IUPAC Nomenclature 12 || Naming Of Bicyclo and Spiro Compound || For Competetive Exams
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- Опубліковано 17 гру 2024
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11 chap 12 || IUPAC Nomenclature 01 || Some Basic Principles and Naming Of Alkanes JEE MAINS/NEET
• 11 chap 12 || IUPAC N...
11 chap 12 || IUPAC Nomenclature 02 || Complex Substituents and cYcLo Alkanes JEE MAINS/NEET
• 11 chap 12 || IUPAC N...
11 chap 12 || IUPAC Nomenclature 03|| Naming Of Alkens and Alkynes JEE MAINS/NEET
• 11 chap 12 || IUPAC N...
11 chap 12 || IUPAC Nomenclature 04 || Functional Groups with Secondary Suffix JEE MAINS/NEET
• 11 chap 12 || IUPAC N...
11 chap 12 || IUPAC Nomenclature 05 || Naming Of Alcohols JEE MAINS/NEET
• 11 chap 12 || IUPAC N...
11 chap 12 || IUPAC Nomenclature 06 || Naming Of Aldehyde and Ketone JEE MAINS/NEET
• 11 chap 12 || IUPAC N...
11 chap 12 || IUPAC Nomenclature 07 || Naming of Carboxlic acid and Aid Halide IIT JEE MAINS /NEET
• 11 chap 12 || IUPAC No...
11 chap 12 || IUPAC Nomenclature 08 || Naming Of Acid Amide and Ester IIT JEE MAINS / NEET ||
• 11 chap 12 || IUPAC No...
11 chap 12 || IUPAC Nomenclature 09 || Naming of Cyanides , Amines and Ethers IIT JEE MAINS /NEET
• 11 chap 12 || IUPAC No...
IUPAC Nomenclature 10 | Naming of Polyfunctional Compound | MOre than One Functional Group JEE /NEET
• IUPAC Nomenclature 10 ...
11 chap 12 || IUPAC 11 || Naming Of Aromatic Compounds - BeNZeNe Rings IIT JEE MAINS /NEET |
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6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
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The test series follows very logical sequence of Basic to Advance questions.&
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11 chap 12 || IUPAC Nomenclature 01 || Some Basic Principles and Naming Of Alkanes JEE MAINS/NEET
ua-cam.com/video/ZgccHLOj3W4/v-deo.html
11 chap 12 || IUPAC Nomenclature 02 || Complex Substituents and cYcLo Alkanes JEE MAINS/NEET
ua-cam.com/video/R2RvDt6NWlo/v-deo.html
11 chap 12 || IUPAC Nomenclature 03|| Naming Of Alkens and Alkynes JEE MAINS/NEET
ua-cam.com/video/VUoEdUgvGNo/v-deo.html
11 chap 12 || IUPAC Nomenclature 04 || Functional Groups with Secondary Suffix JEE MAINS/NEET
ua-cam.com/video/pWtpwjj7ZdY/v-deo.html
11 chap 12 || IUPAC Nomenclature 05 || Naming Of Alcohols JEE MAINS/NEET
ua-cam.com/video/3nvTs9lkhag/v-deo.html
11 chap 12 || IUPAC Nomenclature 06 || Naming Of Aldehyde and Ketone JEE MAINS/NEET
ua-cam.com/video/wIkiE0PE8bE/v-deo.html
11 chap 12 || IUPAC Nomenclature 07 || Naming of Carboxlic acid and Aid Halide IIT JEE MAINS /NEET
ua-cam.com/video/OPdpILw2db0/v-deo.html
11 chap 12 || IUPAC Nomenclature 08 || Naming Of Acid Amide and Ester IIT JEE MAINS / NEET ||
ua-cam.com/video/8aQ9TL68BeU/v-deo.html
11 chap 12 || IUPAC Nomenclature 09 || Naming of Cyanides , Amines and Ethers IIT JEE MAINS /NEET
ua-cam.com/video/wmCl7By2wfk/v-deo.html
IUPAC Nomenclature 10 | Naming of Polyfunctional Compound | MOre than One Functional Group JEE /NEET
ua-cam.com/video/RN7_Q38RePk/v-deo.html
11 chap 12 || IUPAC 11 || Naming Of Aromatic Compounds - BeNZeNe Rings IIT JEE MAINS /NEET |
ua-cam.com/video/5qE2KJS1C4U/v-deo.html
IUPAC Nomenclature 12 || Naming Of Bicyclo and Spiro Compound || For Competetive Exams
ua-cam.com/video/zZAJsddI8os/v-deo.html
Sir Ur vedio is very helpful...Mjh pehlu smjh ni araha tha pr ab aagya...Bs Ek Chezz Puchni he apse...K ..Jb Hm Longst se smalest chain Ki trf ja rahe hte jen Jese Apne Example B de Jsme Functnal Grp OH he or sbstituent Bromine he...To Is me Smal numbrng ks ko deni he...Fnctnal Grp ko Keh Sbstituent ko?R likhte kse hen Substitunt ko ya Fnctnal Grp ko?
Ya Phr jsko B Aajye Smal no koi msla ni Substitute ko k Fnctnal Grp ko?Bs ye rule folow krna he..Largest se smalest pr ana he...Cahcje Ksi ko b Sbstutnt ya f.grp ksi ko b smlest numbr ajaye
Sir...Last example Me B To Cooh Or Oh dono fnctnal Grp hen ...To is me Cooh ko Kam Numbrng ari he or Oh Ko Zyada halan k Dono Chain equal hen
Obgog
only one request why u put ur channel name physics vala.....
Who is here after watching the whole 12 video series....
concept is crystal clear..!!
Is 12th series enough jor jee mains?
@@vishnujaju5039 Haan Bhai...par iske baad Apne coaching Ka material bhi padhna aur questions solve Karna jee level k
Completed just now...✌🏻. #crystal_clear
@Ashish Singh wow well done bro but i am stuggling for the completiotion of the syllabus.....but i am sure latest by december i will do it ........let's hope 4 the best...best of luck 4 jee 2021
Yes concept clear
Kindly Poll for next chapter in physics and Chemistry starting 21st November. Poll going in community tab of our channel
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Physics Wallah - Alakh Pandey shm
can anyone tell me how to poll
@@harshkumar3489 search for sirs channel Physicswallah and then open community tab above...u can find it there...
Heat and thermodynamics sir
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid (answer of bicyclo compound)
Harjinder Singh bro oxo will come na for ketone as suffix.. formyl is for aldehyde i think.
It will be : 10-bromo-5-vyano-11-ethyl-6-oxo-bicyclo[7.2.0]undecane-4-carboxylic acid.
Am I ryt??
@@omkarrane9696 CHO is aldehyde and that carbon in CHO is not counted so it's name is formyl
@@omkarrane9696 no bro jab count nhi karte to formyl kehte hai
@@omkarrane9696 it is not ketone it is aldehyde CHO
To all present and future viewers:
Remember that "keto" is now replaced by "oxo" by IUPAC. In some cases, while giving alphabetical priority, this makes a difference.
Right 💯💯👍😌
can you explain it
thanks dude✨
When keto carbon is not counted, it is termed as oxo.
thanks😊
Hw1.
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid.
Hw2.
9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide
Correct dost
Same same
@@AnuragSingh-zc7wt great
I looking for this
@@rahulkhatkar3163 what
At 17:45 sir there will be bicyclo [3.2.1]oct-6-ene-3-carbonitrile.
22:20 the answer of the Christmas tree is 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4- carboxylic acid
Correct me , if I am wrong !! 🤔🤔🤔
Bahut hard bro ..shi h
Bahut hard...shi h..mera v yehi h
Right bro...
Correct ..mera v yhi answer hai
Sahi hai bhai.... You are topper😊
It's 2023, but these videos of yours are still grabbing all the views. Thank you so much sir for such an amazing content of Organic Chemistry. Hats off to your hard work and patience :)
Yeah paaa ji
Bahut bahut sukriya
Hey are you in 11th ?
@@alakhpandey7470 tu coun be
Sir some lines for you
"Aapse seekha hai maine behisaab se zyada,
Kisi Thokar kisi vyakhyan(lecture) kisi kitaab se zyada.
.
Jo baitha lagane aapke gyan ka andaaza,
Nikla har nadi, Har samandar har talaab se zyada.
.
Agar gyan hi sabse azeez jaydaad hai to,
Aap ameer ho har seth,har vyapari har nawab se zyada.
.
Ye kuch lafz kahne the kabse, aaj kah diye,
Suna hai lafzo se khushi milti hai kisi khitaab se zyada.”
Osm yrrr .....😍😍😍
bhai sahi khel gya..nice lines
Very nice beautiful
Kuch dino se dekh Raha hoon main..... Kuch dino se dekh Raha hoon main..... Tum UA-cam par time bita rahe ho kitaabon se ZYAADA😂😂😂
@@ShubhamSharma-uu9yn maja nhi aaya bhai bekar shayari h teri😊😊
34:10 Hw
9-Ethyl-6-formyl Spiro[4.5]dec-3-ene-1-carboxamide
Right
👍
1 amido 9 ethyl spiro [4,5] dec 3-ene-6-carboaldehyde
Bhai ethyl ko chota no milna chahiye due to alphabetical preference
@@God..MAHI..7pehle first point of difference ke accordingly numbering karni hoti hai.
Alphabetically numbering Krna last option hai
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo (7.2.0)undecane-4-carboxylic Acid.........love you alakh sir...❤️❤️❤️❤️❤️❤️
👏🏼👏🏼
Great bro
mera bhi yahi aaya
Pls answer this so confused
21:21 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
Students after watching all lecture of Alakh sir organic chemistry
School Teacher - what is IUPAC
Le students - Halwa
😅
😂😂
🤣🙌
Then "Patt Se HeadShot"
🤣🤣
@@manishkr.shakya6826 bhot sahi
completed watching all the 12 videos in the list. Honestly, it helped so muchhh. Ab lag rha h ki organic aane lagi h nd it's all bcoz of u Sir!🙏❤️
same here 😂👍
same pichhh...........
Same same😊
Same with me...
Hii
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid (answer of bicyclo compound)
Loved the whole series sir!!
Bhai C tripal bond N ko sir ne example 3 mei carbonitrile likha hai aur tumne 5-cyano
Mujhe yehi clear nhi hai 🙄😕☹️
Yaha Carbonitrile likhu ya 5-cyano 😕😕😕😕
@@thakurraj9119 are bhai ! o sir likhe hai us jagah pr jab C triple bond N "F.G." rahe lekin is compound me to carboxylic acid functional group hai isliye ye sirf ek substituent hai
ᗷᕼIᗩ ᗯᗩᕼᗩ ᑭᗩ ᗯO ᖴ G Tᕼᗩ Yᗩᕼᗩ Yᗩ SᑌᗷSTITᑌEᑎT ᕼIᗩ
@@thakurraj9119 BHAI CARBON COUNT KIA TOH CARBONITRILE CRBON COUNT NAHU KIYA TOH CYANO
King of organic chemistry is the physics wallah.
And also king of physics.
@@NishaSingh-px1bz from which region u r?
@@muskangoswami9711 I am from Bihar but now I live in Indore. And your name
I m also from that region
Now i m in gujarat ..
10 bromo 5 cyano 11ethyl 6 formyl bicyclo(7.2.0) undecane 4 carboxylic acid
🤜🤜🤜🤜
9 ethyl 6 formyl Spiro(4.5) Dec 3 ene 1 carboxamide
🤜🤜🤜
Correct answer 👍
5-cyano nhi ....carbonitrile hoga
@@shreysharma726 Not really bro ! Carbonitrile is used when Cyanide is a PFG(Primary functional group )here Cyanide is just a substituent and as a substituent it takes cyano not carbonitrile .Here PFG is COOH
(Carboxylic acid)
@@AjCreations1 bhai ...first of all ...I'm a boy ...not a babe 😂.....and secondly ...yeah you are right ...it should be cyano ...
@@shreysharma726 Autocorrect bro my keyboard is addicted of using babe 😂 so its just turn into something it should not be 😀
Alakh sirs smile is a magic,which tells us how much he is dedicated to his work
H.W 33:33
9-ethyl -6-formyl Spiro[4.5] dec-3-ene-1-carboxamide
22:20 Bicyclo homework
10-Bromo-5-cyano-11-ethyl-6-formylbicyclo[7.2.0]undecane-4-carboxylic acid
Correct
Correct
Why undecane?
@@manojkumarchaubey3133 Because 11 carbon compounds 😅
Ethanyl
Xmas tree
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo(7.2.0) undecane-4-carboxylic acid
Ya i got same
Same...
I am agree
Same
i got same too
Finally IUPAC completed 🥳
Thank you sir❤️
10-Bromo-5-cyano-11-ethyl-6-formyl Bicyclo(7.2.0)undecane-4-carboxylic acid
Sahi hai
Ryt👍
Yes mine matching too
Sirf ek bande ne answer likha 4 lakh logo me se😅😅
V good
10-Bromo-5-cyano-11-ethyl-6-
formal bicyclo (7.2.0) undecane-4-carboxylic acid
😊😊
34:08 9 ethyl-6 formyl spiro [4.5] dec-3-ene-1-carboxamide
Yes
💯🤜
@@harshitmohan1760 because here CHO is a substitute not functional group.... If it was functional group then we use carbaldehyde
@@bhumikachauhan5258 hmm I got it.
@@bhumikachauhan5258 Thnx!
H.W - 1) ans :-
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
H.W - 2) ans :-
9-ethyl-6-formyl spiro [4.5] dec-3-ene-1-carboxamide
Noice brother ✌️
Right😀😀😀
Correct✅ 👍✌
Waha carbanitrile aayenga not cyano 🤔🤔
Not carboxylic acid instead oic acid is preferable
🅷🆆 1
10-Bromo-5-cyano-11-ethyl-6-formyl Bicyclo [7.2.0] Undecane-4-Carboxylic acid.
🅷🆆 2
9-ethyl-6-formyl Spiro [4.5] Dec-3-ene-1-Carboxamide
𝕿𝖍𝖆𝖓𝖐𝖘
9-Ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide (ans. oh HW 2) hoga bro...
@@abhishekrajshah watch video once again
@@harishkanojiya1551 understand, u r right
@@abhishekrajshah nice brother 👍👍
Bijumani Brahma is right
I have lost all my fear of nomenclature.Thank you sir.
Me too
Same
Merko ek baat ab realise hui ki bacchoo ki achi tarah samjhane ke liye teacher ke andar 3 gun hona zaroori h
1st he should himself know all concepts clearly
2nd he should know how to transfer these huge info. In small chunks
3rd know student's first occuring doubts ...
@@namangarg6660 sahi kaha brooo
@@namangarg6660 yaa! Agree naman🤟👍🏿
The best teacher I have I ever seen....sir u made me loving organic chemistry...❤️❤️
H.W QUES- (1) 22:18 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
(2) 34:10 9-ethyl-6-formyl spiro [4.5] dec-3-ene-1-carboxamide
QUESTION CORRECTION-
17:50 bicyclo [3.2.1] oct-6-ene-3-carbonitrile
Yes 👍 same
Nice
Ethyl ka numbering pehle aayega[34 :10]
Same bro
@@talkwithstatus999 Correct hai buddy koi galti nhi hai isme
22:20 The answer for the christmas tree is 10-bromo 5-cyano 11-ethyl 6-formyl bicyclo [7.2.0] undecane - 4 - carboxylic acid
Yes, it's correct. 👍
Correct vro 👍
@yoyo Sharma correct ans is
10- Bromo-5-cyano-11-ethyl-6-formyl byclo( 7.2.0)undecane-4-carboxylic acid
😊
@yoyo Sharma carbaldehyde tab ata jab ring se attached functional gp. Ki tarah kaam kare ab to voh substitute hai to formyl hoga
Same ans Mera bhi😁
So the students who are confused in the second HW
7-ethyl se kaafi log shuruaat kar rahe hain
No dear, after naming the left side cycle and the 4° carbon atom you are going through ethyl that is totally wrong because you must go to CHO group first because it's nearer than ethyl group.
First point difference me ye baat batayi gayi hai .
Jab sab kuch fail ho jaaye tab alphabet ke order me chalna hai.
The right ans is
9-ethyl-6-formyl Spiro [4.5] dec-3-ene-1-carboxamide
@Vladimir Vladimirovich Putin It is my pleasure to help you guys.
Thank you sir for this help
Wrong
thanku
@@itsmylife3692 welcome
10- Bromo-5-Cyano-11-ethyl-6-formyl bicyclo (7.2.0) undecan-4- carboxylic acid (answer of bicyclo compund)
9-ethyl-6-formyl spiro(4.5) dec-3-ene carboxamide ( answer of spiro compound)
And thanks alakh sir for making our concepts crystal clear. He is the best teacher for physics and chemistry for neet and jee♥️♥️
Sahi hai sahi hai
Bro second galat h
9 ethyl nahi aayega 7 ethyl aayega kyuki alphebitical order dekhte hai
@@H11GAMER alphabetical order ko baad mein preference dete hain numbering mein kon pehele aata hain usko likhte hain
@@manjulasharma1623 ok bro
22:20 answer: 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0.]-undecane-4-carboxylic acid
Yes
Yes bro
Finally iupac khatam hogyi lockdown abhi bhi chal rha hai!!
Maja aagya aisi iupac pdhke
He is also a corona warrior♥️
22:23
Answer to homework question (Christmas tree type) is
10-bromo-5-cyano-11-ethyl -6-formyl bicyclo [7.2.0] undecan-4-carboxylic acid.
Tell if some correction to be done.
I think it will be undecane...
@@baishali01 yeahh..
yaha cyano kyu likhe matlab carbon count nhi hoga to carbonitrile aayega na ?? plz reply
@@homeacount4969 Yeah it would be carbonitirle...
@@homeacount4969 woh prefix name h .... Subsituent ki trah use hua h cyanide main functional grp toh cooh h
Thanks thanks a lot sir for all the videos in IUPAC naming. :)
U made it easy for me.......
Bhagwan aapko hamesha tarriki deh.........
10-bromo-5-cyano-11-ethyl-6-formyl,bicyclo[7.2.0] undecane-4-carboxylic acid is right ans. of H.W.
bhai yeah 11 class mai hai
Did you notice something at 15:40😒😒
Sir ne COOH ko primary functional group le liye or uske baaad numbering ke liye kaha ki function group ko priority doh par😖
Par in the case of Spiro sir ne kaha ki ek baar primary functional group decide ho gaya uske baad functional group or substitutent m koi priority nahi raheti🤔🤔
Please reply if anyone is reading my comment 🙏🙏🙏🙏🙏
thanks
@@prashujoshi8179 ha
@@d.celestio1574 welcome
who prefer watching old alakh sir videos than the new one
Both are osm😊😊
ur mom
@@sankhalpsunod4102 epic reply 🤣🤣
@@sankhalpsunod4102 😂😂😂
@@sankhalpsunod4102 ur dad
1St h.w
10-Bromo-5-cyano-11-ethyl-6-formyl bicyclo (7.2.0) Undecane-4-Carboxlic acid
2nd h.w
9-ethyl-6-formyl spiro(4.5) dec-3-ene-1-Carboxamide
Perfect bro
@@sumonisingh6949 tq
@@sachinrajawat7437 brother answer will be 7 _ethyl 10 _formyl Spiro(4. 5) dec_ 3 ene 1 carboxamide
Ek vaari aur dekh lo yrr😊
2nd is right
@@sumonisingh6949 yss
Bicyclo compound HW
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid
Spiro compound HW 9-ethyl-6-formyl-spiro[4.5]dec-3-ene carboxamide
Thank you very much sir for clearing all doubt about nomenclature, Love from Bangladesh
It should be 9-formyl-6-ethyl spiro [4.5] dec-3-ene -1 - carboxamide as first point of difference >>alphabetical order
@@Bhavya_Khatribut yha pr alphabetically numbering nhi hogi na kyuki 6 pr hi substituent mil ja rha h
17:35 the name of compound should have been bicyclo[3.2.1] oct-6-ene-3-carbonitril. < 3(position) was missing before carbonitril
U r right bro✔️✔️✔️
Hw1
10_bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
Hw-2
9-ethyl-6-formyl-spiro(4.5) dec 3 ene 1 carboxamide
Why undecane
Correct
@@shubhamchouhan7722 I think 6ethyl 9formyl will come
Bicyclo hw 1) 10-bromo_5-cyano_11-ethyl_6-formyl bicyclo[7.2.0] undecane-4 carboxylic acid
Spiro hw 2). 9-ethyl_6-formyl spiro [4.5]DEC-3ene-1 carboxamide
Thank you sir
22:00....
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane 4 carboxylic acid
Tridecane hoga vi... Baki sab sehi hai
It gives my face a broad smile 😊😸.. Just after starting video. It seems that in the whole world , I am finally listening to .... I can't explain
HW 2 : 9-ethyl-6-formyl Spiro (4.5) dec-3-ene-1-carboxamide
Our 1-Spiro-2-Best-4-intelligent(1.84 million) students ka dil ke -dhadkan 24K Gold -physics wallah -1-and only_Alakh sir
Love you alwaysdehyde
Huge love and respect for you.
Ya ..........I don’t know what to comment
But I like it but did not give it a like
😂😂😂😂😂
@@cowgoskippyboom5967 it's your choice 🙂
Did you notice something at 15:40😒😒
Sir ne COOH ko primary functional group le liye or uske baaad numbering ke liye kaha ki function group ko priority doh par😖
Par in the case of Spiro sir ne kaha ki ek baar primary functional group decide ho gaya uske baad functional group or substitutent m koi priority nahi raheti🤔🤔
Please reply if anyone is reading my comment 🙏🙏🙏🙏🙏
The legend who can even change the question while solving that question 30:57 😃😃😃 Indias greatest teacher from my opinion.
Hmm
no
Yes
Hw:1
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo ( 7.2.0) undecane-4-carboxylic acid.
Correct
@@jenilvaghasiya233 yes absolutely right
@@jenilvaghasiya233 can u help me to reach 2k plzzz🙏🙏 subscribe my channel
Correct
@@AmanKumar-vc7wl bhai subscribe me plzzz
(9 ethyl 6 formyl spiro [4•5] dec 3 ene carboxamide) is the ans of last que of spiro compound
right bro
Right 👍
Dude wudnt 6 be fr ethyl?
@@077_niveshpandey6 we have to first check the lowest locant rule
@@ainymony8098 no bro cho pehle h
H.W @ 22:05
10 bromo 5 cyano 11 ethyl 6 formyl bicyclo (7.2.0) undecan 4 carboxylic acid
Undecan nahi undecane aayega bro
@@uavideos8560thanks bro i almost forgot
You are really a great teacher.....
1) 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
2) 9-ethyl-6-formyl spiro [4.5] dec-3-ene 1-carboxamide
Enjoying your lecture too much sir and also helpful for me...
Thank you so much sir......
numbering kaise kiya bata sakti hai?
here why will we get cyano ? we should get carbonitrile because we are not counting the carbon of cynaide
@@19-adanish93 take bridge head carbon as 1 or 2
after taking 1 or 2 start numbering the largest carbon chain then come to smallest and follow so on..... Hope it helps you
@@ashishreddy5382 samjha samjha ....thanks
@@ashishreddy5382 See in that question -COOH group is also present which has a higher priority than cyanide grp. So we need to consider the -COOH grp. as the primary func. grp. and thus the cyanide grp. becomes the substituent and so its named as cyanide and not carbonitrile....Hope this helps.
22:20 Homework : 10-bromo-5-cyano-11-ethyl-6-formyl Bicyclo[7.2.0]-undec-4-Carboxylic acid
It's correct
single bond h to undecane
After teaching by him we don't need any offline teacher. He is just awesome 😍. Thank you 🤗 so much Sir for doing such a hard work for us 👤.
*Love you Alakh Sir* ♥️
🙌🙌🙌🙌🧿❤🤟
7-ethyl-10-formyl Spiro(4.5)dec-3-ene-1-corboxamide
9-ehyl-6-formylSpiro(4.5) dec-3-ene-1-carboxamide(Answer of Spiro compound homework)
7 -ethyl -10 formyl spiro [4.5] dec -3-en carboxaminde
@Seema Parween same answer 👍.
Correct,thank you👍👍👍👍
@@Create_clicks Wrong brother. Number the functional group first. I guess u hv numbered the double bond first.
@@Create_clicks 👍🏻
22:20 ans for xmas tree is
10-bromo-11-ethyl-6-formylbicyclo[7.2.0]undecane-4-carboxylic acid
@ Arya Keskar will it be formyl or carboaldehyde
wrong, you forgot cyano
@@mirudhubasini1128 carboaldehyde is only used if aldehyde is primary functional group
HW
*BICYCLO
10-bromo 5-cyano 11-ethyl 6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid
*SPIRO
9-EthylC6-formyl Spiro [4.5] dec-3-ene-1-carboxamide
ALL 12 LECTURES WERE VERY GOOD AND CLEAR.THANKYOU SIR.
I had no idea about IUPAC nomenclature before.
But after seeing all the 12th videos of Physics wala, Now i can confidently say that i can deal any type of question.
Big thanks to Alakh sir❣️ may God gives u a long life sir😊❤️
Same here brother ❤
Finally Watched All 12 videos of Nomenclature. I started watching in November and ended in April ..
A very Wide chapter ..😂
😂😂 yaar
Koi web series start karo .. pura season ek din mein khatam karoge
@@srishtinema3713 Tmhare saath bhi aisa hi hai kya?
@@amrutrajyadwad Sad but truth bro😓
Nahi iupac ke saath to nahi but aur bakki ke chapters ke saath jaroor hota hain yaar
H.w Qs-1 ans
10-bromo-5-cyano-11-ethyl-6-
formyl bicyclo(7.2.0)undecane-
4-carboxylic acid
H.w Qs-2 ans
7-ethyl-10-formyl Spiro(4.5)Dec
-3-ene-1-carboxamide
Correct
Correct 💯💯
Wrong he
Correct ans
9-ethyl-6-formyl Spiro[4.5] dec-3-ene carboxamide
By first point of difference.
9 ETHYL 6 FORMYL SPIRO[4.5] DEC-3 ENE 1- CARBOXAMIDE
Finally I completed nomenclature with crystal clearity
finally completed full iupac nomemclature..tqq... so much alakh sir....
@@sarthakshukla786 are bhai vo aldehyde nhi hai vo ketone hai
@@sarthakshukla786 carbon main chain m count krenge to oxo or nhi krenge to formyl, it is only for aldehyde
@@sarthakshukla786 ketone m aisa kuch b nhi hai, ketone m keto ya oxo m se kuch b likh sakte hai
@Mohd Shaiba likhwaya to tha, par un dono m se kuch b use kr sakte hai
@@sarthakshukla786 are bhai baat vo hi hai, keto likho ya oxo
21:27 The HW ans :- 10-Bromo-5-Cyano-11-ethyl-6-formyl Bicyclo [7.2.0] Undecane-4- Carboxylic Acid
Heyy buddy it's [7.2.0]
@@heisenberg_780 yes
HW-1
10-bromo-5cyano-11-ethyl-6-formylbicyclo[7.2.0]undacanecarboxylic acid 22:27
H W 2:9-ethyl-6-formyl spiro[4.5]dec-3-ene-1-carboxamide Thank you so much sir🙏🙏🙏now I'm feeling I know something about chemistry
Hw1
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo(7.2.0)undecane-4-carboxylic acid
Hw2
9-ethyl-6-formyl spiro(4.5)dec-3-en-1-carboxamide
just aa little correction u need to do
dec-3-ene-1-carboxamide dont cancel e because it is carboxamide.
but yeah why the hell i need to dis after a year after
Spiro:- 9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide.🤘
No bro wrong
.......7 ethyl 10 formyl ......
Because it is not funtional group so set as alpha bet ....
@@ayushabd89 plse see again properly!
@@ayushabd89 substituents in 6,9 position have lowest first point of difference than 7,10.position have more priority than the alphabetical order
@uggj
Bhai 6 - formyl nhi 6-oxo. Hoga. Q ki. Aldehyde ka carbon. Count nhi hua hai...
9-ethyl-6-formyl spiro(4.5)dec-3-ene carboamide is the answer for 2nd homework question
love you sir for making my organic strong in this lockdown
6-ETHYL - 10-FORMYL AYE GAA
Yeah, correct.
Answer for X-mas tree
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4- carboxylic acid
Shouldn't it be carbonitrile instead of cyano?
@@shivamarora9322 carbonitrile will be used if it is treated as functional group and it's carbon is not counted but here it acts as substituent so cyano is correct
@@priyanshumishra1853 exact but fir bhi wrong .....see ethyl blonder mistake
Carbon of nitrile , aldehyde can't be taken into consideration...and functional group is carboxylic acid ....so I think this one is not correct !!
Should I use keto or oxo in place of ketone if it is treated as substituent please help 😊
34:05 answer of the last home work question is 9-ethyl-6-formyl Spiro [4.5] Dec -3- ene carboxamide
Right bro...
Correct
Sabi hai
@@roshnikumari9751 right. 7-ethyl-10-formylspiro[4.5]dec-4-ene-1-carboxamide
@@Hunter_6585 wrong nmbring..
Priorityvise you should give less nmbr to CHO then ETHYL
Sir 18:03 mae 3 question ka nam.... Ye hoga..... Bicylo[3.2.1]oct-6-ene-3-carbonitrile ..... Sir apne carbonitrile ki pos. Nahi batayi
Yep I was also thinking same
Yes you are correct
Ha mai bhi yeh Soch Raha tha
Yes...Maine bhi ehi kya..I think it's a very little mistake to Sir..bcz he is such a great person.😊😊😊
Maine apne notes me 3 likha tha phir kaat diya ye soch ke ki 3 nahi hoga phir dubara likha. 😅😅😅😅😅😅😅😅😅
*Bicycle compound*:10-bromo 5-cyano 11-ethyl 6-formyl bicyclo[7.2.0] undecane carboxylic acid.
*Spiro compound*: 9-ethyl 6-formyl spiro[4.5]dec-3-ene carboxamide
Thank you sir ❤️🔥
Bro i think the bicyclo one is ur correct but it will be undecane- 4- carboxylic acid..u missed the 4
Bro I think your Spiro compound is incorrect as alphabetical preference ke according ethyl ko least no. milna chahiye
According to me it will be
Spiro:- 7-ethyl-10-formyl spiro[4.5] dec-3-ene-1-carboxamide
I agree with you
@@piyushkumar5-aayushkumar8-65 no , first we give no. acc to first point of difference then we see alphabetical order if no option left
HW:1:
10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[ 7.2.0] undecane-4- Carboxylic acid
HW:2:
9-ethyl-6-formyl Spiro [4.5] dec-3-ene-1- carboxamide.
Right
Yes I got the same thing
It's wrong I think cause numbering will be done alphabetically so do check
Answer for Spiro is 7- ethyl - 10 - formyl Spiro [ 4. 5 ] Dec - 3 - ene -1- carboxamide
@@sanjanamishra4389 ok, but
Here "cho "substituent is comes on the 6 th place but alkyl substituent comes on the 7 place so as we know that we first go to lowest no for substituent.
If tie between them substituent then we go through alphabetically
Yes
22:20 I got answer is = 10-bromo-5-cyano-11-ethyl-6-formylbicyclo(7.2.0)undecane-4-carboxylicacid.
Bicyclo homework answer: 10 - Bromo - 5 - cyano - 11 - ethyl - 6 - formyl bicyclo [7.2.0] undecane - 4 - carboxylic acid
Spiro homework answer: 9 - Ethyl - 6 - formyl spiro [4.5] dec - 3-ene - 1 - carboxamide
Thank you buddy ......I had mistake in Spiro hw I gave 1st no. To double bond ..... Thank you yrrr❤️😎
@@VishalPatil-rg9co Wlcm bhai....We are there for helping each other only....
your 2nd answer is wrong bro we will give small no to ethyl ,not to formyl (go alphabetically while numbering) ....if i am wrong then correct me
in spiro cho connected by ring so carbaldehyde will be used
@@priyanshu7 yup bro ❤️
✨ HW - 1 ✨
1) 10 - Bromo - 5 - cyano - 11 ethyl - 6 formyl bicylo ( 7.2.0) undecane -4 - carboxylic acid
✨ HW -2 ✨
2) 9- ethyl - 6 formyl Spiro [ 4.5 ] Dec 3-ene 1-Carboxamide
No
Formyl
no oxo yes
Why cyano bro why not carbonitrile
And why undecane why not tridecane
@@ishitatayal2200 bcz cooh have more priority than cyanide
10-Bromo- 5-cyano-11 -Ethyl-6-Formylbicyclo(7.2.0)undecane-4-carboxylic acid And 9-Ethyl-6-Formylspiro(4.5)dec-3-ene-1-carboxamide
I think Spiro ans is incorrect
Ans : 7 - ethyl-10- formyl - Spiro ( 4.5) Dec -3-ene carboxamide
Please do correct me if I am wrong
You are not correct brother, check again
It Is Absolutely Correct.
is cyano a substituent or functional group??
@@Isha-te9mf functional group
34.10 H.w Answer 7-ethyl-10-formyl spiro[4.5]dec-1-ene-4-carboxamide
I enjoys whole IUPAC Series in lockdown and learnt a lot. Thanks to Alakh Sir
1) 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo[7.2.0] undecane-4-carboxylic acid.
2) 9-ethyl-6-formyl spiro[4.5] dec-3-en-1-carboxamide.
2)7-ethyl-10-formyl spiro (4.5)dec-3-ene-1-carboxamide
correct
1st HW 10-Bromo-5-Cyano-11-ethyl-6-Formyl-Bicyclo (7.2.0) - Undecane-4-Carboxylic acid
2nd HW 7-ethyl-10-formyl-Spiro(4.5) - Dec-3-ene - carboxamide
Bro formyl 6th carbon par hoga....& ethyl 9th carbon par....due to low locent rule
10-Bromo-5cyano-11-ethyl-6-formylbicyclo(7.2.0)undecan-4-carboxylic acid
e to lga undecan me
34:10 hw...
9-ethyl-6-formyl spiro [ 4.5 ] dec-3-ene-1-carboxamide
Right bro
Ryt same ans
6 ethyl 9 formyl spiro(4.5) dec 3 ene 1 carboxamide because alphabetically counting will take place as here CHO will not be considered as functional group
Correct brOOO
galat hai bhai iska 7-ethyl-10-formylspiro[4.5]decane-1-carboxamide .
reason: CHO ko formyl as a substituent and ethyl starts from e so no. from ethyl firstly
22:22 Christmas tree - 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane -4-carboxylic acid
34:19 H/W Q2 → 9-ethyl-6-formyl spiro [4.5] dec-3-en-1-carboxamide
HW - 2
7 -ethyl - 10 - formyl Spiro [4.5] dec - 3 - ene -1- carboxamide
Bro 7 methyl 10 oxo kyu nahi hoga spiro wale me ???
@@ShivamKumar-xb6ow bro methyl to hai hi nahi and and pehle priority lowest set of locants ki hoti hai isliye CHO ko side jaenge pehle , and ek aur baat OXO ki jagah FORMYL lagega kyunki aldehyde ka carbon chain mein nahi hai, I hope it will be helpful for you
@@iitaspirant7877 ha thanks
Wrong
34:10 Hw is 9-ethyl-6-formyl-spiro[4.5]dec-3-ene-1-carboxamide...thank u Sir for clearing my all doubts in nomenclature...❤️ u r the king of organic chemistry....
Sir, you are the bestest teacher I have ever seen
The answer of Christmas tree = 10(bromo),5-(cyano),11-(ethyl),6-(formyl) bicyclo [7,2,0]undecane-4-carboxylic acid
Mera bhi yahi aya
5 carbonitrile hoga na?
@@Rohitkumar-fj8sf nop. Its cyano. Carbonitrile is the secondary suffix
Bicyclo:- 10-bromo-5-cyano-11-ethyl-6-formyl bicyclo [7.2.0] undecane-4-carboxylic acid.✌️
Brother, it will be 5- carbonitrile as carbon of cyanide group is not included
@@mananambaliya7397 no it will be 5 - cyano
Q.2) spiro compound H.W
7-ethyl-10-formyl spiro[4.5]dec-3-ene-1-carboxamide
At 22:22
1) 10 Bromo 5 Cyano 11 ethyl 6 formyl Bicyclo [7•2•0] Undecane-4- Carboxylic acid
At 34:10
2) 7 ethyl-10 formyl Spiro [4•5] Dec-3- ene-1-Carbamoyl
I think this one is correct...👍
Thankyou so much sir ji
Wrong hai 2nd cho ke or jayenge
@@ravindrachauhan9680 bro alphabetically jao....then you'll get correct answer
2nd is wrong, carbamoyl is used for prifix
Both answers are correct
9-Ethyl-6-formyl Spiro (4.5) dec-3-ene-1-carboxamide
😊😊
Home work:-1
10-Bromo-5-cyano-11-ethyl- -6- formyl bicyclo [ 7.2.0 ] undecane-4-carboxylic acid .
Home work:-2
9- Ethyl-6-formyl spiro [ 4.5 ] dec-3-ene-1-carboxamide .
Homework 2= 7-ethyl 10- formyl spiro (4.5) dec 3- ene 1- carboxamide
@@Shivanisharma-yx4lz yes this one is correct
@@Shivanisharma-yx4lzyes this I got
@@Shivanisharma-yx4lz correct :- 9- Ethyl-6-formyl spiro [ 4.5 ] dec-3-ene-1-carboxamide
@@Shivanisharma-yx4lz lowest set of locants b/w -> 1,3,6,9 and 1,3,7,10 is the first one.
Lowest set of locants has more priority over alphabetical order
Completed!!! Wah! Feeling hi kuch aur hai😌
do u go any coaching
My college itself gives coaching, including boards, but probably not best, i whole point of me coming here is that. We rarely get time to go that detailed as alakh sir.
World best teacher alakh Pandey sir🙏🙏🙏🙏🙏🙏🙏💜💜💜❤️❤️😘
Finally for the first time I understood iupac nomenclature with full clarity thank you sir.
2. 9-ethyl-6-formyl spiro[4.5] dec-3-ene-1-carboxamide
Ha bhai mera bhi yahi aa raha hai
Ryt h aapka
Right ans.
Your answer is correct..👌👌👌
Correct ans.bro