Aromatic Side Chain Oxidation to Carboxylic Acid
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- Опубліковано 3 жов 2024
- Leah4sci.com/redox presents: Aromatic Side Chain Oxidation to Carboxylic Acid
Need help with Orgo? Download my free guide ’10 Secrets to Acing Organic Chemistry’ HERE: leah4sci.com/or...
This video walks you through the aromatic side chain oxidation reaction where any alkyl chain attached to benzene is oxidized to a carboxylic acid. Learn the patterns, recognize what to look out for, and work through practice questions together.
In this video:
[0:15] Introduction to oxidation
[1:30] Molecules not susceptible to oxidation
[2:57] Oxidizing a benzene ring
[4:44] How to oxidize a double ring
This is Redox Video #11. Catch the entire Orgo Oxidation Reduction Video Series Along with the Redox Practice Quiz and Cheat Sheet on my website at leah4sci.com/redox
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That last example was a gift brought down from heaven during my time of need
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Got to say...your videos really help.IIT-JEE is a very difficult examination here in India which gives us admission to higher tier colleges.Cheers and keep up the good work.Hope you reach 100k soon though:)
wow! that's great! You're welcome and glad to help!
I wanted to understand the reaction that gives us COOH but I guess we don't really need to, thanks for the clear explanation Professor!
Glad it was helpful! You're welcome.
a huge shout-out to you! the best video explaining this topic in an easy way! Thanks a lot!
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This video explains EVERYTHING so well. thanks so much
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I am from Iraq, and I would like to thank you for your beautiful explanation. My exam is tomorrow and I am grateful that you saved my life.🤣😂🩷 (I apologize if there are errors in writing the sentence, I use Google Translate )@@Leah4sci
Thank you ... It helps me to understand this reaction much better than before.
Thanks a lot for your help.
Glad it helped! You're welcome!
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thank you so much! may God always bless you........ your lessons are always straight to the point and much understandable.
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Thank you for the video 😊💕 it really helps a lot especially that you have explained it well. 💞
You're welcome 😊 Glad it was helpful!
I needed mechanism with cro3, but it also helped me
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~ India
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Wow you explained this so easily thank you !!!!
Glad to help!
You're a life saver! Thank you! But where can I find the reduction of alkyl side chains video (if there's one)?
I'm not quite sure which reaction you're referring to. This video is showing reduction of alkyl side chains on an aromatic ring. To watch my full series on Redox Reactions, make sure to visit Leah4sci.com/Redox
For even more on this topic and other organic reactions, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
This is great content. Thank you for the time and effort!
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Fan of u from india loved the video tqs a load
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@@Leah4sci I would like to see more such videos! Keep up the good work!
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Nice explanation
Thanks!
I guess its very long since this video wasade but I was wondering, is this oxidation classified as an example of subsitution in the benzene ring?
Nice clear and concise video btw!
Even though it appears to create a new group on the ring, I would not classify this as a substitution reaction, as it does not follow the traditional mechanism for an electrophilic or nucleophilic aromatic substitution.
For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
Thank you mam love from India❤
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Thanks a lot , you are indeed a life saver
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Can you also upload a mechanism for that ?
Thanks for the clarification.
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Thanks for clarifying my doubt
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Always glad to save a life ;)
I liked ur Explaination
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Really helpful
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That was a good little vid. Understood this concept quick! ...we'll see if it sticks haha
FIngers crossed (after I finish typing) that it does!
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In the last question, there were 3 carbons, why did we oxidise only 2 of them? Due to steric hindrance or what? Good video tho! Keep It up!
And will it make hydrogen bonding in the last question?
There were only two benzylic carbons, directly substituted on to the benzene ring. Only those two carbons are oxidized to carboxylic acids (because of the high reactivity of their benzylic protons), and the third carbon that joined them together is cleaved in the process.
And yes, carboxylic acid groups are great at participating in hydrogen bonding interactions.
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what happens to the molecule that gets cut off? would it be the second product of the reaction? if not, where does it go to?
Yes, it would be a side product in solution (Unless CO2 then it bubbles out as gas). Most professors focus on just the ring but if you have to show a complete reaction, make sure to account for the side product as well
Thanks for the upload 🤘🏾
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helped me alot ... thank you
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Thanku you clear my doubt😊
Glad to help!
Miss I have one doubt, what if the carbon has no benzylic H but has triple bond ? Will it form benzoic acid?
If you have a question about the example in this video, I'd be glad to answer. However, since I don't offer tutoring over social media, for help with questions like this and more, I recommend joining the organic chemistry study hall.
Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
Plz make a video explaining oxidation and reduction in Nitrogen groups in organic chemistry☺☺ sister....
The free videos are what I do as I have time. For more help with this topic, feel free to contact me through my website: leah4sci.com/contact
Thanks of giving this knowledge but I want know exact mechanism involved in oxidation of kmno4 with alkylbenzene ..
You're very welcome. I'm sorry, but I don't offer tutoring over UA-cam comments. For help with this and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join
Thank you so much ❤‼️
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Mam, please make a vedio on selective oxidation and selective reduction
I have one like it in the LiAlH4 vs NaBH4 video
excellent
Thanks!
thanks
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i am BEGGING for anyone on the internet to actually write out the mechanism! this is infuriating! everyone skips over it
I'm so sorry. For in-depth help with questions like this and more, I always recommend joining my organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
Nice and helpful...
Glad you liked it
Love from India😍
Thanks!
so my question is , is there colour change in the case of KMnO4
This video doesn't address that particular question. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
I’d like to ask you, 0:55 Is it Methyl benzene? Then we make [O] under special condition to give banzoic acid,
Is this correct ?
Yes, that is correct. The specific reaction you are referencing is the oxidation of methyl benzene (common name: toluene) to make benzoic acid.
For oxidation of benzyl acholol by kmno4 also the same mechanism?
Yes, it would produce the exact same product as seen here in this video.
What if it has alcohols after the benzylic H
Usually, we see this reaction happen when there is strictly an alkyl chain attached to a benzene ring. Meaning, a branched or unbranched carbon chain with a benzylic hydrogen. For further questions, feel free to follow up with me through my website at Leah4sci.com/contact
ty
You're welcome!
Will it work the same with h2cro4?
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
Kmno4 is acidified or alkaline?
For which reaction exactly? Please email me at contact@leah4sci.com with your question and a time stamp.
all examples were not covered
Which example ,specifically, are you referring to?
Why in products I have benzoic acid rather than c6h5cook??
I don't know which exact reaction you're referencing in this video. But I understand the question. Technically, a second step of an acid workup is required to convert the benzoate to benzoic acid. Which form of the molecule predominates is largely dependent on the pH of the final solution.
@@Leah4sci thank you so much for answer ♥️ yeah my question wasn't strictly about reaction in this video.I asked because i had in my textbook reaction : ethylbenzene+ KMnO4 ---> MnO2 +KOH + CO2 +C6H5COOH
For me is should be rather ---> MnO2 +K2CO3+KOH + H2O + C6H5COOK
And that's why i started looking for video which maybe explain this situation more
Good
Thanks
@@Leah4sci thank you very much mam for guidance
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Thanks
Two weeks lectures in 5 minutes!!!!
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oh wow! Glad to help!
I want to know the mechanism because without it I will fell empty on concept.
I don't have any videos covering the mechanism. most professors do not require you to know it
Love ❤️ from India
12th science student give me your best wishes to pass me in 12 with 80%
Inshallah 👍
Best wishes, happy my videos are helping you!
@@Leah4sci Thank you ❤️
Anyone else using this to help with hydroxylation of mitragynine?? 😁
I'm unsure. For help with topics like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
Thanks alot! اسال الله ان يهديك يا اختي
You're welcome!
What happens to the cut off groups?
Side products
@@Leah4sci Yeah... he asked what happens to them?
Love u mam
Thanks!
🙏🏼🙏🏼 🇮🇳 thanks mam
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