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•Question:> (opposite direction) Train A length:- 150m Train B length:- 100m Total >250m Total time taken to cross:- 10sec Train A speed:- 30kmph We have to find speed of train B. •Solution:- Speed= Distance ÷ Time =250÷10 =25m×18/5 (need ans in Kmph) Total speed= 90kmph. ●speed of second train = 90 - 30 = 60kmph.
1:27:15 solve that question or just use logic that man has 10km/h downstream and 2km/h upstream..and he traveled more than 2 hours so the distance can't be less than 4 km in any case according to simple logic. Anyone explain
42:00 (St + So ) * t = Lt + Lo 30=( 25/3 ) after converting to m/s , Lt+ Lo= 150 + 100= 250 25/3 + So * 10 = 250 25/3 + So = 250/10 25/3 + So = 25 So = 50/3 but this is in m/s have to convert to km/hr so, 50/3 * 18/5 = 60 Ans
See in question it's given Lt = 150m Lo = 100m t = 10s St = 30 km,/h And we have to find So So the solution will be based on the formula = St + So × t = Lt + Lo Put the values now 30 + So × 10 = 150 + 100 30 + So × 10 = 250 30 + So = 250 /10 30 + So = 25 Now bcz the 25 is in m/s we have to change in km/h bcz all the options are in km/h So 30 + So = 25 × 18÷5 After this the equation will be 30 + So = 90 Therefore So = 90 - 30; = 60 km/ h Hence the ans is 60 km/ h
Thank you, sir, aapki teaching skills itini acchi he ki ab me sapne me bhi quants karne lagi hu. kash aap thole jaldi mile hote but abhi bhi der nahi hui he..... thank you🙇♀🙏
This is the my most feared topic in entire quants syllabus but you made it look so easy and simple that I'm hating myself for being this dumb. Thank you sir for everything, I can literally solve any problem from this topic, may every weak student in quants find a teacher like you 🙏
@@rohansingh8761 Even i was lookin for the same thing. So bsically (25/3 + x) 10 = 250 => 250/3+10x=250 => 10x= 250-250/3( this was in addition so becomes subraction) => 10x=500/3 => x= 16.666 => 16.6666 * 18/5 = 59.99 = 60
foundation playlists are a gem sir aaj tak kabhi ye concept samajh nahi aaya 12th paar ho gayi aur parso JIPMAT exam hai aaj jakar finally full clear thankyou sir MBA ke liye to aapse hi padhungi
sir i have been watching your sessions and I have to say thank you so much for making these sessions . What an amazing video . Such a lovely session . May god bless you .
Such that..up condition. D=40km/h T=8hrs. So speed=d/t 40/8=5 And down condition.. D=49km T=7km :49/7 =7 Now: sb-sw=5....equ(1)st And sb+sw=7 equ.(2) Ko add krne pr 2sb = 12 Sb= 6 km/h.
A train overtakes two persons walking at 2 km/hr and 4 km/hr respectively and completely passes them respectively in 9 sec and 10 sec. The length of the train is
Last q koi quadratic way me solve krke batao plzz (14/5+x) + (9/5-x) = 5 Isko solve krne pe x(x-1)= 20 ara hai Sirne opt se 2 bataya vo samjha But ye last wale equation ko solve krke ans 2 kaise ayega any scholar here ?k
Solve the equation you have written by applying a^2-b^2= (a+b)(a-b) you’ll get a quadratic equation.. on solving the quadratic equation you’ll get two solutions 1 and -2 … speed can’t be negative hence 1and 2 both are true option a and B both are correct
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•Question:> (opposite direction)
Train A length:- 150m
Train B length:- 100m
Total >250m
Total time taken to cross:- 10sec
Train A speed:- 30kmph
We have to find speed of train B.
•Solution:-
Speed= Distance ÷ Time
=250÷10
=25m×18/5 (need ans in Kmph)
Total speed= 90kmph.
●speed of second train = 90 - 30
= 60kmph.
Thanks Brother
Where are you form ?
I like ur method bro
Sir ka method ( formula) se kyu ans nahi araha 🙃
We'll explained 🫡
if you had met me 2 years ago i would have cleared cat in 2020. best teaching style and soothing voice.
2020 was 4 years ago
😂😂😂@@Pratham-uw5mk
@@Pratham-uw5mk he commented on Dec 2022
Comment m to to 1 year ago sikha rha @@dangerboy7726
Understood this concept now after 6 years. Always used to cram this in my school time. Thank you
lol same here and also algebra, that thing was scaring me in my school time 😂
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fikar not
1:27:15 solve that question or just use logic that man has 10km/h downstream and 2km/h upstream..and he traveled more than 2 hours so the distance can't be less than 4 km in any case according to simple logic. Anyone explain
Best Teacher, having a clear thought process.
42:00 (St + So ) * t = Lt + Lo
30=( 25/3 ) after converting to m/s , Lt+ Lo= 150 + 100= 250
25/3 + So * 10 = 250
25/3 + So = 250/10
25/3 + So = 25
So = 50/3 but this is in m/s have to convert to km/hr so,
50/3 * 18/5 = 60 Ans
25/3 from where and how ?
Thank you sir for such amazing session ❤❤
The homework ans 1) 60km/h
2) 6km/h ...
It is awesome studying with you 😊❤
How did u got 60 kmph please explain
See in question it's given
Lt = 150m
Lo = 100m
t = 10s
St = 30 km,/h
And we have to find So
So the solution will be based on the formula = St + So × t = Lt + Lo
Put the values now
30 + So × 10 = 150 + 100
30 + So × 10 = 250
30 + So = 250 /10
30 + So = 25
Now bcz the 25 is in m/s we have to change in km/h bcz all the options are in km/h
So
30 + So = 25 × 18÷5
After this the equation will be
30 + So = 90
Therefore
So = 90 - 30;
= 60 km/ h
Hence the ans is 60 km/ h
@@itstitanop1751 hope it's clear now ☺️
@@nausheenalia2142 yes now I got it. Tysm 🙂
@@itstitanop1751 Areh it's easy just practice and learn the formula 👍🏻😊 don't worry
42:00 answer 60 km / hr
47:20 answer 45 seconds sir
I was avoiding these topics since 2 years but you made it easy for me heartful thanks to you sir.❤
Exactly, mere sath bhi yhi huva
Vinit's sir's way of teaching is saving a lot of students, I am sure. He is making everything so easy. Thanks
Sir aap kitne pyaare ho yaar itne acche se kabhi koi nahi samjhata
His every 'Halua' is a confidence booster 🎉
Thank you, sir, aapki teaching skills itini acchi he ki ab me sapne me bhi quants karne lagi hu. kash aap thole jaldi mile hote but abhi bhi der nahi hui he..... thank you🙇♀🙏
1:21:30 answer 6km
Sir coaching me is topic ko 2 baar samjha tha pr ek qn nhi bna tha pr sch me apka samjhaya hua sare qn bn rhe thankyou so much ❤️
YES ,Sir chamak gya bilkul thanks to you from the deepest part of our heart
New to this but mba wallah teachers are best doesn't matter which subjects u r studying but they make u understand the tuffest thing
Sir no words no words. Mtlb unbelievable. Sir. I will get good percentile in cat then the credit goes to yu
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answer of homework =} (St+So)*T=Lt+Lo =} 60km/h
How did you do this .
This is the my most feared topic in entire quants syllabus but you made it look so easy and simple that I'm hating myself for being this dumb. Thank you sir for everything, I can literally solve any problem from this topic, may every weak student in quants find a teacher like you 🙏
Sir aapke padhane ka style sabse alag hai.....Bahut maja aati hai aapse padhne me....Thanku sir
HW1 -
Formula to be used - St - So * T =Lt + Lo
Answer - 60km/hr
St+So since it is in the opposite direction
HW
1 -> 60 km/h
2 -> 6 km/h
My answer for first is coming wrong. Please share the solution
Please provide me the solution of question 1
@@rohansingh8761 Even i was lookin for the same thing. So bsically
(25/3 + x) 10 = 250
=> 250/3+10x=250
=> 10x= 250-250/3( this was in addition so becomes subraction)
=> 10x=500/3
=> x= 16.666
=> 16.6666 * 18/5 = 59.99 = 60
How u got that 500/3 ?? 🙄
you made it complicated,
its just only 4 steps@@prashanthkumar1187
loved the train concept, was able to solve all on my own
Love you sir, your teaching Style is amazing. because of you Confidence level is very high
Thankyou so much sir. Very awesome and helpful class.please create playlists for other mba entrance exams also like cmat, mah CET and etc.
Really impressive sir, thanks alot
foundation playlists are a gem sir
aaj tak kabhi ye concept samajh nahi aaya 12th paar ho gayi aur parso JIPMAT exam hai
aaj jakar finally full clear
thankyou sir
MBA ke liye to aapse hi padhungi
Hii
wounderful sir . very nice explanation. hats off !!!!
chamak gaya sir By Heart ❤
Answer to homework…
Lt= 150 m
Lo= 100 m
T= 10 sec
St= 30 kmph
So= x kmph
We know, (St+So)*t= Lt+Lo
[(30+x)*5/18]*t= 150+100
(150+5x/18)* 10= 250
150+5x/18= 250/10
150+5x/18= 25
150+5x = 25*18
150+5x = 450
5x= 450-150
5x= 300
X= 300/5
X= 60 kmph
IN STARTING YOUCONVERTED 30 KMPH INTO MPS SO NOW IN LAST WE HAVE TO CONVERT 60 MPS INTO KMPH ??
@@krishshah7251 that's what am I thinking😢
Second ka bhi solution bta do
sir i have been watching your sessions and I have to say thank you so much for making these sessions . What an amazing video . Such a lovely session . May god bless you .
Osm lect. Sir.❤🎉 thankyou.
Sir homework question second ka answer no.C is correct option
Such that..up condition.
D=40km/h
T=8hrs.
So speed=d/t
40/8=5
And down condition..
D=49km
T=7km
:49/7 =7
Now: sb-sw=5....equ(1)st
And sb+sw=7 equ.(2) Ko add krne pr 2sb = 12
Sb= 6 km/h.
train crossing with length in oppostite dir ka anser - 60km/hour
Homework question 42:11 option B) 60km/hr
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Hi sir. Can you please take a lecture on race and clocks as well? Thank you!
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btw do youu know any other channel to watch this topic
amazing teaching style and thankyou so much for making it easy for us to understand better thankyou so much sir
The way u teach... we get much easily😇😇
A train overtakes two persons walking at 2 km/hr and 4 km/hr respectively and completely passes them respectively in 9 sec and 10 sec. The length of the train is
They are walking in opposite or same direction?
bahut achhi dua milengi aapko
Sir you are genius.
Homework Answer - B (60km/h)
The great teaching skills . 💥
Home work question -train 100m / 9s..
60km/h anssss
answer of hw number 2 is km/h that is option C
Amazing lecture sir 😊😊
when we go up and down the FLYOVER SIR same BOAT CONCEPT APPLIES ?
Amazing lecture
Thank u so much sir 😊
Option b ...60km per hour
Can you plz share the solution
Sir Maza aaya topic me 🙏🙏
first hw answer is 60 km that is option B
1:21:40 6km/hr
I have a question, why does time always be constant in train sums ?
Sir jii lecture me mza aa gya
Sir please Session ka pdf bhi description me provide kardo, taki hm baad mein sare questions practice kar sakein
hello sir aap bahut acche se concept clear kar diye guru ji ......love you sir ji 🥰🥰 but sir aap ne esclatore nhi padhaya hai
Sir pioneer batch ki preparation ke liye koi book bhi Leni hogi practice ke liye ya DPP se practice karna enough hoga?
Sir quant k liya kon sa book follow kare ?
thank u sir.
Relative speed of the two trains moving in the opposite direction i.e., towards each other, then in that case the speed should be S1-S2 ???
Yes
Bhut hen jhakas teacher with jhakas lecture.. Sir bhut thnku aisa lecture upload krte rhyega pura.
Is this helpful for cmat exam also ??? Plz anyone answer
Ans of HW is (b)60 km/h
Same
Sir you teach very well .
Love you 3000>
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Thx sir
So well explained
Very useful lecture
wah!
speechless.
B.60 (st+so)multiplyby2=lt+lo
Ans : 60km/hr
Is foundation batch not sufficient for cat???
Hw 1
Ans- 60km/hr
hey, you have a really beautiful smile. (don't consider me a creep, I'm not trying to slide in)
can you please explain the solution as well?
Thank you
2nd h.w is speed of boat is option [b] 5.5 km/h
Last q koi quadratic way me solve krke batao plzz
(14/5+x) + (9/5-x) = 5
Isko solve krne pe x(x-1)= 20 ara hai
Sirne opt se 2 bataya vo samjha
But ye last wale equation ko solve krke ans 2 kaise ayega any scholar here ?k
Solve the equation you have written by applying a^2-b^2= (a+b)(a-b) you’ll get a quadratic equation.. on solving the quadratic equation you’ll get two solutions 1 and -2 … speed can’t be negative hence 1and 2 both are true option a and B both are correct
Is this video also helpful for CUET PG MBA 2024 students??
1:25:47 3.75
Coaching mei 50,000 rs dekar UA-cam se padh rahi hun 👍🥲
Which coaching
Same
@@tomargamer2.o35 Which coaching ?
Samee😢😢
Same
Hw 2) -6km/hr
Ans HW = 60km/hr
HW 2 = 6 km/hr
60km/h how can you explain it
Ans 2:-6km/hr
Speed of boat in still water - 6 km/ h
Sir please provide dpp solution video
6km/hr is the boats sill water velociity homework 2
Chamka ❤
Could anyone provide me the solution of Homework 1 ? please bcoz I got different solution😮
Homework questions ka option B is correct answer.
Hi, Can you please help me know, if we have two different times for the trains, What do we have to consider?
same time pai lana hai dono ko
A_1) 60KMPH
Will legit dedicate that song by Osho for you sir, "aapke sath sab kuch itna aasan kaise hai" :)
nice song