YOUR videos are AMAZING!!!! I am giving my MCAT soon and cannot emphasize how good your videos are. please do not stop making them. You will definitely blow up soon :)
As always, this video is so helpful, thank you so much! I was always curious about squaring and cubing, but do you have any specific tips on how to cube root or square root a scientific notation number? Say that you have to find concentration of product concentration [X] given pH of x value and other terms. I sometimes ended up with an equation like x^2 = 1.2 x 10^4 I know that square rooting means dividing exponents by 2, but how does one deal with the 1.2? and say the exponent is odd. Do you have any tips for this?
I will eventually make a video on this concept, but here is how I would go about approaching this. For math such as √1.2 you can just estimate that to closest perfect square so in this case √1.2 = √1 = 1. We know that we rounded this down so I would expect the actual answer to be a bit bigger than 1 but that is good enough for the MCAT. When taking the square root or cube root of non-divisible number you will want to change the exponent by adding zeros to the number out front. For example, √5 x 10^-5 we will turn this into √50 x 10^-6. The √50 = √49 = 7 and the √10^-6 = 10^-3 so overall √5 x 10^-5 = 7 x 10^-3. You can use the same technique for cube roots, but I suspect that the math for cube roots would be easier since these values are harder to estimate. Hope that helps!
When you add a kilo to that number you are multiplying it by 10^3 because those SI prefixes are a way of representing math and they must be cancelled our so we don’t change the original value. So if we add in a prefix we must cancel out its impact on the number by multiplying by its inverse. When we add the km we do this by multiplying by 10^-3 to cancel out the 10^3 that gets added in by the kilo. Lets also think conceptually for a moment about your example. 1 µm is much smaller than 1 m which is much smaller than 1 km. So if 1 µm = 10^-6 m then 1 µm in terms of km must be smaller than 10^-6 km. If we take 10^-6 and multiply it by 10^3 then we get 10^-3 km. But that doesn’t make sense because somehow 1 µm is actually more km than regular m.
What about Ronna and Ronto ? The SI prefix name for 10^30 was originally proposed to be *Quecca* and then replaced by *Quetta* , since the former is inappropriate in some languages.
I found you on my last two weeks of studying for this MCAT, I take it next friday. Don't stop making these!
Good luck next Friday and thanks for leaving a comment!!!
YOUR videos are AMAZING!!!! I am giving my MCAT soon and cannot emphasize how good your videos are. please do not stop making them. You will definitely blow up soon :)
Thank you so much!!!
Really appreciate your videos, i hope your channel gets even more traffic as it certainly deserves it
Thank you so much!!!
when the mcat takers needed eightfold MCAT the most, he disappeared. I pray you're doing well!!
As always, this video is so helpful, thank you so much! I was always curious about squaring and cubing, but do you have any specific tips on how to cube root or square root a scientific notation number?
Say that you have to find concentration of product concentration [X] given pH of x value and other terms. I sometimes ended up with an equation like x^2 = 1.2 x 10^4
I know that square rooting means dividing exponents by 2, but how does one deal with the 1.2? and say the exponent is odd. Do you have any tips for this?
I will eventually make a video on this concept, but here is how I would go about approaching this.
For math such as √1.2 you can just estimate that to closest perfect square so in this case √1.2 = √1 = 1. We know that we rounded this down so I would expect the actual answer to be a bit bigger than 1 but that is good enough for the MCAT.
When taking the square root or cube root of non-divisible number you will want to change the exponent by adding zeros to the number out front. For example, √5 x 10^-5 we will turn this into √50 x 10^-6. The √50 = √49 = 7 and the √10^-6 = 10^-3 so overall √5 x 10^-5 = 7 x 10^-3.
You can use the same technique for cube roots, but I suspect that the math for cube roots would be easier since these values are harder to estimate.
Hope that helps!
It does, thank you again!
Of course.
confused, why would we multiply by inverse instead of just multiplying like normal for ex from um to km why cant we just do 10^-6 x 10^3??
When you add a kilo to that number you are multiplying it by 10^3 because those SI prefixes are a way of representing math and they must be cancelled our so we don’t change the original value. So if we add in a prefix we must cancel out its impact on the number by multiplying by its inverse. When we add the km we do this by multiplying by 10^-3 to cancel out the 10^3 that gets added in by the kilo.
Lets also think conceptually for a moment about your example. 1 µm is much smaller than 1 m which is much smaller than 1 km. So if 1 µm = 10^-6 m then 1 µm in terms of km must be smaller than 10^-6 km. If we take 10^-6 and multiply it by 10^3 then we get 10^-3 km. But that doesn’t make sense because somehow 1 µm is actually more km than regular m.
@@EightfoldMCATthanks omg!
What about Ronna and Ronto ?
The SI prefix name for 10^30 was originally proposed to be *Quecca* and then replaced by *Quetta* , since the former is inappropriate in some languages.
I only included the MCAT relevant units so poor Ronna got left out this time.