonnes
I was thinking why it gives vintage vibes... Its 7 years old!
The quality of the video is not not
NOOT NOOT
NOOT NOOT
Thank you a lot！
that woman at 5:10 is kinda creep me out honestly
Rockets ... change in mass and change in velocity at the same time
I know you have played or atleast watched snooker before.
The graph was a bit confusing
Some times the question asks about average force that makes me confussed..
Just change in momentum divide by time taken by N2L
am i the only one who's ocd was triggered when he used(0!) 0 factorial (which is actually 1) in place of 0
🙄
That's not ocd
Thumbs up :-)
my brain farted at the last 5 minutes of the video
3:20 your welcome
Legitimately my handwriting.....
wii
Big P and small p
Ive heard this voice somewhere
headspace? its quite similar i heard
yyyyaaas