Howdy All! Some corrections for you! Vo = -3V is correct, however when we calculated i_3, we forgot our negative sign! i_3 = -0.12mA is the correct answer, meaning that our answer for io is: io = i_2-i_3 = 0.075mA - (-0.12mA) = 0.195mA (into the OpAmp) Sorry for the sign error! ~Andrew
There is a mistake at the end of your calculations. You forgot the negative sign on i3 which would have made i2 positive meaning that there was current entering the op amp from the output side. Please add an annotation or add it to the description to clarify.
The formula that you used to calculate the output voltage(Vout) which is 0v+3v+Vout=0 is incorrect, the right one is 0v-3v-Vout=0. Try it, you won't get stuck again. Everything else is superb. Thank you.
Just a general question here, what purpose does the 25k Ohm resistor from the amplifier's output to ground serve? I've seen circuits that have similar and the purpose escapes me. Thank you.
That represents the resistance of whatever the circuit is driving. IRL it could be a simple resistance like a light bulb or a complex impedance of a speaker.
How to calculate the currents easily, just apply the the Kirchhoff's rule of knots: i2 + i0 + i3 = 0 // i2 flows into the knot, so it's positive, i0 and i3 flows out of the knot, so they are negative 0.075mA +(-0.12mA)+(-i3)=0 // convert to i3 i3 = 0.075mA-0.12mA *i3 = - 0.045mA*
Howdy All! Some corrections for you!
Vo = -3V is correct, however when we calculated i_3, we forgot our negative sign!
i_3 = -0.12mA is the correct answer, meaning that our answer for io is:
io = i_2-i_3 = 0.075mA - (-0.12mA) = 0.195mA (into the OpAmp)
Sorry for the sign error!
~Andrew
Some are still incorrect
bro u realized after 6 years mannnnn
There is a mistake at the end of your calculations. You forgot the negative sign on i3 which would have made i2 positive meaning that there was current entering the op amp from the output side. Please add an annotation or add it to the description to clarify.
i3 doesn't have a negative
@@joanitarzzalwango6392 I think it does
Io is wrong since Vo =-3v if you KCL on that node it must be 75uA=Io+((-3-0)/25K) = Io-120uA then Io = 195uA
loudest intro i have ever heard
The formula that you used to calculate the output voltage(Vout) which is 0v+3v+Vout=0 is incorrect, the right one is 0v-3v-Vout=0. Try it, you won't get stuck again.
Everything else is superb. Thank you.
Sorry, this video should have been redone. It's confusing and has errors.
Passive sign convention!
Good illustration...transparency
Thank you white man. Very helpful
why -3V/25K=0.12mA???? I think it is opposite
Thanks that was very helpful!
Great video, very educational
there is a mistake. i3 is minus 0.12 and i0 is 0.195 mA
Shouldn’t Vo= 3V instead of -3V
Plz suggest me a book for critical problem on op amp
Just a general question here, what purpose does the 25k Ohm resistor from the amplifier's output to ground serve? I've seen circuits that have similar and the purpose escapes me. Thank you.
That represents the resistance of whatever the circuit is driving. IRL it could be a simple resistance like a light bulb or a complex impedance of a speaker.
I don’t understand why it is not -0.12mA…. Didn’t see the correction. Oops
Very helpful thank you
The negative on vo is not there supposed to be there
Volume warning: the first 5 seconds or so are super loud 🔊🔊🔊
bro the sounds from writing on that glass board or whatever makes me feel weird💀
Would you be able to help me solve a problem?
shouldn't V2 be negative?
please correction require Io = I3 +I2
I have a question to ask how will I asked it it's a
perfectly lecture !
Cool video
What is it your are writting on? What's the name of that device?
I believe its called a glass pane :3
wow excelent video....
The intro music is so loud
Thank you.
Merci beaucoup
Lmao we lost about 5 minutes because of dancing with your intro.
Vo is 3v not -3v
Thanks bro.
❤❤
Please can you tell me why "0V+ V40Kohm+V0=0" ?
Aybüke Gökmen KVL
Thank you very much
very helpful. you look like a very nice guy i want you hug you brother
Pen sound 😢
why the dislikes lol
hello friends...chai peelo
How to calculate the currents easily, just apply the the Kirchhoff's rule of knots:
i2 + i0 + i3 = 0 // i2 flows into the knot, so it's positive, i0 and i3 flows out of the knot, so they are negative
0.075mA +(-0.12mA)+(-i3)=0 // convert to i3
i3 = 0.075mA-0.12mA
*i3 = - 0.045mA*
its a good video I just don't like the fact that I have to see his face through the calculations. :/
We happen to think Adam has a wonderful face and makes the calculations even better!
That’s so rude. Your mother should be ashamed.