I'm a Mechanical engineering student and currently taking Dynamics as one of the courses in my uni. Your video is easy to understand especially with the detailed explanation with the chain rule method. I totally get it now. Thank you, Dr Faysal.
that is good and do it this question. 1.the x-coordinate of a particle in curvilinear motion is given by x=2t^3-3t, where x is in feet and t is in seconds. the y-component of acceleration in feet per second squared is given by ay=4t. if the particle has y-components y=0 and y'=4 ft/sec when t=0 find magnitudes of the velocity v and acceleration a when t=2sec. sketch the path for the first 2 seconds of motion, and show the velocity and acceleration vectors for t=2sec.
I'm a Mechanical engineering student and currently taking Dynamics as one of the courses in my uni. Your video is easy to understand especially with the detailed explanation with the chain rule method. I totally get it now. Thank you, Dr Faysal.
that is good and do it this question. 1.the x-coordinate of a particle in curvilinear motion is given by x=2t^3-3t, where x is in feet and t is in seconds. the y-component of acceleration in feet per second squared is given by ay=4t. if the particle has y-components y=0 and y'=4 ft/sec when t=0 find magnitudes of the velocity v and acceleration a when t=2sec. sketch the path for the first 2 seconds of motion, and show the velocity and acceleration vectors for t=2sec.
You're a life saver. Thank you.
thank you for the nice example sir
Very informative sirrr
Hello Dr. Faysal Fayez Eliyan
Thank you for your nice explained videos. Do you have the lecture materials that explain the theory behind the maths.
why is there so much background noise, otherwise great video
I don't understand why dy/dt = dy/dx * dx/dt at the 7:30 mark
Chain rule
should use ft
I agree