Maximum Likelihood Estimates for a Multivariate Normal Distribution

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  • Опубліковано 6 жов 2024
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КОМЕНТАРІ • 44

  • @wg6487
    @wg6487 4 роки тому +5

    This is my at least 4th time reviewing the MLE for MVN. Your explanation is the most concrete.
    Can't wait to see your other videos. Thank you!

  • @isyakumuhammad6982
    @isyakumuhammad6982 5 років тому +2

    Thank you very much!
    this lecture is very clear it help me a lot .
    I hope one day you will explain the EM algorithm of skew normal distribution.

    • @statisticsmatt
      @statisticsmatt  5 років тому +2

      You're welcome. Here's a link that might help with the EM algorithm of skew normal distribution. www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&cad=rja&uact=8&ved=2ahUKEwjAwoDgwsXlAhVFba0KHWAfCnMQFjACegQIBRAB&url=https%3A%2F%2Farxiv.org%2Fpdf%2F1608.02797&usg=AOvVaw1XTDdwnXDtUnbAi3TaMzY4

    • @isyakumuhammad6982
      @isyakumuhammad6982 5 років тому +1

      thank you very much !

  • @ralph6087
    @ralph6087 5 років тому +2

    Thank you! This video helped me alot.

    • @statisticsmatt
      @statisticsmatt  5 років тому +1

      I love hearing comments like this. Many thanks! Makes my day.

  • @l8870
    @l8870 Рік тому

    came in clutch, thank you so much!

    • @statisticsmatt
      @statisticsmatt  Рік тому

      You're so welcome! I love hearing that the videos are helpful. Many thanks for watching. Don't forget to subscribe and let others know about this channel.

  • @trueislam8462
    @trueislam8462 4 роки тому

    Your explanation is so concrete. Thanks for uploading a wonderful derivation.
    Can you please share MLEs of the parameters of a bivariate normal disribution, and which Show that the MLEs are asymptotically unbiased, consistent, sufficient, asymptotically efficient, asymptotically normally distributed.

    • @statisticsmatt
      @statisticsmatt  4 роки тому

      I've had a couple people request this. I'll have to add this to my list to show. Please be patient as I'm not sure when I'll be able to get to this. Many thanks for watching!

    • @trueislam8462
      @trueislam8462 4 роки тому

      @@statisticsmatt thanks. But, can you share any doc file which all of mention things are proved. Please share it if it is possible because im so confused and my exams are too near im thankfull to you if...

    • @statisticsmatt
      @statisticsmatt  4 роки тому

      I don't have doc files with this information. I was just going to prove them from scratch. Have you tried a google search for the information?

    • @trueislam8462
      @trueislam8462 4 роки тому

      @@statisticsmatt yes but unable to get mentioned information

  • @洪佳聖-h5d
    @洪佳聖-h5d 4 роки тому +2

    Thank you for the great video! However, isn't ln(2pi^(-nk/2)) be (-nk/2)ln(2pi)? Why you put it as ln (-nk/2)(2pi)?

    • @statisticsmatt
      @statisticsmatt  4 роки тому +3

      yes, you are correct. i've added an information box to pop up at 2:04 in the video. many thanks. much appreciated.

  • @michaelyang7657
    @michaelyang7657 4 роки тому

    Very solid explanations, thanks a lot!

  • @zeitlichkeit540
    @zeitlichkeit540 5 років тому +1

    Thank you! very clear!

  • @husseinsleiman6119
    @husseinsleiman6119 2 роки тому

    Hello, in 6:15 you multiplied by sigma to get rid of sigma^-1. I was wondering from where you got back (- n*sigma) in the beginning of the equation? thank you for this video your channel is amazing and full of important knowledge.

    • @statisticsmatt
      @statisticsmatt  2 роки тому +1

      For the equation, we pre and post multiple by sigma. Many thanks for watching. Don't forget to subscribe and let others know about this channel.

  • @thetamaeleven869
    @thetamaeleven869 3 роки тому

    what is difference between Maximum likelihood and Full Information Maximum Likelihood for multivariate normal?

    • @statisticsmatt
      @statisticsmatt  3 роки тому

      I'm not 100% sure that I understand the question. Full Information Maximum Likelihood deals with maximizing the log likelihood when there are missing observations. maximum likelihood is used with all data is available. many thanks for watching and don't forget to subscribe.

    • @thetamaeleven869
      @thetamaeleven869 3 роки тому

      @@statisticsmatt thank you for your explation.. Actually, I red an article about SpVAR model. Author used FIML for estimating model parameters. It is confusing me because i have not found the difference between FIML and ML in that article.. would you like to help me give an explanation about it?

  • @parwana-e-aatish9641
    @parwana-e-aatish9641 4 роки тому

    Thank you for uploading a wonderful video.
    Sir please let me know, what will be the MLEs of BIvariate normal distribution

    • @statisticsmatt
      @statisticsmatt  4 роки тому +1

      The derivation is the same except the vectors are 2x1 and the covariance matrix is 2x2. After a quick search, here's a link that may be helpful. www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=&ved=2ahUKEwiilOaVlfvpAhXNTjABHdfmBxIQFjAGegQIBhAB&url=http%3A%2F%2Fdigitalcommons.fiu.edu%2Fcgi%2Fviewcontent.cgi%3Farticle%3D1855%26context%3Detd&usg=AOvVaw1n_fAQH0fotAQrNtBoLfPQ

    • @parwana-e-aatish9641
      @parwana-e-aatish9641 4 роки тому +1

      statisticsmatt thanks for sharing a wonderful document

  • @gmh14
    @gmh14 Рік тому +1

    Is there a resource I can refer to for the MLE estimates of mean and variance in the case of correlated samples in a multivariate Gaussian? Thanks!

    • @statisticsmatt
      @statisticsmatt  Рік тому

      Here's a nice resource on stats.stackexchange.com Nice explanation and links to other sources. Many thanks for watching. Don't forget to subscribe and let others know about this channel.
      stats.stackexchange.com/questions/351549/maximum-likelihood-estimators-multivariate-gaussian

    • @gmh14
      @gmh14 Рік тому

      @@statisticsmatt Thanks, but I think you missed my point on "correlated samples". The solution you linked to considers samples to be IID (independently distributed) and hence, uncorrelated. What if each random variable in the N-variate Gaussian is correlated with a correlation rho? i.e. Corr(X_i, X_j) = rho.

    • @statisticsmatt
      @statisticsmatt  Рік тому

      I did miss that. Thanks for the follow up. I don't have a good reference for this. I was going to "google" this and send you links, but I'm guessing that you've already done that. If you find a good reference, do please let us know. Again, many thanks for watching.

  • @gunnerstone120
    @gunnerstone120 3 роки тому

    Great Video

    • @statisticsmatt
      @statisticsmatt  3 роки тому

      Many thanks for saying that. Much appreciated. Many thanks for watching and don't forget to subscribe!

  • @spyhunter0066
    @spyhunter0066 2 роки тому

    How will be the implementation of the very last formula in the end? Cheers.

    • @statisticsmatt
      @statisticsmatt  2 роки тому

      Here is some R code that we help.
      library("MASS")
      n

  • @gamaputradanusohibien5730
    @gamaputradanusohibien5730 Рік тому

    how if detereminan sigma is negative?

    • @statisticsmatt
      @statisticsmatt  Рік тому

      If I'm understanding your question correctly, I am assuming, without stating it, that sigma is a symmetric positive definite matrix, which implies that the determinant is positive. Many thanks for watching. Also, please let others know about this channel.

  • @zeitlichkeit540
    @zeitlichkeit540 5 років тому

    btw can you explain why \mu^T\Sigma^-1\x_i = \x_i^T\Sigma^-1\mu?

    • @statisticsmatt
      @statisticsmatt  5 років тому

      notice that \mu^T\Sigma^-1\x is a 1 by 1 matrix, which is symmetric by default. taking the transpose does not change it. the right hand side of the equal sign is the transpose of the original.

    • @zeitlichkeit540
      @zeitlichkeit540 5 років тому

      ​@@statisticsmatt Thank you! That is very helpful to me! Other videos are great too.

  • @kavourakos
    @kavourakos Рік тому +1

    you are god

    • @statisticsmatt
      @statisticsmatt  Рік тому

      I'm going to take this as you thought the video was extremely helpful. And I love hearing that the videos are helpful! Many thanks for watching. Don't forget to subscribe and let others know about this channel.