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Rafeeq Engineering Drawing
India
Приєднався 31 січ 2021
Hi friends
I am Mohd Rafeeq Ur Rahman,
Assistant Professor of Mechanical Engineering.
For tuition contact: rafeeqrahman48@gmail.com
Graduated from Muffakham Jah College of Engineering and Technology Hyderabad.
I am here to make you learn Engineering Drawing / Engineering Graphics in an easier way. If you like the way how I am explaining please share knowledge with your friends by sharing my videos.
Don't forget to Subscribe to my channel "Rafeeq Engineering Drawing"
I am Mohd Rafeeq Ur Rahman,
Assistant Professor of Mechanical Engineering.
For tuition contact: rafeeqrahman48@gmail.com
Graduated from Muffakham Jah College of Engineering and Technology Hyderabad.
I am here to make you learn Engineering Drawing / Engineering Graphics in an easier way. If you like the way how I am explaining please share knowledge with your friends by sharing my videos.
Don't forget to Subscribe to my channel "Rafeeq Engineering Drawing"
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You have saved me this was assignment given to me
You have saved me this was my course work
👍👍👍
Bhai very grear explanation... it was Crystal clear.
Thanks alot bhai
Thanks so much
You're welcome!
Isko pad kar to me sem beg le lunga 😢
Bse on the hp means we should draw into vp
Base on HP means front view on VP you have draw
Yes
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First angle projection are third angle projection?
First Angle Projection
Masha allah......very good explanation❤
Thank you 😊
Nice bro 👍
Thanks for the visit
thank uh very much sir🙏🙏
Most welcome
thank uh so much sir😇🙏
Sir u told that we will take 60° but u took 30°
It's 60⁰ with the horizontal or xy reference line.
Thank you sir 😁 4:58
Thank you so much sir, i was finding this question from such a long time
Why are you telling so fast
To avoid lengthy videos
I have watched this video for 45 minutes to understand that
Sir plz explain in kannada full exercise
Sorry i don't know kannada language
Thanks Bro 👍
Welcome 👍
Inclined sectional plane?
Not visible sir..
Ok thanks for informing. I will change camera settings.
. A right circular cone, diameter of base 56 mm and height 65 mm, rests on its base on HP. A section. plane perpendicular to VP and inclined to HP at 45°, cuts the cone meeting its axis at a distance of 36 mm from its base. Draw its front view, sectional top view and true shape of the section.
Sir mara kal exam haai apka no. Milsaktha hai kya free hai toh question send karthu answer bajtha kya sir plzz
Ok. Contact me on my email id.
Sir you have taken only 30 degree angle not 60 degree why do you take like that in question given 60 only na sir
I have taken 60 degree from the horizontal.
Noo I can't understand sir you have take from 55 mm above hp sir
A hexagonal prism ,having a base with a 30mm side and a 70mm long axis,has its face on the h.p. and the axis parallel to v.p. it is cut by a plane ,which is perpendicular to vp and makes an angle of 450 with the hp bisecting the axis.draw the sectional front view and true shape of the section
Sir haching line paralll to 45 degree chahi na
Yes its 45 degree from reference line. You can also take 30, 45, 60 or 135 degree.
Lhai
Sir where to locate the axis of the triangular prism in the the triangular face
Find the center of triangle on both trianglular faces of prism and join them with thin chain line.
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Every questions of engineering graphics is their in ur chanel ?????
Variety of models I have tried to cover. Every question of engineering graphics is not possible to solve.
Sir apne 30 degree lekar ke projection kyo nahi banaya , aur apne baad pe without measuring 30 degree bola , vo sahi nahi lag raha . Baki apka solution sahi hai
30 degree is marked alredy may be thin line is not visible clearly in the video.
Entire drawing measurement lekar hi kiya h
@@RafeeqEngineeringDrawing thank you sir for your reply. But how do I contact you. I have many doubts in ED please help me .
I only came here to find how to find the centre point that you have to measure it instead of vertically rulling down
Measuring may workout in this problem but for other problems it won't work. That's why I am following standrad steps and procedure so that other similar problems also you can easily solve.
Thanks sir ❤❤
Thank you sir . Amezing teaching skill.
You are most welcome
Jazak allah khair❤❤❤❤❤
Please share and support my channel
Draughtsman civil k skill test ki bta do sir kuch
Sorry that's not my field.
Hello Sir! Thanks for sharing this awesome video. Is there any way of finding point lying between b and c accurately (without approximation)
Yes it is by measurements
Love from Bangladesh
I'm
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👍
Liked the way of your explanation 😊
Thanks a lot 😊
Where is the end projection on the orthographic drawing
Orthographic drawings show in the video is a question. I have solved and answer is isometric drawing. End projector is not required
Am looking for exercise 1
Please check playlist
TCFL 1:1s here ? 😂😂
Awesome❤
Thank you
Nice video😊
Thanks 😊
well explained