Real Analysis | The uniform continuity of sqrt(x).
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- Опубліковано 24 лип 2024
- We show that the square root function is uniformly continuous on its domain.
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Thanks for doing all kinds of tutorials! Even ones that might be not as popular!
Very appreciated 🙏❤️
Love your videos. I wish the YT Algorithm had introduced you earlier.
In fact |√x-√y|≤√|x-y| for all non-negative x and y. So it's uniformly continuous.
Excellent lesson!
This is the information I was looking for, I had many doubts, thank you very much my friend.✨👍
Your videos helps me a lot to read U.A by Stephen Abott, thanks you so much
On the open set of ordinal integers between zeroth and second.
Great problem sir, waiting for more of your physics videos.
Thank you so so so much!
14:15
Nope, the 'stop' was cut off. :D
The first good place to stop: ua-cam.com/video/FhaFewKyp-Q/v-deo.html
@@adned6281 Nope, you haven't dug deep enough. Your video is from March 2020 but we can find earlier than that. Look this, this is from January 2020 : ua-cam.com/video/5Xk1SSUuOjU/v-deo.html
@@goodplacetostop2973 Wow, you do know your good places to stop.
Guess my assumption about good place to stop continuity was not justified.
Adned Actually I haven’t found the original good to place... yet. There’s A LOT of videos to go through lol
at 6:22 in your scratch work, aren't you proving that sqrt(x) is a Lipschitz function?
and all Lipschitz functions are uniformly continuos
But sir what if we choose x in 0,1 and y in 1,+infinity how would your result hold in this case
You could have also picked δ = min{δ_1,δ_2,1} and that still confines x and y to one of [0,2] or [1,inf).
what if epsilon = 1000000 and delta1 = delta2 = 10?
Daniel, what would you do with x=1.5
@@jonathanjacobson7012 If x = 1.5 and |x-y| < δ = min{δ_1,δ_2,1}, then |x-y| < 1, so y is in (0.5,2.5). If y is in (0.5,2], then both x and y are in [0,2]. If instead y is in (2,2.5), then both x and y are in [1,inf). Either way, choosing δ = min{δ_1,δ_2,1} guarantees that for all positive real numbers x,y with |x-y| < δ, either both x,y are in [0,2], or both x,y in [1,inf), which is sufficient for Michael's argument.
Is step function is uniformly continuous
What about f(x)=1/x
Set y = x + ẟ/2 and see what happens with |f(x) - f(y)| when x -> 0⁺.
Creo que Mr.Penn debe ser más ordenado y escribir un poco más grandes las letras.
Michael escribe muy bien y claro, pon la pantalla completa para ver las letras más grandes
Sir I'm an 8th grader and having problems while factoring cubics and quartics, could you kindly help me
When a prof is teaching university curriculum, it is not a proper place to ask for help for middle school stuff. There are literally hundreds of middle school math channels out there.
If u want to badly ask questions to Michael, pose specific hard factorization problems on his vids where he posts competition math - have a basic sense of propriety.
@@ancientwisdom7993 i am glad to see that you have the BASIC SENSE OF PROPRIETY, but if sir agrees then I don't think that your BASIC SENSE OF PROPRIETY will be of great worth
Consider going directly to absolute continuity, so a function can be recovered by integrating its derivative. Key for calculus.
Very bad
All of this complicated equations and dividing into those two cases is unnecessary.
Just use delta = epsilon^2 and you're basically immediately done.
UA-cam unsubscribed me. Go figure.