There are hundreds of videos on this subject in youtube. But you are standing out of all because of your simplicity but precise way of explaining. It is very clear to me. Thanks for your good job.
Hai sir, Really useful video. I have worked in SIEMENS and ABB as a electrical engineer but i have realized that i need to improve my technical skills. Your video gives good technical knowledge so keep it up!! And please add more video about relay coordination with upstream and downstream including discrimination time. Atleast add 11/0.433 kV incomer system and two LT motors of small kW rating then please give lecturer about relay setting calculation by considering EI,VI,NI curves. Thanks in Advance!!
Thank you for your comment. I will make video on the co ordination of relays. It may take some time, but I promise you that i will make video on those topic. Pleasr stay connected with my channel.
@@electricaltechnologyandind5335 Sir, everything was okay. you calculated everything but I don’t know where come from 60 m/sec? Pickup -5A, TSM-0.17, say time-0.5sec. But why you don’t use calculated value? 0.5+6=0.56 sec!!!
Please give me an example about the NPS setting and required unbalance current of the transformer to operate the relay.and also describe the TMS setting.thanks
Can you please share the fault current formula you have used? We have MVA actual, Voltage actual, and per unit impedance. How do I derive this formula?
Hello brother, my question is if i have given only characteristic A for ABB relay and fixed TMS by the designer does tripping time vary with fault current?
i have 2 x In given as 2 x 0.1A, time is 0.23 TMS, and Ia=0.1A TMS is fixed value does my relay operation time is different with fault current or it will always operate on same time which i set ? As i see you calculated fault current as with fixed values for PSM
no, for different fault current the psm will be different. the setting calculation is made based on the design fault current, where the fault impedances are ignored, to get the worst condition. but in actual there are fault impedance which reduces the fault current. so your relay operating time will vary. and that is the principle of idmt characteristics. inverse time, i.e. for higher fault current the operating time will be lower and for lower fault current the operating time will be higher.
ELECTRICAL TECHNOLOGY and INDUSTRIAL PRACTICE in my case no where written in serting that its IDMT its only written as Characteristic A whats that means curve?
sandeep kakulapati 1 second ago its depends on system withstandable sc current . For example breaker sc rating 40KA For 1sec, so rated fault current should be cleared within that time
Sir u said that pick up current is equal to pick up of relay then y u didn't put the 5A in denominator of PSM formula sir instead u multiply 120%with full load current, y so sir?
If so sir what is the difference between pick up of relay with CT value in formula and pick up current without CT value in formula which u have used in denominator of PSM? Kindly explain clearly sir!!
see suppose you have full load current 100A, Ct ratio of 120/1 A, then if you say i will set the relay to pick up at 120% of flc the your pick up will be 100*1.2*1/120=1
Hi sir good evening How can we select ct of 4000a when the fault current is More than the CT ratio. How can CT sustains excess current. Kindly let me know sir.
Every equipment has a continuous current rating and a short time withstand rating. Short circuit falls under short time category. That is why you need to specify ct as say 2000/1A, 50kA for 1 sec. High fault current will be tolerated only for 1 sec.
its depends on system withstandable sc current . For example breaker sc rating 40KA For 1sec, so rated fault current should be cleared within that time
Sir in definition you are saying pick up current as 120% of full load current however in calculation you are dividing it by CT ratio. I guess definition should be corrected. Similarly for PSM.
Breaker operating time is 0.5 sec again why you are adding 60msec? Here "t" is the breaker operating time. If you do back calculation you will get 0.495 which is 0.5 sec.
There are hundreds of videos on this subject in youtube. But you are standing out of all because of your simplicity but precise way of explaining. It is very clear to me. Thanks for your good job.
Thanks a lot... This made my day..... Keep sharing.. keep supporting...
Hai sir, Really useful video. I have worked in SIEMENS and ABB as a electrical engineer but i have realized that i need to improve my technical skills. Your video gives good technical knowledge so keep it up!! And please add more video about relay coordination with upstream and downstream including discrimination time. Atleast add 11/0.433 kV incomer system and two LT motors of small kW rating then please give lecturer about relay setting calculation by considering EI,VI,NI curves. Thanks in Advance!!
Thank you for your comment. I will make video on the co ordination of relays. It may take some time, but I promise you that i will make video on those topic. Pleasr stay connected with my channel.
@@electricaltechnologyandind5335
Sir, everything was okay. you calculated everything but I don’t know where come from 60 m/sec? Pickup -5A, TSM-0.17, say time-0.5sec. But why you don’t use calculated value? 0.5+6=0.56 sec!!!
I am from Philippines and i really appreciate this channel. This is very importamtivve
Share with your friends.....
Thank you for teaching. I like these VDO.
What is the use of TMS value calculated in the video?
Please give me an example about the NPS setting and required unbalance current of the transformer to operate the relay.and also describe the TMS setting.thanks
Very informative Sir. Wish more and more will come in the same way
Very good. Thanks 🙏🙏🙏🙏
Can you please share the fault current formula you have used?
We have MVA actual, Voltage actual, and per unit impedance.
How do I derive this formula?
Bro why did you add 60ms to 0.5s? What is the 60ms? What is the difference between the 0.5s and 60ms?
At last you have added 60ms in the Breaker Operating time, Is that you converted 0.17Sec=60ms?
ua-cam.com/video/ISdnXvNDRvc/v-deo.html
Psm.n tms calculation..easy trick
What standards for calculation of protective relay setting calculation
Clear and concise explanation.well done
Very important lesson 👌👌👌
Thanks a lot for the clear explanation
But i have a question how do we find the value of the required operation time which you have equal to 0.5 sec
Take me back to Electrical protection III, thank you sir for this information.
ua-cam.com/video/ISdnXvNDRvc/v-deo.html
Very nice. Thank u Sirji
Keep on, please show us the differential setting calculation for transformer
I shall release a series of videos fr different Protection. So please stay tuned and support
Thank you very match
How to calculate the settings for the feeder relay used on RMU.
😢ssazstslssaz😮s
Thank you! amazing work!
Great work by you
Thank you,
It is what I needed.
Thanks sir for the precise information, great work by you
ua-cam.com/video/ISdnXvNDRvc/v-deo.html
I have doubt in. What is pick up and pick up value is 5A or 1*CT sec /In is same?
Thank you dear. It enhanced my clarity.
Thank you so much sir please make another differential protection relay vedio
Thank you sir,very informative video🙏🙏,Plz Upload new video☑️
Thanks for solving my problem
For motor feeder how we consider
Hello brother, my question is if i have given only characteristic A for ABB relay and fixed TMS by the designer does tripping time vary with fault current?
yes
Yes. Idmtl characteristicvary with time
i have 2 x In given as 2 x 0.1A, time is 0.23 TMS, and Ia=0.1A TMS is fixed value does my relay operation time is different with fault current or it will always operate on same time which i set ? As i see you calculated fault current as with fixed values for PSM
no, for different fault current the psm will be different. the setting calculation is made based on the design fault current, where the fault impedances are ignored, to get the worst condition. but in actual there are fault impedance which reduces the fault current. so your relay operating time will vary. and that is the principle of idmt characteristics. inverse time, i.e. for higher fault current the operating time will be lower and for lower fault current the operating time will be higher.
ELECTRICAL TECHNOLOGY and INDUSTRIAL PRACTICE in my case no where written in serting that its IDMT its only written as Characteristic A whats that means curve?
@@TecKideos
As per IEC standard curve A means IEC standard inverse curve...
while calculating TMS, we have assume t=0.5 sec so how we can assume this data?
sandeep kakulapati
1 second ago
its depends on system withstandable sc current . For example breaker sc rating 40KA For 1sec, so rated fault current should be cleared within that time
Which technical book should we use for 50/51/50N/51N settings
I have a question, what is the time which relay needs to clear the fault?
Check my relay co ordination video
hi sir .how did you get psm value 0.02
Psm= fault current/pick up current
Sir u said that pick up current is equal to pick up of relay then y u didn't put the 5A in denominator of PSM formula sir instead u multiply 120%with full load current, y so sir?
If so sir what is the difference between pick up of relay with CT value in formula and pick up current without CT value in formula which u have used in denominator of PSM? Kindly explain clearly sir!!
see suppose you have full load current 100A, Ct ratio of 120/1 A, then if you say i will set the relay to pick up at 120% of flc the your pick up will be 100*1.2*1/120=1
incase your ct secondary is 5A then the oick up shall be 5
On which basis required time delay is taken 0.5 s
bro, may i know where did you got 0.14 in the calculation?
it is iec standard inverse relay characteristics. i have a video on different relay characteristics. watch that. your doubts will be cleared.
Hi sir good evening
How can we select ct of 4000a when the fault current is More than the CT ratio. How can CT sustains excess current. Kindly let me know sir.
Every equipment has a continuous current rating and a short time withstand rating. Short circuit falls under short time category. That is why you need to specify ct as say 2000/1A, 50kA for 1 sec. High fault current will be tolerated only for 1 sec.
@@electricaltechnologyandind5335
Thanks for clearing my doubt sir...... Thank you so much
Superb I even taken notes of everything
thank you. i was so clear
Where did sir get the 1.732 from ?
WHAT IS THAT FACTOR 0.14 FOR CALCULATING RELAY OPERATING TIME ?
ua-cam.com/video/ISdnXvNDRvc/v-deo.html
please show us some realys, and 220kv breakers details internal connetions and working procedure for example master relay , for 220kv
sf6 breakers ...
There are so many things, ok I shall try to make video on that
Thanks for this video
Thanks for the video. Please let me know why does t is taken as 0.5 sec only
its depends on system withstandable sc current . For example breaker sc rating 40KA For 1sec, so rated fault current should be cleared within that time
Kindly also discuss about the theory behind distance and directional relays
Sir in definition you are saying pick up current as 120% of full load current however in calculation you are dividing it by CT ratio. I guess definition should be corrected. Similarly for PSM.
How to set I> and I>> and Ie and Ie>> what does that term mean
Thanks a lot of.
And what is l> , l>> & l>>> ?
Thanks Sir ❤️❤️❤️❤️❤️❤️❤️❤️
Thanks you so much for your great video , Please tell me what is ( 0.02 & 0.14) in your calculation is it constant ?
yes
Afghan Wind & Solar Ltd Kabul formula for normal inverse curve setting
Good teaching
SIR HOW YOU DERIVED THE FAULT CURRENT ( BY WHAT PRINCIPLE ) ?
ua-cam.com/video/ISdnXvNDRvc/v-deo.html
i love your video
thanks for information
Bro how did you calculate fault current. Please share the formula
FLC/Impedance
Nyc explanation....sir ese type ka more videos upload kijiye
Sure...
Informative video
Hello Gentlemen very nice video
Could you please brief me about
I>,>>,I>>> pickup written in 7SJ62
Good topics
Nice job
Very helpful
Thank you.
0.14 kalkulation for destriction
Nice one
WHERE CAN I GET THE 1.732 NUMBER?
Sqrt(3)
Good tutorial
Please tell me how you said breaker operating time 60ms added.
in generally breaker operating time is 60 mSec. the breaker contacts need 60 mSec time to completely extinguish the arc.
Great
Hi Thanks for the video. Anyway can you make a make regarding TCC curves...Thanks
It is aldready there.. please check my different idmt relay characteristics video
Thanks you...
Sir it is requested make the formula correct,
PSM is the ratio between fault current in secondary of CT to pick up current.
Fault current/ pick up current. Either both shall be primary or secondary.
Please make vedio on relay-relay coordination calculations
already there .. please watch all of my Protection videos
Important part
Beautiful
The formula depends on what kind of relays to be used.
Yes. The formula given is normal inverse
Dear sir please make a vidio on p111 relay setting manually
Picture not showing clear.Make it clear.
Sir 0.08 kya hai plz describe
Where did you get 0.08??? The video was made long time back. I can not remember now
That's %. Impedance!
Thank you
Good
NICE ENGINEER
Nice
Nice explanation
U have any WhatsApp group sir?
No
Sir Daniel-a vanga en zawng helamah like. 🤣🤭 👍
Thanks a lot.
Sir what o.14
Last 0.5sec+60sec
=56sec how is
nice
Most useful
super
Thank you sir
LOVE it
Nic
Love it
joss
Wow
Breaker operating time is 0.5 sec again why you are adding 60msec? Here "t" is the breaker operating time. If you do back calculation you will get 0.495 which is 0.5 sec.
t is relay operating time and 60mS is breaker operating time after receipt of the trip signal from relay
wow
Wosm
Gd