Nucleophiles, Electrophiles, Leaving Groups, and the SN2 Reaction
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- Опубліковано 4 сер 2024
- This is it! The start of the very scary reaction mechanisms! Take it easy, chief. First we will define nucleophiles, electrophiles, and leaving groups. Then, we will examine the mechanism, transition state, and stereospecificity of the SN2 reaction. Push those electrons!
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it is not always the case that if SN2 occurs on the chiral center it will necessarily invert the steriochemistry there. Because if the incoming nucleophile has a different Cahn-Ingold-Prelog priority from the leaving group.
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One question I have regarding this: what property of the leaving group or incoming nucleophile enables the reaction to proceed forward? (i.e. allows the carbon to dissociate from the Cl- and form a bond with OH- instead) Is there a way of theoretically determining which form (OH bound vs Cl bound) is likely to be in higher concentration in a solution that has been allowed to reach equilibrium?
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Perfect explanation. I do think it would be helpful to show another rxn to more clearly depict the inversion of stereochemistry
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Hi there! First off, your videos are amazing and so helpful. Thank you so much for helping students like me understand difficult concepts! Secondly, you mentioned that an inversion happens at a stereocenter but the compound drawn doesn't have a stereocenter. Just wondering why it had an inversion? Thank you!
well it will always invert, but if it's not a chiral center it won't matter!
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I understand the example used in the video but when I try to do an sn2 reaction with OH- and
H
Br-h
H3C I cant seem to figure out where should the OH- attack from.
Good
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Amazing video on explaining SN2 reaction! Just a question, at 2:27, surely you must mean the oxygen atom is the electron-rich atom? Not oxygen-rich atom? Keep up the great work Professor Dave :D
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