Aree You On The Paaath To Ultimate Life Success? twitter.com/3b71570548a9d6abe/status/804630629388152832 Solving for Peeeerceent Abundance with Isotopes Chemistry Sample Problem
@@ikilledyourgin281 It came after the distribution part. When he combined like terms. Adding the x terms together and then, getting the x term by itself by either adding or subtracting the numerical term from both sides. Then it is just simply division to solve for x. Hope this helped.
Bit late but he was just explaining the whole concept in an extremely simplified version just to help everyone understand what we're doing algebraically
Arooj Shahid 100-78.99=21.01 // we know a percentage of one of the isotopes.. so logically since it's out of 100% the result of subtracting 78.99 from 100 will be the percentage of both two isotopes (x+y=21.01)
I can't seem to get the right answer, can you help me? Problem #3a: A sample of naturally occurring silicon consists Si-28 (amu = 27.9769), Si-29 (amu = 28.9765) and Si-30 (amu = 29.9738). If the atomic mass of silicon is 28.0855 and the natural abundance of Si-29 is 4.67%, what are the natural abundances of Si-28 and Si-30?
Absolutely terrible video. You do a sub-par job at explaining the specific of the equations, and I am left more confused at the end than I was at the start. This video was posted by one of my teachers as a resource, and I am disappointed in the quality of the material.
THANK U SO MUCH ISA KANG MALAKING TULONG SA NGA ESTUDYANTENG NASA BINGIT NA NG KAMATAYAN DAHEL SA CHEMISTRY :)
Thanks a lot, this is exactly what I needed.
Aree You On The Paaath To Ultimate Life Success? twitter.com/3b71570548a9d6abe/status/804630629388152832 Solving for Peeeerceent Abundance with Isotopes Chemistry Sample Problem
From South Africa 🇿🇦 this video really helped me understand the concept of isotopes and reletive aomic masses
teacher said id pass if i could answer question like this. Thanks saved my life lol
where did you get the 0.09978?
Amazing video, exactly what I needed for my chemistry homework problem. Thank u sm
literally, saved my life!! Thank you so much!
Thank you so much, this is clear & concise, exactly what I was looking for
Thanks so much for this, just what I was looking for.
man saved my grade THANK YOU
Thanks for the help! Finally understand this concept.
Huhu i dont understand were u get 21.01
How do you obtain those numbers from combining like terms?
you probably don't need this anymore, but he added the terms that didn't have an x, and subtracted them from both sides
@@HTXLemarc thank you
Can you explain to me 0.09978=0.998x? What did you do to get this?
because he rounded up
@@HotPie4Breakfst rounded up what??
@@ikilledyourgin281 It came after the distribution part. When he combined like terms. Adding the x terms together and then, getting the x term by itself by either adding or subtracting the numerical term from both sides. Then it is just simply division to solve for x. Hope this helped.
yo this was mad clutch yo
Thanks I don't think we see this in grade 11 but I wanted to make sure
i am grd 11 student and we are using this right now
Thank you...that helped a lot😊
Is it possible to calculate it without any percentage given?
Super helpful, thanks! :D
where did you get the 21.01%?
100% - 78.99% = 21.01%
Great video
where does 5 5 5 and 1 come from
Bit late but he was just explaining the whole concept in an extremely simplified version just to help everyone understand what we're doing algebraically
Thanks a lot!
Sorry but where did you get the "0.09978" ??
this was at 5:37
@@christen-leebezuidenhout Did you figure this out? Pretty sure he did it wrong. I got x= 14.5% and y=6.5%
Thank you so much
THANK YOU!!
thank you☺
maybe stick to a decimal if 5 decimals then 5 decimals if 3 decimals then 3 decimals no?
Thanks a lot
saved my grade
Thanks!
where did this 21.01% come from?
Arooj Shahid 100-78.99=21.01 // we know a percentage of one of the isotopes.. so logically since it's out of 100% the result of subtracting 78.99 from 100 will be the percentage of both two isotopes (x+y=21.01)
saada ks why was I’m not thinking that thanks
I can't seem to get the right answer, can you help me?
Problem #3a: A sample of naturally occurring silicon consists Si-28 (amu = 27.9769), Si-29 (amu = 28.9765) and Si-30 (amu = 29.9738). If the atomic mass of silicon is 28.0855 and the natural abundance of Si-29 is 4.67%, what are the natural abundances of Si-28 and Si-30?
Mario Nyah the result will be: Si-28= 92.23% // Si-30= 3.1%
My Prof used this EXACT problem on the final. She must of copied it from this youtube video
🙏 Thanks a lot
thanks
8 years late but, thanks
thankx a lottt
BEST
Can you make it clear? Sorry to say this, you didn't clearly show how you solve the problem.
Absolutely terrible video. You do a sub-par job at explaining the specific of the equations, and I am left more confused at the end than I was at the start. This video was posted by one of my teachers as a resource, and I am disappointed in the quality of the material.
You made more confused. The numbers are too big and confusing
ily
This was not helpful at all
Thanks so much!
thanks