just a personal preference and suggestion, let me know if i'm wrong. @time 5:50, normally we would indicate voltage drop as -ve and voltage rise as +ve; and for a resistor, convention is voltage drop. so for easier understanding, the equation using mesh analysis following your direction of current could be: +45(voltage rise) - 12.7ki(voltage drop) - 3(voltage drop) = 0; more of a convention thing. Yours is definitely not wrong as you used voltage drop logic or multiply the whole equation by -1 gives the same eqn. Anyway, great video, thanks for the sharing.
first of all, thank for your helpful video. And i have a question, i read from a book that :"we are not allowed to change dependent sources", can you clarify it for me, please!
in the first example if the two voltage sources "where they connected in series " add together then they will consider to be in the same direction and the result of the voltage sources will be 48 volt or we will subtract them and consider that they are in opposite direction and the result will be 42 volt ????? please if some one know answer me
Can anyone tell me why he put -51Vx and from where he got vx basically? Cuz in the mesh i sum the -7.5 ,+9 and -51 but as a voltages but he took it as -51Vx.
Two thumbs up for recapping the pens constantly, very pleasing to the ears.
Don't do it again ...you are un liking it🥺
The last part should be -70.5 and not -80.5. Hence -1.5/-70.5 and the answer would be 0.0213 A or 21.3 mA. Great video anyways :D
7 years later and still quality material here
Learnt this concept in few minutes because of your video.
Thanks a lot.
loved the tips, thank you so much for sharing this dear
Best video in UA-cam ... For source transformation.... Thanks sir....love from India...
Very end 2nd to last line is supposed to be -70.5i = -1.5. then i = .0213
+StephensEngineering Yes. lol. Kind of stuff always annoys me.
right
@@hoops129 He is not teaching you summation or substraction.
Try to focus on the main theme. Idiot
@@muhammadashikurrahman8367 oof.
@@muhammadashikurrahman8367 no man you are wrong he could have told us to do the math ourselves but he can't give us wrong answers
Thankyou for this video. This rescued my exam. :)
Very good..
I'm from India studying btech 1 st year u r video is simply superb sir thank you
just a personal preference and suggestion, let me know if i'm wrong. @time 5:50, normally we would indicate voltage drop as -ve and voltage rise as +ve; and for a resistor, convention is voltage drop. so for easier understanding, the equation using mesh analysis following your direction of current could be: +45(voltage rise) - 12.7ki(voltage drop) - 3(voltage drop) = 0; more of a convention thing.
Yours is definitely not wrong as you used voltage drop logic or multiply the whole equation by -1 gives the same eqn.
Anyway, great video, thanks for the sharing.
Exactly what KCL and KVL said
Awesome video to understand what source transformation is. It really helped me. Just one mistake is the last part as the other's said. Thank you!
No
very helpful video.... thanks for uploading sir...
Literally a lifesaver in circuits 1. TYSM!
Thank you a lot for this effort
Very informative and well taught
0.0212 A is the right answer for the last question !
BTW thank u Good video!!!
Thank you so much!
God these videos are helpful when used with the book.
Good Video.
Awesome video thank U very much ☺️
This video can totally make anyone understand that method
good video but you messed up the math at the end
This was very helpful, thank you.
Thank you!!
equation = -15%7+14i-51vx+26+2i+9=0
-15%7+16i+35-51vx=0
-15%7+16i+35-51(2i)=0
32.85-86i=0
32.85=86i
i think it is correct
Beautiful.
very helpful u explain it better than my professor in university
9:15 every time I look at my circuits homework
woow so nice
Thank you professor! this was really good!
first of all, thank for your helpful video. And i have a question, i read from a book that :"we are not allowed to change dependent sources", can you clarify it for me, please!
sir you are great thank you so much
this video is what, a good video
Thanks for this! Super helpful
Outstanding
I feel there was a calculation mistake in 2nd problem in the end. 31.5 i- 102 i= 70.5 i whereas u took 80.5 i.. Pls corect me if am mistaken
Thank's sir
Thank you sir
i think you forgot to multiply the 3.5 with 7.5 when you changed your current source back into the voltage source at the end
he did multiply while changing the current source to voltage source in the end...we needed to multiply 15/7 with 3.5 ...which comes out to be 7.5
-70.5i becomes and the result is 0.021276A
thanks a lot u made my day sir
Thank you sri..
13:45 how did write 7.5
Thank you
Just saved me :"D
that was truly useful
0:48 why the current goes upward? Doesn't the current enter positive terminal according to passive sign convention ?
final answer is 0.21A. thank you for this video sir!
brilliant.
Very helpful video. Thankyou 😊
really, really thanks!!! it help me a lot..... more than I can say....
very helpful thankyou sir ....
Very nice
thanks sir
this explanation is very useful for me
Good one
شكرا حبيبي يسلمي راسك
شو جنسية الاستاذ ؟
How to transform if the voltage source is in parallel to the resistor
thank you very much :)
your calculation is incorrect.
31.5 i-102i=-1.5
or -70.5i = -1.5
or i = 1.5/70.5
or i = 0.02 Amp
lol yours is incorrect
@@tibbysho2474 it is correct
Thanks
31,5I - 102.5 = -80.5 IS INCORRECT
Thank you sir!
Helpful
thank you :)
102-31.5=70.5
oh its example 5.5 from Engineering circuit Analysis 8th edition by william hayt...... And its 70.5 instead of 80.5 in 2nd pb.
why it doesn't was +51 vx , the polarity of the voltage at the same direction of the current!!
Why are the Voltage drops positive?
in the first example if the two voltage sources "where they connected in series " add together then they will consider to be in the same direction and the result of the voltage sources will be 48 volt or we will subtract them and consider that they are in opposite direction and the result will be 42 volt ????? please if some one know answer me
Thankyou so much sir!
Can anyone tell me why he put -51Vx and from where he got vx basically? Cuz in the mesh i sum the -7.5 ,+9 and -51 but as a voltages but he took it as -51Vx.
Sir can we apply source transformation at independent sources 12:01
why is it negative 7.5
Thankeww so much sir😃
thx
Can we add 3.5 ohm resister with 26 ohm resister?
thnz
Nice teaching but checkout with your camera
thank u for help bro
while applying kvl 51vx is (+51vx) how come -51vx ? when it is positive going ramp side
he goes clockwise which means he enters the voltage source from the negative terminal
which means -51vx
+Gawkie thnk u
abhishek hinba youre welcome ^^
how do i know that 2 ohms there = to vx?
IN EX.1 cant I add the voltage sources together since they're series aiding? so V=IR, 48=12700I, I = 3.8mA?...
Thanks sir
Video starts at 0:22
why we didnt convert the units?
Excuse me teacher there is something wrong i = 0.021 A
Using the source transformation method, find Vo in the network...how??
source transformation in easiest steps
31.5-102 is equal to 70.5 not 80.5
Why you did source transfermation twice in last question
you can see doing that makes the circuit simplifies into a single loop which we can solve by only one equation
Isn't it 70.5
why Vx=2 ?
Massive screw up at the end there...... -102 + 31.5 = 70.5 Not 80.5..... Oh well.
Last sum that is not 7.5 it is 2.5 I.e 15÷7
i think answer is wrong
31-5 - 102 = 70.5 ******
Ur answer is wrong
LOL.....Wrong calculation...
arapları severim ama dislike verdim
Really bad way of teaching. I wonder how many of he's student actually got jobs in this field?