In objective questions always try to use some short intuitive checks. Realizing that the domain is [-2,3] , check the value at the end points which is sqrt(5).Hence probably the correct choice is either (b) or (d). Next, equate the two radicals i.e. 3-x=2+x which gives x=0.5 which is a likely inflection point. This may not always be true but worth a check. Value at 0.5 is sqrt(10). Since this is one of the option hence you are pretty sure that's the answer. I use to do these tricks to quickly solve objectives when I cracked JEE in 1998.
Sum of two square roots cant be a prime number inside square unless one of the roots become zero, so by observation option D is the correct answer. For eg. √x+√y cant be √z where z is a prime number , unless either x is zero or y is zero
Sir I am in class 10th now, a fiitjee student but I can understand the explaination of the question very well and also able to solve it by 1st method🙏🙏🙏
Function has the addition of two square roots Square roots can never be negative so therefore we took 3 - x >_ 0 2 + x >_ 0 as the square root can be zero hence functioned is defined between -2 and 3 Im a 11th grader forgive me for any wrong logic
In objective questions always try to use some short intuitive checks. Realizing that the domain is [-2,3] , check the value at the end points which is sqrt(5).Hence probably the correct choice is either (b) or (d). Next, equate the two radicals i.e. 3-x=2+x which gives x=0.5 which is a likely inflection point. This may not always be true but worth a check. Value at 0.5 is sqrt(10). Since this is one of the option hence you are pretty sure that's the answer. I use to do these tricks to quickly solve objectives when I cracked JEE in 1998.
🙏asm....Give some more tips and trick for math
Excellent explanation Sir. Thanks and Regards
Sq.rt of ( x - a ) + Sq.rt of ( b - x ) is
Minimum at boundaries of domain & Maximum at mid point of domain interval ..
thank you
Sir aapko starting me positive nahi non-negative bolna chahiye
Super sir explana❤
Sum of two square roots cant be a prime number inside square unless one of the roots become zero, so by observation option D is the correct answer. For eg. √x+√y cant be √z where z is a prime number , unless either x is zero or y is zero
Good morning sir , I am Anant dev student of class 12th F I liked your explanation a lot, Thank you sir
Thanks
Sir I am in class 10th now, a fiitjee student but I can understand the explaination of the question very well and also able to solve it by 1st method🙏🙏🙏
Bro I am in 10th class, I am not able to join any coaching because financial condition 😞. Can you pls send me modules of your coaching. Pls 🙏
@@Princesingh0004 bro I will suggest u best UA-cam channel to study 😢 and app to
Bhai mohit tyagi sir ke lectures dekhlo iit pakka h ❤@@Princesingh0004
Which centre....
Just squaring both side and min value is when the root term is zero and max when the root term is max check via differentiate
Nice solution,but the question is trivialised by the Cauchy Schwartz inequality
Great explanation sir ❤️
Sir use differentiation it can solve fast
Sir in second method differentiation is wrong... You forgot 2 in denominator in 1/√2+x.... But answer is still right how?
Yeah….because 2 comes in the denominator but the lcm would be the same and also denominator is playing no role for giving critical points
Sir wavy curve mhi laga sakte kya
Sir aap maths ke eduniti ban jao 😂
How did you arrive at conclusion, sir, that the minimum is only at -2 or 3?
😂😂😂 because function is defined between-2 and 3 only
In Which standard u are
Function has the addition of two square roots
Square roots can never be negative so therefore we took 3 - x >_ 0 2 + x >_ 0 as the square root can be zero hence functioned is defined between -2 and 3
Im a 11th grader forgive me for any wrong logic
Sir by using AM GM inequality the minima is coming as root 10 what's wrong here?
@@adityasarraf3843 please keep in mind domain also
@@sanjeevsir29077 sir the minima is coming on x=1/2 (using AM GM inequality) which is right well in domain)
Sahi hai bhai differentiation se bhi aa raha hai
❤