Equations of Motion by Graphical Method

Equations of Motion by Graphical Method!
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If somebody ended up here to learn physics and reading comments to make sure that you are not gonna waste your time, then please go on. The best teacher for learning. You won't regret. I feel lucky that we have you sir for learning. Thanks a lot. May you live long. Aamin.

[@mathewjohn8126]

Precisely

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[@upholdjustice372]

10:23 - To find the Displacement, first of all, we can see that the area of this region is enclosed in a Quadrilateral, so let the *Quadrilateral formed be named OABD* (Naming from *Bottom-Left* to the *Top-Left* of the Quadrilateral) .
We can see that *OD || AB, but BD is NOT || OA, therefore the Quadrilateral is a Trapezium/Trapezoid.*
Let *P be a pt on AB* , such that *DP is the corresponding height of AB.*
Since *ar(Trapezium) = [(a+b)/2]×h*
where *a & b are the || sides, and h is the perp. dist. between the || sides,*
==> *ar(OABD) = [(OD+AB)/2]×DP*
==> *ar(OABD) = {[(50+100)/2]×11} m*
==> *ar(OABD) = [(150/2) × 11] m*
==> *ar(OABD) = (75 × 11) m*
==> *ar(OABD) = 825 m*
*∴ The body has been displaced by 825 m in 11 s, away from the starting point.*

[@fascinatingdiarieswithsamr5444]

I was just wondering only why this video is not my fav yt channel, but here it comes, glad to learn.
Thanks a ton for such a great explanation 👍 👏 😀

[@sdfglo6077]

Im in year 9 now and this new topic was really confusing since the teacher didn’t even explain. He just showed the formula so I’m happy I watched this video and learnt where these formulas are coming from

[@PramilaPatra-od5xd]

There is also a algebraic method you know or not ??

[@PramilaPatra-od5xd]

If not first learn that

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Respected sir you leave no stone unturned to deliver us concepts....
Thanks May you live long

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PW FOR JEE NEET NOT FOR BOARD EXAM.
PHYSICS WALLAH BY ALAKH PANDEY JI

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Thanks! You are a natural teacher

[@shreyasidutta4130]

Found this video at the perfect time.. Great explanation!

[@user-kk5vm5zc6u]

Sir please teach this derivation using calculus method for class 11

[@someone_ice]

love ur teaching better than my stupid school teachers

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I mean u explain things extremely well and one does not lose interest and listen to your lectures to the end.
I urge u to take on the topics in physics not easily understood and bring it on YT.
As an example, AC & DC motor and generators, Gyroscopic precession, and many more.

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Thank u so much sir. You made us to understand the concept very clearly . I usually watch ur videos frequently which helps me to learn the concept

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My all subject teacher 😊😊😊😊 thank you so much sir ☺️☺️☺️

[@vasantjartarkar2751]

Excellent demonstration

[@snowflake7624]

From velocity time graph we will get displacement or distance??

[@avigaming7723]

From velocity time graph you get acceleration
By area enclosed under a graph you get distance..

[@amnajaamna]

If the acceleration is in a straight line in specified direction (meaning it's constant and not variable) then distance and displacement can be used interchangebly in a velocity-time graph.

[@muthukumaran3488]

Thank u for the clear explanation sir😊

[@sulagna_.]

Thank you very much sir 🙏🏻

[@MulengaRichard-bx6xu]

Thanks sir for your good explanation

[@gsh20230]

Sir, to derive 2nd equation with graph 24:17
Can we directly use area of trapezium formulae - > 1/2(sum of parallel sides) h
I did by this, and derived it
Will it be right method?

[@lidiwids]

Thanks sir. Was really helpful, keep up the work sir....🎉

[@MartinezTech-jw7dy]

Thanks for making me understand how to derived Equations of motion

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Good explanation Sir

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Thanks

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I really like your class sir.it is very clear.thank you so much sir.

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Thanks sir

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I used to memorize but now i understand...thank you 🙏

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Nicely Explained.......thanks !

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Thank you! For more Videos and Live Classes do check out the Courses on our website: www.manochaacademy.com

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Thank you sir for teaching this clearly😊😊

[@siddhardhabanka7363]

sir in distance calucation in 5 sec we are actually caluclating the area under the graph so area units are m^2 but at the end of solution we are using distance units meters how? isn't contrast the units or is there any point i miss here could you pls let me clarify my doubt pls

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[@pandugamer8610]

Sir,I am studying in class 9.
I have a doubt regarding this topic.
Why do we take the initial velocity as non-zero at time 0 seconds on Velocity-Time graph to derive equations of motions.
Actually,Can velocity be non-zero when time taken is 0 ?
Sir,I am very confused.
Sir,Please clear my doubt..🙏

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Very well explained .Really enjoyed

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Please I need explanation on the relationship between temperature and humidity

[@naveedkhan-nt3eq]

Outstanding

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Thanks 😊

[@terencewright2223]

Great video. Thank you.

[@user-mh4th8zf8f]

our teacher say to read the equcation but this teacher say how become the equcation by graphial method👍

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Sir you are great thanks for your efforts 🙏❤

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Sir please explain about oblique projectile motion

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Nothing to say too much..
Just thank you so much ☺️

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BEAUTIFUL EXPLANATION

[@physics67]

Thank you.

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Very nice explanation

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Ready to hit 1 million subscribers

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Thank u for best explanation

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Really thanks a lot sir for ur clear explanation

[@rik_77]

VERY NICE SIR! Thanks

[@MunasheCharntelC]

Well explained thank you so much

[@rajvinderkaur5956]

We can also prove the 3rd equation by 2nd equation just put the value of t and eliminate

[@purshotamgami2037]

After 11:03 min, you introduced 3) area = xy = vt- this is not same as (0.5*u+v)average velocity x time

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Nice session

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Excellent sir.. 🙏🙏🙏🙏🙏🙏🙏

[@omxky]

Sir I am currently in 11th, your video got recommended to me while I was revising these derivations.
So I wanted to say thanks because you really helped in class 9th and 10th. I was able to secure 94% in class 10. Thankyou Sir

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Congratulations 👏 on your results! Great to hear that your videos were helpful! We are uploading Class 11 videos also on our channel! So you can watch them too :)

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Thank you sir for work done

[@abbanmuneesa]

Sir when we put vsq. At right side the u became - u

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10th like

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Thanks sir for help

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Thank you 💞 bro

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Welcome 😊

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I appreciate you guy

[@_sarath_official_8438]

Because, how can height be t. And parallel line would be v

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sir we can uderstand lesson easily

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god bless you

[@hafinessevoice2311]

Kinda confused; but how is 30 the maximum velocity....I thought it should be 40 cus it's the highest number.

[@ULTRAMARINEEDITZ1106]

Its because the body only reached 30m/s in the graph

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Hindi naam ki bhi koi chiz hai iss duniya mein

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Sir please explain in hindi 🙏

[@_sarath_official_8438]

Third derivation is quite confusion

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999k subscribers

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Tomorrow is my exam I was totally screwed until I saw this video

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please can I get the video before this